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Mathematisch-

Naturwissenschaftliche Fakultät

Fachbereich Mathematik

Prof. Dr. Andreas Prohl Dr. Ananta Kumar Majee

Stochastische Differentialgleichungen

Summer Semester 2017 Tübingen, 02.06.2017

Homework 7

Problem 1. Let X =

Xt; 0 ≤ t ≤ T be the Itô integral Xt := Rt

0fsdWs. Compute the quadratic variation process

X

=

X

t; 0≤t≤T . Problem 2.Let0≤t <1. Consider the SDE

dXt=− Xt

1−tdt+dWt, X0= 0.

i) Show that its solution is

Xt= (1−t) Z t

0

1

1−sdWs. It is known asBrownian bridge.

ii) Deduce that

Xt: 0≤t <1 is a Gaussian process. Compute its mean and covariance function.

iii) Show that 0 =L2−lim

t↑1 Xt.

Problem 3.Letb :Rn → Rn andσσσ :Rn → Rn×n be locally Lipschitz functions, i.e., for everyN ≥0 there existsCN >0such that

kb(x)−b(y)kRn+kσσσ(x)−σσσ(y)kL(Rn,Rn)≤CNkx−ykRn ∀x,y∈[−N, N]n.

i) Show that for everyx∈Rn, we can find a stopping timeτx, almost surely positive, and a stocha- stic process

Xxt; 0≤t < τx such that

Xxt =x+ Z t

0

b(Xxs)ds+ Z t

0

σ

σσ(Xxs)dWs ∀t < τx. (1)

ii) Show that the process

Xxt; 0 ≤ t < τx is unique in the sense that if τ˜x is an almost surely positive stopping time and if

Yxt; 0≤t <τ˜x is a stochastic process such that

Ytx=x+ Z t

0

b(Ysx)ds+ Z t

0

σσσ(Yxs)dWs ∀t <τ˜x,

thenτ˜x ≤τx, andP-a.s.,

Ytx1{t<τ˜x} =Xxt1{t<˜τx} ∀t≥0.

The process

Xxt; 0≤t < τx is called the solution of the SDE (1) up to the explosion timeτx.

Problem 4. (Part I)LetIk =

tj Jj=0 be an equi-distant mesh of sizek = kJ > 0. In the lecture, we

Seite 1/2

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use the Euler method

Yj+1−Yj =b(Yj)k+σσσ(Yj)∆jW (0≤j≤J−1)

to construct an Rn-valued solution of the martingale problem MP(σσσσσσ>,b, µ) on [0, T], where both b andσσσare continuous on[0, T]×Rn, with asymptotic linear growth, i.e.,

kb(x)kRn +kσσσ(x)kL(Rm,Rn)≤CT 1 +kxkRn

∀x∈Rn.

Letn=m= 1.

i) Prove the existence of a constantC >0such that

sup

k>0

0≤j≤Jmax E h

kYjk4

Rn

i

≤C

1 +E h

kY0k4

Rn

i

exp(CT).

ii) For everyk= TJ, letY(k)∈L2

F(Ω;C([0, T];Rn))denote the ‘ continuified Euler iterate’. Show that sup

k>0

E h

sup

0≤s≤T

kYs(k)k4

Rn

i

≤C.

Date of submission: 14.06.2017.

Seite 2/2

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