3–1
3 . C o n s ti tu ti o n o f s ta rs
3–2 Constitutionofstars1C o n s ti tu ti o n o f s ta rs
Inordertosolvethestructureequationsthephysicalpropertiesofthestellar materialandinteractionwiththeradiationfieldneedtobeknown. 1.Equationofstate:ρ ( P ,T ,X
i)
⇒c
P,δ
,∇ad 2.Opacities:κ ( P ,T ,X
i)
3.nuclearreactionratesandenergyproduction(incl.neutrinolosses):r
ij( P ,T ,X
i)
,ǫ ( P ,T ,X
i)
,ǫ
ν( P ,T ,X
i)
3–3 Equationofstate1
E q u a ti o n o f s ta te : T h e id e a l g a s
Idealgas:P = n k T
withρ = n µ m
Handm
H=
1.
6605·10−24g
P=ρkT µmHρ=µmHP kT lnρ=lnP−lnkT+lnµmH dlnρ=αdlnP−δdlnkT+(ϕdlnµmH) α=∂lnρ ∂lnP=1δ=−∂lnρ ∂lnT=1(ϕ=∂lnρ ∂lnµ=1) Deviationsfromidealgascausedbyradiationpressureandionisation canbedescribedviaα,δ(andϕ),whichwilldeviatefromunity. 3–4 Equationofstate2M e a n a to m ic w e ig h t
fullyionisedplasma:Elementi
withchargeZ
i,massfractionX
i,atomicweightµ
iandpartialdensityρ
i,Partialnumberfraction: ni=ρi µimH=ρXi µimH Totalpressure: P=Pe+X iPi=ne+X ini! kT =X iZini+X ini! kT=X i(1+Zi)nikT=X iρ µimHXi(1+Zi)kT meanatomicweight(completelyionised): 1 µ=X i
Xi(1+Zi) µi neutralplasma: 1 µ=X i
Xi µi
3–5 Equationofstate3
M e a n a to m ic w e ig h t
Meanatomicweightpernucleon 1 µ0=X iXi µi meanatomicweightperelectron(completeionisation:
Z
ielectronsperion) 1 µe=X iXiZi µi hydrogenµi Zi
=
1helium=
4 2=
2metals≈2 1 µe=X+1 2Y+1 2Z=X+1 2Y+1 2(1−X−Y)=X+1 2 µe=2 X+1completeionisation(partialionisation:later) 3–6 Equationofstate4N o n -i d e a l e ff e c ts : ra d ia ti o n p re s s u re
Prad=1 3u=a 3T4 →P=Pgas+Prad=ρkT µmH+a 3T4 definition:β=Pgas P⇒1−β=Prad P ρ=µmH kTP−a 3T4 α=∂lnρ ∂lnP=P ρ∂ρ ∂P=P ρµmH kT=P Pgas=1 β δ=−∂lnρ ∂lnT=−T ρ∂ρ ∂T=−T ρ −µmH kT2 P−a 3T4 −µmH kT
4a 3T3 =T ρ ρ T+µmH kT
4a 3T3 =1+1 ρµmH kT
4a 3T4=1+4Prad P−Prad=P−Prad+4Prad P−Prad =P+3Prad P−Prad=1+3Prad P 1−Prad P=1+3(1−β) 1−(1−β)=4−3β β ϕ=∂lnρ ∂lnµ=1
3–7 Equationofstate5
N o n -i d e a l e ff e c ts : ra d ia ti o n p re s s u re
energydensitypermass(monoatomicgas=3degreesoffreedom) u=3 2kTn ρ+aT4 ρ Withρ=µmHn∇
ad=
1+(4+β)(1−β) β2 5 2+4(4+β)(1−β) β2 limitingcases: withoutradiation:β
→1⇒∇ad→2 5 radiationpressure:β
→0⇒∇ad→1 4 3–8 Equationofstate6N o n -i d e a l e ff e c ts : Io n is a ti o n B o lt z m a n n e q u a ti o n
