Analysis of a Population Model with Strong Cross-Diffusion in an Unbounded Domain
Michael Dreher
Konstanzer Schriften in Mathematik und Informatik Nr. 216, Juni 2006
ISSN 1430–3558
c Fachbereich Mathematik und Statistik
c Fachbereich Informatik und Informationswissenschaft Universit¨at Konstanz
Fach D 188, 78457 Konstanz, Germany Email: preprints@informatik.uni–konstanz.de
WWW: http://www.informatik.uni–konstanz.de/Schriften/
Konstanzer Online-Publikations-System (KOPS) URL: http://www.ub.uni-konstanz.de/kops/volltexte/2007/2236/
URN: http://nbn-resolving.de/urn:nbn:de:bsz:352-opus-22364
Strong Cross-Diffusion in an Unbounded Domain
Michael Dreher∗
Abstract
We study a parabolic population model in the full space and prove the global in time existence of a weak solution. This model consists of two strongly coupled diffusion equations describing the population densities of two competing species. The system features intrinsic growth, inter- and intra-specific competition of the species, as well as diffusion, cross-diffusion and self-diffusion, and drift terms related to varying environment quality. The cross-diffusion terms can be large, making the system non-parabolic for large initial data. The method of our proof is a combination of a time semi-discretization, a special entropy symmetrizing the system, and compactness arguments.
2000 Mathematics Subject Classification: 35K55, 35D05, 92D25
Keywords: global existence, weak solution, time semi-discretization, viscous regularization, weighted Sobolev spaces
1 Introduction
Following Shigesada, Kawasaki and Teramoto [17], the time evolution of the population densities of two interacting species can be modeled by the system
∂tuj−div (∇((δj+δj1u1+δj2u2)uj) +τjuj∇U) = (αj−βj1u1−βj2u2)uj, uj(0, x) =uj0(x),
)
(1.1) where j = 1,2 and x∈Ω⊂Rn,n= 1,2,3. The function uj =uj(t, x) ≥0 denotes the population density of a species j. The parameters δj and δji describe diffusion phenomena: δj is the diffusion rate,δjj is a self-diffusion rate, andδji forj6=iare the cross-diffusion rates. The parametersτj are related to population flows in direction to areas of better environmental quality, which is described by the environment potential U. The coefficient αj is the intrinsic growth rate, and the parameters βji correspond to the inter-specific and intra-specific competition.
In case of Ω 6= Rn, appropriate boundary conditions on uj have to be added, for instance no-flux boundary conditionsJj·ν = 0, whereJj =∇((δj+δj1u1+δj2u2)uj) +τjuj∇U, andν is the normal vector on ∂Ω.
∗Fachbereich Mathematik und Statistik, P.O.Box D187, Universit¨at Konstanz, 78457 Konstanz, Germany, michael.dreher@uni-konstanz.de
1
The system (1.1) can be written in the form
∂t u1
u2
−div
A(u1, u2) ∇u1
∇u2
+
τ1u1 0 0 τ2u2
∇U
∇U
= f1
f2
, (1.2)
where Ais the diffusion matrix, A=
δ1+ 2δ11u1+δ12u2 δ12u1
δ21u2 δ2+δ21u1+ 2δ22u2
. (1.3)
Systems (1.2) with a matrixAas in (1.3) have numerous applications: we mention reaction-diffusion problems [3], where U is an electric potential; or the drift-diffusion equations as in the theory of semi-conductors [14]. And forδj = 0,δ12=δ21= 0, we have at hand a degenerate parabolic system as it appears in porous medium problems [10].
The matrixA may not be positive definite for large positive values ofu1,u2; and then the standard approach towards a prioriestimates of an energy ofL2 type will not work. Additionally, maximum principles are not available because the two equations of (1.2) form a strongly coupled system.
We list some known results:
Steady state solutions in bounded domains Ω were studied, e.g., in [12], [13], [16]. Depending on the ranges of the diffusion, growth and competition parameters, one of the species may be extinct;
or there can be constant steady states; or non-constant steady states are possible and segregation of the species may happen. Numerical simulations of the steady state equations can be found in [8].
