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II. Directed graphs 105

6. On the infinite Lucchesi-Younger conjecture 128

6.7. Extending an algorithmic proof of Frank

6.7.2. Feasible dijoins

is nested. We call a dicut B ∈B nestedly F-tight if B =LB for some nested setB ⊆ Bof F-tight dibonds.

Lemma 6.7.10. Every finite F-tight B ∈B is nestedly F-tight.

Proof. Let B be a decomposition of B into finitely many F-tight dibonds such that the number of pairs (A, A0)∈ B × B such thatA andA0 cross is minimal. We show that B is nested. Suppose for a contradiction that A, A0 ∈ B are crossing.

Then

B0 := ((Br{A, A0})∪ {A∧A0, AA0})

is a decomposition of B into F-tight dibonds in B by Lemma 6.7.1. An easy calculation shows that every dibond which is nested with both A and A0 is also nested with bothAA0 andAA0. Similarly, a dibond which crosses bothAA0 andAA0 also crosses bothAandA0. HenceB0 contradicts the minimality choice of B.

As above, the question whether this is in reality a stronger condition remains open.

Question 6.7.11. Is every F-tight dicut B ∈B also nestedly F-tight?

(E1) for every finite dicut δD(X)∈B the equation

|Z∩δD

F(X)|=|Z ∩δD+

F(X)|<∞ holds;

(E2) for every finite dicutδD(X)∈B with|J(Z, X)| ≥2 there is an F-tight di-bondδ(Y)∈Bsuch that J(Z, XY) andJ(Z, X∪Y) partition J(Z, X).

Remark 6.7.12. Every directed cycle C inDF for which every jumping edge it contains is basic is exchangeable.

We continue with a lemma that allows us to modify a givenB-dijoin to another B-dijoin given some exchangeable set.

Lemma 6.7.13 (Exchange Lemma). If ZE(DF) is exchangeable, then FZ := (F r{f ∈F |f ∈(Z∩F)})∪(Z∩E(D))

is a B-dijoin of D.

Proof. By property (E1), it suffices to show that |δD(X)∩F| ≥ |J(Z, X)|+ 1 for each dicut δD(X)∈B, since then either ZδD(X) is non-empty or {f ∈FδD(X)|fZF} is a proper subset of FδD(X). We show this claim by induction on |J(Z, X)|.

For |J(Z, X)|= 0 this is trivial. For |J(Z, X)|= 1, note that |δD(X)∩F|>1 since δD(X) is not F-tight.

For |J(Z, X)| ≥ 2 let δ(Y) be as in property (E2). Since B is finite-corner-closed, the corners δD(X∩Y) and δD(X∪Y) are in B. Now |J(Z, X∩Y)|

and |J(Z, X∪Y)| are both less than|J(Z, X)| by property (E2). Hence we get

D(X∩Y)∩F| ≥ |J(Z, X∩Y)|+ 1 and |δD(X∪Y)∩F| ≥ |J(Z, X∪Y)|+ 1 by induction. Moreover, sinceδ(Y) is anF-tight dibond we get that|J(Z, Y)|= 0 and |δD(Y)∩F|= 1. Finally these inequalities together with Remark 6.2.2 and property (E2) yield

D(X)∩F|=|δD(X∩Y)∩F|+|δD(X∪Y)∩F| − |δD(Y)∩F|

≥ |J(Z, X∩Y)|+ 1 +|J(Z, X∪Y)|+ 1−1

=|J(Z, X ∩Y)|+|J(Z, X∪Y)|+ 1

=|J(Z, X)|+ 1, finishing the proof.

Before we continue, we fix the following notation. LetC be a directed cycle in any digraph D. If eE(D) is an edge both of whose endvertices lie on C, then there exists a unique directed cycle in C+e that contains e. We shall call that cycleC(e).

In order to prove a lemma telling us that we can obtain an exchangeable negative directed cycle from any negative directed cycle in DF, we need the following technical lemma.

Lemma 6.7.14. Let D be a digraph, let ZD a directed cycle and let M ={sitiE(Z)|i∈[m]}a set of m≥2edges such thatsiti+1E(D)for every i∈[m] (where tm+1 :=t1). Then there exists an integer q >0 such that each edge of E(Z)rM lies in precisely q many of the directed cycles of {C(siti+1)|i∈[m]}.

Proof. Let C := {C(siti+1)|i∈[m]}. We prove the statement by induction on m. For m= 2 we immediately see that q= 1 holds. Now suppose the statement holds for some integer m≥2 with any digraph and any cycle that satisfy the conditions. Let a digraph D, a cycle Z and a set M as in the statement be given such that |M|=m+ 1. We define the auxiliary digraph D0 := (D− {s1t2, s2t3}+s1t3)/s2t2. Note that in D0, the setE(Z)r{s2t2}forms a directed cycleZ0 containing the m edges of the setM0 :=M r{s2t2}. Applying the induction hypothesis to M0 together with D0 andZ0 yields some integer q0 >0 as in the statement of the lemma.

Next we again consider D,Z andM, and distinguish two cases: If the directed s1–t3 path onZ containss2t2, then every edge ofE(Z)rM lies in precisely q0+ 1 many directed cycles of C. If the directed s1–t3 path on Z does not contain s2t2, then each edge ofE(Z)rM lies in preciselyq0 many directed cycles ofC. Since we get in both cases an integer as required, this competes the proof of the lemma.

The following lemma uses the same ideas as [20, Lemma 9.7.13], including Lemma 6.7.14, whose proof has been omitted in [20, Lemma 9.7.13]. We include a full proof for the sake of completeness.

