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Lecture 8: Understanding the Power

Spectrum of the Temperature Anisotropy and

Introduction to CMB Polarisation

1

The lecture slides are available at

https://wwwmpa.mpa-garching.mpg.de/~komatsu/

lectures--reviews.html

(2)

Part I: Cosmological Parameter

Dependence of the Temperature Power Spectrum

2

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Before starting: Let’s recap the Big Picture

In words!

How does the power spectrum constrain the baryon density?

Via the speed of sound, the increased inertia of a photon-baryon fluid, and Silk damping.

They all depend on R (the baryon-photon energy density ratio), which is proportional to ΩBh2. Note h2! It is not just ΩB.

3

q q

q

(4)

q

EQ

= a

EQ

H

EQ

~ 0.01 (Ω

M

h

2

/0.14) Mpc

–1

Before starting: Let’s recap the Big Picture

In words!

How does the power spectrum constrain the total matter density?

Via the boost of the amplitude of sound waves and the ISW due to a decaying gravitational after the horizon re-entry.

They all depend on qEQ (the wavenumber of the matter-radiation equality), which is proportional to ΩMh2. Note h2! It is not just ΩM.

q q q

(5)

Before starting: Things you haven’t learned yet

How does the power spectrum constrain the Hubble constant?

Via the (comoving) distance to the last scattering surface, rL. Particularly interesting now because of the “Hubble constant tension”.

How does the power spectrum constrain the dark energy?

The same: via rL.

How does the power spectrum constrain the epoch of reionization?

The temperature power spectrum cannot constrain this.

5

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How does r L depend on H 0 and dark energy?

We must know ΩMh2 in advance. The CMB peak heights tell us ΩMh2, which then enables us to determine Η0 if we assume a flat Universe. Otherwise, we cannot really determine H0 or ΩΛ! (Unless we use gravitational lensing of the CMB.)

6

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a 0 r L = ca 0

Z t

0

t

L

dt

a(t) = ca 0

Z a

0

a

L

da

a a ˙ = ca 0

Z a

0

a

L

da

a 2 H (a)

Friedmann’s equation

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H

2

(a) = H

02

M

a

3

+ ⌦

k

a

2

+ ⌦

! H

02

M

a

3

+ 1 ⌦

M

Flat Universe Ωk=0

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/ ⌦

M

h

2

a

3

+ h

2

M

h

2

ΩM + Ωk + ΩΛ = 1

(7)

7

(8)

The sound horizon, rs, changes when the baryon density changes, resulting in a shift in the peak positions.

Adjusting it makes the physical effect at the last scattering manifest

8

(9)

Zero-point shift of the oscillations

9

(10)

Zero-point shift effect

compensated by (1+R)–1/4 and Silk damping

10

(11)

Less tight coupling:

Enhanced Silk damping for low baryon density

11

(12)

Total Matter Density

12

(13)

Total Matter Density

13

(14)

Total Matter Density

First Peak:

More ISW and boost due to the decay of Φ

14

(15)

Total Matter Density

2nd, 3rd, 4th Peaks:

Boosts due to the decay of Φ

Less and less effects at larger multipoles

15

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Two Other Effects

Spatial curvature

We have been assuming a spatially-flat Universe with zero curvature (i.e., Euclidean space). What if it is curved?

Optical depth to Thomson

scattering in a low-redshift Universe

We have been assuming that the Universe is transparent to photons since the last scattering at z=1090. What if there is an extra scattering in a low-redshift Universe?

16

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Spatial Curvature

It changes the

angular diameter distance, d

A, to the last scattering surface; namely,

rL -> dA = R sin(rL/R) = rL(1

rL2/6R2) + … for positively- curved space

rL -> dA = R sinh(rL/R) = rL(1

+

rL2/6R2) + … for negatively- curved space

Smaller angles (larger multipoles) for a negatively curved Universe

17

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18

(19)

19

(20)

late-time ISW

20

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Optical Depth

Extra scattering by electrons in a low-redshift Universe damps temperature anisotropy

C

l

-> C

l

exp(–2τ)

at l >~ 10

where τ is the optical depth

re-ionisation

21

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22

(23)

23

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Since the power spectrum is uniformly suppressed by exp(–2τ) at l>~10, we cannot determine the amplitude of the power spectrum of the gravitational potential, Pφ(q), independently of τ.

Namely, what we constrain is the combination: exp(–2τ)Pφ(q)

Important consequence of the optical depth

Breaking this degeneracy requires an independent determination of the optical depth. This requires

POLARISATION

of the CMB.

/ exp( 2⌧ )A s

24

(25)

+CMB Lensing Planck

[100 Myr]

Cosmological Parameters Derived from the Power Spectrum

(26)

The Hubble Constant Tension

The role of the CMB

Can we explain, in words, how this measurement was obtained?

Wong et al. (2020)

(27)

The CMB peak positions are controlled by cos(qrs).

We measure q in the angular wavenumber, l ~ qrL.

Thus, the CMB power spectrum gives a direct measurement of the distance ratio: rs/rL.

You already know how to obtain a0rs = 145 Mpc (see Lecture 5).