If δ12 = 0 or δ21 = 0, then the matrix A has a triangular form, and the general framework of [2]
gives the local well-posedness of initial-boundary value problems for (1.2). For results concerning global existence and global attractors of such weakly coupled systems, we refer to [6] or [15].
In [11], the existence and uniqueness of a local smooth non-negative solution was shown for a one- dimensional domain Ω, and δjj = 0, δ12 = δ21 = 1. Under the additional assumption δ1 = δ2, this smooth solution turns out to be global in time. For δjj = 0 and small initial data, the global existence and uniqueness of solutions in arbitrary dimensions was proved in [7]. For large self- diffusion coefficients, in the sense of 0 < δ21<8δ11, 0< δ12 < δ22, the existence and uniqueness of a non-negative strict solution for Ω⊂R2 was demonstrated in [19]. Under the same assumption on theδji, the global existence of a weak solution in the case of arbitrary dimensions was proved in [8].
The global existence of weak solutions without assumptions on the size of the coefficients, in spatial dimensions up to three, was shown in [5].
In contrast to the above mentioned results, which assumed a bounded domain Ω, the present paper deals with the population model (1.1) in the unbounded domain Ω =Rn,n= 1,2,3.
To be specific, we list our assumptions: the coefficients are supposed to satisfy δj, δji, βji>0,
αj ≥0, τj ∈R.
(1.4) We assume that the initial datau10, u20are positive functions onRnand belong to weighted Lebesgue spaces and Orlicz spaces:
uj0(x)>0, x∈Rn, j= 1,2, (1.5)
uj0(x)hxi, uj0(x) lnuj0(x)∈L1(Rn), uj0 ∈L2(Rn), j = 1,2, (1.6)
where hxi= (1 +|x|2)1/2.
The environment potential U = (t, x) is a function on (0,∞)×Rn with
∇U ∈C([0,∞), L3(Rn) +L∞(Rn)), (1.7)
∇U ∈C([0,∞), L2(Rn)), (1.8)
△U ∈C([0,∞), L2(Rn) +L∞(Rn)). (1.9)
Then a global in time weak solution exists:
Theorem 1.1. Suppose (1.4) and (1.7)–(1.9). Define the entropy density functional e, e(f) =fln(f)−f+ 1, f ≥0.
There is a weight function ̺ =̺(t, x) on (0,∞)×Rn, depending only on the coefficients of (1.1), with the following property:
For each pair of initial functions with (1.5) and (1.6), there is a non-negative solution (u1, u2) belonging toL∞loc(R+, L1(Rn))andL2loc(R+, H1(Rn)), which satisfies (1.1)in the distributional sense.
The entropy of this solution relative to the weight function ̺ exists:
E(t) =
2
X
j=1
Z
Rn
e
uj(t, x)
̺(t, x)
̺(t, x) dx <∞, 0≤t <∞, and we have the a prioriestimate:
kEkL∞(0,T)+X
j
√uj
2
L2((0,T),L2(Rn,hxidx))+X
j
kujk2L2((0,T),H1(Rn)) (1.10)
+X
j
√uj
2
L2((0,T),H1(Rn))+k√u1u2k2L2((0,T),H1(Rn))
≤C(T), 0< T <∞.
We give some remarks on the strategy of the proof. Consider first the case of a bounded domain Ω, and assume that sufficiently regular positive solutions uj exist. Multiplying the equations of (1.1) with lnuj, integrating over Ω, and performing suitable integrations by part, an estimate of the form (1.10) can be derived, where E is defined as in Theorem 1.1, but with ̺ ≡ 1. Of course, this derivation is only formal. To show the existence of non-negative solutions uj, we introduce wj = lnuj, derive a system of differential equations for the wj, and seek a bound of wj(t,·) in the space H2(Ω). The continuous embedding H2(Ω) ⊂ L∞(Ω) for n ≤ 3 will then show uj > 0.
This approach can be made rigorous with a discretization of the time variable as in [9], and a subsequent spatial discretization with finite differences or a Galerkin scheme, and possibly a viscous regularization. This way, an approximate solution can be obtained. The convergence of this sequence of approximate solutions is shown by compactness arguments and the Lions-Aubin Lemma. The limit then is a weak solution of (1.1). However, we have to remark that the uniqueness of such weak solutions and their regularity are delicate questions, see [1].
