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B. Main Constructions 33

10. Real-Valued Variational Problems

C. Applications

respect to the trial spaceP10 is the solutionuh toLap(uh, v) =hhhf, viiiM g for allv∈P10. Naturally, there is also the notion of age-Galerkin solution.

10.5 Remark. By 2.12, we know that the Dirichlet problem has no solution for general f ∈ L2, but only forf ⊥H, and the solution is unique up to harmonic components, in other words: there is a unique solution inH. But the space of harmonic functions is one-dimensional, consisting only of the constant functionsand these are ruled out by the boundary value requirements.

10.6 Fact (Schwarz 1995, also cf. 2.19). The de Rham complex (H1,0Ω, d) of a smooth compact Riemannian manifold is a Fredholm complex, so the Dirichlet problem is uniquely solvable, and duL2 ≤C

f L2 with the Poincaré constant C

from 2.10b.

This means thatL−1 is a bounded linear operator.

If∂M is piecewise smooth or convex (that means, convex where it is not smooth), then M is H2-regular, i. e. there is a constant C depending on M, but not on f, with uH2 ≤C f L2, that means that L−1 L2,H2 ≤C in this case.

10.7 Lemma (Céa). Situation as in 10.1. Let ube the Dirichlet potential and uh be the g-Galerkin solution tof ∈L2. Then uh is the orthogonal projection of uontoP10 with respect to Lap(·,·).

Proof. AsP10⊂H10, alsoufullls Lap(u, v) =hhhf, viiiL2 for allv ∈P10 by whichuh was dened. So we have the so-called Galerkin orthogonality Lap(u−uh, v) = 0for all suchv∈P10, which is the characterising property of the projection error, q. e. d.

10.8 Corollary. Situation as in 10.1. Let Π be the orthogonal projection H10 → P10 with respect to Lap(·,·) and Π := id−Π be the projection error. Then for any k for which both sides are dened,

u−uhHk ≤ f L2 ΠL−1 L2,Hk.

10.9 Proposition. Situation as in 10.1 with dimensionn≤3. Then Π H2,H1−1h, and if additionallyM isH2-regular, then

u−uh H1.C

−1 f L2.

Proof. It suces to show that there is oneuh∈P1with u−uhH1−1h uH2, then the projection ofuwill produce a smaller error than thisuh. As usual, we takeuhto be the Lagrange interpolation ofu(which is well-dened, asH2⊂C0in dimension≤3, cf.

Adams 1975, Theorem 5.4.c). And this interpolation estimate is exactly 7.5, q. e. d.

10.10 Proposition (AubinNitsche). Situation as in 10.1. Then ΠL−1 L2,L2 ≤ ΠL−1 2L2,H1. Under the same conditions as in 10.9,

u−uhL2 .C2

h2ϑ−2 f L2.

10. Real-Valued Variational Problems Proof. First, note that for a right-hand sideg, the solutionL−1g is characterised by hhhg, viiiM g = Lap(L−1g, v)for allv∈H10. Now for a right-hand sidef ∈L2, consider

ΠL−1f L2(M g)= sup

g∈L2

hhhΠL−1f, giiiL2

gL2

= supLap(ΠL−1f, L−1g) gL2

(∗)= supLap(ΠL−1f,ΠL−1g) g L2

≤ ΠL−1f H1 ΠL−1 L2,H1, where we have used in(∗)thatΠand henceΠis aLap-orthogonal projection, q. e. d.

10.11 Remark. It would of course be possible to consider other interpolation procedures

than just nodal Lagrange interpolation, for example averaged Taylor polynomials as in Brenner and Scott (2002, section 4.1), which would circumvent the dimension restrictions. However, the emphasis of this thesis lies more on the dierent possible ap

plications of the Karcher simplex construction than on optimal results for the Dirichlet problem.

10.12 Lemma. Situation as in 10.1. LetF(v) :=hhhv, fiiiM,g, and letLapeandFebe dened

similar toLapandF, but withgeinstead ofgeverywhere. Then|(Lap−Lape) (v, w)|. C00h2 dvL2 dwL2 and|(F−Fe)v| .C00h2 v L2.

Proof. Exactly as in 7.3, q. e. d.

Remark. In the understanding of Hildebrandt et al. (2006), the weak LaplacianLg is a mappingH1→(H1),Lgu:v7→Lap(u, v). In this setting, 10.12 can be seen as a convergence result for the weak Laplacians: Lg−Lge H1,(H1).C00h2.

