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Convex vNM–Stable Sets for a Semi Orthogonal Game. Part III: A Small Economy - Uniqueness and Multiple Solutions

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Center for

Mathematical Economics

Working Papers 500

2014

Convex vNM–Stable Sets for a

Semi Orthogonal Game

Part III:

A Small Economy - Uniqueness and Multiple Solutions

Joachim Rosenm¨ uller

Center for Mathematical Economics (IMW) Bielefeld University

Universit¨ atsstraße 25 D-33615 Bielefeld · Germany e-mail: imw@uni-bielefeld.de http://www.imw.uni-bielefeld.de/wp/

ISSN: 0931-6558

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m 2 (1 − h 3 ) ≥ h 2 (1 − m 3 ).

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h τ < m τ (τ = 2, 3)

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ε > 0

(

ϑ x b

(

η

$$

(

e

234

S

5 th STEP :

2 *

&!$55'

h 2 + h 3 ≤ m 2 + m 3 ≤ 1,

m 2 < h 2 , h 3 < m 3 .

23

234

$

)

((

* )

( J

((

!$*$

*((

m 2 >

h 2 , h 3 > m 3

*

$

(15)

?

?

2

/

(

H

* 7 )

$

(

H b

(

(

&

ϑ ¯ = ϑ x ¯ ∈ H b

1)

ϑ ¯ ∈ / H b

(

ϑ b ∈ H b

&& ( &'(

'

&

(

(

'

'

S b

&!

$

56'

ϑ b dom S b ϑ ¯

$

J

(

(

)

ϑ b

*

c m = ( m b 1 , . . . , m b 4 )

&!

$

5'

m b τ := ess inf D τ ϑ b (τ = 1, 2, 3, 4).

1 st STEP :

&!$5' %

(

$$$

( m b 2 , m b 3 ) ≥ (h 2 , h 3 ).

1

ϑ b

( * &J((!

$

6'

a 23 c m ≥ h 2 , a 32 c m ≥ h 3 .

1)

)

2

3

)

m c

2 !$!$

#

*

(

)

2, 3

(

*

)

x ¯

$

$

)

(h 2 , h 3 )

$ K

(

m b 3 ≤ h 3

* 2

!

$

!

$

(

ϑ 0 := (1 − t) ϑ b + te 23 ∈ H b

)

t := ¯ x 3 − m b 3

$

J

(

( )

ϑ 0

*

m 0

&!

$

5'

(m 0 2 , m 0 3 ) ≥ (¯ x 2 , x ¯ 3 ).

)

( )

(

!

$

5

$

2 nd STEP :

# / (

&!

$

5'

x ¯ 4 ≥ m b 4 .

@ )

&!

$

5'

¯

x 1 λ 1 + ¯ x 2 λ 2 + ¯ x 3 λ 3 + ¯ x 4 λ 4 = 1, b

m 1 λ 1 + m b 2 λ 2 + m b 3 λ 3 + m b 4 λ 4 ≤ 1

(16)

a 23 x = h 2

a 32 x = h 3

h 2 h 3

x 2

x 3

x ¯ m 0

c m

{x a 23 x ≥ h 2 , a 32 x ≥ h 3 }

2

!

$

!4

2

3

)

m c

x ¯

b

m 1 λ 1 + m b 4 λ 4 ≤ x ¯ 1 λ 1 + ¯ x 4 λ 4 = 1 − (¯ x 2 λ 2 + ¯ x 3 λ 3 )

= 1 − (h 2 λ 2 + h 3 λ 3 ) = 1 − λ 0 23 .

#

ϑ 0

( *

*

b

m 1 + m b 4 ≥ 1 = ¯ x 1 + ¯ x 4 .

K

− m b 1 λ 1 − m b 4 λ 1 ≤ −¯ x 1 λ 1 − x ¯ 4 λ 4

b

m 1 λ 1 + m b 4 λ 4 ≤ x ¯ 1 λ 1 + ¯ x 4 λ 4

(

(λ 4 − λ 1 )m 0 4 ≤ (λ 4 − λ 1 )¯ x 4

$

&!$5'

$$

(

*

0

¯

x 1 ≤ m b 1

$ K * (* ) -

1, 4

)

x ¯

m 0

2 !$#$

3 rd STEP :

%

(

$$$

&!$6'

b

m 1 + m b 4 = 1 .

1

(

ϑ 1 := ϑ b − tλ 4 λ D 1 + tλ 1 λ D 4

(17)

?

