Asymptotic behaviour of solutions of semilinear hyperbolic systems in arbitrary domains
F.Jochmann
Institut fur angewandte Mathematik, Humboldt Universitat Berlin Unter den Linden 6 10099 Berlin Abstract:
In this paper the long time asymptotic behavior of solutions of semilinear symmetric hyperbolic system including Maxwell's equations and the scalar wave-equation in an ar- bitraty domain are investigated. The possibly nonlinear damping term may vanish on a certain subset of the domain. It is shown that the solution decays weakly to zero if and only if the initial-state is orthogonal to all stationary states. In the case that the nonlinear damping is in addition montone, also strong local Lq-convergence is shown.
AMS:
35B40, 35Q60, 35L05, 35L40, 78A35.1 Introduction
The subject of this paper the long time asymptotic behavior of solutions of semilinear hyperbolic systems of the form
@t
E
=E(1)"
3
X
k=1Hk@k
F
!;S
(txE
)#
(1.1)
@t
F
=E(2) X3k=1Hk@k
E
(1.2)with the initial-condition
E
(0x) =E
0(x)F
(0x) =F
0(x): (1.3)Here
E
2C(01)L2(IRM)) andF
2C(01)L2(IRN)) are the unknown functions depending on the timet0 and the space-variablex 2. IR3is an arbitrary domain.Hk 2IRNM are constant matrices, E(1) 2L1(IRMM) and E(2) 2L1(IRNN) are 1
positive symmetric variable matrices, which depend on the space-variable x 2 and satisfy E(1) = 1 and E(2) = 1 on 0 def= nGwith some subset G.
The generally nonlinear function
S
: 01)IRM !IRM satisesS
(txy
) = 0 for allx20 = nGand
S
(tx0) = 0 for allx2t 2(01):That meams that the damping-term
S
(txE
) is only present on a certain subsetG. The following coerciveness-assumption is imposed.yS
(xy
)(x) min fjy
jpjy
jgfor ally
2IRMx2G:Here p 2 21) and 2 L1(G) is a positive function on G, which does not necessarily have a uniform positive lower bound on G.
This means that
S
(txy
) is allowed to be bounded as jyj ! 1 and jS
(txy
)j behaves like jyjp;1 for small jyj. For exampleS
(txE
)def= (x)jE
jq(1 +jE
jq);1E
with q 2 01) is possible.A domain D(B) L2(IRM+N) containing C01(IRM+N) is chosen, such that the operartor
B(
E F
)def=
E(1)
3
X
k=1Hk@k
F
!E(2)
3
X
k=1Hk@k
E
!!is skew-adjoint on D(B), i.e. B = ;B with respect to a weighted scalar-product. The choice of D(B) involves boundary-conditions on @ supplementing 1.1-1.2.
A physically important example for this system are Maxwell'sequations describing the propagation of the electromagnetic eld
"@t
E
= curlH
;S
(txE
) and @tH
=;curlE
(1.4)supplemented by the initial-boundary conditions
~n^
E
= 0 on (01);1~n^H
= 0 on (01);2 (1.5)E
(0x) =E
0(x)H
(0x) =H
0(x): (1.6)In 1.5 ;1 @ and ;2 def= @n;1.
E
H
denote the electric and magnetic eld respectively which depend on the time t 0 and the space-variable x 2 andS
(txE
) describes a possibly nonlinear resistor. The dielectric and magnetic susceptibilities "2L1() are assumed to be uniformly positive.For 1.4, 1.5 the operator B is dened in the space X def= L2(CI6) by
B(
E
F
)def= (";1 curlF
;;1 curlE
) for (E
F
)2D(B)def= WE WH:2
Here WH is the closure of C01(IR3n;2CI3) inHcurl(), where Hcurl(), is the space of all
E
2L2(CI3) with curlE
2L2().WE denotes the set of all
E
2Hcurl(), such thatZ
E
curlF
;F
curlE
dx= 0 for allF
2WHwhich includes a weak formulation of the boundary-condition~n^
E
= 0 on ;1, see 5].Another example for 1.1-1.2 is the rst-order system corresponding to the initial- boundary-value-problem of the scalar wave-equation with nonlinear damping, see 3], 4], 7].