10.13 Proposition. Situation as in 10.1 withH2-regularM. Letuh, ueh∈P10be the Galerkin

solutions toLgu=F andLgeue=Fe. Then

uh−uehL2+C duh−dueh L2.C00C2

h2 f L2.

Proof. During this proof, · always means · L2(M g). Let us rst consider the deriva

tive term on the left-hand side: For somev with v = 1, we have duh−dueh = Lap(uh−ueh, v)

≤ |Lap(uh, v)−Lape(ueh, v)|+|Lape(ueh, v)−Lap(ueh, v)|

≤ |(F−Fe)v|+|(Lape−Lap)(ueh, v)|

.C00h2 f v +C00h2 dueh dv Then use dueh ≤C

f from 10.6. For the estimate of uh−ueh, use the Poincaré

inequality again, q. e. d.

Remark. As in the euclidean setting, the proofs carry over to an arbitrary continuous, stronglyH10-elliptic bilinear form onH1 instead ofLap.

Variational Problems in Ωk

10.14 Assumption. Situation as in 10.1. For k= 0, . . . , n, let there be nite-dimensional subspacesPΩk ofH1,0k(orH0,1k, if needed) withL2andH1,1approximation order hanalogous to 7.4:

min

vh∈PΩk v−vhL2+ dv−dvhL2+ δv−δvhL2

| {z }

only for 10.15a

≤αh vH2

and similar for

t

v =

t

vh = 0 or

n

v =

n

vh = 0. Furthermore, assume that the Dirichlet problem is H2-regular and the Hodge decomposition u = da+δb+c is H1-regular, which means daH1 . uH1 etc. We abbreviate hhh ·,· iiiL2(M ge)as hhh ·, · iiie. 10.15 Proposition. Assume 10.14. Let u = da+δb+c be the Hodge decomposition of

u∈ H1,1k, which can be computed as a= argminF[u] overa ∈H1,1k−1t and b = argminG[u] overb∈H1,1k+1n as in 2.14. If ah= argminF[u] overah∈PΩk−1t and bh= argminG[u]overbh∈PΩk+1n , then

da−dah L2+ δb−δbhL2 ≤αh uH1. (10.15a) If u=dae+δbe+ce is the Hodge decomposition with respect to ge, and if ah,e and bh,e are dened similiarly, then

da−daeL2+ δb−δbeL2+ c−ceL2 .C00h2 uL2, (10.15b) dah−dah,e L2+ δbh−δbh,eL2 .C00h2 uL2. (10.15c) Proof. ad primum: By the EulerLagrange equation hhhda, dviii = hhhu, dviii for all v ∈ H1,1k+1t andhhhdah, dviii=hhhu, dviiifor allv ∈PΩk+1t , we know that dah is the L2-best approximation ofdain d(PΩkt), which is smaller thanαh ∇da by assumption.

ad sec.: If hhhdah,e, dviiie− hhhu, dviiie = 0, then hhhdah,e, dviii − hhhu, dviii.C00h2( dah,e + u) v and hencehhhdah−dah,e, dviii.C00h2( dah,e + u) v for allv∈PΩkt. The same calculation is valid fordah−dah,e instead ofda−dae. Thec−ceestimate comes out

as the remainder, q. e. d.

10.16 Remark. <a> 10.15b is our analogue of thm. 3.4.6 in Wardetzky (2006).

<b> In general, there will be no exact nite-dimensional Hodge decomposition inPΩk, as we have not required any connection betweend(PΩk)andPΩk+1. There is a Hodge decomposition in the space of Whitney forms with convergence proven by Dodziuk (1976, thm. 4.9). Variational problems in a specic spaceP−1k of piecewise constant forms will be treated in 10.24sqq.

<c> The feec setting of Arnold et al. only has a weak Hodge decompositionu = dah+ ˜bh+ch ofu∈PΩk as in 2.13, but as its parts are also orthogonal projections, there is an estimate

dah−dah,e L2+ ˜bh−˜bh,eL2+ ch−ch,e L2 .C00h2 uL2

corresponding to 10.15b.

