AB M
|AM| : |MB| = p : q p q
|AM| |MB|
AM MB
p q
AB p + q
AM p MB q
A M B
q p
p q
M AB
A M B
m
w −m |AB| = w w
MB |MB| = m M m
(w −m) : m = p : q w > m p > 0 q > 0
p = q = 1 w −m = m
M w
∗
w1 w2 m w1 > m > w2 p q w1 w2 m
(w1 −m) : (m−w2) = p : q w1 > m > w2 p > 0 q > 0
w2 = 0 ∗∗
p q m
p : q p : q ∈ {w1 : w1,w1 : m,w1 : w2,m :w1,m : w2,w2 : w1,w2 : m}
p : q = w1 :w1,p :q = w1 : m p : q = w1 : w2.
(w1−m) : (m−w2) = w1 : w1 w1−m = m−w2 =⇒m = 12(w1+w2) ma w1 w2 1
2(w1 +w2)
(w1 − m) : (m − w2) = w1 : m m(w1 − m) = w1(m − w2) =⇒ m2 = w1w2 =⇒ m = √w1w2
mg w1 w2 √w1w2
(w1 − m) : (m − w2) = w1 : w2 w2(w1 − m) = w1(m − w2) =⇒ m = w2w1+w1w22 = 1 2
w1+w1
2
mh w1 w2 2w1w2 : (w1 + w2)
= 2 :
w11 + w12
ma mg mh
∗∗
AB BC
|AB| |BC| AC
H M
D H
BD ⊥ AB E
DM BE ⊥ DM A M B C
E H D
|DM| = |AM| = 12
|AB|+|BC|
|DM|
|AB| |BC|
ACD ∗∗∗
|BD|2 = |AB| · |BC| |BD| =
|AB| · |BC|
|BD| |AB| |BC|
DMB DEB
|BE|2 = |DE|
|DM| − |DE|
= |DE||DM| − |DE|2
|BE|2 = |BD|2 − |DE|2
|DE|
12
|AB|+|BC|
− |DE|2 = |DE||DM| − |DE|2 = |BD|2− |DE|2
= |AB||BC| − |DE|2
|DE| = |AB|+|BC2|AB||BC|| |DE|
|AB| |BC|
w1 w2
n w1 w2 wn n ≥ 2
wi
i 1 2 3 4 5
wi 3 4 6 5 4 ⇒ma = 4,4
ma−wi wi
ma 1,4 0,4 −1,6 −0,6 0,4
ma ma = 15(3 + 4 + 6 + 5 + 4) = 4,4 ma
wi
ma 0
w1 w2 wn n ≥ 2 1n(w1 + w2 + ... + wn) ma
e i ai wi
i
i 0 1 2 3 4 5
ai 2000 2240 2419,20 2878,85 3022,79 3173,93
wi 1,12 1,08 1,19 1,05 1,05
ai i = 1, 2, ..., 5 a0 = 2000 a1 = w1a0 a2 = w2a1 = w1w2a0 a5 = w5a4 = w1w2w3w4w5a0
mg a∗i = ai i = 1, 2, 3, 4
a∗1 = mga0 a∗2 = mga∗1 = m2ga0 a∗5 = m5ga0
mg a∗5 = a5 mg
m5ga0 = w1w2·...·w5a0 mg = √5w1w2 ·...·w5
mg 1,1
w1 w2 wn n ≥ 2 √n w1w2 ·...·wn
mg
200 kmh
i 1 2 3 4 5
vi i kmh 185,4 198,7 201,1 199,2 218,4
v v
v = .
L L
185,4 L
198,7 L
218,4
v
v = 5L
185,4L + 198,7L + ... + 218,4L = 5
185,41 + 198,71 + ... + 218,41 ≈ 200,016.
mh
w1 w2 wn n ≥ 2 1 n w1+w1
2+...+wn1
mh
11 + 12 + 13 + ...
n (n+2)
2
11
n
+
11 n+2=
2
n + n + 2
=1 n + 1
.1+12+13+14+...