This strategy will fail in case of Ω = Rn: first, it is natural to assume that uj(t, x) decays to zero for |x| → ∞, making the standard entropy infinite for all times. Second, since lnuj(t, x) = −∞
at infinity, the partial integrations have to be justified. And ultimately, the above compactness
arguments no longer hold. We overcome these difficulties by introducing the modified entropy from Theorem 1.1, which compares the functionuj against an exponentially decaying weight function̺.
The time derivative of this weight function will then reinstate the needed compact embedding.
With minor modifications of the proof, we can also study the case of Ω being the exterior domain of an obstacle, with no-flux boundary conditions on ∂Ω. Finally, we remark that the machinery of our proof works also for the bounded domain case with no-flux boundary conditions. Then we can put̺≡1 andκ0 = 0 and consider the case of vanishing competition rates,βji= 0.
2 Proof of Theorem 1.1
2.1 Construction of an Entropy
For simplicity of notation, we scale the functions u1 and u2 by multiplications with appropriate constants in such a way that the constants δ12 and δ21 become both equal to one.
Then we choose a positive constant κ0 with the property that 8κ20≤β12+β21, 4δjκ20≤1,
δjj+1
2τj2
κ20 ≤ 1
16βjj, j= 1,2. (2.1) Next, we determine a positive number λin such a way that the function κ=κ(x) =hλxi satisfies
k∇xκ(x)kL∞(Rn)≤κ0.
Then we set µ(t) = 1+t1 for 0≤t <∞, and define weight functions
σ =σ(t, x) =−µ(t)κ(x), ̺(t, x) = exp(σ(t, x)), (t, x)∈[0,∞)×Rn. By the choice of the parameters, we have
0< ̺(t, x)<1, |∇xσ(t, x)| ≤µ(t)κ0 ≤κ0, (t, x)∈[0,∞)×Rn.
For positive real numbers ̺ and v, we put Φ̺(v) =vln
v
̺
−v+̺.
Observe that Φ̺(v)≥0 for̺, v >0; and Φ̺(·) has a minimum atv=̺, taking the value zero there.
For two functions u1, u2, taking positive values on [0,∞)×Rn, we write our generalized entropy functional E as
E(t) =
2
X
j=1
Z
Rn
Φ̺(t,x)(uj(t, x)) dx, 0≤t <∞. (2.2)
2.2 The Semi-discretization Scheme
We define a small time step-size h >0 and settk =kh, fork= 0,1, . . .. Thinking ofukj =ukj(x) as an approximation of uj(tk, x), we wish to solve the system
ukj −uk−1j
h −div
∇(δj +δj1uk1 +δj2uk2)ukj +τjukj∇U(tk,·)
= (αj−βj1uk1−βj2uk2)ukj, forj= 1,2 andk∈N+. However, it seems hard to prove the existence of a solution to this system.
Instead, we perform an exponential change of the dependent variables and insert a higher order elliptic regularization:
uk,εj −uk−1,εj
h +ε(△4+hxi8)wk,εj −div
∇(δj+δj1uk,ε1 +δj2uk,ε2 )uk,εj +τjuk,εj ∇U(tk,·) (2.3)
= (αj−βj1uk,ε1 −βj2uk,ε2 )uk,εj , j= 1,2, k∈N+, wk,εj (x) = ln uk,εj (x)
̺(tk, x)
!
, (2.4)
whereε >0 is a small parameter. Of course, the transformation (2.4) is only valid ifuk,εj (x)>0 for all x∈Rn.
For fixed h >0 and ε >0, we define the discrete entropy Ek,ε =
2
X
j=1
Z
Rn
Φ̺(tk,x)(uk,εj (x)) dx, tk=kh, k∈N0.
Lemma 2.1. Suppose ε > 0 and uk−1,εj ∈ L2(Rn) with Ek−1,ε < ∞, and uk−1,εj (x) > 0 almost everywhere in Rn, j= 1,2.
