• Keine Ergebnisse gefunden

Player 1 chooses a node v0 ∈X

N/A
N/A
Protected

Academic year: 2021

Aktie "Player 1 chooses a node v0 ∈X"

Copied!
2
0
0

Wird geladen.... (Jetzt Volltext ansehen)

Volltext

(1)

Lehr- und Forschungsgebiet

Mathematische Grundlagen der Informatik RWTH Aachen

Prof. Dr. E. Grädel, R. Wilke

WS 2018/19

Logic and Games — Assignment 2 Due : 23th October at 12:00 in the lecture or at our chair.

Exercise 1 10 Points

(a) Construct the satisfiability gameGψ for the given Horn formulaψand compute the winning regions of both players.

(U →Y)∧(Y ∧ZV)∧(1→U)∧(X→Z)∧(U ∧YX)∧(V →0)

(b) Construct the Horn formula ψG for the following game graph G and determine, using the marking algorithm for Horn formulae, whether Player 0 wins from node 1.

1 2 3

4 5 6

7 8 9

Exercise 2 13 Points

Athreshold gameG:= (V, E, t) consists of a finite directed graph (V, E) and a threshold function t:V →N0. From position vV the rules are as follows:

1. Player 0 chooses a set XvE with |X| ≥t(v).

2. Player 1 chooses a node v0X. The play continues from v0. The first player who is unable to move loses. Infinite plays are draws.

The decision problem whether Player 0 has a winning strategy from a given node is defined as Threshold:=n(G, v) : G is a threshold game, v∈WG0o.

(a) Show thatThreshold isPtime-hard, by reducing GameinLogspacetoThreshold, i.e. showing Game≤LogspaceThreshold.1

(b) Show that Threshold∈Ptime, by proving Threshold≤PtimeSat-Horn.

(c) Provide (in pseudo-code) analternating Logspace-algorithm that decidesThreshold.

1As in the lecture,Gamedenotes the decision problem for reachability games whether the given node is in the winning region of player 0.

http://logic.rwth-aachen.de/Teaching/LS-WS19/

(2)

Exercise 3 7 Points A rectangular chocolate bar with n×m pieces can be seen as a {0, . . . , n} × {0, . . . , m} grid, such that the faces of the grid correspond to the pieces and the edges to the break lines between the pieces.

Consider the following two player game on a chocolate bar: The players alternate each turn, in which the current player chooses a node of the corresponding grid, that is the bottom left corner of a still existing piece. All pieces to the top right of the node are removed. Whoever takes the last piece loses.

Show that one player (who?) has a winning strategy for each size of the bar (except for one special case).

Hint: Do not present the strategy, but rather prove its existence using the determinacy theo- rem for finite, well-founded2 reachability games.

2A game is well-founded it does not admit infinite plays.

http://logic.rwth-aachen.de/Teaching/LS-WS19/

Referenzen

ÄHNLICHE DOKUMENTE

process L which associates the conceptual controls of each player at each time t with the evolutionary histories of the environment and the cerebral motor activities of the

Secretion of YscP from Yersinia enterocolitica is essential to control the length of the injectisome needle but not to change the Type III secretion substrate

Strikingly, a specific attenuation of mechanical hypersensitivity upon induction of inflammatory pain and in the initial stage of neuropathic pain (7 days post

We remark that for complete simple games, a class in between weighted and simple games, a power index (called Shift index) based on counting so-called shift- minimal winning

The Asia-Pacific Economic Cooperation summit (APEC; a forum to promote sustainable growth and prosperity in the region with a membership of 21 economies), which Russia is

In other words, the theory of “emptiness” has quite probably from the very outstart given too little consideration to the fact that in a system of interlinked power, the position

In Section 4 we employ the results of Section 3 in order to reveal the ‘finite-strategy’ nature of the game; namely we show that in terms of the Nash equilibrium points, the

(2004) within a similar game-theoretic context, the small players prefer delaying their decision while the large player benefits from signalling and thus moves first. Since