∗∗∗∗
{1, 2, 3, 4, 5, 6} 3
2 6 4 3 6
11 + 12 + 13 + 14 + ...
∗
≈ 14,392 1,51·1043
> 100
12 + 13 > 2· 14 = 12 14 + 15 + 16 + 17 > 4· 18 = 12
18 + 19 + ... + 151 > 8· 161 = 12
1 1+
„1 2 + 1
3
« +
„1 4 + 1
5 + 1 6 + 1
7
« +
„1 8 + 1
9 + ... + 1 15
«
+ ...>1 +1 2+ 1
2+1 2+ ...
112 + 212 +
312 + 412 + ...
∗
112 + 212 + 312 + 412 + ...
1 12 +
„ 1 22 + 1
32
« +
„ 1 42 + 1
52 + 1 62 + 1
72
« +
„ 1 82 + 1
92 + ... + 1 152
« + ...
<1 + 2· 1
22 + 4· 1
42 + 8· 1
82 + ... = 1 + 1 2 + 1
4 + 1 8 + ...
2 < 2
∗∗
P(x) = x· 1− x
π 1 + x
π 1− x
2π 1 + x
2π 1− x
3π 1 + x 3π
·...
sin 0 ±π ±2π
±3π
x sinx = x ·
1− πx22 1− 4πx22 1− 9πx22
·...
sinx
x3 x5 x7
sinx
x x3
x sinx = x1−x3
π12 + 4π12 + 9π12 + ...
+x5(...)−...
x1 − x3
π12 + 4π12 + 9π12 + ...
+ x5(...) − ...
= x1− x63 + 120x5 −...
x3
1 12 + 1
22 + 1
32 + ... = π2 6 .
ζ(s)
ζ(s) = 11s + 21s + 31s + ... s ≥ 2
ζ(4) = 114 + 214 + 314 + ... = 90π
ζ(s) s ≥ 6
ζ(s) p1 = 2
p2 = 3 p3 = 5 ζ(s) =
1− p1s 1
−1
1− p1s 2
−1
1− p1s 3
−1
·... s > 1 s > 1
n 2n n > 1
s
ζ(s)
π(x) < x
• ≥ 4
•
a 11 + 12 + 13 + 14 + ... = a
b c
11 + 13 + 15 + 17 + ... = b 12 + 14 + 16 + 18 + ... =c ∗∗∗
a = b+c
a b c b c
a = b+c > 2c = 2·1
2 + 14 + 16 + 18 + ...
= 11 + 12 + 13 + 14 + ... = a
a a > a
11 + 12 + 13 + 14 + ... = ∞
1 + 1 + 1 + 1 + ... = ∞ 1 + 1 + 1 + 1 + ... = ∞
e
•
•
•
k2 ∗ k
1 n
n n = 2008
s ≤ n
1 2 3 s
s s
s
s s
s g u
g g g 0
g u u g u 0
u u g −2
1 2 3 s
1 2 3 s s = 2007 s = 2008
1004 s s = 2005
s = 2006 1003 s
s = 4m− 1 s = 4m
s = 4m+ 1 s = 4m+ 2 m s ≤ n
∗
n n! + 1 n! 1·2·3·...·n
n
n < 10t t
n! +m m > 1 n m n! +m m ≥ 1
n = 1 2 4 nn + 1
n nn + 1
∗ †
n ≤ 100 nn + m m 1 20
n ≤ 100 m ≤ 20 nn +m
m 1 2 3 4 6 7 9 10
n 1, 2, 4 1, 3 2 1, 3, 7, 43 1 2, 4, 6, 32 2 1, 3, 7, 9, 39
m 12 13 14 15 16 18 19 20
n 1, 5 2, 4, 16, 42 3, 23 2, 4 1, 3, 13 1, 19, 49 2, 10, 30 3, 53
m 100
1≤ n ≤ 200 −100 ≤ m ≤ 100 n ≤ 15 m ≤ 20
n ≤ 12 m ≤ 20
6·8 = 48
5·5+4·6 = 25+24 = 49
5·6 + 4·5 = 30 + 20 = 50
10 cm 5·√
3 cm 5+8·5·√
3+5 = 10+40·√ 3≈ 79,28 < 80
10 : 4 = 2,5 3· 4 = 12
90◦
1
2
24−21 = 3
x y z x ≤ y ≤ z
x +y + z = x · y ·z xyz
yz1 + xz1 + xy1 = 1 x ≤ z xy1 ≥ yz1 y ≤ z
xy1 ≥ xz1 1 = 1
yz + 1
xz + 1
xy ≤ 3 xy.