Then the problem (2.3)–(2.4) has a solution wk,ε1 , w2k,ε ∈H4(Rn) with hxi4wk,εj (x) ∈L2(Rn). The functions uk,εj belong to H4(Rn) and take only positive values on Rn. The functions uk,εj , wk,εj solve (2.3)in the distributional sense:
1 h
Z
Rn
(uk,εj −uk−1,εj )ψdx+ε Z
Rn
wjk,ε(△4+hxi8)ψdx (2.5)
− Z
Rn
((δj+δj1uk,ε1 +δj2uk,ε2 )uk,εj )△ψdx+τj
Z
Rn
uk,εj (∇U(tk,·))∇ψdx
= Z
Rn
(αj −βj1uk,ε1 −βj2uk,ε2 )uk,εj ψdx, j= 1,2, ψ∈C0∞(Rn).
Furthermore, if h >0 is small enough, then we have the a prioriestimate Ek,ε−Ek−1,ε+εh
2
X
j=1
△2wk,εj
2
L2(Rn)+
hxi4wjk,ε
2 L2(Rn)
(2.6)
−hµ′(kh) 2
2
X
j=1
Z
Rn
κ(x)uk−1,εj (x) dx+1 2h
2
X
j=1
δjj
∇uk,εj
2
L2(Rn)+ h 16
2
X
j=1
βjj
uk,εj
2 L2(Rn)
+h
3
2
X
j=1
δj ∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+ 2κ20
q
uk,ε1 uk,ε2
2 L2(Rn)
≤3hα0Ek,ε+hCβ ̺k
2
L2(Rn)+ 3hα0 ̺k
L1(Rn)
+ 2 Z
Rn
̺k−̺k−1
dx+hCτ,δk∇U(tk,·)k2L2(Rn), where α0 = max(α1, α2) and Cβ, Cτ,δ are constants defined below.
Proof. We exploit the Leray-Schauder fixed-point principle. For a parameter ζ ∈ [0,1] and given functionsuk,εj andwk,εj satisfying (2.4) withwjk,ε∈H2(Rn), and uk−1,εj ∈L2(Rn) withuk−1,εj (x)>0 on Rn, we look for functionsWjk,ε as solutions to
ε(△4+hxi8)Wjk,ε =−ζuk,εj −uk−1,εj
h (2.7)
+ζdiv
∇(δj+δj1uk,ε1 +δj2uk,ε2 )uk,εj +τjuk,εj ∇U(tk,·) +ζ(αj−βj1uk,ε1 −βj2uk,ε2 )uk,εj , j= 1,2.
Fromwjk,ε∈H2(Rn) andn≤3 we getwk,εj ∈L∞(Rn) and∇wk,εj ∈L6(Rn)∩L2(Rn). Then it follows that exp(wk,εj ) ∈L∞(Rn) and ∇exp(wk,εj )∈L6(Rn),∇2exp(wk,εj )∈L2(Rn). As a consequence, the function uk,εj , defined via (2.4), belongs to H2(Rn). Then the right-hand side of (2.7) belongs to L2(Rn), where we have used (1.7) and (1.9).
By the Lax-Milgram theorem, this problem has a unique solution (W1k,ε, W2k,ε) in the space X4 =n
v∈H4(Rn) : hxi4v(x)∈L2(Rn)o .
For 0 ≤ ζ ≤ 1, we define a mapping, with parameter ζ, S = S(wk,ε1 , w2k,ε;ζ) = (W1k,ε, W2k,ε) from H2(Rn) into X4, which is compactly embedded intoH2(Rn), as can be seen from a variant of the Arzela-Ascoli theorem, compare also [4].
Clearly, the operatorS(·,·; 0) has a unique fixed point (W1k,ε, W2k,ε) = (0,0).
Next, we show that a fixed point (wk,ε1 , wk,ε2 ) to S(·,·;ζ) satisfies an a priori estimate inX4, inde- pendent ofζ. The Leray-Schauder fixed-point principle will then guarantee the existence of at least one fixed point of S(·,·; 1).