Today we saw how rL depends on cosmology (in a flat Universe):

27

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a

0

r

L

= ca

0

Z

a0

aL

da

a

2

H (a) /

Z

a0

aL

da a

2

p

M

h

2

a

3

+ h

2

M

h

2

CMB -> Distance Ratio -> (Physics) -> H 0

Physical Assumption: the sound horizon r

s

(28)

CMB -> Distance Ratio -> (Physics) -> H 0

Physical Assumption: the sound horizon r

s

The CMB peak positions are controlled by cos(qrs).

We measure q in the angular wavenumber, l ~ qrL.

Thus, the CMB power spectrum gives a direct measurement of the distance ratio: rs/rL.

You already know how to obtain a0rs = 145 Mpc (see Lecture 5).

Today we saw how rL depends on cosmology (in a flat Universe):

28

<latexit sha1_base64="tvvcBXmPIDrpOwDLma0bwz/eZtw=">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</latexit>

a

0

r

L

= ca

0

Z

a0

aL

da

a

2

H (a) /

Z

a0

aL

da a

2

p

M

h

2

a

3

+ h

2

M

h

2

If we used an incorrect value of r

s

, we would infer r

L

incorrectly, hence

an incorrect value of H

0

!

(29)

So…?

Bernal, Verde and Riess (2016); Poulin et al. (2019)

The CMB-inferred value of H0 is too low, by 10 percent.

This means that the inferred value of rL is too high, by 10 percent.

This may mean that the value of rs we calculated using the standard understanding of physics was too high by 10 percent.

If we managed to reduce the calculated value of rs by 10 percent, we could resolve the Hubble constant tension.

Is that possible? Not really, but one way to achieve this would be to increase H(a) by 10 percent in the radiation era. => Early Dark Energy?

29

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Part II: Basics of the CMB Polarisation

30

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31

Credit: ESA

(32)

32

Credit: ESA

CMB is weakly polarised!

(33)

Polarisation

No polarisation

Polarised in x-direction

33

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Photo Credit: TALEX

34

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horizontally polarised Photo Credit: TALEX

35

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Photo Credit: TALEX

36

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Generation of polarisation

The necessary and sufficient conditions

To generate polarisation, we must satisfy the following two conditions

Scattering

Anisotropic incident light

However, the Universe does not have a preferred direction. How do we generate anisotropic incident light?

37

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Physics of CMB Polarisation

Necessary and sufficient condition: Scattering and Local Quadrupole Anisotropy

CreditWayne Hu 38

(39)

(l,m)=(2,0) (l,m)=(2,1)

(l,m)=(2,2)

39

Quadrupole

temperature anisotropy

seen by an electron

(40)

Generation of temperature quadrupole

The punch line

When the Thomson scattering is efficient (i.e., tight coupling between photons and baryons via electrons), the distribution of photons from the rest frame of

baryons appears isotropic.

Only when tight coupling weakens

, a local quadrupole

temperature anisotropy in the rest frame of a photon-baryon fluid can be generated.

In fact, “a local temperature anisotropy in the rest frame of a photon-baryon fluid” is equal to

viscosity.

40

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Part III: Stokes Parameters

41

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Stokes Parameters

[Flat Sky, Cartesian coordinates]

a b

42

(43)

Stokes Parameters

change under coordinate rotation

x’

Under (x,y) -> (x’,y’): y’

(44)

Compact Expression

Using an imaginary number, write

Then, under the coordinate rotation we have

44

(45)

Alternative Expression

With the polarisation amplitude, P, and angle, , defined by

• Then, under coordinate rotation we have We write

and P is invariant under rotation.

45

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Help!

That Q and U depend on coordinates is not very convenient…

Someone said, “I measured Q!” but then someone else may say, “No, it’s U!”. They flight to death, only to realise that their coordinates are 45

degrees rotated from one another…

The best way to avoid this unfortunate fight is to define a coordinate-

independent quantity for the distribution of polarisation patterns in the sky

46

To achieve this, we need

to go to Fourier space

(47)

Appendix: Effects of Neutrinos on the Temperature Power Spectrum

47

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The Effects of Relativistic Neutrinos

To see the effects of relativistic neutrinos, we

artificially increase the number of neutrino species from 3 to 7

Great energy density in neutrinos, i.e., greater energy density in radiation

Longer radiation domination -> More ISW and boosts due to potential decay

(1)

48

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49

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After correcting for more ISW and boosts due to

potential decay

50

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(2): Viscosity Effect on the Amplitude of Sound Waves

The solution is

where

Hu & Sugiyama (1996)

Bashinsky & Seljak (2004) Phase shift!

51

(52)

After correcting for the viscosity effect on the

amplitude

52

(53)

(3): Change in the Silk Damping

Greater neutrino energy density implies greater Hubble expansion rate,

Η

2

=8πG∑ρ

α

/3

This

reduces

the sound horizon in proportion to H–1, as rs ~ csH–1

This also reduces the diffusion length, but in proportional to H–1/2, as a/qsilk ~ (σTneH)–1/2

As a result,

l

silk

decreases relative to the first peak position

, enhancing the Silk damping

Consequence of the random walk!

Bashinsky & Seljak (2004)

53

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After correcting for the diffusion length

54

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Zoom in!

55

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56

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(4): Viscosity Effect on the Phase of Sound Waves

The solution is

where

Hu & Sugiyama (1996)

Bashinsky & Seljak (2004) Phase shift!

57

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After correcting for the phase shift

Now we understand everything quantitatively!!

58

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