• Keine Ergebnisse gefunden

Winter 2016 / 17

N/A
N/A
Protected

Academic year: 2021

Aktie "Winter 2016 / 17"

Copied!
3
0
0

Wird geladen.... (Jetzt Volltext ansehen)

Volltext

(1)

Exercises to Wissenschaftliches Rechnen I/Scientific Computing I (V3E1/F4E1)

Winter 2016 / 17

Prof. Dr. Martin Rumpf

Alexander Effland — Stefanie Heyden — Stefan Simon — Sascha Tölkes

Problem sheet 4

Please hand in the solutions on Tuesday November 22 !

Exercise 10 4 Points

Consider the following generalized definition : Definition (General Finite Element). Let

1 . K ⊂ R

n

be a bounded closed set, K 6= ∅, with piecewise smooth boundary, 2 . P be a k-dimensional space of functions on K (k ≥ 1),

3 . the set of degrees of freedom Γ = { γ

1

, . . . , γ

k

} be a basis for P

0

. Then ( K, P , Γ ) defines a finite element.

Let Q

k

= {

j

c

j

p

j

( x ) q

j

( y ) : p

j

, q

j

∈ P

k

} and K be a rectangle.

x

0

x

1

x

3

x

2

x

0

x

3

x

1

x

2

Figure 1 : Left: bilinear Lagrange element. Right: no finite element.

Here, a filled point indicates that at this vertex the value is a degree of freedom.

(i.) Show that ( K, Q

1

, Γ ) with Γ as depicted in the left drawing in Figure 1 is a finite element (bilinear Lagrange element).

(ii.) Show that ( K, Q

1

, Γ ) with Γ as depicted in the right drawing in Figure 1 is no

finite element.

(2)

Exercise 11 4 Points Consider the Hermite finite element ( T, P

3

, Γ ) with the following 10 degrees of freedom

Γ ( p ) = ( Γ

α

( p ))

α=1,...,10

=

p ( x

i

) ,

k

p ( x

i

) , p

x

0

+ x

1

+ x

2

3

i∈{0,1,2},k∈{1,2}

.

x

0

x

1

x

2

(i.) Show that any function in P

3

( T ) is uniquely determined by an Hermite finite element function on T.

(ii.) Let T

h

be any triangulation of a polygonal domain Ω ⊂ R

2

, V

h

be the space of Hermite finite elements on T

h

. Show that a function v ∈ V

h

is not necessarily differentiable.

Exercise 12 4 Points

Consider the quartic finite element ( T, P

4

, Γ ) with the following 15 degrees of freedom Γ ( p ) = ( Γ

α

( p ))

α=1,...,15

= n p ( x

i

) , p ( x

j

) ,

k

p ( x

i

) , D

2

p ( x

i

)( x

l

− x

i

, x

m

− x

i

) o for i, l, m ∈ { 0, 1, 2 } , j ∈ { 3, 4, 5 } , k ∈ { 1, 2 } , i 6= m 6= l 6= i.

x

0

x

1

x

2

x

3

x

4

x

5

Figure 2 : Quartic finite element.

Here, a filled point/circle indicates that at this vertex or midpoint the value/the gradient is given. An arrow shows that at the vertex the second order directional derivative in the direction of the line segments is provided.

(i.) Prove that any function in P

4

( T ) is uniquely determined by this finite element function on the triangle T.

(ii.) Show that ( T, P

4

, Γ ) is affine equivalent to the finite element ( T, ˆ P

4

, ˆ Γ ) on the

reference triangle ˆ T with nodes ˆ x

0

= ( 0, 0 ) , ˆ x

1

= ( 1, 0 ) , and ˆ x

2

= ( 0, 1 ) .

(3)

Exercise 13 4 Points Let ω ∈ ( π, 2π ) and

Ω = { ( r cos ( ϕ ) , r sin ( ϕ )) | 0 < r < 1, 0 < ϕ < ω } . Further, let u be the solution of

∆u = 0 in Ω u = g on ∂Ω , where g ( r, ϕ ) = r

πω

sin (

ωπ

ϕ ) .

Now, consider a uniform triangulation of Ω and the finite element space V

h1

( ) of continuous and piecewise linear finite elements. Prove the estimate

k uI

h

u k

H1,2()

C ( u, ω ) h

ωπ

,

where I

h

is the interpolation operator on V

h1

( ) .

Hint: Use that for a suitable α = α ( h ) > 0 we have that u ∈ H

2,2

( \ B

α

( 0 )) . Further,

estimate the H

1,2

-norm on B

α

( 0 ) .

Abbildung

Figure 1 : Left: bilinear Lagrange element. Right: no finite element.
Figure 2 : Quartic finite element.

Referenzen

ÄHNLICHE DOKUMENTE

Exercises to Wissenschaftliches Rechnen I/Scientific Computing I (V3E1/F4E1). Winter 2016

Exercise 4 We are given an irreducible aperiodic Markov chain with finite state space E, transition matrix P and stationary distribution π.. Show that the first return process to

Exercise Sheet 5, Proseminar Stochastic Processes Winter Semester 2016-17, 250069 PS.. Exercise 1 The Taqqus of the Planet Koozebane each have K ∈ N offspring before

Allfällige Kopplungen mit anderen Kernen können dadurch im Signal nicht erkannt werden, da sie durch die Verbreiterung überlagert werden.. Der Effekt hat aber keine Konsequenzen für

1.4. S is, however, not measurable. This follows from the following surprisingly difficult result: every measurable function on a finite compact measure space is almost surely

Lecture and exercises: Philipp Harms, Tolulope Fadina Due date: November 2,

Lecture and exercises: Philipp Harms, Tolulope Fadina Due date: November 9,

Lecture and exercises: Philipp Harms, Tolulope Fadina Due date: Thursday November 24,