?

x 1 + x 4 = 1

λ 1 x 1 + λ 4 x 4 = 1 − λ 0 23

1

1

x 1

x 4

1−λ 0 23

λ 4

1−λ 0 23

λ 1

(¯ x 1 , x ¯ 4 )

( m b 1 , m b 4 )

{x λ 1 x 1 + λ 4 x 4 ≤ 1 − λ 0 23 , x 1 + x 4 ≥ 1}

2

!

$

#4

1

4

)

m c

x ¯

)

t := ( m b 1 + m b 4 ) − 1 λ 4 − λ 1

(

(

)

(

(

m 1

)

ϑ 1

&!$5'

&!

$

6

*

'

(m 1 2 , m 1 3 ) ≥ (¯ x 2 , x ¯ 3 ).

*

)

t

&!$6!'

(m 1 1 + m 1 4 ) = 1

@

(m 1 1 , m 1 4 )

7*

&!$6#'

λ 1 x 1 + λ 4 x 4 ≤ 1 − λ 0 23

)

(

( m b 1 , m b 4 )

$

m b 1 4 ≥ m b 4

b

m 1 1 ≥ m b 1

)

*

)

2

!

$

# &!

$

6!' &!

$

6#'

(

*

*

x

) 7 * *

x 1 ≥ x ¯ 1

$

ϑ 1

(

$

@

*

(

)

ϑ 1

(

ε

234

( '(' ( )

ϑ b

7

D 2 ∪ D 3

ϑ 1

/

ϑ b

D 4

$

7

*

ϑ 1 ∈ H b

(*

ϑ b

*

ϑ 1

0

&!$6'$

4 th STEP :

/

(

(

)

ϑ b

D 2 ∪ D 3

(h 2 , h 3 )

$ /

(

$$$

&!$65'

( m b 2 , m b 3 ) = (h 2 , h 3 )

(18)

$

J

((

!

$*

c m

α 1 , α 2 , α ¯

* (($ .

x ? := α 1 e 12 + α 2 e 34 + ¯ αx

0

(x ? 2 , x ? 3 ) = ( b x 2 , b x 3 ) = (α 1 , α 2 ) + ¯ α(h 2 , h 3 ) .

(x ? 2 , x ? 3 ) − (α 1 , α 2 ) = ¯ α(h 2 , h 3 ) .

7

*

x ?? := x b − (α 1 e 12 + α 2 e 34 )

¯ α

x ?? := (x ? 2 , x ? 3 ) − (α 1 , α 2 )

¯ α

0

(x ?,? 2 , x ?,? 3 ) = (h 2 , h 3 ) .

%

(

x ?? ≥ 0

$ )

0 ≤ t ≤ 1

b

x − t(α 1 e 12 + α 2 e 34 )

7

x 1 + x 4 = 1

x 2 + x 4 ≥ 1

)(

x b

e 12

e 34

* 7 7$ ) ) (

t < 1

x t 4 = 0

x t 1 = 1

x t 2 ≥ 1 λ 1 x t 1 + . . . + λ 4 x t 4 > λ 1 + λ 2 = 1

$ 7*

x t 4 = x ?? 4 ≥ 0

$ /

x ?? 1 > 0

(( * * 2 !$# 7

x 1 + x 4 = 1, λ 1 x t 1 + λ 4 x t 4 ≤ 1 − λ 0 23

(*

x

x 1 ≥ x 1

$

(

ϑ ?? := ϑ b − (α 1 e 12 + α 2 e 34 )

¯ α

(

(

(

(h 2 , h 3 )

D 2

D 3

$

ϑ b = αϑ ?? + (α 1 e 12 + α 2 e 34 ) ,

*

(

)

ϑ ??

* (

ϑ e

(

ε − 234

(

)

ϑ b

*

α ϑ e + (α 1 e 12 +α 2 e 34 )

(

ε −

234

$

ϑ ?? ∈ H b

$

)

(

* )

*

ϑ b

*

ϑ ?,?

0 (

&!

$65'$

5 th STEP :

(19)

?

?

%

ϑ b

*(

D 2 ∪ D 3

$

$$$

&!$66'

ϑ b = h 2

D 2 , ϑ b = h 3

D 3 ,

ϑ ?

* ) ( )

ϑ b

(h 2 , h 3 )

)(

D 2 ∪ D 3

D 4

0

ϑ ? := ϑ b

D 1 + h 2 D 2 + h 3 D 3 + ϑ b

D 4 + ( Z

D 2 ∪D 3

ϑdλ b − λ 0 23 ) D 4 .

ϑ ?