Let (w1k,ε, wk,ε2 ) = (W1k,ε, W2k,ε)∈X4 be a solution to (2.7). Multiply (2.7) with wk,εj , integrate over Rn, and sum overj= 1,2:
ζX
j
Z
Rn
(uk,εj −uk−1,εj )wjk,εdx+εhX
j
△2wjk,ε
2 L2(Rn)+
hxi4wk,εj
2 L2(Rn)
(2.8)
−ζhX
j
Z
Rn
wjk,εdiv
∇(δj+δj1uk,ε1 +δj2uk,ε2 )uk,εj +τjuk,εj ∇U(tk,·) dx
=ζhX
j
Z
Rn
wjk,ε(αj−βj1uk,ε1 −βj2uk,ε2 )uk,εj dx.
For simplicity of notation, we set ̺k(x) = ̺(tk, x), σk(x) = σ(tk, x), µk = µ(tk), µk1 = µ′(tk), Uk(x) =U(tk, x). Moreover, we fix
α0= max(α1, α2), β0 = max(β12, β21).
We estimate the first term:
Ek,ε−Ek−1,ε =X
j
Z
Rn
uk,εj wjk,ε−uk,εj +̺k
−
uk−1,εj wjk−1,ε−uk−1,εj +̺k−1 dx
=X
j
Z
Rn
(uk,εj −uk−1,εj )wk,εj dx
+X
j
Z
Rn
uk−1,εj
lnuk,εj −lnuk−1,εj
+ (uk−1,εj −uk,εj ) dx
+X
j
Z
Rn
uk−1,εj (σk−1−σk) +̺k−̺k−1 dx
≤X
j
Z
Rn
(uk,εj −uk−1,εj )wk,εj dx+X
j
Z
Rn
uk−1,εj ln uk,εj uk−1,εj
!
+ 1− uk,εj uk−1,εj
! dx
+X
j
Z
Rn
µk1hκ(x)uk−1,εj +̺k−̺k−1 dx.
In the second integral of (2.8), we perform integration by part and exploit Young’s inequality:
−X
j
Z
Rn
wjk,εdiv
∇(δj+δj1uk,ε1 +δj2uk,ε2 )uk,εj +τjuk,εj ∇Uk dx
=X
j n
X
l=1
Z
Rn
δj(∂lwk,εj )(∂luk,εj ) dx
+X
j n
X
l=1
Z
Rn
(∂lwjk,ε)
(∂l(δj1uk,ε1 +δj2uk,ε2 )uk,εj ) +τjuk,εj ∂lUk dx
=X
j n
X
l=1
Z
Rn
δj ∂luk,εj
uk,εj −∂lσk
!
(∂luk,εj ) dx+X
j n
X
l=1
Z
Rn
∂luk,εj
uk,εj −∂lσk
!
∂l(uk,ε1 uk,ε2 ) dx
+X
j n
X
l=1
Z
Rn
∂luk,εj
uk,εj −∂lσk
!
δjj∂l(uk,εj )2+τjuk,εj ∂lUk dx
= 4X
j
δj ∇
q uk,εj
2 L2(Rn)
−2X
j
δj Z
Rn
q uk,εj
∇σk
∇ q
uk,εj
dx + 4
∇
q
uk,ε1 uk,ε2
2 L2(Rn)
−4 Z
Rn
q
uk,ε1 uk,ε2
∇σk
∇ q
uk,ε1 uk,ε2
dx + 2X
j
δjj
∇uk,εj
2
L2(Rn)−2X
j
δjj
Z
Rn
uk,εj
∇σk ∇uk,εj dx
+X
j
τj
Z
Rn
(∇uk,εj )
∇Uk
dx−X
j
τj
Z
Rn
uk,εj
∇σk ∇Uk dx
≥4X
j
δj ∇
q uk,εj
2 L2(Rn)
+ 4 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+ 2X
j
δjj ∇uk,εj
2 L2(Rn)
−X
j
δj Z
Rn
uk,εj ∇σk
2 dx−X
j
δj ∇
q uk,εj
2 L2(Rn)
−2 Z
Rn
uk,ε1 uk,ε2 ∇σk
2 dx