occupationdensitiesoftwoboundenergylevelsofanioninthermodynamic equillibrium: ni nj=gi gje−Ei−Ej kTg
i,g
j=
statisticalweights(numberofstatesofsameenergy;see:Pauli exclusionprincipal). Usingthepartitionfunction: U(T):=X jgje−Ej kT ni N=gi U(T)e−Ei kT3–9 Equationofstate7
N o n -i d e a l e ff e c ts : Io n is a ti o n
generalizeBoltzmannformulatoionisation: upperstate=2-particles(Ion+freeelectron) •EnergyE=Eion+p2 2mep=
electronmomentum •statisticalweightg=
gup·Ge(
p)
; statisticalweight:ion:gup;electronwithmomentump:Ge(p) →insertintoBoltzmannformula: nup(p) nlow=gupGe(p) glowexp −Eup−Elow kTexp
−p2/2me kT
|{z} equilibriumdistributionforfreeelectrons(Maxwelldistribution) thermalmeanvalueoverallmomenta: nup(p) nlow=gup glowexp −Eup−Elow kT
·
∞Z 0
Ge(p)exp
−p2/2me kT
dp 3–10 Equationofstate8
N o n -i d e a l e ff e c ts : Io n is a ti o n
StatisticalweightofthefreeelectronGe(
p)
continuousspectrumofstates:numberofstatesintheinterval[p,p+
dp]? phasevolume:dΩ=
∆x·∆y·∆z |{z} space·∆px·∆py·∆pz |{z} momentumspacequantummechanics: Heisenberg’principleofuncertainty: ∆x·∆px≈h∆y·∆py≈h∆z·∆pz≈h HencethereisafinitenumberofphasecellsavailabledΩ
/
h3 eachcanbe occupiedwith2electronsofdifferentspin(Pauli’sexclusionprinciple). ⇒Ge(p)dp=2·dΩ h3 dΩ=
4π
p2 dpdV(sphericalcoordinates);electrondensityne=
numberofelectronspervolume;ForoneelectronthereisdV=
1/
neavailable. dΩ=1 ne4πp2dpGe(p)=21 ne4π h3p2dp3–11 Equationofstate9
N o n -i d e a l e ff e c ts : Io n is a ti o n
Sahaequation: nup nlow=1 ne2 2πmekT h23 2gup glowe−Eup−Elow kT Makinguseofthepartitionfunction
U
jforionisationstagej
wecancomputethe densityratiooftwosubsequentstagesofionisation:N
jandN
j+1 Nj Nj+1=neUj Uj+1C1T−3 2eχj kT=:neΦj(T)C
1=
1 22πmekT h2−3 2 ionisationfraction(N =
PJ j=1N
j): Nj N=QJ−1 l=j[neΦl(T)] 1+PJ m=1Qj−1 l=m[neΦl(T)] 3–12 Equationofstate10
N o n -i d e a l e ff e c ts : Io n is a ti o n
Example:hydrogenplasma IneutralhydrogenU
I≈2 IIionisedhydrogenU
II=
1 NI NII=neUI UIIf(T)=2nef(T) degreeofionisation(n
e= N
II,N
I+ N
II= N
): x=NII NI+NII=ne NI+NII (1−x)N xN=xN2f(T)→1−x 2x2N=f(T) (quadraticequationforx
)3–13 Equationofstate11
N o n -i d e a l e ff e c ts : Io n is a ti o n
