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Proof of Multiscale Convergence

By the Lipschitz assumption(A2)we have

kU(·,0;q)u0−U(·,0; ˜q)u0kC(Iε,X)kq−q˜kC(Iε) ku0k+λ(Tε) . Thus for the initial Lipschitz estimate:

kSε(q)−Sεq)kC(Iε)εTεkq−q˜kC(Iε)(1 +λ(Tε)).

With Tε sufficiently small, this implies that Sε is a contraction and hence Banach’s fixed-point theorem yields existence and uniqueness ofqε.

For the breakdown result, note that by g’s boundedness, limtTεqε(t) ex-ists. If qε(Tε) Q we could extend qε beyond Tε locally, contradicting the

maximality of Tε. Henceqε(Tε)∈∂Q.

3.4 Proof of Multiscale Convergence

We use the following classical result for averaging of an ordinary differential equations with periodic right-hand side, cf. [SVM07, Theorem 2.8.1]:

Theorem 3.4.1. LetQ⊂Rn be connected, bounded and open. Letf: R×Q→ Rn be 1-periodic, continuous in its first and uniformly Lipschitz continuous in its second argument. Then for anyx0∈Qthere is aT >0such that a solution x0: [0, ε1T]→Qof

x0(t) =εf(x0(t)) :=ε Z 1

0

f(s, x0(t))ds, x0(0) =x0

exists. The solution x0 is a first order approximation of the solution xεof xε(t) =εf(t, xε(t)), xε(0) =x0

in the sense that there is an ε>0 such that for any0 < ε < ε the solution xεexists for all t∈[0, ε1T] and there holds

max

t[0,ε−1T]|xε(t)−x0(t)|ε.

Proof. The existence of limit solutions on the O(ε1)-timescale follows by rescaling to slow time, τ := εt, and using that x 7→ R1

0 f(s, x)ds is Lips-chitz continuous, since f is. The main ingredient for the averaging result is a comparison ofx0 andxεby keepingxεfixed on small intervals, see [Art07] for

details.

Corollary 3.4.2. There exists T > 0 independent of ε such that the limit equation

q0(t) =ε Z 1

0

g(q0(t), uπ(s;q0(t)))ds, q0(0) =q0 (3.2) has a unique solutionq0: [0, ε1T]→Q. Furthermore, there is anε>0such that for all0< ε < ε the solutionqε,π of

qε,π (t) =εg(qε,π(t), uπ(t;qε,π(t))), qε,π(0) =q0. (3.7) exists for t∈[0, ε1T] with

max

t[0,ε1T]|qε,π(t)−q0(t)|ε.

Proof. Define G(t, q) := g(q, uπ(t;q)). Then qε,π (t) = εG(t, qε,π(t)) and G is continuous and1-periodic intand Lipschitz continuous inq, the latter following from the Lipschitz continuity of g by assumption and ofuπ byLemma 3.3.2.

The time-average ofG is the right-hand side of the limit equation and hence

we can apply the averaging theorem.

With this result, it remains to prove that qε is close to qε,π. For this, we first make the additional assumption that g is bounded by M > 0. By careful analysis of the constants involved, we will lift this restriction later on.

To this end, let the constant in ≲ be independent ofM. We will first prove that uε(t) := U(t,0;qε)u0 reaches anε-neighborhood of uπ(t;qε(t), ε) after a boundary layer of sizeO(|lnε|)and stays there, i.e.uεis slaved touπ. Lemma 3.4.3. Let K N and (ak)Kk=0 be non-negative with ak ≤bak1+c forb, c≥0andk= 1, . . . , K. Then ak≤bka0+cPk1

j=0bj fork= 1, . . . , K.

Proof. Follows by induction.

Lemma 3.4.4. There existsC >0 such that there holds

kU(t,0;qε)u0−uπ(t;qε(t))k≲eαtku0−u0π(q0)k+εM for all t∈Iε with constants independent of|Iε|.

Proof. First, using the assumption of exponential stabilityA1we get kU(t,0;qε)u0−U(t,0;qε)u0π(q0)k≲eαtku0−u0π(q0)k.

Hence it remains to prove that kU(t,0;qε)u0π(q0)−uπ(t;qε(t))kεM. For this, letL∈Nand the constant in≲in the following be independent ofL. Let Ik:= [tk, tk+1)fork= 0, . . . , K with0 =t0< t1< . . . < tK+1=Tε such that

|Ik|=Lfork= 0, . . . , K1 and|IK| ≤L.

Let t Ik for k = 0, . . . , K and define qεk := qε(tk). Note that by the boundedness assumption ongand sincet−tk ≤L we have

|qε(t)−qεk|=|qε(t)−qε(tk)| ≤ε Z t

tk

|g(qε(s), uε(s))|ds≤εLM. (3.8)

We estimate

kU(t,0;qε)u0π(q0)−uπ(t;qε(t))k

≤ kU(t,0;qε)u0π(q0)−uπ(t;qkε)k+kuπ(t;qε(t))−uπ(t;qkε)k. The Lipschitz property ofuπ byLemma 3.3.2andineq. (3.8) yields

kuπ(t;qε(t))−uπ(t;qkε)k|qε(t)−qεk|εLM and hence

kU(t,0;qε)u0π(q0)−uπ(t;qε(t))k ≤ kU(t,0;qε)u0π(q0)−uπ(t;qεk)k+εLM.

