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UNIVERSIT¨ AT KONSTANZ Fachbereich Physik

Prof. Dr. Matthias Fuchs

Raum P 907, Tel. (07531)88-4678 E-mail: matthias.fuchs@uni-konstanz.de

Renormierungsgruppe und Feldtheorie Sommersemester 2008

Ubungsblatt 3, Ausgabe 21.05.2008, abzugeben bis 28.05.2008 ¨

3. The Gaussian Approximation

In this problem we shall introduce the Gaussian approximation to incorporate fluctuation effects and will use this technique to calculate the critical exponents from a Landau free energy. The Gaussian approximation provides the lowest order systematic correction to mean field theory by assuming that the fluctuations are independent random variables. The Landau free energy is a functional of the order parameter field

L[ η ] = Z

d d r 1

2 γ(∇η(r)) 2 + atη 2 (r) + 1 2 bη 4 (r)

+ a 0 V, (1)

where γ, a, b (all positive) and a 0 are phenomenological parameters and t = (T − T c )/T c is the temperature relative to the critical point.

(a) It is convenient to work in Fourier space using the transform pair η k =

Z

d d r η(r) e −ik·r η(r) = 1 V

X

k

η k e ik·r .

Note that by retaining the discrete version of the back transform we will be able to perform functional integrals before taking the continuum limit. Set b = 0 in (1) and show that the Landau free energy can be expressed as

L[ η ] = 1 V

X

k

1

2 |η k | 2 [2at + γk 2 ] + a 0 V. (2) Mean field theory only considers states with k = 0, corresponding to a spatially constant η(r). States with k 6= 0 represent fluctuations. Why is it necessary to introduce an upper limit Λ to the sum over k?

(b) The free energy is related to the Landau function by a functional integration over all possible order parameter fields

Z = e −βF = Z

Dη e −βL[η] . (3)

In general η k is complex and both real and imaginary parts can be varied independantly.

The functional measure is then given by a product of integrals Z

Dη ≡

Z Y

|k|<Λ

d(Re η k )d(Im η k ),

(2)

Evaluate the functional integral (3) using the Landau function (2) to obtain the free energy

F = a 0 V − 1

2 k B T X

|k|<Λ

log

2πV k B T 2at + γk 2

. (4)

As the field η(r) is taken to be real we have introduced a factor of 1/2 in front of the summation. Why? (HINT: consider the relation between η k and η −k for real η(r)).

(c) The two-point correlation function can similarly be calculated using a functional integral.

k η k

i = 1 Z

Z

Dη η k η k

e −βL[η] , (5)

where Z is given by (3). Show that this correlation function is given by h|η k | 2 i = k B T V

2at + γk 2 ≡ V G k (6)

for k = −k and that it is zero otherwise. Use the asymptotic k → ∞ result G k ∼ k −2+η to find the value of the exponent η and the sum rule k B T χ T = G k=0 to find the exponent γ, where χ T ∼ |t| −γ . The correlation function can be written in the form

G k = k B T γ(k 2 + ξ −2 ) ,

where ξ is the correlation length. Find the exponent ν for the divergence of ξ at the critical point (ξ ∼ |t| −ν ).

(d) Express the real space correlation function G(r, r ) = hη(r)η(r )i as a sum over k vectors.

How can the translational invariance of the system be identified from this result?

(e) We now calculate the heat capacity from (4). The heat capacity is given by c = −T ∂ 2 (F/V )

∂T 2 . (7)

Perform the derivative to obtain c = A + B, where A ≡ k B T

2V T c 2 X

|k|<Λ

4a 2

(2at + γk 2 ) 2 B ≡ − k B

V T c

X

|k|<Λ

2a (2at + γk 2 ) . We will look at the two terms A and B seperately. Replace the summation in the expression for A by an integral and make a change of variables q = ξk, where ξ is the correlation length, in order to extract the divergent behaviour. By considering the behaviour of the integral in various dimensions d show that A ∝ ξ 4−d∼t

(2−d/2) , for d < 4 and that it remains finite for d > 4. Repeat this procedure for B to show that the

specific heat behaves as C ∼ t −(2−d/2) for d < 4 and remains finite for d > 4. We have thus shown that the specific heat exponent α = 2 − d/2 in the Gaussian approximation.

(f) In parts (a)-(e) we have considered states with T > T c by considering fluctuations about

η(r) = 0. For T < T c we need to expand about one of the two spontaneously occuring

minima in the free energy. We thus replace the potential for fluctuations by a harmonic

potential. Using η( r ) = η s + ψ( r ), where η s = ±(−at/b) 1/2 , calculate the Landau free

energy to quadratic order in ψ(r) and express your answer in the Fourier components of

ψ(r). (HINT: Once you have obtained the Landau free energy in terms of ψ there is no

need for a new calculation to arrive at the required result ).

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