10. Real-Valued Variational Problems

10.17 Mixed form of Dirichlet problem. Arnold et al. (2006, 2010) have shown how

to construct nite-dimensional subcomplexes(PΩ, d)of(H1,0Ω, d)and solve the mixed Dirichlet problem therein. Holst and Stern (2012) have extended this to the situation where the domain of the Sobolev space and the nite-dimensional approximation are endowed with dierent, but close Riemannian metricsg and ge, which leads to the situation that the inclusion map PΩk(M ge) → H1,0k(M g) is not norm-preserving anymore, but only an almost-isometric map. Their setting directly applies to Finite Element computations on the KarcherDelaunay triangulation:

Proposition (Holst and Stern 2012, thm. 3.10). Assume 10.14, and use the no

tation from 2.17sq. For f ∈ L2k, let (σ, u, p) ∈ PS and (σe, ue, pe) ∈ PSe be the solution of the mixed formulation 2.18 of the Dirichlet problem in M g and M ge re

spectively, where PS = PΩkt ×PΩk+1t ×PHkt is a stable choice of trial spaces from Arnold et al. (2006, eqn 7.14), and PSe diers from PS only by the last factor (PHke)t, the harmonic trial functions with respect toge. Then

σ−σeH1+ u−ueH1+ p−peL2 .C00

γ h2 f L2, whereγ is the inf-sup constant as in 2.18 (but overPΩk).

Proof. The solutions= (σ, u, p)with respect to the correct scalar productg fullls b(s, t) =F(t)for every test triplet= (τ, v, q)∈PS. On the other hand, the distorted solutionse fulllsbe(se, te) =Fe(te)for allte∈PSe with the obvious denition ofbe

andFe. As the trial spaces only dier in the last termq, we have be(se, te) =be(se, t) +hhhue, qe−qiiie=be(se, t) +hhhue, qiiie

(becauseue ⊥PHke). Now observehhhue, qiii=hhhπue, qiii, where π is the orthogonal pro

jection ontoPHk, and by 10.16c the projection of a PHke element onto PHk is small.

Hence

hhhue, qiiie=hhhue, qiii+ (hhhue, qiiie− hhhue, qiii).C0,10 h2 u q .

Weakening the right-hand side, we obtain|be(se, t)−Fe(t)|.C00h2 s t. By the scalar product comparison 10.12, also|b(se, t)−F(t)|.C00h2 s t, and taking this together withb(s, t) =F(t), we have

b(s−se, t).C00h2 s t .

Now, by the inf-sup-condition 2.18b,γ s−se ≤suptb(s−se, t)/ t, q. e. d.

Dirichlet Problems with Curved Boundary

The case that the analytical and the computational domain actually coincide is not the only interesting problem. When for example a Dirichlet problem on the unit disk in hyperbolic space is considered, a Karcher triangulation with respect to the whole hyperbolic space will not exactly cover the unit disk. But the treatment of such a boundary approximation is standard in Finite Element theory, and the main task is

to carefully inspect which arguments have to be modied because they rely on the Euclidean structure of the domain. We give a presentation according to Dörfler and Rumpf (1998) and do not treat the dierence between g and ge, as this comparison can be done separately by using 10.13 after 10.21.

The usual setup for boundary approximation is that a domain Ω is replaced by a simplicial domain Ωh whose boundary vertices lie on ∂Ω. By (n−1)-dimensional interpolation estimates, one then gets that ∂Ω and ∂Ωh are only . h2κ far apart, whereκbounds the curvature of∂Ωandhthe mesh size ofΩh. We translate this, for Ω⊂M, into the following

10.18 Situation. Let M =rK be a piecewise at and (ϑ, h)-small realised simplicial com

plex. LetΩ⊂M be a full-dimensional domain andΩh=rK¯a realised full-dimensional subcomplex, connected by a normal graph mapΦ :∂Ω→∂Ωh,p7→exppdν, where d:∂Ω→R is Lipschitz-continuous andν is the outer normal on∂Ω, with the follow

ing properties: First, the retraction inverse (p, t) 7→ expttdν is injective (to ensure that no topology change may happen). Seond, it is short in the send that|d| ≤αh2, Lip d≤αh≤1, and|∇dd| ≤α(wheredis smooth) for someα∈R. Let all principal curvatures of ∂Ωin M be bounded by κ. This implies that for small hthe norms of dΦand∇dΦare bounded, see section 11.

10.19 Lemma. Situation as in 10.18. If v ∈ H1(Ωh), then v L2(Ωh\Ω) . αh2 dvL2(Ωh\Ω)

and vL2(∂Ω∩Ωh).√

αh dvL2(Ωh\Ω) for small h.

