Flavour Physics Problem Set 1.
FS 2019 Andreas Crivellin Rafael Silva Coutinho https://www.physik.uzh.ch/en/teaching/PHY568/FS2019.html Given on: 20. February 2019
Exercise 1. Phase space for B¯ →πµ¯ν decays Consider the decay
B(p)¯ →π(k)µ(q1) ¯ν(q2). In the rest frame of the ¯B, we define:
k|B−RF¯ = (k0,0,0,−|~k|),
q|B−RF¯ = (q0,0,0,−|~q|), (1)
whereq =q1+q2 is the energy transfer to the leptons. In the rest frame of the lepton pair, we have:
q1|`−RF= (q01,|~q1|sinθ,0,|~q1|cosθ),
q2|`−RF= (q02,−|~q2|sinθ,0,−|~q2|cosθ). (2) In general, you can write the Lorentz-Invariant Phase Space (LIPS) for an n-body decay by decomposing it into aj-body and an (n−j+ 1)-body phase space as following:
dΦn(p;p1, . . . , pn) =dΦj(qj;p1, . . . , pj) dΦn−j+1(p;pj+1, . . . , pn, qj) dqj2
2π . (3)
(a) Compute the LIPS elementdΦ2(p;k, q) in the rest frame of the ¯B.
(b) Compute the LIPS elementdΦ2(q;q1, q2) in the lepton restframe for massless leptons.
(c) Give a qualitative argument how the result would change for non-vanishing lepton masses.
(d) Compute the full LIPS elementdΦ3(p;k, q1, q2).
Exercise 2. Photon self-energy
To practice some of the methods commonly used in loop calculations, we will compute the fermionic contribution to the photon self-energy, as shown in Fig. 1. Consider the internal fermions to have a mass m. The amplitude can be written as:
iA=εµ(q) iΠµν(q2, m, µ)
ε∗ν(q). (4)
(a) The tensor Πµν can be decomposed according to Πµν =gµνΠa+qµqν
q2 Πb. (5)
How can Πa and Πb in general be determined?
(b) Under the assumption that the photon is transversely polarized, relate Πa and Πb. 1
µ ν q
Figure 1: The Feynman diagram corresponding to the amplitude to be computed in Problem 1.
(c) Can the two fermions in the loop be of different flavor in the SM, and why/why not? If not, what would need to happen for it to be possible?
(d) Use Feynman rules to write an explicit expression for Πa and express it in terms of the scalar integrals
A0(m) =
Z ddl (2π)d
1 l2−m2, B0(p;m1, m2) =
Z ddl (2π)d
1 l2−m21
1
(l+p)2−m22 .
(6)
Hint: In convergent integrals, you can shift the integration variable l→l+v.
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