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(b) If for any i, j∈I there existsk∈I such thatTi∪Tj ⊆Tk, thenSi∈ITi is a preordering ofK

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Fachbereich Mathematik und Statistik Prof. Dr. Salma Kuhlmann

Lothar Sebastian Krapp Simon Müller

WS 2018 / 2019

Real Algebraic Geometry I

Exercise Sheet 3

Extensions of orderings and Laurent series

Exercise 9 (4 points)

Let K be a field and let T ={Ti|iI} be a family of preorderings onK. Show that:

(a) The intersectionTi∈ITi is a preordering onK.

(b) If for any i, jI there existskI such thatTiTjTk, thenSi∈ITi is a preordering ofK.

Exercise 10 (4 points)

Show by induction on n ∈ N: Any ordering on a field K extends to an ordering on the field of rational functions in several variables K(x1, . . . ,xn).

Exercise 11 (4 points)

We proved in lecture 2 that each Dedekind cut of R corresponds to an ordering on R[x] and in particular onR(x). Describe explicitly the ordering onR[x] corresponding to each Dedekind cut of R. Proceed as follows:

(a) Retrieve the orderings on R[x] corresponding to 0+ and 0, using the derivatives of a generic polynomial p∈R[x] at 0.

(b) Using the same techniques as in (a), describe the orderings on R[x] corresponding to all the remaining Dedekind cuts of R.

(c) Conclude that there exists a function

σ:R[x]→R such that sign(p(x)) = sign(σ(p)) for anyp∈R[x].

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Exercise 12 (4 points)

We denote the set of real formal Laurent seriesby

R((X)) :=

( X

i=m

aiXi

m∈Z, ai ∈R )

.

For any 06=A∈R((X)), we define v(A) to be the smallest integer m such that am 6= 0. Moreover, for any

A=

X

i=m

aiXi∈R((X)) andB =

X

i=n

biXi ∈R((X)), we define:

• thecoefficientwise addition

A+B :=

X

i=k

(ai+bi)Xi,

where k= min{m, n} and we setai = 0 for i < mand bi= 0 fori < n;

• theconvolution product

AB:=

X

i=m+n

X

j+k=i

ajbk

Xi;

• theorder relation

A≥0 :⇐⇒A= 0∨A6= 0∧av(A)>0.

It can be shown that R((X)) endowed with these operations and order relation is an ordered field and that R[[X]] is a subring of R((X)).

(a) Show that the map v :R((X))× → Z is a discrete valuation on R((X))× =R((X))\ {0}, i.e.

that for anyA, B ∈R((X))×, the following hold:

(i) v(A+B)≥min{v(A), v(B)}.

(ii) v(AB) =v(A) +v(B).

(b) Deduce thatR((X)) is not real closed.

Please hand in your solutions by Thursday, 15 November 2018, 08:15h (postbox 16 in F4).

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