• Keine Ergebnisse gefunden

Lösungen Teil 1

N/A
N/A
Protected

Academic year: 2021

Aktie "Lösungen Teil 1"

Copied!
17
0
0

Wird geladen.... (Jetzt Volltext ansehen)

Volltext

(1)

Lösungen Teil 1

1

OA=83, 0, 4<; OB=81, 1, 1<; OC=8-7, 5, 11<; Solve@HOB-OALŠ lHOC-OAL,8l<D

8<

Die Punkte liegen icht auf einer Geraden.

2

Ÿ a

a1=81, 3, 0<; a2=86, 2, 0<; r1=82,-3, 1<; r2=8-1,-4, 1<; Solve@a1Š la2,8l<D

8<

Richtungsvektoren nicht parallel

solv=Solve@r1+ la1Šr2+ ma2,8l,m<D ••Flatten 9l ®0,m ® 1

€€€€2=

Schnittpunkt=r1+ la1. solv@@1DD 82,-3, 1<

Ÿ b

a1=84, 3, 0<; a2=8-8,-6, 0<; r1=80, 0, 0<; r2=810, 6, 3<; Solve@a1Š la2,8l<D

99l ® -1

€€€€2==

Richtungsvektoren parallel

solv=Solve@r1+ la1Šr2+ ma2,8l,m<D ••Flatten 8<

(2)

Kein Schnittpunkt

Ÿ c

a1=80, 0, 1<; a2=82, 0,-1<; r1=83, 0, 5<; r2=81,-3, 6<; Solve@a1Š la2,8l<D

8<

Richtungsvektoren nicht parallel

solv=Solve@r1+ la1Šr2+ ma2,8l,m<D ••Flatten 8<

Kein Schnittpunkt

Ÿ d

a1=87, 2,-1<; a2=8-14,-4, 2<; r1=84,-3, 2<; r2=8-10,-7, 4<; Solve@a1Š la2,8l<D

99l ® -1

€€€€2==

Richtungsvektoren parallel

solv=Solve@r1+ la1Šr2+ ma2,8l,m<D ••Flatten 8l ® -2-2m<

3

xg@s_D:= -1+s 6;

yg@s_D:= -4+s 2;

zg@s_D:= 1+s 0;

g@s_D:=8xg@sD, yg@sD, zg@sD<; g@sD 8-1+6 s,-4+2 s, 1<

xh@t_D:= 2+t 1;

yh@t_D:= -3+t 3;

zh@t_D:= 1+t 0;

h@t_D:=8xh@tD, yh@tD, zh@tD<; h@tD 82+t,-3+3 t, 1<

Solve@g@sDŠh@tD,8s, t<D 99s® 1

€€€€2, t®0==

(3)

Schnittpunkt=h@0D 82,-3, 1<

w@t_D:=Schnittpunkt+

t HHg@1D-g@0DL •Norm@Hg@1D-g@0DLD+Hh@1D-h@0DL •Norm@Hh@1D-h@0DLDL; w@

tD

92+2$%%%%%%%2

€€€€5 t,-3+2$%%%%%%%2

€€€€5 t, 1=

w@t Sqrt@52D •2D 82+t,-3+t, 1<

8w@t Sqrt@52D •2D< ••Transpose••MatrixForm i

kjjjjj jj

2+t -3+t 1

y {zzzzz zz

4

OA=83,-2, 2<; OB=8-3, 5, 8<; OU=82, 1,-3<; OV=81, 5, 4<; OW=86,-2,-1<;

g@t_D:=OA+t HOB-OAL; g@tD

83-6 t,-2+7 t, 2+6 t<

F@l_,m_D:=OU+ l HOV-OUL+ m HOW-OUL; F@l,mD

82- l +4m, 1+4l -3m,-3+7l +2m<

solv=Solve@g@tD Š F@l,mD,8t,l,m<D ••Flatten 8t® -3,l ® -3,m ®4<

Schnittpunkt=g@tD •. solv 821,-23,-16<

5

Ÿ a

F@l_,m_D:=81, 2,-3<+ l 8-1, 4, 7<+ m 84,-3, 2<; F@l,mD

81- l +4m, 2+4l -3m,-3+7l +2m<

(4)