@t2'= div (Er');S(x@t') (1.7)
supplemented by the initial-boundary-onditions
'= 0 on (01)@ (1.8)
'(0x) =f0(x) and @t'(0x) =f1(x) (1.9) for initial-data f0 2H01 () and f1 2 L2(). Here E 2 L1(IR33) is a symmetric matrix-valued function satisfying E = 1 on 0 = nG.
Note that
u
def= (@t'Er')2C(01)L2(IR4)) solves the system@t
u
= ( div (u
2::u
4)Eru
1);(S(txu
1)000) (1.10)which is of the form 1.1-1.3.
The set N of stationary states for 1.1-1.3 is the set of all
u
2D(B) withB
u
+F(tu
) = 0 for all t 0, where the nonlinear operator F : (01)X ! X is dened byF(t
u
)def= ;E(1)S
(tu
1( ))0: From the assumptions onS
it followsf(
E F
)2 ker B :E
= 0 on GgN:Conversely assume
u
= (E F
) 2 D(B) with Bu
+F(tu
) = 0. Since B is skew-adjoint this yields 0 =<u
Bu
>X= ; <u
F(tu
) >X= RuS
(txE
)dx which impliesE
= 0 onG by the coerciveness assumption. Hence the set of stationary states is given byN =f(
E
F
)2 ker B :E
= 0 onGg:The aim of this paper is to show
(
E
(t)F
(t))t!1;! 0 in L2() weakly (1.11)3
if and only if the initial-data (
E
0F
0)2L2() obeyZ
E(1);1
E
0e
+E(2);1F
0f
dx= 0 for all (e
f
)2N: (1.12)In the case of Maxwell's equations 1.4-1.6 the condition 1.12 on (
E
0F
0) impliesdiv ("
E
0) = 0 on 0 and div (H
0) = 0 on (1.13) since N contains all elements of the form (r'r) with '2C01(0) and 2C01().The proof of 1.11 is based on a suitable modication of the approach in 3], 11] for the case that the operator B does not necessarily have purely discrete spectrum. The basic idea is to show that for each f 2 C01(IRnf0g) and
g
2!0(E
0F
0) the function f(iB)g
is real-analytic and vanishes on G, where !0(
E
0F
0) denotes the !-limit-set with respect to the weak topology of the orbit belonging to the initial-state (E
0F
0). This implies f(iB)g
= 0 for allf 2C01(IRnf0g) and henceg
2 ker B. (Here the operator f(iB) can be dened by the spectral-theorem, since iB is self-adjoint in L2(CIM+N).)If
S
is independent of t and monotone with respect toE
strong Lr-convergence is shown, i.e.jj
E
(t)jjLr(K)+jjF
(t)jjL2(K)t!1;! 0 for all 1 r <2 and compact setsK (1.14) if the initial-data (E
0F
0)2L2() obey condition 1.12.Finally 1.11 is used to prove that the solution the wave-equation 1.7-1.8 in an arbitrary domain IR3 decays with respect to the energy-norm on each bounded subdomain of . The case of a bounded domain has been considered in 3] and 11]. Here the domain is not necessarily bounded. For all R2 (01), f0 2H01 ()) and f1 2L2()) it is shown that
jjr'(t)jjL2( \BR)+jj@t'(t)jjL2( \BR)
t!1
;!0:
2 Notation, Assumptions
For an arbitrary open set K IR3 the space of all innitely dierentiable functions with compact support contained inK is denoted by C01(K).
Let IR3 be a (connected) domain and let 0 be an open subset, such that G def= n0 has nonempty interior. The variable matrices E(1) 2 L1(IR(MM)) and E(2) 2L1(IR(NN)) assumed to be symmetric and uniformly positive in the sense that y? E(1)(x)yc0jyj2 and z? E(2)(x)z c0jzj2 (2.15) for allx2y2IRM and z 2IRN with some c0 2(01) independent of xyz.
Next,
E(1)(x) = 1 and E(2)(x) = 1 for allx20 = nG: (2.16) 4
The assumptions on
S
: 01)IRM !IRM are the following.S
(txy
) = 0 ifx20 = nG (2.17)S
(y
) measurable for xedy
2IRM (2.18)and Lipschitz-continuous, i.e. there exists L2(01), such that
j
S
(txy
);S
(txy
~)j Ljy
;y
~j for ally y
~ 2IRM and x2: (2.19)j
S
(txy
)j2 C0 <y
S
(txy
)> for allt 0x2Gy
2IRM (2.20)with some C0 2(01). Moreover,
yS
(xy
)(x) min fjy
jpjy
jgfor ally
2IRMx2G: (2.21) Here 2 L1(G) with > 0 and p 2 21). The function does not necessarily have a uniform positive lower bound on G. It follows from the two latter assumptions thatS
(txy
) = 0 if and only ify
= 0 for allx2G.In the sequel Lq(K) denotes for a measurable subset K G the weighted Lq-space endowed with the norm
jjujjLq(K) def= ZKjujqdx1=q where q211) and as in 2.21.