Example:hydrogenplasma electronpressure: Pe=nekT=(N+ne)kT |{z} Pgasne N+ne =PgasxN N(1+x)=Pgasx (1+x) Foranyarbitrarychemicalcomposition: Numberoffreeelectronsperatom(incl.ions): E:=ne N=x ρ=(N+ne)µmH=Nµ0mH=neµemH µ=ρ mH(N+ne)=ρ mH(1+E)N=µ0 1+E=µeE 1+E 3–14 Equationofstate12
N o n -i d e a l e ff e c ts : Io n is a ti o n
Example:HydrogenPlasmaρ
∼µ
P Tundµ =
µ0 1+Emitµ
0= co n st
. lnρ=−ln(1+E)+lnP−lnT+const δ=−∂lnρ ∂lnT=1 1+E∂E ∂lnT+1 applicationtohydrogenplasma:(E = x
).differentiateSahaequation:∂E ∂lnT: δ=1+1 2x(1−x) 5 2+χH kT +4(1−β) β (incaseofradiationpressure).3–15 Equationofstate13
N o n -i d e a l e ff e c ts : Io n is a ti o n
Example:HydrogenPlasma specificheatc
P=
∂u ∂T P+ P
∂v ∂T Pu
consistsof •kineticenergyofionsandelectrons •ionisationenergy u=3 2(n+ne)kT ρ+uion=3 2(n+ne)kT (n+ne)µmH+uion =3 2kT µ0mH(1+E)+uion 3–16 Equationofstate14
N o n -i d e a l e ff e c ts : Io n is a ti o n
Example:HydrogenPlasmaE = x
forHydrogenplasma. cP= 5 2(1+x)+Φ2 H G(x) k µmH mitΦ
H=
5 2+
χH kTandG ( X ) =
2 x(1−x)χ
Histheionisationenergyofhydrogen(13.6 eV). Forradiationpressure:5 2→5 2+4(1−β)(4+β) β2. ∇ad=Pδ TρcP=2+x(1−x)ΦH 5+x(1−x)Φ2 H (withoutradiationpressure) hydrogenconvectionzoneintheSun3–17 Equationofstate15
N o n -i d e a l e ff e c ts : Io n is a ti o n
ingeneral:numberofelectronspernucleus E=ne N=X νiZiX r=0xr i with
ν
i=
ni N=
Xiµ0 µix
r i=degreeofionisationforr
-thstageofionisationofelementi
. internalenergy: uion=X iXi µimH
ZiX r=0xr i
r−1X s=0χs i ⇒
δ, c
P⇒∇ad needsnumericalsolution(P
radtobeconsidered)c
P:specificheatatconstant(total)pressureP = P
gas+ P
rad 3–18 Equationofstate16L im it s fo r th e v a lid it y o f S a h a -B o lt z m a n n e q u a ti o n s
e.g.centreofthesun:P
e=
2.
6·1017dyn cm2,T =
17·106K
⇒n
H=
1026cm
−3 Sahaequationyieldsx =
0.
76,⇒24%of hydrogenshouldbeneutral! pressureionisation:decreaseofionisation potentials potentialseverelydisturbed,ifthedistance oftheatomsequaltheirdiameters.3–19 Equationofstate17
L im it s fo r th e v a lid it y o f S a h a -B o lt z m a n n e q u a ti o n s
hydrogenatom: Bohr’sRadiusa
0, principlequantumnumbern
, Radius:a = a
0n
2 distance:d =
3 4πnH1 3 equate: a=d⇒n2=1 a0 3 4πnH1 3 InsertdensityofthecentreoftheSunn
2=
0.
