Quantenmechanik I – WS 06/07 – Prof. M. Gaberdiel
Exercise sheet I
Return: 7.11.2006
Question 1 [Compton effect]:
Consider the elastic scattering of a photon of energy and momentum (cp1,p1) off an electron at rest, whose energy and momentum are (mc2,0). Let us denote by (cp2,p2) the energy and momentum of the scattered photon, and by (cp
m2c2+p2,p) the energy and momentum of the electron after the collision. Since the scattering is assumed to be elastic, total energy and momentum are conserved. Under this assumption, show that
1 ν2 − 1
ν1 = h
mc2(1−cosθ), (1)
whereνi are the frequencies of the photons before and after scattering,cpi =hνi, and θis the scattering angle,i.e. the angle between p1 and p2. The quantityh/mcis often called the “Compton wavelength” of the electron.
(cp2,p2) (cp1,p1)
(mc2,0)
(c!m2c2+p2,p)
1
Figure 1: Schematics of the Compton effect.
Question 2 [Bohr atom ]:
Inspired by Rutherford’s experiments (1911), in which he showed that the atom con- sisted of a small, positively charged core surrounded by the negatively charged electrons, Niels Bohr in 1913 introduced his model of the atom, in which the electrons orbit the proton on circular paths at a radius r. The values of the orbital kinetic moment and of the allowed radii are quantized according to
mvnrn = n~, (2)
rn = n2~2
me2. (3)
(a) Use the De Broglie relation,λ= hp, wherep=mvis the momentum of the electron, to show that
λ rn = 2π
n , (4)
thus that the waves of the electron “fit around the orbit”,
(b) Show that the speed of an electron in a Bohr orbit is much less than the speed of light (thus demonstrating that it is reasonable to neglect relativistic effects).
(c) Show that the wavelength of light emitted from a Bohr atom (taking, for example, the transition from the orbit with n =∞ to the orbit with n = 1) is much greater than the size of the Bohr atom (which you can take to be the radius of the first Bohr orbit, the “Bohr radius”).
Question 3 [Galileo invariance of Schr¨odinger equation ]: Suppose that Ψ(x, t) is a solution of the time-dependent Schr¨odinger equation for a free particle, i.e.,
i~∂tΨ(x, t) =−~2
2m∂x2Ψ(x, t). (5)
Show that, for any constant u,
Ψu(x, t) = Ψ(x−ut, t) exp im
~
ux− im 2~
u2t
(6) is also a solution of the time-dependent Schr¨odinger equation.