Y@n_,x_D:=85,-2,-3<+ n 822,-23,-4<+ x 813, 0, 29<; Y@n,xD

85+22n +13x,-2-23n,-3-4n +29x<

solv=Solve@Y@n,xD Š F@l,mD,8n,x,l,m<D ••Flatten 8<

Kein Schnittpunkt: Ebenen parallel

Ÿ b

F@l_,m_D:=85, 1, 8<+ l 81, 0, 3<+ m 82, 1,-1<; F@l,mD

85+ l +2m, 1+ m, 8+3l - m<

Y@n_,x_D:=811, 7,-16<+ n 86, 2,-1<+ x 8-1,-1, 3<; Y@n,xD

811+6n - x, 7+2n - x,-16- n +3x<

solv=Solve@Y@n,xD Š F@l,mD,8n,x,l,m<D ••Flatten 9n ® -6

€€€€7 + €€€€m

7,x ® 30

€€€€€€€

7 - €€€€€€€€€5m

7 ,l ® -24

€€€€€€€

7 - €€€€€€€€€3m 7 = HF@l,mD •. solvL ••Simplify

9€€€€€€€€€€€€€€€€€€€€€€€€€11H1+ mL

7 , 1+ m,-16

€€€€€€€

7 H1+ mL=

HY@n,xD •. solvL ••Simplify 9€€€€€€€€€€€€€€€€€€€€€€€€€11H1+ mL

7 , 1+ m,-16

€€€€€€€

7 H1+ mL=

Schnittgerade, hier dargestellt mit Parameter m

H1-t ^ 6L • H1-tL ••Simplify 1+t+t2+t3+t4+t5

6

Remove["Global`*"]

F[l_,m_]:={2,3,1}+l{4,-2,3}+m{1,0,-2};

F[l,m]

82+4l + m, 3-2l, 1+3l -2m<

solv=Solve[{x,y,z}==F[l,m],{l,m,x}]//Flatten 9l ® 3-y

€€€€€€€€€€€€

2 ,m ® 1

€€€€4 H11-3 y-2 zL, x® 1

€€€€4 H43-11 y-2 zL=

(5)

(x1-x==0 /.solv) x1+ 1

€€€€4 H-43+11 y+2 zLŠ0

(%/.x1->x)//Simplify 4 x+11 y+2 zŠ43

7

Remove["Global`*"]

F[{x_,y_,z_}]:=3x-7z-21;

P1={0,0,z}; P2={0,y,0}; P3={x,0,0};

solv1=Solve[F[P1]==0,{z}]//Flatten 8z® -3<

P1={0,0,z}/.solv1 80, 0,-3<

solv2=Solve[F[P2]==0,{y}]//Flatten 8<

P2={0,y,0}/.solv2 80, y, 0<

y ist beliebig. Setze y=1

y=1;

solv3=Solve[F[P3]==0,{x}]//Flatten 8x®7<

P3={x,0,0}/.solv3 87, 0, 0<

F[l_,m_]:= P1+l(P2-P1)+m(P3-P1);

{F[l,m]}//Transpose//MatrixForm i

kjjjjj jj

7m l

-3+3l +3m y {zzzzz zz

8

Remove["Global`*"]

(6)

Ÿ a

PA={4,3,-2}; PB={-3,1,2}; PC={1,0,2};

F[l_,m_]:= PA+l(PB-PA)+m(PC-PA);

{F[l,m]}//Transpose//MatrixForm i

kjjjjj jj

4-7l -3m 3-2l -3m -2+4l +4m

y {zzzzz zz

Ÿ b

PA={2,-3,0}; PB={-4,6,2}; PC={0,0,9};

F[l_,m_]:= PA+l(PB-PA)+m(PC-PA);

{F[l,m]}//Transpose//MatrixForm i

kjjjjj jj

2-6l -2m -3+9l +3m 2l +9m

y {zzzzz zz

Lösungen Teil 2

1

Remove["Global`*"]

OA={-1,0,5}; OB={3,-4,7}; OC={2,2,3};

a = ArcCos[(OB-OA).(OC-OA)/(Norm[OB-OA] Norm[OC-OA])]

€€€€p 2

%/Degree//N 90.

b = ArcCos[(OA-OB).(OC-OB)/(Norm[OA-OB] Norm[OC-OB])]

ArcCosA 6

€€€€€€€€€€€€€•!!!!!!!53 E

%/Degree//N 34.4962

g = ArcCos[(OA-OC).(OB-OC)/(Norm[OA-OC] Norm[OB-OC])]

ArcCosA$%%%%%%%%%%€€€€€€€17 53 E

(7)

%/Degree//N 55.5038

Ÿ Kontrolle

Ha + b + gL •Degree••N 180.