Proof. ad primum: It suces to show the claim for smoothv. Considerλ∈Ωh\Ω. As d(λ, ∂Ωh).αh2, there is a curveγ[λ] :µ;λfor someµ∈∂Ωhwith length.αh2. If his small, this curve can be supposed to be a straight line lying entirely in one simplex ofK¯. Asv(µ) = 0,

v(λ) = ˆ

γ[λ]

dvγ.˙ (10.19a)

Supposeγis arclength-parametrised. Now we can again apply the arguments from the proof of 7.5 (keeping in mind thatγ[λ]has length hthere, butαh2 here):

ˆ

h∩Ω

|v|2

(10.19a)

≤ ˆ

h∩Ω

ˆ

γ[λ]

|dv|2 (7.5a)

. αh2 ˆ

h∩Ω

ˆ

γ[λ]

|dv|2

(7.5b)

. α2h4 dv2L2(Ωh\Ω)

ad sec.: Because∂Ωhis a graph over∂Ω, the inverse is also true:∂Ωis a graph (usually not normal) over ∂Ωh, so we can introduce coordinates in which a simplex fof ∂Ωh

lies in the xm-plane and ∂Ω is parametrised by (x1, . . . , xm−1) 7→ (x1, . . . , xm+1, ρ). Then

v2L2(∂Ω∩rf)= ˆ

t

|v|2»

1 +|dρ|2

(11.10b)

. ˆ

rf

|v|2

(10.19a)

. ˆ

rf

ˆ

γ[λ]

|dv|2 (7.5a)

. αh2 dv2L2(Ωh\Ω),

q. e. d.

10. Real-Valued Variational Problems

10.20 Lemma. Situation as in 10.18. For v : M → R, which is H2 continuous in Ω and

M \Ω, let [v] be the jump of v across ∂Ω. If h is small, there is a continuous ex

tension u¯ of u∈ H2(Ω) ontoΩ∪Ωh such that u|¯ = u, u¯H2(Ωh\Ω) . uH2(Ω) and [d¯u ν]L2(∂Ω∩Ωh). uH1(Ω).

Proof. By assumption, all points inΩh\Ωare covered by the homotopy Φt: p7→expptν,

where at eachp∈∂Ω∩Ωh, the parameter t is chosen within ]0;d(p)] (in particular, points with negatived(p)are excluded, as they would parametrise Ω\Ωh instead of Ωh\Ω). For an image point of Φt, setu(exp¯ ptν) :=u(expp−tν), the reection along

∂Ω. Thisu¯is continuous, and[d¯u ν] =±2du ν. TheH2norm-preservation follows from the assumptions on Φ(but note thatu¯ is notH2 in Ωh∪Ω due to the jump on∂Ω,

even thoughΦtis smooth), q. e. d.

10.21 Proposition. Situation as in 10.18. Let u∈ H20(Ω) be the solution of Lu =f with

respect toΩ, and let uh ∈P10(Ωh) be the Galerkin solution over Ωh for an extension of the right-hand sidef by zero ontoΩh\Ω. Then du−duhL2(Ω).√

αh uH2(Ω)for smallh, whereuh has been extended by zero inΩ\Ωh.

Proof. Letu¯ be the extension ofufrom 10.20. Assume we can show

¯

u−uH1(Ωh). u¯−vH1(Ωh)+αh2H2(Ωh\Ω)+√

αh [d¯u(ν)]L2(∂Ω∩Ωh) (10.21a) for every v ∈P1(Ωh). Then the claim is proven by 7.5 and 10.20. Supposed v ∈P1, observe that in dv−duh = suphhhdv−duh, dwiii/ dw , it suces to take w∈P1. So we have

d¯u−duhL2(Ωh)≤ d¯u−dv + dv−duh = d¯u−dv + sup

w∈P1

hhhdv−duh, dwiii dw

= d¯u−dv + sup

w∈P1

hhhdv−d¯u, dwiii+hhhd¯u−duh, dwiii dw

≤2 d¯u−dv + sup

w∈P1

hhhd¯u−duh, dwiii

dw .

And now, iff¯is the extension off byf¯= 0inΩh\Ω, hhhd¯u−duh, dwiiiL2(Ωh)=

ˆ

h∩Ω

hd¯u, dwi −f w+ ˆ

h\Ω

hd¯u, dwi −f w¯

= ˆ

h∪Ω

(−∆u−f)

| {z }

=0

w+ ˆ

∂Ωh∩Ω

w du ν+ ˆ

h\Ω

−w∆u+ ˆ

∂(Ωh\Ω)

w d¯u(−ν),

as−ν is the outer normal ofΩh\Ω. So this gives

hhhd¯u−duh, dwiiiL2(Ωh)≤ ∆¯uL2(Ωh\Ω) wL2(Ωh\Ω)+ [du(ν)]L2(∂Ω∩Ωh) wL2(∂Ω∩Ωh), which shows, together with 10.19 for the w norms, the claimed estimate 10.21a,

q. e. d.