The matricesHj 2IRNM obey the following algebraic condition, which is fullled in the examples 1.4-1.6 and 1.7-1.9.
3
X
k=1kHk
!
3
X
k=1kHk
!
3
X
k=1kHk
!
=jj2
3
X
k=1kHk
!
for all 2IR3 (2.22) LetW0 L2(CIM) be the space of all
e
2L2(CIM) with P3k=1@k(Hke
)2L2() in thesense of distributions endowed with the norm
jj
e
jj2W0 def= jje
jj2L2 +jjX3k=1@k(Hk
e
)jj2L2:Furthermore, let D(A) with C01(CIM) D(A) be closed subspace of W0 with respect to the above norm and
A
e
def= X3k=1@k(Hk
e
) fore
2D(A): (2.23)Then the adjoint operatorA obeys C01(CIN)D(A ) and A
F
=;X3k=1@k(Hk
F
) for allF
2D(A ): (2.24)5
For a vector
w
2CIM+N we denote byw
1 the rst M and byw
2 the last N components ofw
.Now, the following operators are dened.
LetD(B0)def= D(A)D(A ) and
B0
w
def= (;Aw
2Aw
1) forw
2D(B0) = D(A)D(A ):Next, B def= EB0 with E def= diag (E(1)E(2)), i.e. D(B)def= D(B0) and
B
w
def= EB0w
=;E(1)Aw
2E(2)Aw
1 (2.25) forw
2D(B). It turns out that B is a densely dened skew self-adjoint operator in the Hilbert-spaceX def= L2(CIM+N) endowed with the scalar-product<
F G
>Xdef= Z E;1FG
dxThis follows from the closedness ofA, which implies thatA =A=A. (It is advantageous for following considerations to consider a complex space X. But whenever the
S
(txE
)occurs in an equation, the function
E
is of course assumed to be real-valued.) Now, letN be the set of alla
2 ker B witha
1(x) = 0 for all x2G.Moreover, letX0 def= N? be the space of all
w
2X with <u
w
>X= 0 for allu
2N.For
w
2L2(IRM+N) a functionu
2C(IRX) is called a weak soution to the problem 1.1-1.3, ifdtdh
u
(t)a
iX =;hu
(t)Ba
iX +hF(tu
(t))a
iX for alla
2D(B) (2.26)Here F : (01)X !X is dened by F(t
u
)def= ;E(1)S
(tu
1( ))0:2.26 is equivalent to the variation of constant formula
u
(t) = exp (tB)w
+Z t0
exp((t;s)B)F(s
u
(s))ds (2.27) where (exp (tB))t2IR is the unitary group generated by B. Since F(t ) is assumed to be Lipschitz-continuous in X by assumption 2.19, it follows from a standard result that this integal-equation has a unique solutionu
2C(01)X), see 8], ch.7.2.27 yields the energy-estimate 12 d
dtjj(t)jj2X =hF(t
u
(t))u
(t)iX =;ZGS
(txu
(t)1)u
(t)1dx 0: (2.28)In the sequel T( )
w
2C(01)X) denotes the unique solution to 1.1-1.3 in the sense of 2.26.6
3 Weak convergence for
t ! 1In the following lemma it is shown in particular that T( )
w
2 L1((01)X) , i. e.jjT(t)
w
jjX is bounded ast !1.Lemma 1
Supposew
2X andu
(t)def= T(t)w
. ThenZ
1
0
h
u
(t)F(tu
(t))idt+jju
(t)jj2X jjw
jj2X (3.29)Z
1
0
jjF(t
u
(t))jj2Xdt C0jjw
jj2Xwith some C0 2(01) independent of
w
. Moreover,u
1 2Lp((01)L1(K)) for all bounded measurable subsets K G: (3.30)Proof:
Letu
(t) = (E
(t)F
(t))def= T(t)w
. By the assumptions 2.20 onS
one hasjjF(t
f
)jj2X C0hF(tf
)f
i for allf
2Xwith some C0 >0 independent of