2

Remove["Global`*"]

OP={1,2,0}; F[{x_,y_,z_}]:=x-y+2z-3; nVec={1,-1,2};

h[l_]:=OP+l nVec;

solv=Solve[F[h[l]]==0,{l}]//Flatten 9l ® 2

€€€€3=

OS=h[l]/.solv 95

€€€€3, 4

€€€€3, 4

€€€€3=

OPgespiegelt=OP+2(OS-OP) 97

€€€€3, 2

€€€€3, 8

€€€€3=

d=Norm[2(OS-OP)]

4$%%%%%%%2

€€€€3

Norm[OP-OPgespiegelt]

4$%%%%%%%2

€€€€3

% //N 3.26599

3

Remove["Global`*"]

OP={p1,p2,p3}; a={a1,a2,a3}; b={b1,b2,b3};

g1[l_]:=OP+ l a;

g2[m_]:=OP+ m b;

s1[l_]:=OP+ l (a/Norm[a]+b/Norm[b]);

s2[m_]:=OP+ m (a/Norm[a]-b/Norm[b]);

(8)

((a/Norm[a]+b/Norm[b]).(a/Norm[a]-b/Norm[b])//Simplify)/.{Abs[a1]^2->a1^2,Abs[a2]^2 ->a2^2,Abs[a3]^2->a3^2,Abs[b1]^2->b1^2,Abs[b2]^2->b2^2,Abs[b3]^2->b3^2}

Ha12b12+a22b12+a12b22+a22b22+a12b32+a22b32-

a12Hb12+b22+b32L-a22Hb12+b22+b32LL • HHa12+a22+a32L Hb12+b22+b32LL

%//Expand 0

4

Remove["Global`*"]

a={3,8,x}; b={3,-8,x};

a.b == Norm[a] Norm[b] Cos[60 Degree]

-55+x2Š 1

€€€€2 H73+Abs@xD2L

Solve[a.b == Norm[a] Norm[b] Cos[60 Degree],{x}]

99x® -•!!!!!!!!!!183=,9x®•!!!!!!!!!!183==

%//N

88x® -13.5277<,8x®13.5277<<

5

Remove["Global`*"]

OA={2,-4,-9}; OB={0,6,1}; OX[s_]:={3,12,16}+s {3,10,11};

Simplify[(OA-OB).(OX[s]-OB)]==0 -204H1+sLŠ0

solv=Solve[(OA-OB).(OX[s]-OB)==0,{s}]//Flatten 8s® -1<

OC=OX[s]/.solv 80, 2, 5<

OD=OC+(OA-OB) 82,-8,-5<

6

Remove["Global`*"]

(9)

HNFF[x_,y_,z_]:=(x+2y+3z-5)/Sqrt[1^2+2^2+3^2];

HNFY[x_,y_,z_]:=(x+2y+3z+2)/Sqrt[1^2+2^2+3^2];

HNFF[0,0,0]

- 5

€€€€€€€€€€€€€•!!!!!!!14

HNFY[0,0,0]

$%%%%%%%2

€€€€7

HNFY[0,0,0]-HNFF[0,0,0]

$%%%%%%%2

€€€€7 + 5

€€€€€€€€€€€€€•!!!!!!!14

N[%]

1.87083

7

Remove["Global`*"]

NFFF[x_,y_,z_]:=(3x-y+3z-1)/Sqrt[3^2+(-1)^2+2^2];

HNFY[x_,y_,z_]:=(-6x+2y-4z-7)/Sqrt[(-6)^2+2^2+(-4)^2];

Print[NFFF[x,y,z], " ",HNFY[x,y,z]]

-1+3 x-y+3 z

€€€€€€€€€€€€€€€€•!!!!!!!€€€€€€€€€€€€€€€€14 €€€€€€€€€

-7-6 x+2 y-4 z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€

2•!!!!!!!14

Normalenvektoren nicht paralle!

Solve[{NFFF[x,y,z]==0, HNFY[x,y,z]==0},{x,y,z}]

99x® -25

€€€€€€€

6 + y

€€€€3, z® 9

€€€€2==

N[%]

88x® -4.16667+0.333333 y, z®4.5<<

Schnittgerade! Abstand = 0.