1 ≤ xy3 y {1, 2, 3} x = 1
x ≤ y x ≤ 3y
(x,y)
y = 2 x = 1 z = 3 x = 1 y = 2 z = 3
↑
↓
x ↑ y
↓ 99 = 1 + 13x −9y 9(y + 11) = 1 + 13x
1 + 13x 9
y ≥ 0 13x ≥ 98 x ≥ 8
x = 11 y = 5 99 = 1 + 13·11−9·5
0 3 7
1 4 8
2 5 1
2 5 9
3 0 4
3 6 2
4 1 5
4 7 3
5 2 6
5 8 4
6 3 7
6 9 5
7 4 8
8 5 1
8 5 9
9 6 2
10 − 3 = 7 16·7 = 112
(2007 + 2007) + (2007−2007) + (2007·2007) + (2007 : 2007)
2008 = 2008
x = −1,x = 0
T(x) := (x+x) + (x−x) + (x·x) + (x : x) = 2x+ 0 +x2+ 1 = (x+ 1)2.
T(x)
x+1 = x + 1
x = 2007
x −1 = x = 0
0 9
1·103+ 9·102 + 5·101+ 8·100 1958 10
0 7
8
S1 = 1−2 + 3−4 + 5−6 + 7−... + 2007−2008 S2 = 1 + 2−3 + 4−5 + 6−7 + ...−2007 + 2008
e e
e
499 500 501 502 502 503 504
505
S S
p = 5 p4 − 1 10
0
1 + 20072009 2008
Z = 20092008 −20072008 16
Z
2 251
7571
141%
200%
2, 4, 6, 8, ... , 50 1
n = 0 n = 1 n = 2
2008 √
2011·2009 + 1 √
2009·2007 + 1 √
2007·2005 + 1
(a+ 1)·(a−1) + 1 = √
a2−1 + 1 = √
a2 = a
√2011·2009 + 1 = 2010 √
2009·2007 + 1 = 2008
√2007·2005 + 1 = 2006
2010+2008+2006
3 = 60243 = 2008
12 1
3 1
4
n sn = n
i=1 1i
(sn)
k n 2k−1 < n ≤ 2k 1n ≥ 21k
2k−1 2k
s2k =
2k i=1
1
i = 1 +
k j=1
⎛
⎝ 2
j
i=2j−1+1
1 i
⎞
⎠ ≥ 1 +
k j=1
⎛
⎝ 2
j
i=2j−1+1
1 2j
⎞
⎠
= 1 +
k j=1
2j−1 1
2j = 1 +
k j=1
1
2 = 1 + k 2. (sn)
123671
x2
yz − y2
xz − z2
xy = 3 x2z
y − 2z y = 2 x,y,z ≥ 1
x > y
2y ≥ x2 −2
x2
yz = y2
xz + z2 xy + 3 z2
xy > 0 x2
yz > y2
xz x3 > y3 x > y y 2y = x2z −2z = (x2−2)z ≥ x2−2 z ≥ 1 x2−2 > 0
2x > 2y ≥ x2− 2 2x > x2 −2 0> x2 −2x + 1−3
3> (x −1)2
x ≥ 1 x = 1 x = 2
x = 1 −z
y = 2
x = 2 2z
y = 2 y = z
4 y2 − y
2 − y
2 = 3 y3 + 3y2 = 4 y = 1
x = 2,y = 1,z = 1
n
n = 2007
n > 3
n = 4 n = 6 n = 8 n > 8
•
•
•
v = st s = tv s = 2,5·(vB +vF) s = 3,75·(vB − vF)
vf
2,5·(vB +vF) = 3,75·(vB −vF)
⇐⇒ 2,5vB + 2,5vF = 3,75vB −3,75vF
⇐⇒ 6,25vF = 1,25vB
⇐⇒ vF = 1
5vB
s = 2,5(vB + 15vB) = 3vB
t = vsB = 3vvBB = 3 [Stunden]
2
a0 b0 a0 : b0 = 1 : √ 2
an bn an+1 = b2n
bn+1 = an
an : bn = 1 : √ n 2
a0 b0 c0 a0b0c0 = 1 m3 a0 < b0 < c0
an+1 = c2n bn+1 = an cn+1 = bn an : bn : cn = a0 : b0 : c0 n
a0 : b0 : c0 = c20 : a0 : b0 b0
a0 = 2ac00 bc00 = ba00 c0 = ba002
b0
a0 = 2ac00 = 2ab220 0
b0
a0 = √3
2 bc00 = √3 2
a0b0c0 = 1 1 = a0b0c0 = a0 · ba00a0 · cb00 ba00a0 = 2a30 a0 = 3
12 = √31
2 b0 = a0√3
2 = 1 c0 = √3 2
x1,x2,x3...