Heat Flow

Goal. As a short outlook on Galerkin methods for parabolic problems, we consider the approximation of heat ow under perturbations of metric. We decided to exclude the general convergence theory (see e. g. Thomée 2006, chap. 1) and concentrate on the dierence between Galerkin approximations with respect tog andge.

10.22 Proposition. Situation as in 10.1. For a time interval[0;a], let uh, uh,e be the time-continuous Galerkin approximation to the heat ow with initial value u0 ∈ P10 and right-hand side f ∈L([0;a],L2(M g))for metricsg andgerespectively, that means

hhhu˙h, viii+hhhduh, dviii=hhhf, viii for allv∈P1, uh|t=0=u0, hhhu˙h,e, viiie+hhhduh,e, dviiie=hhhf, viiie for allv∈P1, uh,e|t=0=u0, wherehhh ·,· iiie is the abbreviation forhhh ·,· iiiM ge. Then their dierence can be estimated by

uh−uh,eL(L2).C00Ch2 u0H1+C00Ch2ˆ

f(t)2L2

1/2 .

Proof. The proof follows the line of the usual convergence proof for parabolic problems as in Thomée (2006, thm. 1.2): Considerε:=uh−uh,e. By the dening equations for uh anduh,e, we have

hhhε, viii˙ +hhhdε, dviii=hhhf, viii − hhhu˙h,e, viii − hhhduh,e, dviii.

By 7.3 and 10.12, we have

|hhhu˙h,e, viii − hhhduh,e, dviii − hhhf, viii|.C0,10 h2h,e v + duh,e dv + f v , where all norms are L2 norms. So we have for v = ε, together with the Poincaré constantC from 2.10c,

1 2

d

dt ε2+ dε2.C00Ch2h,e + duh,e + f dε .

Then Young's inequality gives2cab≤c2a2+b2, hence we obtain a separated summand dε2on the right-hand side, which can be cancelled (the suppressed constant belongs toc):

1 2

d

dt ε2.(C00C

h2)2h,e2+ duh,e2+ f 2 Integration over[0;a]gives, asε|t=0= 0,

ε2≤(C00C

h2)2 ˆ

˙

uh,e2+ duh,e2+ f 2.

From the usual regularity theory for parabolic problems (Thomée 2006, eqn. 1.20, casem= 0), we know that´

( ˙u2+ u2H1). u0H1

f 2, which shows the desired

estimate forε, q. e. d.

10. Real-Valued Variational Problems

10.23 Proposition. Situation as above. Let unh, unh,e be the Galerkin approximation to the

heat ow with implicit Euler time discretisation with respect tog and ge respectively, that means

hhh∂u¯ nh, viii+hhhdunh, dviii=hhhf, viii for allv∈P10, u0h=u0, hhh∂u¯ nh,e, viii

e+hhhdunh,e, dviii

e=hhhf, viiie for allv∈P10, u0h,e=u0

for the backward dierence quotient∂v¯ n :=τ1(vn−vn−1). Then their dierence at time t=nτ can be estimated by duh−dunh,e L2.Kh2t, whereKdepends on the geometry,

f L(L2)and u0H1.

Proof. As before, letεn:=unh−unh,e. Then

hhh∂ε¯ n, viii+hhhdε, dviii=hhhf, viii − hhh∂u¯ nh,e, viii − hhhduh,e, dviii, and the right-hand side is bounded by

|hhh∂u¯ nh,e, viii − hhh∂u¯ nh,e, viiie|+|hhhduh,e, dviii − hhhduh,e, dviiie|+|hhhf, viii − hhhf, viiie| .C00h2 ∂u¯ nh,e v + duh,e dv + f v .C00C

h2 ∂u¯ nh,e + duh,e + f dv .

Denote the whole term in parentheses asΛ. As before, it is bounded in terms of the given data. Then again the choicev=εn gives

εn 2− hhhεn−1, εniii+ dεn2.C00C

h2τΛ dεn 2 and so

εn2+ dεn 2.C00C

h2τΛ dεn2+C2

n−1n .