f
. Therefore, the energy-estimate 2.28 yields 12 ddtjjT(t)
w
jj2X hF(tf
)f
i ;C0;1jjFT(t)w
jj2X: This implies 3.29 by Gronwall's lemma.To prove 3.30 let
f
2 X and denea b
2L2((GIRM) bya
(x)def=f
1(x) if jf
1(x)j 1 anda
(x) def= 0 if jf
1(x)j > 1. Moreover,b
(x) def=f
1(x) if jf
1(x)j > 1 andb
(x) def= 0 ifj
f
1(x)j 1.Then it follows from assumption 2.21 that
a
(x)S
(txa
(x))(x)ja
(x)jp andb
(x)S
(txb
(x))(x)jb
(x)j for allx2G. Holder's inequality yieldsjj
f
1jjL1(K) jja
jjL1(K)+jjb
jjL1(K) (3.31) CK1jja
jjLp(K)+jjb
jjL1(K)=CK1Z
Gj
a
(x)jpdx1=p+ZGjb
(x)jdxCK1
Z
G
a
(x)S
(txa
(x))dx1=p+ZGb
(x)S
(txb
(x))dx CK1Z
G
f
(x)S
(txf
(x))dx1=p+ZGf
(x)S
(txf
(x))dx=CK1(h
f
F(tf
)i)1=p+hf
F(tf
)i CK21 +jj
f
jj2;2X =p(h
f
F(tf
)i)1=pFinally, the assertion follows from 3.29 and 3.31
2
7
Lemma 2
X0\D(Bn) is dense in X0\D(Bm) for all mn2IN with m < n.Proof:
Let
w
2X0\D(Bm) and denew
def= n(;B);nw
2D(Bn) for > 0. ThenjjBk(
w
;w
)jjX (3.32)=jjBk
w
;( ;B);1]nBkw
jjX !1;! 0 for allk 2f01::mg: Suppose
a
2N. Then<
w
a
>X=<w
n( +B);na
>X=<w
a
>X= 0: Hencew
2X0. By 3.32 the proof is complete.2
Lemma 3
i)w
=B02w
on for allw
2(ran B0)\D(B20), in particular;
e
=A Ae
and;f
=AAf
on for alle
2(ranA )\D(A) andf
2(ranA)\D(A ).with A
e
2D(A ) and Af
2D(A).ii)
w
=B2w
on 0 = nG for allw
2X0\D(B2).Proof:
Let
u
2 C01(CIM+N)D(B0n) for alln 2IN. Then it follows from 2.22 using Fourier- transform thatF(B03
u
)1() =;i0
@ 3
X
j=1jHj
1
A
3
X
k=1kHk
!
3
X
l=1lHl
!
F(
u
2)()=;ijj2
3
X
l=1lHl
!
F(
u
2)() Analogously,F(B03
u
)2() =;ijj2
3
X
l=1lHl
!
F(
u
1)() and henceB03
u
=B0u
for allu
2 C01(CIM+N): (3.33) Now, assumew
2(ran B0)\D(B02), i.e.w
=B0v
with somev
2D(B03). ThenZ (B02
w
)u
dx=hB03v
u
iL2 =hw
B30u
iL28
=h
v
B0u
iL2 =hw
u
iL2 =Zw
u
dxfor all
u
2C01(), which means B02w
=w
in the sense of distributions.To prove ii) let
w
2 X0 \D(B2). Supposeu
2 C01(0CIM+N). and dene ~u
def= (B02;)u
2C01(0CIM+N) D(Bn0). Then 3.33 yieldsB0u
~ = 0 and hence ~u
2N. Inparticular 0 =h
w u
~i, becausew
2X0. Since E = 1 on 0, it followsBu
~ =B0u
~2D(B) and ~u
= (B2;)u
. Withw
2X0 and ~u
2N one obtains0 =h
w
u
~iX =hw
B2u
iX ;hw
u
iX =hB2w
u
iX ;hw
u
iX=Z B2
w
]u
;w u
dxSince for all
u
2C01(0CIM+N) is arbitrary, the assertion follows.2
Remark 1
Due to the facts that generally E(j) 6= 1 anda
1 = 0 on G for alla
2 N wehave
w
1 6= (B2w
)1 on G for allw
2X0\D(B2) in general.For example is the case of Maxwell's equations 1.4-1.6 all
w
2X0\D(B2) obey (B2w
)1 =;";1 curl (;1 curlw
1). The conditionw
2X0 impliesdiv ("
w
1) = 0 on 0 and div (w
2) = 0 on , as mentioned in the introduction, but it does not provide any information on the divergence ofw
1 on the set G, sincea
1 = 0 on G for alla
2N.In the next lemma it is shown that X0 is an invariant space ofT(t).