( * (

ϑ e

(

ε − 234

T

234

)

(

ε > 0

$ (

λ h := h 2

h 2 + h 3 λ 1 + h 3

h 2 + h 3 λ 2

/

ϑ b

(

T b 23 ⊆ D 23

)*(( ((

)

(

/

(h 2 , h 3 )

$

ϑ e

/

ϑ b

T 4

ϑ ?

/

ϑ b

T 4

$

)

*

(

ε > e 0

0

e ε − 123

T e 234 ⊆ T b 23 ∪ T 4

)* (

e δ > 0

(

ϑ e := (1 − e δ) ϑ b + e δ λ h + ϑ e 2

/

ϑ b

T e 234

$

ϑ( b T e 234 ) < e ε(1 − h 3 ) = v( T e 234 )

λ h ( T e 234 ) ≤ e

ε(1 − h 3 ) = v( T e 234 )

) *

e δ

(

ϑ( e T e 234 ) < e ε(1 − h 3 ) = v( T e 234 )

$

ϑ e dom T e 234 ϑ b

$

7

*

ϑ ? ∈ H

(*

ϑ b

*

ϑ ?

$

0

(

&!$66'$

6 th STEP :

K

)

ϑ b ∈ H b

ϑ b = x b 1 ≥ x 1

D 1

ϑ b = h τ

D τ (τ = 2, 3)

$

x b 1 + x b 4 = 1

D 4

*

b x 4 := 1 λ(D 4 )

Z

D 4

ϑdλ b .

*

λ 1 x b 1 + λ 2 h 2 + λ 3 h 3 + λ 4 b x 4 = 1

λ 1 b x 1 + λ 4 b x 4 = 1 − λ 0 2 3

(20)

b

x 1 + b x 4 ≥ 1 .

)

2

!

$

#

(x 1 , x 4 )

*

) 7

*

7$

x b 1 = x 1

)

b

x 1 + b x 4 = 1

)

x b 4 = x 4

$

7

*

ϑ b ≥ ϑ x ¯

(

ϑ b = ϑ ¯ x

(

$

0

*

(

$

H

( & ((

J

H b

$ 2

)

b

H

(

*

(

$

@

* (

!$*#

ϑ = ϑ b x ∈ H b

$

7

*

H b ⊆ H

H b = H

(21)

?

?

!

"

2 × 2

3/( & !" #"' /*

(

&#$*'

h 1 = 0, h 2 + h 3 ≥ 1 h 4 = 1

&#$!'

λ 1 + λ 3 ≥ 1 .

( b τ 1 , τ b 2 ) = (1, 3)

* 7 *

h b τ 1 + h τ b 2 = 0 + h 3 < 1

$

)

λ 0

/ 4

11

& #

"'$

1

/

(

h 1 , h 2

)

ε

(.

3.6

3/(

3.7

)

!

"$

)

(

)

$

&

(

(

'&

&#

$*'&#$

!'

(

&

(

(

'

&

(

&

'

'

&#

$

#'

a 14 := (1, 0, 0, 1) ;

v(a 14 ) = 1 = e 12 a 14 = e 34 a 14 = c 0 a 14 a 23 := (0, 1, 1, 0)

v(a 23 ) = 1 = e 12 a 23 = e 34 a 23 < c 0 a 23 = h 2 + h 3

a 24 := (0, 1, 0, 1) ;

v(a 24 ) = 1 = e 12 a 24 = e 34 a 24 < c 0 a 24 = h 2 + 1 a 13 := (h 3 , 0, 1, 0)

v(a 13 ) = h 3 = e 12 a 23 = c 0 a 23 < e 34 a 23 = 1 a 123 := ((h 2 + h 3 ) − 1, 1 − h 3 , h 2 , 0)

v(a 123 ) = 1 − h 3 = e 12 a 123 = e 34 a 123 = c 0 a 123

K

*

)

(

)

ε

-

(

+

((

* ,$

)

(

ε > 0

0

λ(T 13 ) = εa 13 = ε(h 3 , 0, 1, 0)

v(T 13 ) = λ 1 (T ) = λ 3 (T ) = εh 3 < λ 2 (T ) = ε,

&#

$5'

T 13

ε

13

>:<:8ED

$

(

* )

T 123 ⊆ D 123

0

→ λ(T 123 ) = εa 123 = ε((h 2 + h 3 ) − 1, 1 − h 3 , h 2 , 0),

v(T 123 ) = λ 1 (T ) = λ 2 (T ) = λ 3 (T ) = ε(1 − h 3 ) ,

&#$6'

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