26, ⇒eventhegroundstateshouldnotexist. Sahaequationvalidford >
10a
0: ρmax=µ0mHnion<3µ0mH 4π(10a0)3 =2.66·10−3 µ0g cm3 3–20 Equationofstate18N o n -i d e a l e ff e c ts
Degeneracy Athighdensity,Maxwell-distributionisnolongerapplicablebecauseofthePauli exclusionprincipleofquantummechanics⇒Fermidistribution later! Whicheffectdominates? Pgas=Prad⇔k µ0mHρT=a 3T4 ⇔T ρ1 3= 3k aµmH1 3 =3.2·107 µ1 33–21 Opacity1
O p a c it y
Whenwederivedtheequationofenergytransportbyradiationweassumedthat wecanuseanwavelengthindependentopacity.However,opacitycanbea strongfunctionofwavelength.Fourbasictypesofopacitysources: bound–bound Photonisabsorbedbyatom,whichisinan excitedstateafterwards→lineabsorption)bound–free “Photo-ionisation”:anelectronisknockedfree fromanatom.Thresholdenergyforthis process→edges 3–22 Opacity2
O p a c it y
free–free Anfreeelectronpassingbyannucleus absorbsaphoton→continuousabsorption. (inverseprocessisknownasbremsstrahlung.)Thomsonscattering Asingle,isolatedelectronisscatteringa photon→continuousabsorption,wavelength independent. FiguresfromM.Richmond/RIT(Rochester/USA)
3–23 Opacity3
O p a c it y
Wavelengthdependenceofopacitysources(schematic)⇒needforsomeclever averaging. 3–24 Opacity4O p a c it y
Rosselandmean 1κ = π a c T
Z∞ 01
κ
ν∂ B
ν∂ T dν
PhysicalinterpretationwiththefrequencydependentdiffusionequationF
ν=
− 1κ
ν∂ B ∂ T
4π
3ρ
∇T
•Contributiontotheintegralproportionaltonetflux. •Highestweightforfrequencyrangeswithhighestflux3–25 Opacity5
O p a c it y
RelativecontributionstotheRosselandmeaninthestellarinteriorfortypical chemicalmixandconditions 3–26 Opacity6O p a c it y
Opacitiesforsolarmix. Parameterforsolarinterior. dots=solarmodel majoreffortstocalculateopacitiesgoingon:OPAL(LosAlamos) OpacityProject(OP):Internationalcollaborations3–27 Energyproduction1
E n e rg y p ro d u c ti o n in s ta rs
massdefect∆ M
: thermonuclearfusionofatomicnucleiX
tonucleiY
.∆ M =
X XM
X−M
Y energyproduced:E = ∆ M c
2 bindingenergypernucleon:f = [( A
−Z ) m
n+ Z m
p−M
nuc]
c2 A 3–28 Energyproduction2E n e rg y p ro d u c ti o n in s ta rs
netreaction:41H
→4H e
initialmassPM
X=4×1.
0081=4.
0324m
amu finalmassM
Y=4.
0039=4.
0039m
amu massdefect∆ M
=0.
0285m
amu∆ M
=0.7%ofinitialmassE =
0.
0285×1.
6605·10−24 ×(
3·1010)
2=
4.
3×10−5er g =
26.
5M eV
energyproductionpermass:∆ E
PM
xm
amu=
6.
3×1018er g g =
6.
3×1014J kg
3–29 Energyproduction3
N u c le a r re a c ti o n ra te s
ReactionratesCoulombbarrier:
E
Coul( r
0)
≈Z
1Z
2M eV
averagekineticenergyofprotonsinthe coreoftheSunT
≈107K
⇒E = k T =
1ke V E
kin≈1 1000E
Coul( r
0)
numberofparticlesinthehighenergy tailoftheMaxwelldistribution:f ( E )
∼e
−E kTf ( E
Coul) = e
−1000=
10−434 numberofnucleons intheSun1057 inthevisibleUniverse1080 3–30 Energyproduction4N u c le a r re a c ti o n ra te s
Quantummechanicaltunnelling: Probability:P
0= p
0E
−1 2e
−2πηη =
rµ
2Z
1Z
2e
2 4π ǫ
0~√E =
rµ
2α Z
1Z
2c
√E µ =
m1m2 m1+m2isthereducedmass; makinguseofthefinestructurecon- stantα =
e2 4πǫ0~c=
1/
137p
0isaconstantthatdependsonµ
inthecoreoftheSun:(T =
107K
):P
0=
10−20 (1keVprotons)3–31 Energyproduction5
N u c le a r re a c ti o n ra te s
Reactionsrates: Lab:numberofreactionsper timeintervaldt
:(i:injectedparticles, t:targets) dN=σnids=σnivdt reactionspertime: dN dt=N τ=σ(v)vni reactionrate: r=dN dtdV=σ(v)vnint 3–32 Energyproduction6N o n -r e s o n a n t re a c ti o n c ro s s s e c ti o n s
Fromquantummechanics:Maximumcrosssectionπ λ
2 dBλ
dB:deBroglie-wavelengthλ
dB=
~p =
~ √ 2m E
crosssectionincludingtunneleffect:σ ( E )
∼π λ
2 dBP
0( E ) = S ( E )
1E e
−2πηη =
r
µ
2α Z
1Z
2c
√E S ( E )
:astrophysicalreactioncrosssectionS ( E )
mustbedeterminedinthelab. problem:crosssectionsareverysmall.MeasurementsaremostlypossibleforE >
0.