x1 = x2 = 1 x2n+1x2n−1−x2n2 = 1 x2n+12 −x2nx2n+2 = 1
xn n = 3, 4, 5, 6, 7, 8
2, 3, 5, 8, 13, 21
∗
x2n+12 −x2nx2n+2 (∗)= x2n+1x2n−1− x2n2 (∗∗)= x2n−12 −x2n−2x2n = ... = x3x1−x22 = 1
(∗) x2n+12 − x2nx2n+2 − (x2n+1x2n−1 − x2n2 ) = x2n+1(x2n+1 − x2n−1) − x2n(x2n+2 −x2n) (•)= x2n+1x2n −x2nx2n+1 = 0
(∗∗) x2n+1x2n−1 − x2n2 − (x2n−12 − x2n−2x2n) = x2n−1(x2n+1 − x2n−1) − x2n(x2n −x2n−2) (•)= x2n−1x2n −x2nx2n−1 = 0
(•)= xk+2 =
xk+1 +xk
12n − 1 11
13n−1 12
14n−1 13 n = 1, 2, 3, ...
n ∈ a
an −1 = (a− 1)(an−1 +an−2+ ... +a1 + 1)
a = 1 a = 2 a = 12 a = 13 a = 14
n ∈ an−1 a−1
(x + 1)n −1 (x+1)n−1 =
n−1 k=0
n k
xn−k+1−1 =
n−1 k=0
n k
xn−k = x·
n−1 k=0
n k
xn−k−1
x ≡ m mod n
x :n m
a ≡ 1 mod (a− 1)
=⇒ an ≡ 1n ≡ 1 mod (a− 1)
=⇒ an− 1≡ 1n −1≡ 1−1≡ 0 mod (a−1)
A(1) 1
A(n+ 1) A(n)
n = 1 a1−1 = a−1 = 1·(a−1) n ⇒ n+ 1 n
an+1 −1 =an+1 −a+ (a−1) = a·(an −1) + (a−1) an − 1 a − 1
=⇒ an+1 −1 a −1
n
an −1 = (a2−1 + 1)·an−2−1 = ((a− 1)(a+ 1) + 1)·an−2− 1
= (a− 1)(a + 1)an−2+an−2−1
a2 − 1
a1−1 = a−1 a−1
a = 12 n = 2
122−1 = 12·12−1 = 12 + ... + 12
12−
−1 = 11+12 + ... + 12
11−
= 11+11·12, 1
a
12n + 1 13 n ∈
n = 2k + 1 k = 0, 1, 2, ...