8

Remove["Global`*"]

(10)

OP={-1,0,3};

HNFF[x_,y_,z_]:=(-x+2y+5z+2)/Sqrt[(-1)^2+2^2+5^2]; HNFF[{x_,y_,z_}]:= HNFF[x,y,z];

HNFF[x,y,z]

2-x+2 y+5 z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€•!!!!!!!30

HNFF[OP]

3$%%%%%%%6

€€€€5

N[%]

3.28634

9

Remove["Global`*"]

HNFF[x_,y_,z_]:=(3x-5y-4z-10)/Sqrt[3^2+(-5)^2+(-4)^2];

HNFF[x,y,z]

-10+3 x-5 y-4 z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€

5•!!!!2

HNFY1[x_,y_,z_]:=(3x-5y-4z-10)/Sqrt[3^2+(-5)^2+(-4)^2]+4;

HNFY1[0,0,0]

4-•!!!!2 N[%]

2.58579

HNFY2[x_,y_,z_]:=(3x-5y-4z-10)/Sqrt[3^2+(-5)^2+(-4)^2]-4;

HNFY2[0,0,0]

-4-•!!!!2 N[%]

-5.41421

10

Remove["Global`*"]

HNFF[x_,y_,z_]:=(-x-2y+z-2)/Sqrt[(-1)^2+(-2)^2+(1)^2];

HNFF[x,y,z]

-2-x-2 y+z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€•!!!!6

(11)

OA={3,4,2}; OB={1,-1,5}; OC={3,0,1}; nVec=Cross[(OB-OA),(OC-OA)]

817,-2, 8<

HNFY[x_,y_,z_]:=({x,y,z}.nVec+dD)/Norm[nVec]; HNFY[{x_,y_,z_}]:=HNFY[x,y,z];

HNFY[x,y,z]

dD+17 x-2 y+8 z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€•!!!!!!!!!!357 €€€€€€€€€€€€€€€

solv=Solve[HNFY[OA]==0,{dD}]//Flatten 8dD® -59<

HNFY[x_,y_,z_]:=({x,y,z}.nVec+dD)/Norm[nVec]/. solv;

HNFY[x,y,z]

-59+17 x-2 y+8 z

€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€•!!!!!!!!!!357€€€€€€€€€€€€€€€€€€

Simplify[Sqrt[357] HNFY[x,y,z]-Sqrt[6] HNFF[x,y,z]]==0 -57+18 x+7 zŠ0

Simplify[Sqrt[357] HNFY[x,y,z]+Sqrt[6] HNFF[x,y,z]]==0 -61+16 x-4 y+9 zŠ0

11

Ÿ Der Umkreismittelpunkt liegt auf den Senkrechten durch die Seitenmittelpunkte.

Remove["Global`*"]

OA={a1,a2,a3}; OB={b1,b2,b3}; OC={c1,c2,c3};

OM[l_,m_]:=OA+l (OB-OA)+m (OC-OA)//Simplify;

OM[l,m]

8b1l +c1m -a1H-1+ l + mL, b2l +c2m -a2H-1+ l + mL, b3l +c3m -a3H-1+ l + mL<

OM ist Lösung des Gleichungssystems:

r^2 = |OM-OA|^2, r^2 = |OM-Ob|^2, r^2 = |OM-OC|^2 (3 Gelichungen, Unbekannte r, l, m)

{r^2==(OM[l,m]-OA), r^2==(OM[l,m]-OB), r^2==(OM[l,m]-OC)}

8r2Š8-a1+b1l +c1m -a1H-1+ l + mL,

-a2+b2l +c2m -a2H-1+ l + mL,-a3+b3l +c3m -a3H-1+ l + mL<, r2Š8-b1+b1l +c1m -a1H-1+ l + mL,-b2+b2l +c2m -a2H-1+ l + mL,

-b3+b3l +c3m -a3H-1+ l + mL<, r2Š8-c1+b1l +c1m -a1H-1+ l + mL, -c2+b2l +c2m -a2H-1+ l + mL,-c3+b3l +c3m -a3H-1+ l + mL<<

Solve[{r^2==(OM[l,m]-OA).(OM[l,m]-OA), r^2==(OM[l,m]-OB).(OM[l,m]-OB), r^2==(OM[l,m]-OC).(OM[l,m]-OC)},{l,m,r}]//Simplify

(12)