To estimate the first term on the right we add and subtractU(t, tk;qε)u0π(qkε):

kU(t,0;qε)u0π(q0)−uπ(t;qkε)k ≤ kU(t,0;qε)u0π(q0)−U(t, tk;qε)u0π(qkε)k +kU(t, tk;qε)u0π(qkε)−uπ(t;qεk)k. (3.9) For the first term, we split the evolution on[0, t]into[0, tk]and the remainder [tk, t]. Using the assumption of exponential stability(A1)this results in

kU(t,0;qε)u0π(q0)−U(t, tk;qε)u0π(qεk)k

≲eα(ttk)kU(tk,0;qε)u0π(q0)−u0π(qεk)k. (3.10) For the second term the periodicity andtkNimply

uπ(t;qkε) =U(t, tk;qεk)uπ(tk;qεk) =U(t, tk;qkε)u0π(qkε) and thus the Lipschitz assumption(A2)yields

kU(t, tk;qε)u0π(qεk)−uπ(t;qεk)kkqε−qkεkC(tk,t) ku0π(qkε)k+λ(L)

εL(1 +λ(L))Mkuπ(·;qkε)kCπ(X)

εLλ(L)M,

where we used Lemma 3.3.3 and assumed, without restriction of generality, that λ(L)≥1. Using the last estimate andineq. (3.10)inineq. (3.9) leads to

kU(t,0;qε)u0π(q0)−uπ(t;qε(t))k

≲eα(ttk)kU(tk,0;qε)u0π(q0)−u0π(qεk)k+εLλ(L)M (3.11) for anyt∈Ik. By passing to the limitt↑tk+1 fork < K this yields

kU(tk+1,0;qε)u0π(q0)−uπ(tk+1;qk+1ε )k

≲eαLkU(tk,0;qε)u0π(q0)−u0π(qkε)k+εLλ(L)M.

This is an inequality of the form of Lemma 3.4.3. Together with kU(tk,0;qε)u0π(q0)−u0π(qεk)k= 0

fork= 0, an application of this lemma yields fork= 0, . . . , K that kU(tk,0;qε)u0π(q0)−uπ(tk;qεk)kεLλ(L)M

k1

X

j=0

(CeαL)j

with a constantCindependent of LandM. We may chooseLindependent of M such thatCeαL<1. This implies, with≲now depending onL, that

kU(tk,0;qε)u0π(q0)−uπ(tk;qεk)kεM

fork= 0, . . . , K. Using this estimate inineq. (3.11)yields the claimed bound

for allt∈Ik and concludes the proof.

We now use the previous result to establish thatqε is close to qε,π, where qε,π was defined, repeated here for convenience, as solution of

qε,π (t) =εg(qε,π(t), uπ(t;qε,π(t))), qε,π(0) =q0. (3.7) Lemma 3.4.5. LetT >0 be fixed and|Iε| ≤ε1T. Then we have

maxtIε|qε(t)−qε,π(t)|εM, with constant depending onT.

Proof. Using the Lipschitz continuity ofg anduπ, we have fort∈Iε that

For the second term we use our estimate fromLemma 3.4.4to see that ε Lemma 3.3.3. By Lipschitz continuity ofuπ there holds for the third term:

ε and application of Gronwall’s inequality yields the claimed estimate

|qε(t)−qε,π(t)| ≤εMeCεtεM,

Proof. By the previous result and Corollary 3.4.2 we see that the estimate is valid on a possibly ε-dependent interval Iε for ε small enough. It remains to prove that the interval of existence may be extended to [0, ε1T]. Since the trajectory of the averaged equation Γ0 := q0([0, ε1T]) is compact and contained inQ, we can findη >0such that aη-neighborhood ofΓ0is contained in Q. Choosing ε small enough such that εMη for all 0 < ε < ε the previous corollary implies thatqε cannot leave this neighborhood (and hence Q) for any such ε. ByLemma 3.3.4solutions only cease to exist if qε crosses the boundary ofΩ. Hence for all0< ε < ε the solutionqεmust exist at least

untilε1T.

A simple consequence of our results is an estimate on the fast component, albeit limited by a boundary layer att= 0:

Lemma 3.4.7. For any δ∈(0,T)there exists ε =ε(δ, M)>0, such that for all 0< ε < ε there holds

max

t−1δ,ε−1T]kU(t,0;qε)u0−uπ(t;q0(t))kεM.

Proof. ByLemma 3.4.4, we have fort∈[0, ε1T]that

kU(t,0;qε)u0−uπ(t;qε(t))k≲eαtku0−u0πk+εM.