−2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
−X
j
δjj Z
Rn
(uk,εj )2 ∇σk
2 dx−X
j
δjj ∇uk,εj
2 L2(Rn)
−1 2
X
j
δjj
∇uk,εj
2
L2(Rn)−
X
j
τj2 2δjj + 1
∇Uk
2
L2(Rn)−X
j
τj2 2
Z
Rn
(uk,εj )2 ∇σk
2 dx
≥3X
j
δj
∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+1 2
X
j
δjj
∇uk,εj
2 L2(Rn)
−X
j
δj(µkκ0)2 Z
Rn
uk,εj dx−2(µkκ0)2 Z
Rn
uk,ε1 uk,ε2 dx
−X
j
δjj+1
2τj2
(µkκ0)2 uk,εj
2 L2(Rn)−
X
j
τj2 2δjj + 1
∇Uk
2 L2(Rn). Finally, we consider the right-hand side of (2.8):
X
j
Z
Rn
wk,εj
αj −βj1uk,ε1 −βj2uk,ε2 uk,εj dx
=X
j
αj
Z
Rn
Φ̺k(x)(uk,εj (x)) dx+X
j
αj
Z
Rn
uk,εj −̺kdx−
2
X
j=1 2
X
i=1
βji
Z
Rn
wjk,εuk,εi uk,εj dx
≤α0Ek,ε+α0X
j
Z
Rn
uk,εj dx
−β12
Z
Rn
̺kuk,ε2 uk,ε1
̺k ln uk,ε1
̺k
! + 1
!
dx−β21
Z
Rn
̺kuk,ε1 uk,ε2
̺k ln uk,ε2
̺k
! + 1
! dx
−1 2
X
j
βjj
Z
Rn
(̺k)2
uk,εj
̺k
!2
ln
uk,εj
̺k
!2
+ 1
dx +
Z
Rn
(β12uk,ε2 +β21uk,ε1 )̺kdx+1 2
X
j
βjj ̺k
2
L2(Rn)−(α1+α2) ̺k
L1(Rn). From the elementary inequality z≤2zlnz−2z+ 4 forz≥0 we then obtain
α0X
j
Z
Rn
uk,εj dx≤2α0Ek,ε+ 4α0 Z
Rn
̺kdx.
And by Young’s inequality, with a constant Cβ = max(2β02/βjj) + (β11+β22)/2, Z
Rn
(β12uk,ε2 +β21uk,ε1 )̺kdx+1 2
X
j
βjj ̺k
2
L2(Rn) ≤ 1 8
X
j
βjj uk,εj
2
L2(Rn)+Cβ ̺k
2 L2(Rn).
We define an auxiliary function L = L(z) = zlnz + 1 for z > 0 and summarize the estimates obtained so far:
ζ
Ek,ε−Ek−1,ε
−ζX
j
Z
Rn
uk−1,εj ln uk,εj uk−1,εj
!
+ 1− uk,εj uk−1,εj
! dx +ζX
j
Z
Rn
−µk1hκ(x)uk−1,εj −̺k+̺k−1 dx +εhX
j
△2wjk,ε
2
L2(Rn)+
hxi4wjk,ε
2 L2(Rn)
+ζh
3X
j
δj ∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+1 2
X
j
δjj ∇uk,εj
2 L2(Rn)
+1 2ζhX
j
βjj Z
Rn
(̺k)2L
uk,εj
̺k
!2
dx+ 2ζhκ20 Z
Rn
uk,ε1 uk,ε2 dx
≤ζh
X
j
δj(µkκ0)2 Z
Rn
uk,εj dx+ 4κ20 Z
Rn
uk,ε1 uk,ε2 dx
+ 3ζhα0Ek,ε
−ζh Z
Rn
̺k β12uk,ε2 L uk,ε1
̺k
!
+β21uk,ε1 L uk,ε2
̺k
!!
dx +ζhX
j
δjj+1
2τj2
κ20+βjj 8
uk,εj
2
L2(Rn)+ζhCβ ̺k
2
L2(Rn)+ 3ζhα0 ̺k
L1(Rn)
+ζhCτ,δ ∇Uk
2
L2(Rn), Cτ,δ =X
j
τj2 2δjj
+ 1.