1M eV
.Butastrophysicallyinterestingrange1...10keV! ⇒oftenrelyonextrapolation3–33 Energyproduction7
N o n -r e s o n a n t re a c ti o n c ro s s s e c ti o n s
(lhs:totalcrosssection—rhs:astrophysicalfactorS(E)) 3–34 Energyproduction8N u c le a r re a c ti o n ra te s
Velocitydistribution r=nintvσ(v)=nintZ∞ ovσ(E)f(E)dE Maxwell-Boltzmann-distributionforbothpartners⇒distributionofrelative velocitiesisalsoMaxwellian: f(E)dE=2 √ π√ E (kT)3 2e−E kTdE mitσ(E)=S(E)1 Ee−2πηandE=1 2mv2 vσ(v)=Z∞ 0S(E)1 Ee−2πη |{z} σ(E)
r 2 µ√ E |{z} v
2 √ π
√ E (kT)3 2e−E kT |{z} f(E)
dE vσ(v)=23 2 √ πµ
1 (kT)3 2
Z∞ 0S(E)e−E kT−η√ EdE
3–35 Energyproduction9
G a m o v p e a k
mit η=2πη√ E=√ 2mπαZiZtcS ( E )
≈S
0= co n st
fortherelevantenergyrange r∼vσ∼J=Z∞ 0eg(E)dE withg ( E ) =
−E kT−η√ E Crosssectionforfusion: σ(E)=S(E) Eexp−r EG E! Gamovenergy:E
G= η
2=
2m c
2( π α Z
1Z
2)
2E
0isthepeakenergy 3–36 Energyproduction10R e s o n a n t n u c le a r re a c ti o n s
Nuclearreactiona + X
→Y + b
,orX ( a ,b ) Y
ExcitedintermediatenucleusC
∗ formswhichcandecayviadifferentchannels (τ
≈10−21s
): a+X→C∗ →X+a →Y1+b1 →Y2+b2 →... →C+γb
1,b
2,. ..
neutrons,protons,α-particles,noelectrons(τ ( β
−de ca y )
≈1s
). EnergylevelsoftheexitednucleusC
∗ :3–37 Energyproduction11
R e s o n a n t n u c le a r re a c ti o n s E < E
minstationarylevels⇒de-excitationtothegroundlevelbyγ-radiation, Widthofenergylevels:smallE > E
minquasistationarylevels,decayviatunnelling⇒smalllifetimeτ
⇒ largerwidth:∆ E
·τ
≈~(Heisenberg’suncertaintyprinciple) 3–38 Energyproduction12R e s o n a n t n u c le a r re a c ti o n s
Oneresonanceatanappropriateenergymaydominatethereactionratetotally!3–39 Energyproduction13
M e a s u ri n g c ro s s s e c ti o n s : L U N A
LUNA=LaboratoryforUndergroundNuclearAstrophysics(GranSasso,Italy) LUNAI-50 kV LUNAII-400 kV L’AquilaTeramo Figure3.FloorplanoftheLaboratoriNazionalidelGranSasso (LNGS).TheplacesallocatedforthetwoLUNAaccelerator facilitiesaremarked. rhs:Rep.Prog.Phys72,086301(2009) 3–40 Energyproduction14
M e a s u ri n g c ro s s s e c ti o n s : L U N A
400KVacceleratorofLUNA Figure2 TheLUNAsetup.Thetwobeamlinesareintheforeground,andtheacceleratorisinthebackground.The beamlineontheleftisdedicatedtothemeasurementswithsolidtargets,whereastheoneontherighthosts thewindowlessgastarget.Thesetupforthestudyof3He(4He,γ)7Beisshownduringinstallation;theshield isonlypartiallymounted. Annu.Rev.Nucl.Part.Sci.60,53(2010)3–41 Energyproduction15
M e a s u ri n g c ro s s s e c ti o n s : L U N A
400KVacceleratorofLUNA 4He+ beam 4×10–4 mbar 3He0.7 mbar 3He
Water-cooled collimators Diameter: 15 mmDiameter: 7 mmLead shield LeadLead 135% HPGe detector
3He gas inlet 7Be catcher
Lead Calorimeter