Lemma 4
i) < T(t)w
a
>X=<w
a
>X for allw
2X,a
2N and t0.ii) T(t)
w
2X0 for allw
2X0 and t 0.Proof:
Suppose
w
2 X0 anda
2 N, that meansa
2 ker B anda
1 = 0 on G. Then 3.51 and 2.27 yield< T(t)
w
a
>X=<exp(tB)w
;Z t0
exp ((t;s)B)F(sT(s)
w
)dsa
>X=<
w
exp(;tB)a
>X ;Z t
0
< F(sT(s)
w
)exp((s;t)B)a
>X ds=<
w
a
>X ;Z t
0
< F(sT(s)
w
)a
>X ds=<w
a
>X : Hence, i) is proved. ii) follows from i) and the denition X0 def= N?.2
9
In the sequel let !0(
w
) denote the !-limit-set of the solution T( )w
with respect to the weak topology of X, i.e. the set of allg
2X, such that there exists a sequence tn n!1;! 1with T(tn)
w
n!1;!g
in X weakly, that means with < T(tn)w f
>Xn!1;!<g f
>X for allf
2X.Since theT( )
w
2L1((01)X) by lemma 1 the weak!-limit-set!0(w
) in nonempty for allw
2X.Theorem 1
i) Letw
2X . Then !0(w
)N.Proof:
Let
u
(t) def= T(t)w
for t 2 IR. Supposeg
2 X and tn n!1;! 1 with T(tn)w
n!1;!g
in X0weakly. Since
u
(tn+t) = exp (tB)u
(tn) +Zttn+tn
exp((tn+t;)B)F
u
()d by 2.27, it follows from lemma 1, 3.29 thatjj
u
(tn+t);exp (tB)u
(tn)jjXZ tn+t
tn jjF
u
()jjXd t1=2Zttn+tn
jjF
u
()jj2Xd1=2 n!1;! 0 for allt2 IRand henceu
(tn+t)n!1;! exp(tB)g
in X weakly for all t2IR: (3.34) Suppose 2 C01(IR) and denef
def= RIR(t)exp(tB)g
dt andf
(n) def= RIR(t)u
(tn+t)dt Then 3.34 yields by the dominated convergence-theoremh
f
(n)h
iX =ZIR(t)hu
(tn+t)h
iXdtn!1
;! Z
IR(t)hexp(tB)
g h
iXdt =hf h
iXfor all
h
2X , i.e.f
(n)n!1;!f
weakly. In particularf
(n)1 n!1;!f
1 inL2(G)L1(K) weakly for all bounded K G: (3.35) On the other hand it follows from lemma 1 iii) thatjj
f
(n)1jjL1(K) jjjjLp (IR)
Z b+tn
a+tn jj
u
1(t)jjpL1(K)dt!