99r® -1

€€€€2 ,HHHa12+a22+a32-2 a1 b1+b12-2 a2 b2+b22-2 a3 b3+b32L Ha12+a22+a32-2 a1 c1+c12-2 a2 c2+c22-2 a3 c3+c32L Hb12+b22+b32-2 b1 c1+c12-2 b2 c2+c22-2 b3 c3+c32LL •

Ha12b22+a12b32-2 a1 b22c1-2 a1 b32c1+b22c12+b32c12-2 a12b2 c2+ 2 a1 b1 b2 c2+2 a1 b2 c1 c2-2 b1 b2 c1 c2+a12c22-2 a1 b1 c22+b12c22+ b32c22+a32Hb12+b22-2 b1 c1+c12-2 b2 c2+c22L-2 a12b3 c3+

2 a1 b1 b3 c3+2 a1 b3 c1 c3-2 b1 b3 c1 c3-2 b2 b3 c2 c3+a12c32-

2 a1 b1 c32+b12c32+b22c32+a22Hb12+b32-2 b1 c1+c12-2 b3 c3+c32L- 2 a2H-b1 b2 c1+b2 c12+a1Hb1-c1L Hb2-c2L+b12c2+b32c2-b1 c1 c2+

a3Hb2-c2L Hb3-c3L-b2 b3 c3-b3 c2 c3+b2 c32L-2 a3Hb3 c12-b2 b3 c2+ b3 c22+a1Hb1-c1L Hb3-c3L+b12c3+b22c3-b2 c2 c3-b1 c1Hb3+c3LLLL, l ®HHb12-a2 b2+b22-a3 b3+b32-b1 c1+a1H-b1+c1L+a2 c2-b2 c2+a3 c3-b3 c3L

Ha12+a22+a32-2 a1 c1+c12-2 a2 c2+c22-2 a3 c3+c32LL •

H2Ha12b22+a12b32-2 a1 b22c1-2 a1 b32c1+b22c12+b32c12-2 a12b2 c2+ 2 a1 b1 b2 c2+2 a1 b2 c1 c2-2 b1 b2 c1 c2+a12c22-2 a1 b1 c22+b12c22+ b32c22+a32Hb12+b22-2 b1 c1+c12-2 b2 c2+c22L-2 a12b3 c3+

2 a1 b1 b3 c3+2 a1 b3 c1 c3-2 b1 b3 c1 c3-2 b2 b3 c2 c3+a12c32-

2 a1 b1 c32+b12c32+b22c32+a22Hb12+b32-2 b1 c1+c12-2 b3 c3+c32L- 2 a2H-b1 b2 c1+b2 c12+a1Hb1-c1L Hb2-c2L+b12c2+b32c2-b1 c1 c2+

a3Hb2-c2L Hb3-c3L-b2 b3 c3-b3 c2 c3+b2 c32L-2 a3Hb3 c12-b2 b3 c2+ b3 c22+a1Hb1-c1L Hb3-c3L+b12c3+b22c3-b2 c2 c3-b1 c1Hb3+c3LLLL, m ®HHa12+a22+a32-2 a1 b1+b12-2 a2 b2+b22-2 a3 b3+b32L

Ha3 b3+a1Hb1-c1L-b1 c1+c12+a2Hb2-c2L-b2 c2+c22-a3 c3-b3 c3+c32LL • H2Ha12b22+a12b32-2 a1 b22c1-2 a1 b32c1+b22c12+b32c12-2 a12b2 c2+

2 a1 b1 b2 c2+2 a1 b2 c1 c2-2 b1 b2 c1 c2+a12c22-2 a1 b1 c22+b12c22+ b32c22+a32Hb12+b22-2 b1 c1+c12-2 b2 c2+c22L-2 a12b3 c3+

2 a1 b1 b3 c3+2 a1 b3 c1 c3-2 b1 b3 c1 c3-2 b2 b3 c2 c3+a12c32-

2 a1 b1 c32+b12c32+b22c32+a22Hb12+b32-2 b1 c1+c12-2 b3 c3+c32L- 2 a2H-b1 b2 c1+b2 c12+a1Hb1-c1L Hb2-c2L+b12c2+b32c2-b1 c1 c2+

a3Hb2-c2L Hb3-c3L-b2 b3 c3-b3 c2 c3+b2 c32L-2 a3Hb3 c12-b2 b3 c2+ b3 c22+a1Hb1-c1L Hb3-c3L+b12c3+b22c3-b2 c2 c3-b1 c1Hb3+c3LLLL=, 9r® 1