Copper shield Roots pump 2,000 m3 h–1 Figure3 Thesetupforthestudyof3He(4He,γ)7Be.ThedevicetodetectRutherfordscattering,thecalorimeter,andthegermaniumdetector areindicated. Annu.Rev.Nucl.Part.Sci.60,53(2010) 3–42 Energyproduction16
M e a s u ri n g c ro s s s e c ti o n s : L U N A
S (eV b)
ECM (keV)
Solar Gamow peak
0.6 0.5 0.4 0.3 0.2 0.1 001020304050
Schmid et al. (54) LUNA 2002 (28)
Griffiths et al. (53) Figure5 The2H(p,γ)3HeastrophysicalfactorS(E)withthetotalerror. Annu.Rev.Nucl.Part.Sci.60,53(2010) theppIreaction:2
H ( p, γ )
3H e
measuredatsolarenergies.3–43 Energyproduction17
M e a s u ri n g c ro s s s e c ti o n s : L U N A
Solar Gamow peak ECM (keV)Dwarakanath & Winkler (58) Krauss et al. (59) LUNA 1998–1999 (26, 27) Kudomi et al. (60)
Cross section (b)
10–5 10–6 10–7 10–8 10–9 10–10 10–11 10–12 10–13 10–14 10–15 10–16 1030100 Figure6 Crosssectionofthe3He(3He,2p)4Hereaction.DatafromLUNA(26,27)andfromothergroups(58–60). ThedashedgraylineistheextrapolationbasedonthemeasuredS(E)-factor(27). Annu.Rev.Nucl.Part.Sci.60,53(2010) theppIreaction3
H e (
3H e,
2p )
4H e
measuredatsolarenergies. 3–44 Energyproduction18M e a s u ri n g c ro s s s e c ti o n s : L U N A
Counts (keV h)
–1
1003He(4He,γ)7Be 10–1 10–2 10–3 00.5
Laboratory γ-ray background 1.0 Eγ (MeV)
1.52.0 Figure7 3He(4He,γ)7Bespectrumatabeamenergyof250keV(red)andthelaboratorybackground(blue). Annu.Rev.Nucl.Part.Sci.60,53(2010) theppIIreaction3
H e (
4H e, γ )
7B e
measuredatsolarenergies.3–45 Energyproduction19
M e a s u ri n g c ro s s s e c ti o n s : L U N A
10340K207Bi 208TI 2H(p,γ)3He 14N(p,γ)15O 15N(p,γ)16O 11B(p,γ)12C102 101 100 10–1 10–2 051015
10–3 10–4 10–5
Counts (keV h) –1
Eγ (MeV)
Laboratory γ-ray background Figure9 Bismuthgermanatespectrumtakenwitha100-keVprotonbeamonnitrogenofnaturalisotopicabundance. Red,peaksfrom14N(p,γ)15Oand15N(p,γ)16O;darkyellow,beam-inducedbackground;blue,laboratory background.Inspiteofthesmallisotopicabundanceof15N(0.366%only),thepeakarisingfrom 15N(p,γ)16Ocanbeeasilyseenthankstothemuch-reducedbackground. Annu.Rev.Nucl.Part.Sci.60,53(2010) protonreactionsonnitrogenisotopesimportantintheCNOcycle. 3–46 Energyproduction20
M e a s u ri n g c ro s s s e c ti o n s : L U N A
78 6 5 4 3 2 1 0050100150200S (keV b)
Lamb & Hester (82) Schröder et al. (83) NACRE extrapolation 1999 (81) LUNA data 2004 (29) (solid target) LUNA extrapolation 2004 (30) TUNL data 2005 (93) LUNA data 2006 (31) (gas target) Solar Gamow peak ECM (keV) Figure10 AstrophysicalS(E)-factorofthe14N(p,γ)15Oreaction.Theerrorsarestatisticalonly(thesystematicones aresimilar). Annu.Rev.Nucl.Part.Sci.60,53(2010) the14
N ( p, γ )
15O
reactionoftheCNcyclehasnotyetbeenmeasuredatsolar energies,butLUNAresultsarelowerbyafactorof2thanearlierones.Important forageofoldeststarclustersandsolarneutrinorates.3–47 Energyproduction21
H y d ro g e n b u rn in g
41H
→4H e ∆ M c
2=
26.
