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Problem 23: Path integral for charged particle in elm. eld 5 points The Lagrangian of a charged particle in an external electromagnetic eld is

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Friedrich-Schiller-Universität Jena Winter term 2017/18 Prof. Dr. Andreas Wipf

Dr. Luca Zambelli

Problems in Advanced Quantum Mechanics Problem Sheet 10

Problem 23: Path integral for charged particle in elm. eld 5 points The Lagrangian of a charged particle in an external electromagnetic eld is

L = m

2 x ˙

2

+ L

int

, L

int

= e

c x ˙ · A (t, x ) − eϕ(t, x ).

where the potentials are related to the electromagnetic elds via E = −∇ϕ − 1

c

∂t A , B = ∇ × A . The corresponding Hamilton-Function reads

H = 1 2m

p − e

c A (t, x )

2

+ eϕ(t, x ),

The wave function at time t is related to the wave function at time t − via ψ(t, x ) =

Z

d

3

y K (t, x ; t − , y )ψ(t − , y )

We assume that the path integral representation for the evolution kernel K holds true,

K(t, x ; t

0

, y ) ∝

x(t)=x

Z

x(t0)=y

D x e

iS/~

For small we may approximate the Riemann-integral as S ≈ m

2 u

2

+ L

int

, L

int

= e c

u · A

t −

2 , x − u 2

− eϕ t −

2 , x − u 2

with u = x − y. Then the path integral for the propagation during the time interval is ψ(t, x ) = lim

→0

C

3

Z

d

3

u exp im

2 ~ u

2

exp i

~ L

int

ψ(t − , x − u ) ,

where C

= (m/2πi ~ )

1/2

. In the lecture is has been stated that for → 0 this wave function obeys the time-dependent Schrödinger equation with above Hamiltonian. The essential steps to prove this statement have been sketched in general and worked for two typical terms appearing in an expansion in . In this exercise you should now ll the gaps in the arguments and prove the statement in detail.

Submission date: Thursday, 11. January 2018, before the lecture begins.

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