1=p
n!1
;! 0 (3.36)
10
for allt2 IR. Here ab 2IRwith supp (ab). 3.35 and 3.36 yield
f
1 = 0 onK for all bounded K Gand all 2C01(IR) wheref
def= RIR(t)exp(tB)g
dt. This implies(exp (tB)
g
)1 = 0 on Gfor all t2IR: (3.37)SinceiB is self-adjoint inX,f(iB) =RIRf()dE can be dened by the spectral-theorem for a Borel-measurable functionf :IR!CI. Here (E)2IR denotes the family of spectral- projectors of iB. If f 2C01(IR), then bounded operator f(iB) has the representation
f(iB)
u
=ZIRf^(t)exp (;tB)u
dt for allu
2X: (3.38)Here ^f denotes the Fourier-transform of f. To see this let
u v
2X. Thenhf(iB)
u v
i=ZIRf()dhEu v
i= (2);1=2ZIRZIRf^(t)exp(it)dtdhE
u
v
i= (2);1=2ZIRf^(t)ZIRexp(it)dhE
u
v
idt= (2);1=2ZIRf^(t)hexp (;tB)
u v
idt= (2);1=2hZIRf^(t)exp (;tB)
u
dtv
iSuppose f 2C01(IRnf0g). Then 3.37 and 3.38 yield
(f(iB)
g
)1 = 0 on G: (3.39)Moreover,
f~(iB)
g
=Bf(iB)g
=;E(1)A (f(iB)g
)2E(2)A(f(iB)g
)1 on (3.40)where ~f() = f(). In particular 3.39 and 3.40 yield in the case that f is replaced by g()def= ;1f()2C01(IRnf0g) that
(f(iB)
g
)2 =E(2)A(g(iB)g
)1 = 0 on Gand hence by 3.39
f(iB)
g
= 0 onG (3.41)11
Since E(x) = 1 on nG, 3.39 - 3.41 yield
B0f(iB)
g
=B(f(iB)g
) = ~f(iB)g
for allf 2C01(IRnf0g) (3.42) with ~f() =f().In particular it follows by induction
f(iB)
g
2( ran B0)\D(B0n) with B0nf(iB)g
=Bn(f(iB)g
) (3.43) for allf 2C01(IRnf0g) and n2IN.The aim of the following considerations is to show that f(iB)
g
is real analytic on . This will be achieved by means of a local integral representation.Let f 2C01(IRnf0g) and choose 2C01(IRnf0g) with () = 1 on supp f. Dene
F
(t) def= exp(;tB)(iB)g
= (2);1=2ZIR^()exp((;t;)B)g
d:Then 3.43 and lemma 3 i) yield
@t2
F
(t) =B2F
(t) =B02F
(t) =F
(3.44) in particular@nt
F
=BnF
( )2L1(IRL2()) andn
F
=B02nF
( ) =B2nF
( )2L1(IRL2()) for all n2IN which impliesF
2C1(IR) and@jt@
F
2L1(IRK) for all compact Kj 2IN0 and 2IN03: (3.45) Suppose x0 2 and choose R >0 with B2R. LetK(x)def= (4jxj);1f^(;jxj) for 2IR and x2IR3 Then 3.45 yields for allx 2BR=2(x0)
limr!0
Z
IR
Z
@Br(x)~n(y)K(x;y)ry
F
j(y) (3.46);
F
j(y)ryK(x;y)]dS(y)d= (4);1rlim
!0
r;3ZIRf^(;r)Z@B
r
(x)~n(y)(x;y)]
F
j(y)dS(y)d!
=ZIRf^()
F
j(x)d=ZIRf^()(exp(;B)(iB)g
)j(x)d 12= (2)1=2(f(iB)(iB)
g
)j(x) = (2)1=2(f(iB)g
)j(x): For all x2BR=2(x0) and ally2B2R(x0) with y6=x one has by 3.44divyK(x;y)ry
F
j(y);F
j(y)ryK(x;y)]=K(x;y)y
F
j(y);F
j(y)yK(x;y)=K(x;y)@2
F
j(y);F
j(y)@2K(x;y)=@K(x;y)@
F
j(y);F
j(y)@K(x;y)]and hence
Z
IR
Z
@BR(x0)~n(y)K(x;y)ry
F
j(y) (3.47);
F
j(y)ryK(x;y)]dS(y)d; Z
IR
Z
@Br(x)~n(y)K(x;y)ry
F
j(y);F
j(y)ryK(x;y)]dS(y)d=ZIRZB
R
(x0)nBr(x) div yK(x;y)ry
F
j(y);
F
j(y)ryK(x;y)]dyd=ZB
R
(x0)nBr(x)
Z
IR@K(x;y)@
F
j(y);
F
j(y)@K(x;y)]ddy= 0since K(x;y)j;j!1! 0 and@K(x;y)j;j!1! 0, whereas
F
and @F
remains bounded as jj!1 by 3.45 for xedy 6=x.Now, 3.46 and 3.47 yield for all x2BR=2(x0) (2)1=2(f(iB)
g
)j(x) =ZIRZ@BR
(x0)~n(y)K(x;y)ry
F
j(y) (3.48);
F
j(y)ryK(x;y)]dS(y)dSince f 2C01(IR), there exists a constant C1 2(01) with (1 +2)jf^(k)()j C1k for all 2IRand k 2IN:
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