731M eV
Twoprotonsareconvertedintoneutrons(β+ -decay).Twoneutrinosare produced,whichcarryaway2...30%oftheenergy. Tworeactionchainsforhydrogenburning: proton-protonchain, CNOcycle 3–48 Energyproduction22H y d ro g e n b u rn in g : p p c h a in s
Threevariantsoftheppchain pp1pp2pp3energyproductionrate: ǫpp∼ρX2 T5 (approximationvalidfor T≈107 K).
3–49 Energyproduction23
H y d ro g e n b u rn in g : p p c h a in s
timescalesforppreactions: (I)1H +
1H
→2D + e
++ ν
1010 years (II)2D +
1H
→3H e
10s (III)3H e +
3H e
→4H e +
21H
106 years Changeofabundancesof2D
and3H e
inrelationto1H
(I)und(II)havetooccurtwice,before(III)canstart (I)creates2D
,(II)destroys2D
, (II)creates3H e
,(III)destroys3H e
. 3–50 Energyproduction24H y d ro g e n b u rn in g : p p c h a in s
inanequilibriumstateabundanceof2D
und3H e
willbedeterminedby: rI=N1H τ1H=rII=N2D τ2D rII=N2D τ2D=2rIII=2N3He τ3He ⇒N2D N1H=τ2D τ1H=3·10−17 N3He N1H=τ3He τ1H=5·10−5 energyproductioncoefficient: ǫpp∼ρX2T5 (validforT≈107 K).FusionprocesswiththesmallestT-sensitivity.3–51 Energyproduction25
H y d ro g e n b u rn in g : C N O c y c le
CNOcycle(s) •catalyticprocess •catalyst(e.g.C)mustbe available •sequenceofprotoncap- turesfollowedbyβdecay •energyproductionrate: ǫCNO∼ρXXCNOT16 (approximationvalidfor T≈107.5 K). 3–52 Energyproduction26C N O -c y c le (B e th e -W e iz s ä c k e r- p ro c e s s )
timescalesforthereactionsintheCN-cycle: (I)12C ( p, γ )
13N
107 years (II)13C ( p, γ )
14N
106 years (III)14N ( p, γ )
15O
108 years (IV)15N ( p, α )
12C
105 yearsβ
+ -Zerfälle13N ( e
+ν )
13C
,15O ( e
+ν )
15N
: 1...10min3–53 Energyproduction27
H y d ro g e n b u rn in g : C N O c y c le
TheCNO-cyclemodifiestherelativeabundancesoftheC,N,andOisotopes •thetotalnumberof CNOnucleiremains constant, •however,mostCand Onucleiconverted into14 Nbecause 14N ( p, γ )
15O
isthe slowestreactionof theCNOcycle(s)EvolutionofCNO-isotopeswithtime: Equilibriumreachedafter≈108 years. 3–54 Energyproduction28
H y d ro g e n b u rn in g : C N O c y c le
TheCNO-cyclemodifiesrelativeabundancesoftheC,N,andOisotopes •totalnumberofCNO nucleiremainsconstant, •mostCandOnucleicon- vertedinto14 Nbecause 14N ( p, γ )
15O
istheslow- estreaction •theabundanceratio ofthecarbonisotopes 12C /
13C
decreasesto≈ 4. ”Smokinggun”forfor CNOcycle(solarvalue: 89).(lhs:absolutevalues—rhs:isotoperatios)3–55 Energyproduction29
H y d ro g e n b u rn in g
Additionalcycles:NeNa-,MgAl-cycles 3–56 Energyproduction30H e liu m b u rn in g
Combiningof4 He-nucleitoform12 C(and16 O). 4He+4He→8Be−92keV endothermreaction⇒8 Bedecaysto4 Hewithinτ (
8B e) =
2.
