• Keine Ergebnisse gefunden

Theoretische Physik WS 12/13

N/A
N/A
Protected

Academic year: 2021

Aktie "Theoretische Physik WS 12/13"

Copied!
3
0
0

Wird geladen.... (Jetzt Volltext ansehen)

Volltext

(1)

Physikalisches Institut Ubungsblatt 2 ¨

Universit¨ at Bonn 19. Oktober 2012

Theoretische Physik WS 12/13

Ubungen zu Theoretische Physik IV ¨

Priv.-Doz. Dr. Stefan F¨ orste

http://www.th.physik.uni-bonn.de/people/forste/exercises/ws1213/tp4

–In-class exercises–

A 2.1 Saddle-point method

In the context of statistical physics it is often necessary to solve integrals of the form I = lim

N→∞

Z b

a

e N f (x) dx.

If f(x) is an analytic function on the interval [a, b] and has a global minimum at x 0 ∈ (a, b) then

I = lim

N→∞ e N f (x

0

)

s 2π

N |f 00 (x 0 )| , where f 00 (x 0 ) ≡ ∂ 2 f (x)

∂x 2 x=x

0

.

Show Stirling’s formula

N ! → √

2πN N N e −N as N → ∞ using the saddle-point method.

Hint: Use the integral representation of the gamma function N ! = Γ(N +1) = R ∞

0 x N e −x dx.

A 2.2 Ensemble of quantum mechanical harmonic oszillators

Consider a system of N distinguishable, non-interacting, quantum mechanical, harmonic oscillators with equal angular velocity ω. States of the complete system are then given by the individual oscillator states

|n 1 , n 2 , . . . , n N i = |n 1 i ⊗ |n 2 i ⊗ · · · ⊗ |n N i . We write shorthand

a i ≡ 1 ⊗(i−1) ⊗ a ⊗ 1 ⊗(N−i) = 1 ⊗ · · · ⊗ 1 ⊗ a

ite Stelle

⊗ 1 ⊗ · · · ⊗ 1

for the lowering operator of the ith oscillator (with similar expressions for a j , N j , H j ).

The Hamilton operator of the system is given by H =

N

X

j=1

~ ω

a j a j + 1 2

.

First, consider the case N = 3 with total energy E = 9 2 ~ ω of the system.

1

(2)

(a) How many different states realize this value of the energy?

(b) What is the probability p() for a given oscillator to have the energy ?

Now we want to determine the number of states for a given energy E in the limit of a very big number of oscillators N 1. In general, it is given by

Ω(E) ≡ Sp δ(E − H).

(c) What is Ω(E) for the given system?

(d) Show, that

Ω(E) = Z dk

2π e ikE

e −ik ~ ω/2 1 − e −ik ~ ω

N

and further, that

Ω(E) = Z dk

2π e N(ik(E/N)−log(2i sin(k ~ ω/2))) .

(e) This integral can be computed using the saddle-point method. Show, that Ω(E) is given by

Ω(E) = exp (

N

" E

N + 1 2 ~ ω

~ ω log

E

N + 1 2 ~ ω

~ ω −

E

N − 1 2 ~ ω

~ ω log

E

N − 1 2 ~ ω

~ ω

#) .

–Homework–

H 2.1 Spin precession of a spin-1/2 particle (5+5=10) Points The Hamilton operator of a spin-1/2 particle in a homogeneous magnetic field B is given by

H = − γ 2 ~

3

X

j=1

σ j B j ,

where γ is the gyromagnetic constant and σ i (i = 1, 2, 3) are the Pauli matrices.

The time variation of the polarisation is given by

∂P i

∂t = ∂ hσ i i

∂t .

Here, σ i is to be understood as an operator in the spin-1/2 representation of the rotation group.

2

(3)

(a) Express the time variation of the polarisation in terms of the density matrix ρ(t) and show

i ∂P i

∂t = − γ 2

X

j

B j Sp ([σ i , σ j ]ρ) .

(b) Show the Bloch equation

∂t P = γ (P × B) . Hint: [σ i , σ j ] = 2i P

k σ k ijk .

H 2.2 Spin ensemble (4+2+2+2=10) Points

Consider a system of N (N 1) non-interacting spin-1/2 particles in a constant magnetic field B. Each of the particles has a magnetic moment µ, which can be aligned parallelly or anti-parallelly to the magnetic field. Let n 1 (n 2 ) be the number of magnetic moments aligned parallelly (anti-parralelly) to the magnetic field. The energy of the system is then given by E = −(n 1 − n 2 )µB.

(a) Show, that the number of states having an energy between E and E + δE is given approximately by

ω(E, δE) = N ! N

2 − 2µB E

!

N

2 + 2µB E

! δE 2µB , where E δE µB.

Hint: What is the energy difference between two energy levels?

(b) Use Stirling’s formula, as it was derived in exercise A 2.1, to find an approximation to ln ω(E, δE ).

(c) Interprete the function ln f(n 1 ) ≡ ln

N!

n

1

!(N −n

1

)!

as a continuous function of n 1 . Its Taylor expansion around the maximum n 1,max up to second order is then given by

ln f (n 1 ) = ln f (n 1,max ) + 1

2 (n 1 − n 1,max ) 22 ln f(n 1 )

∂n 2 1

n

1

=n

1,max

.

Using the approximation ln n! ≈ n ln n − n, calculate the maximum n 1,max as well as

2

lnf (n

1

)

∂n

21

n

1

=n

1,max

.

(d) Use the exponential of the Taylor expansion of ln f(n 1 ) to show that ω(E, δE) is given approximately by the Gaussian distribution

ω(E, δE ) = 2 N r 2

πN δE 2µB exp

"

− 2 N

E 2µB

2 # .

3

Referenzen

ÄHNLICHE DOKUMENTE

As for the conductivity sensor, the result of calibration shows that a set of coefficient for the conversion from the frequency to the conductivity decided at the time of the

In this paper, we have shown how to compute the period lattice of loosely periodic func- tions, and applied the technique to the computation of the unit group of a finite extension K

Given this parameter set and a fixed number of samples m = 256, calling the estimator to calculate the costs for exhaustive search, Coded-BKW, using lattice reduction to

The number of spirals on a sunflower is always a Fibonacci number (or a number very close to a Fibonacci number), for instance in the large picture of on the previous slide there are

unfolding theorem whose proof requires some preparations about isochoric unfoldings and it requires a generalization of the classical Brieskorn module of a hypersurface singularity

In this paper we initiate the study of the Roman (k, k)-domatic number in graphs and we present sharp bounds for d k R (G).. In addition, we determine the Roman (k, k)-domatic number

Moreover, by (4.9) one of the last two inequalities must be proper.. We briefly say k-set for a set of cardinality k. Its number of vertices |V | is called the order of H. We say that

Previous experimental research has shown that such models can account for the information processing of dimensionally described and simultaneously presented choice