an + 1 =a2k+1+ 1 = ((a+ 1)−1)2k+1 + 1 = (a+ 1)(...)−1 + 1
= (a+ 1)(...), (a+ 1)|an + 1
12n+ 1
13 n ∈
1n n > 1 1 : n
L
1n
371 = 1 : 37 = 0,027 027 027... = 0,027 L
371
= 3
m 1n
p1 p L
1n
= m L
p1
= m m = 1 2 3
p = 2 L
1p
= p− 1 L
p1
(1, 102) (1, 103) (1, 104)
∗
m n L
1n
= m
13 = 0,3 331 = 0,03 3331 = 0,003 L
m 1
i=13·10i−1
= m m ∈
19 = 0,1 991 = 0,01 9991 = 0,001 L
m 1
i=19·10i−1
= m m ∈
11 = 0,9 111 = 0,09 1111 = 0,009 L
m 1
i=11·10i−1
= m m ∈ ,
m = 1
m p
L
p1
= m
L1
n
L
p1
p n
19 7 17
100 7 17 19
23 29 47 59 61 97
1 000 10 000
1 000 16860 ≈ 0,36 10 000
1229467 ≈ 0,38
0,40 0,35
(x,y) 1x + 1y = 13
\{0, 3}
1x + y1 = 13 3xy x
x 1 x+1
y = 1
3 ⇐⇒ 3y+3x = xy ⇐⇒3y = x(y−3)⇐⇒ x = 3y
y −3 = 3+ 9 y − 3.
x (y − 3) 9 (y −3) ∈
{−9,−3,−1, 1, 3, 9} y ∈ {−6, 0, 2, 4, 6, 12} y = 0 y
y ∈ {−6, 2, 4, 6, 12} x ∈ {2,−6, 12, 6, 4}
(2,−6) (−6, 2) (12, 4) (6, 6) (4, 12)
n
n = 4 n = 7 n = 10
n = 4 n = 7 n = 10 n = 5
n = 6
2 : 3
n = 1
n = 2 n = 3
n = 6 n = 8
3 : 4 n = 5 n = 7 n = 8 n > 8
n > 8 3 n = 6 n = 7 n = 8
n > 8
n = 4 n > 5 n
A P B
Q
C D
α1
α2
ABCD |AB| > |CD|
AB D
AB P
AC Q AC
A α1 α2
α1 = 2α2 QC AD
|QC| = 2|AD| α1
α2
M
QDC = 90◦ C D Q
M r =
|MC| A α2 B
α1
P Q
C D
M
β2 = α2
β1 = β2
CDM CD
δ = 180◦−β1−β2
χ = 180◦−δ
α2
A B
α1
P Q
C D
M β1 β2
χ δ
δ = 180◦−2β2
χ = 180◦−δ = 2β2
α1 = 2α2
=⇒ |AD| = |MD| = |MC|= 12|QC|
=⇒ QC AD
|AD| = 12|QC|
=⇒ |AD| = |MD|
=⇒ AMD AM
=⇒ α1 = χ
=⇒ α1 = 2α2
n
a b a
a = 0 a
b a 10−1 = 9
b = a 9· 9 = 81
aaabb
a ∗ ∗ ... ∗ ∗ n 1. 2. 3. (n−1). n.
a a b
2n−1 a b
n a (2n−1−1)n
a b a b
81·(2n−1−1) n n = 5 81·(25−1−1) = 1215n
n = 6 81·(26−1−1) = 2511 n = 7 81·(27−1−1) = 5103
∗
0,514
3 : 5 e e
e 3
8
∗ †
38 ·8e+ 58 ·0e = 3e
38 ·0e+ 58 ·8e = 5e
16
N =
496
· 43 · 10N1
43·9N ≈ 8·10−8 43
N A
A
∗∗
K R
14 r K
πr2
πR2 = r
R
2
A P(A)
0 1
1 0
A B
C A B P(C) =P(A) +P(B)
∗∗∗
Ω
Ω A A
P(A) P(∅) = 0 P(Ω) = 1
A1 A2 A3 Ai ∩Aj = ∅ i = j
P(A1 ∪A2∪A3 ∪...) =P(A1) +P(A2) +P(A3) + ...
σ
Ω Ω
P
A
∅ ∈A Ω ∈ A A1∪A2∪A3∪...∈ A A1,A2,A3, ... A σσ
(Ω,A,P)
Ω σ A
A P
∗∗∗
e