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Physikalisches Institut Exercise 00

Universit¨at Bonn 13. April 2011

Theoretische Physik SS 2011

Exercises on General Relativity and Cosmology

Priv. Doz. Dr. S. F¨orste

–Class Exercises–

Exercise 0.1: Lorentz boosts

Consider a boost in the x-direction with speed vA = tanh(α) followed by a boost in the y-direction with a speed vB= tanh(β). Show that the resulting Lorentz transformation is the same as doing a pure rotation followed by a pure boost, and determine the rotation and boost.

Exercise 0.2: Electromagnetism

Maxwell’s equations are given by

→∇ ·−→

E =, −→

∇ ×−→

B = ∂−→ E

∂t +−→ J , −→

∇ ·−→

B = 0, −→

∇ ×−→

E =−∂−→ B

∂t

To make their properties under Lorentz transformation explicit, we can choose an anti- symmetric 4×4 tensor, Fµν, the electromagnetic field tensor and the (charge and current) source density four-vector,Jµ, as:

Fµν(t,x) =

0 E1 E2 E3

−E1 0 B3 −B2

−E2 −B3 0 B1

−E3 B2 −B1 0

Jµ(t,x) = (, J) =

3(x−x(t)), eδ3(x−x(t))dx(t) dt

(a) Show that ∂µFµν =−Jν and µνρσνFρσ = 0 reproduce Maxwell’s equations. What are the Lorentz invariants that can be constructed?

(b) Verify in the rest frame that

fµ≡ dpµ

dτ =eFµνdxν

is the correct equation for the electromagnetic four-force fµ acting on a charged particle. (pµ=m dxµ/dτ)

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(2)

Exercise 0.3: Energy-momentum tensor

In analogy to the electrical charge and current density vector above, we can define a

“charge” and “current density” for the matter 4-momentum,pµ, thematter energy-momen- tum tensor:

Tmµν(x, t)≡pµ(t)dxν(t)

dt δ3(x−x(t))

(a) Show that the energy-momentum tensor is only conserved up to aforce density, Gµ which vanishes for free particles:

νTµν =Gµ

(b) Check that for the (interacting) electromagnetic quantities given above, we get Gµ to beFµνJν.

(c) The electromagnetic energy-momentum tensor was defined in the lecture as:

Temµν ≡FµρFνρ− 1

µνFρσFρσ

Show that the divergence of this cancels with that of Gµ defined in (b), so that Tmµν+Temµν is conserved.

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