Noting that L(z)≥ 12z andµk≤1, we re-order the terms:
ζ
Ek,ε−Ek−1,ε
+εhX
j
△2wk,εj
2
L2(Rn)+
hxi4wk,εj
2 L2(Rn)
+ζX
j
Z
Rn
uk−1,εj −µk1hκ(x)−ln uk,εj uk−1,εj
!
−1 +
1−δj(µkκ0)2h uk,εj uk−1,εj
! dx
+ζh
3X
j
δj ∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+ 2κ20
q
uk,ε1 uk,ε2
2 L2(Rn)
+ζhX
j
δjj 2
∇uk,εj
2
L2(Rn)+ζhX
j
1 8βjj−
δjj+1
2τj2
κ20
uk,εj
2 L2(Rn)
≤ζh
4κ20−1
2(β12+β21) Z
Rn
uk,ε1 uk,ε2 dx+ 3ζhα0Ek,ε +ζhCβ
̺k
2
L2(Rn)+ 2ζ Z
Rn
̺k−̺k−1
dx+ 3ζhα0 ̺k
L1(Rn)+ζhCτ,δ ∇Uk
2 L2(Rn).
Observe that δjκ20 ≤ 14 and (µk)2 =−µk1, by (2.1). Using 8κ20 ≤β12+β21 from (2.1), we can drop the first integral on the right-hand side, and deduce that
ζ
Ek,ε−Ek−1,ε
+εhX
j
△2wk,εj
2
L2(Rn)+
hxi4wk,εj
2 L2(Rn)
+ζX
j
Z
Rn
uk−1,εj −µk1hκ(x)−ln uk,εj uk−1,εj
!
−1 +
1 +µk1h 4
uk,εj uk−1,εj
! dx
+ζh
3X
j
δj ∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+ 2κ20
q
uk,ε1 uk,ε2
2 L2(Rn)
+1 2ζhX
j
δjj ∇uk,εj
2
L2(Rn)+ 1
16ζhX
j
βjj uk,εj
2 L2(Rn)
≤3ζhα0Ek,ε+ζhCβ ̺k
2
L2(Rn)+ 3ζhα0 ̺k
L1(Rn)
+ 2ζ Z
Rn
̺k−̺k−1
dx+ζhCτ,δ ∇Uk
2 L2(Rn).
The a prioriestimate ofwjk,ε in the space X4 is found if we chooseh so small that 3hα0 <1 and if we can show that the integral on the left-hand side is positive.
From ln(z)≤z−1 for z >0, we deduce that
−µk1hκ(x)−ln uk,εj uk−1,εj
!
−1 +
1 +µk1h 4
uk,εj
uk−1,εj ≥ −µk1h κ(x)− 1 4
uk,εj uk−1,εj
! ,
and this is greater than −12µk1hκ(x) for those xwith uk,εj (x)≤2uk−1,εj (x), sinceκ(x)≥1.
Now we study those xwithuk,εj (x)>2uk−1,εj (x). We have ln(z)≤ηz−1 with η= 12(ln(2) + 1)<1 forz≥2, from which it follows that
−µk1hκ(x)−ln uk,εj uk−1,εj
!
−1 +
1 +µk1h 4
uk,εj
uk−1,εj ≥ −µk1hκ(x) +
1 +µk1h 4 −η
uk,εj uk−1,εj
≥ −µk1hκ(x),
under the assumption−µk1h≤4(1−η).
We end up with thea priori estimate ζ
Ek,ε−Ek−1,ε
+εhX
j
△2wk,εj
2
L2(Rn)+
hxi4wk,εj
2 L2(Rn)
−ζhµk1 2
X
j
Z
Rn
κ(x)uk−1,εj (x) dx+ζhX
j
δjj
2 ∇uk,εj
2
L2(Rn)+ζhX
j
βjj
16 uk,εj
2 L2(Rn)
+ζh
3X
j
δj ∇
q uk,εj
2 L2(Rn)
+ 2 ∇
q
uk,ε1 uk,ε2
2 L2(Rn)
+ 2κ20
q
uk,ε1 uk,ε2
2 L2(Rn)