And of course dεn 2 is smaller than the last left-hand side, which gives dεn . C0,10 C

h2τΛ +C2

n−1 . Then the claim follows by induction overn, q. e. d.

Discrete Exterior Calculus

10.24 Observation. As we have noticed in 2.19, all variational problems from section 2

are uniquely solvable in (P−1k, d) like in (Ωk, d)by the construction of P−1k as a (co-)chain complex. As(P−1k, d)just a gentle way of writing the simplicial cochain complex (Ck, ∂), its (co-)homology is isomorphic to the de Rham complex' one (a short direct proof, called the theorem of de Rham, is given in Whitney 1957, sec.

iv.29, although de Rham 1931 proved isomorphy to singular, not simplicial coho

mology). Therefore, we can hope for approximating smooth solutions of variational problems by ones inP−1k.

10.25 Situation. Let rK be a realised oriented regular n-dimensional simplicial complex

without boundary with a piecewise at,(ϑ, h)-small metricg. Let λs,s∈K, be the simplices' circumcentres, and suppose λis > 0 for all their components (i. e. rKg is well-centred). Assume 9.20a and that the Hodge decomposition u = da+δb+c is H1-regular, meaning daH1 . uH1 etc. We use the Poincaré inequality in the form 2.11b.

10.26 Proposition. Situation as in 10.25. For a functionf ∈H1, letu∈H2be the solution of the Poisson problem hhhdu, dviii =hhhf, viii for all v ∈ H1, and let uh ∈ P−10 be the solution ofhhhduh, dvhiii=hhhf, vhiiifor all vh∈P−10. Then

hhhdu−duh, dvhiii.C˜

h( ∇f vh + ∇du dvh ) for all vh∈P−1k. Proof. Letvandvhbe connected by 9.20b. Then

hhhdu−duh, dvhiii=hhhdu, dviii − hhhduh, dvhiii+hhhdu, dvh−dviii=hhhf, v−vhiii+hhhdu, dvh−dviii,

and both terms can be estimated as claimed, q. e. d.

10.27 Proposition. Situation as in 10.25. Letu=da+δb+cbe the Hodge decomposition of u∈H1,1k, and letu¯=dah+δbh+ch be the Hodge decomposition of itsL2-orthogonal projection ontoP−1k. Then

hhhda−dah, dvhiii.C˜

h uH1 dvhL2

hhhδb−δbh, δvhiii.C˜

h uH1 δvhL2

for allvh∈P−1k.

Proof. We know that da is characterised by hhhda, dviii = hhhu, dviii for all v ∈ H1,0k. Naturally, ah is characterised by hhhdah, dvhiii = hhh¯u, dvhiii for all vh ∈ P−1k, but the right-hand side is hhhu, dvhiii if du is the orthogonal projection onto P−1. So we can proceed exactly like before, but using 9.19 to connect onlydvanddvhinstead ofvand vh:

hhhda−dah, dvhiii=hhhda, dviii−hhhdah, dvhiii+hhhda, dvh−dviii=hhhu, dv−dvhiii+hhhda, dvh−dviii, the ∇da produced by the latter term can be estimated by uH1 by assumption. The same procedure is feasible forδbandδbh (where another test formv can be employed

such thatδv is close toδvh), q. e. d.

10.28 Proposition. DeneS1:=H1k−1×H1k×H1Hk andP−1S:=P−1k−1×P−1k× P−1Hk. Suppose s = (σ, u, p) ∈ S1 is a solution of the Poisson problem in mixed form as in 2.17, and sh = (σh, uh, ph) ∈ P−1S is the solution of the corresponding nite-dimensional problem. Then for allth= (τh, vh, qh)∈P−1S,

b(s−sh, th).C˜h( ∇f L2+ ∇sL2) thH1,0,

where the left-hand side is of course not to be taken literally as in 2.18a, but with P−1 exterior derivatives forsh andth, i. e. consisting of terms like hhhdu−duh, dvhiiietc.

Proof. In the spirit of 10.26, we start with

b(s−sh, th) =b(s, t)−b(sh, th) +b(s, t−th).

As before, the rst two terms arehhhf, v−vhiii, which is well-controlled by the right-hand side of the claim. Inb(s, t−th), there are many easy terms, which we do not explicitely discuss once more. Only hhhu, q −qhiii = hhhu, qhiii is iteresting. Estimating it actually

11. Approximation of Submanifolds