Using the Lipschitz continuity of uπ and the estimate for qε−q0 from the Corollary 3.4.6, we hence get

kU(t,0;qε)u0−uπ(t;q0(t))k

≤ kU(t,0;qε)u0−uπ(t;qε(t))k+kuπ(t;qε(t))−uπ(t;q0(t))k

≲eαtku0−u0πk+εM +|qε(t)−q0(t)|

≲eαtku0−u0πk+εM.

Fort≥t(ε) =−α1ln(ε(1+M))we have eαt≤ε(1+M). Sinceε1δ > t(ε) for all 0 < ε < ε if ε =ε(δ, M) is sufficiently small, the claimed estimate

follows.

Proof for unbounded g

We will now prove that one can drop the assumption ofg being bounded. We reduce this to the previous case by replacing g with a bounded function gR outside a ball of radius R in X. Careful analysis of the preceding estimates then shows that forRsufficiently large andεsufficiently small this change has no effect on the solutions.

Lemma 3.4.8. ForR >0 definePR:X →X byPR(u) :=uforkuk ≤Rand PR(u) :=Ruu for kuk> R. Then PR is Lipschitz continuous with constant 1.

Proof. Letu1, u2∈Xand assume without restriction of generality thatku1k ≤ ku2k. If ku2k ≤ R we have kPR(u1)−PR(u2)k = ku1−u2k. For the case ku2k> Randku1k< Rletv∈X denote the orthogonal projection ofu1onto Ru2. Then it is easy to see that kv−PR(u2)k ≤ kv−u2kand hence

kPR(u1)−PR(u2)k2=ku1−PR(u2)k2≤ ku1−vk2+kv−u2k2=ku1−u2k2.

If ku1k > R first assume that ku1k =ku2k, i.e. there existsα > Rˆ such that u1= ˆαuu1

1 andu2= ˆαuu2

2. Sinceα7→αkuu11uu22kis increasing the claim follows since α > R. In the last case,ˆ R <ku1k <ku2k, we use the already proven cases together withPR◦Pu1=PR to see that

ku1−u2k ≥ ku1−Pu1(u2)k ≥ kPR(u1)[PR◦Pu1](u2)k

≥ kPR(u1)−PR(u2)k.

Lemma 3.4.9. For any R > 0 there exists a bounded, Lipschitz continuous function gR:Q×X Rn such that gR(q, u) = g(q, u) for all q Q and kuk ≤Rwith the same Lipschitz constant as g.

Proof. DefinegR(q, u) :=g(q, PR(u)). ThengR(u) =g(u)forkuk ≤Rand the Lipschitz continuity follows from the previous lemma. Since

|gR(q, u)|=|g(q−q0+q0, PR(u0))||q−q0|+kPR(u)k+|g(q0,0)|≲1 +R, where we used thatQis bounded,gR is bounded.

Lemma 3.4.10. ForR >0large enough the limit solution q0 solves q0(t) =ε

Z 1 0

gR(q0(t), uπ(s;q0(t)))ds, q0(0) =q0 for all t∈[0, ε1T].

Proof. The set Γ :={uπ(s;q0(t)) | s∈ [0,1], t [0, ε1T]} ⊂X is bounded.

Hence we can choose R >0 large enough such thatkuk ≤Rfor allu∈Γ and henceg(q0(t), uπ(s;q0(t))) =gR(q0(t), uπ(s;q0(t))).

Now letqε,R denote the solution with right-hand sidegRwhereR >0is at least as large as required by the previous lemma. For the bound M >0 ofg we have M ≲1 +RR for R sufficiently large. Then by the results of the previous section there is anε(R)>0such that for all0< ε < ε the solution qε,R exists for[0, ε1T]and there holds

kqε,R(t)−q0(t)kεR,

kU(t,0;qε,R)u0−uπ(t;qε,R(t))k≲eαtku0−u0πk+εR

for allt∈[0, ε1T], where we implicitly used thatq0is also the solution of the limit equation forgR. WithR-independent constantsC >0 we get

kU(t,0;qε,R)u0k ≤C ku0−u0πk+kuπ(t;qε,R(t))k+εR

≤C ku0−u0πk+kuπ(t;q0(t))k+|qε,R(t)−q0(t)|+εR

≤C ku0−u0πk+kuπ(t;q0(t))k+εR . Fixing R > 0 such that C ku0−u0πk+kuπ(t;q0(t))k

R2 and making the corresponding ε(R) > 0 small enough such that 12 + 1 holds for all 0< ε < ε we getkU(t,0;qε,R)u0k ≤Rfor allt∈[0, ε1T]and hence

qε,R(t) =εgR(qε,R(t), U(t,0;qε,R)u0) =εg(qε,R(t), U(t,0;qε,R)u0).

But this implies thatqε,Rfor suchRand0< ε < εsolves the originaleq.(3.1), henceqε,R =qεand of course the estimates from the previous section still hold.