6·10−16s
. τ(8 Be)stilllargecomparedtocollisionaltimescale:≈105 collisionsof4 He duringτ (
8B e)
whichallowstoform12 C 8 Be+4 He→12 C+γ Highreactionratebecauseofaresonance. energyproductionrate:ǫ3α∼ρ2 Y3 T303–57 Energyproduction31
H e liu m b u rn in g
12C
maycaptureanotherα-particle:12C +
4H e
→16O + γ
resonantreaction(“subthreshhold”):q =
7.
16M eV
Figure22.ThepresentstatusoftheSfactordatafor12C(α,γ)16O. ThetotalSfactormeasurementofERNA(filled-incircles)[12]is comparedwithrecentE1(opentriangles)andE2(opensquares) γ-raymeasurements[98]andtheEx=6.05MeVcascadedata (opencircles)[100].Thesolidlinerepresentsthesumofthesingle amplitudesofanR-matrixfit[99](thedottedanddashedlinesare theE1andE2amplitudes,respectively).Inaddition,theR-matrix fitof[100]totheircascadedata(dotted–dashedline)isshown.The lattercomponentisnotincludedinthesumandmightexplainthe highyieldintheERNAdatabetweentheresonances.Furthercapturesarealsoendotherm 16
O ( α ,γ )
20N e
,20N e( α ,γ )
24M g
,... But16O ( α ,γ )
20N e
isnon-resonant→ veryhightemperaturesneeded. noα-capturesbeyond16 Oduringhe- liumburningphasesofstellarevolu- tion. reactioncrosssectionisstill uncertainbyafactorof3. 3–58 Energyproduction32H y d ro g e n a n d h e liu m b u rn in g
fractionsofenergyproductionfrompp-,CNO- and3α-processes: uppermainsequence(sp. typeAandearlier):CNO- cycle lowermainsequence(sp. typeGandlater)pp-chain 3α-process:T≥108K⇒ notduringmainsequence phase Moreonnuclearburningtoironlater!3–59 Energyproduction33
N e u tr in o s
Theroleofneutrinos verysmallcross-section: σν≈ Eν mec22 ·10−44 cm−2 solarneutrinos:E
ν≈1M eV
⇒σ
ν≈10−44cm
−2 ,1018 timessmallerthan photonabsorptioncross-sections! meanfreepath: lν=1 nσν=µmH ρσν=2·1020 ρcm Sunρ =
1g cm
−3 ⇒l
ν=
100p c
whitedwarfρ =
106g cm
−3 ⇒l
ν=
3000R
⊙ ⇒neutrinosescapewithoutinteraction,theirenergyislostfromthestellar interior. 3–60 Energyproduction34N e u tr in o s
neutrinoproductionduringhydrogenburning.5possiblereactions: 3He(3He,2p)4He 7Be(e–,ν)7Li 8Be*(4He)4He8B(e+ν)8Be* * Be produced into an excited level
7Li(p,4He)4He 7Be(p,γ)8B
3He(4He,γ)7Be3He(p,e+ν)4He 14%0.02%
86%14%0.00003%
2H(p,γ)3He
1H(p,e+ν)2H 99.75%0.25%
1H(pe–,ν)2H Q/MeV 1