€€€€2 ,HHHa12+a22+a32-2 a1 b1+b12-2 a2 b2+b22-2 a3 b3+b32L Ha12+a22+a32-2 a1 c1+c12-2 a2 c2+c22-2 a3 c3+c32L Hb12+b22+b32-2 b1 c1+c12-2 b2 c2+c22-2 b3 c3+c32LL •

Ha12b22+a12b32-2 a1 b22c1-2 a1 b32c1+b22c12+b32c12-2 a12b2 c2+ 2 a1 b1 b2 c2+2 a1 b2 c1 c2-2 b1 b2 c1 c2+a12c22-2 a1 b1 c22+b12c22+ b32c22+a32Hb12+b22-2 b1 c1+c12-2 b2 c2+c22L-2 a12b3 c3+

2 a1 b1 b3 c3+2 a1 b3 c1 c3-2 b1 b3 c1 c3-2 b2 b3 c2 c3+a12c32-

2 a1 b1 c32+b12c32+b22c32+a22Hb12+b32-2 b1 c1+c12-2 b3 c3+c32L- 2 a2H-b1 b2 c1+b2 c12+a1Hb1-c1L Hb2-c2L+b12c2+b32c2-b1 c1 c2+

a3Hb2-c2L Hb3-c3L-b2 b3 c3-b3 c2 c3+b2 c32L-2 a3Hb3 c12-b2 b3 c2+ b3 c22+a1Hb1-c1L Hb3-c3L+b12c3+b22c3-b2 c2 c3-b1 c1Hb3+c3LLLL, l ®HHb12-a2 b2+b22-a3 b3+b32-b1 c1+a1H-b1+c1L+a2 c2-b2 c2+a3 c3-b3 c3L

Ha12+a22+a32-2 a1 c1+c12-2 a2 c2+c22-2 a3 c3+c32LL •

H2Ha12b22+a12b32-2 a1 b22c1-2 a1 b32c1+b22c12+b32c12-2 a12b2 c2+ 2 a1 b1 b2 c2+2 a1 b2 c1 c2-2 b1 b2 c1 c2+a12c22-2 a1 b1 c22+b12c22+ b32c22+a32Hb12+b22-2 b1 c1+c12-2 b2 c2+c22L-2 a12b3 c3+

2 a1 b1 b3 c3+2 a1 b3 c1 c3-2 b1 b3 c1 c3-2 b2 b3 c2 c3+a12c32-

2 a1 b1 c32+b12c32+b22c32+a22Hb12+b32-2 b1 c1+c12-2 b3 c3+c32L- 2 a2H-b1 b2 c1+b2 c12+a1Hb1-c1L Hb2-c2L+b12c2+b32c2-b1 c1 c2+

a3Hb2-c2L Hb3-c3L-b2 b3 c3-b3 c2 c3+b2 c32L-2 a3Hb3 c12-b2 b3 c2+ b3 c22+a1Hb1-c1L Hb3-c3L+b12c3+b22c3-b2 c2 c3-b1 c1Hb3+c3LLLL, m ®HHa12+a22+a32-2 a1 b1+b12-2 a2 b2+b22-2 a3 b3+b32L

L •

Referenzen

ÄHNLICHE DOKUMENTE

Konstruktion mit dem Zirkel Seite 25.. Zeichnungstechnik Technische Dokumente Kap. ➢ Mit Hilfe von Bildern, Zeichen und Symbolen werden technische Sachverhalte

[r]

Du verkaufst in deinem Tante-Emma-Laden Obst. Dazu steht eine Schale an der Kasse, in der Birnen liegen. Diese beziehst du kostenfrei und ausreichend aus deinem eigenen

5. Als sie einen Zaubertrank trinkt, wird sie auf die Größe eines 15cm großen Pilzes geschrumpft und erlangt so Zutritt zum Wunderland. Bei einem Würfel sollte das

8.There aren’t many people in town during the

Bike tyres are usually made of rubber.. Phones are usually made

2 H-Atome gehen verloren bei der Einführung einer Doppelbindung oder einer Zyklisierung.. Mit

Die Normalparabel geht durch den Koordinatenursprung; der Graph der Exponentialfunktion schneidet die y-Achse; die Hyperbel ist bei x = 0 nicht definiert und schneidet