Lemma 6.7.15. For every negative directed cycleC inDF there is an exchangeable negative directed cycle Z of DF with ZrJFCrJF.

Proof. Let C be a negative directed cycle in DF. If there is a chorde of C in JF such that C(e) is still negative and strictly smaller than C, then we consider

this cycle instead. Iterating this process yields a negative directed cycle Z with ZrJFCrJF such that no further such chord exists. We claim that Z is exchangeable.

Since Z is a finite directed cycle it trivially satisfies property (E1). For prop-erty (E2) we consider the following claim.

Claim. There is an enumeration x1y1,· · · , xnyn of ZJF such that xjyi/ JF for all i, j ∈[n] with 1≤i < jn.

First we show that if this claim is true, then property (E2) holds. Consider a dicut δD(X)∈B withxkyk, x`y`J(Z, X) for somek, `∈[n] with k < ` such that xiyi/ J(Z, X) for all i with k < i < `. Then applying Lemma 6.7.6 to U :={xj|`jn}andW :={yi|1≤ik}gives anF-tight dicutδ(Y) with UV(D)rY and WY. By Lemma 6.7.7 we have that yjV(D)rY for all j with `jn andxiY for alli with 1≤ik. Hence with this Y we get the desired bipartition of J(Z, X) into J(Z, X∩Y) and J(Z, XY).

In proving the claim we may assume that|Z∩JF| ≥2 as otherwise the claim holds trivially. Now we consider an auxiliary digraph H on the vertex setZJF where there is an edge with tail xy and head x0y0 if and only if xy0JF. Then the desired enumeration is an enumeration of V(H) with no backwards edges and hence its existence is equivalent to the non-existence of a directed cycle in H. So assume for a contradiction there is a directed cycle (x1y1)· · ·(xm+1ym+1) in H (with x1y1 =xm+1ym+1). Hence this cycle corresponds to chordsxiyi+1JF of Z.

By the minimality of Z the cyclesC(xiyi+1) are non-negative for all i∈[m]. By applying Lemma 6.7.14 with DF, Z and the edges x1y1, . . . , xmym, there exists an integer q >0 such that each edge in Z − {xiyi|i∈[m]} lies in precisely q many cycles C(xiyi+1). Therefore,

n

X

i=1

cF

C(xiyi+1)=q·cF(Z), contradicting that Z is negative.

Let us call aB-dijoin F feasible if the auxiliary graphDF together with the cost-functioncF does not contain any negative cycles. Theorem6.2.21and Lemma6.7.5 then imply that for DF andcF there always is a feasible integer-valued potentialπ if F is feasible.

As discussed before, Lemmas 6.7.13 and 6.7.15 immediately yield as a corollary that finite weakly connected digraphs do always contain a feasible B-dijoin, since the exchange process strictly decreases the size of the dijoin.

Corollary 6.7.16. For every finite weakly connected digraph D and every finite-corner-closed class B of finite dibonds of D there is a feasible B-dijoin.

The question about the existence of a feasible potential in infinite digraphs is a cornerstone of this proof method. While we conjecture that they always exist, we are not able to prove this conjecture in its entirety. We will prove some special cases of this conjecture in Section 6.8.

Conjecture 6.7.17. For every weakly connected digraphDand every finite-corner-closed class B of finite dibonds of D there is a feasible B-dijoin.

This conjecture is weaker than Conjecture 6.1.3, since as the following lemma illustrates each B-dijoin that features in a B-optimal pair is feasible.

Lemma 6.7.18. Let D be a weakly connected digraph, let B be a finite-corner-closed class of finite dibonds of D, and let (F,B) be a B-optimal pair for D.

Then F is feasible.

Proof. Suppose for a contradiction that DF contains a negative directed cycle C.

Let FE(C) = {f1, f2, . . . , fn} for somen ∈N. Also let fiE(D) denote the edge that is mapped to fi by for every i∈[n]. Since (F,B) is a B-optimal pair forD, there exists a unique finite dicut Bi ∈ B containingfi for everyi∈[n]. Fur-thermore,Bi contains no further edge of F by definition. Hence, every Bi is an F -tight dicut of D. Let Xi, YiV(D) be the sides of Bi such that ED(Xi, Yi) =Bi holds for every i∈[n]. Since Bi is F-tight, we know by Lemma 6.7.7 thatBi is also F-rigid for every i∈[n].

Next let us consider the intersection of C with any cut EDF(Xi, Yi) in DF. Since C is a directed cycle, we know that

|E(C)∩−→

EDF(Xi, Yi)|=|E(C)∩−→

EDF(Yi, Xi)|

holds. However, since Bi is F-rigid and contains only the edgefi from F, there exists an edge eiE(C)EDF(Xi, Yi) such that c(ei) = 1 holds for every i∈[n].

Furthermore, we know thatei 6=ej holds ifi, j ∈[n] andi6=j, because all elements

of Bare disjoint by definition. Now we have a contradiction to the negativity of C by the following inequality:

cF(C)≥

n

X

i=1

cF(fi) +

n

X

i=1

cF(ei)≥0.

The converse of the previous lemma, that every feasible B-dijoin features in a B-optimal pair is not true. We illustrate this fact with the following example.

Example. In this example we shall consider the weakly connected infinite di-graph D depicted twice in Figure 6.7.1. Before we analyse D in detail, let us define Dproperly. Let A={ai|i∈N}andB ={bi|i∈N}be two disjoint count-ably infinite sets. Additionally, let r be some set which is neither contained in A nor in B. Now we set

V(D) :=AB∪ {r}.

Next, we defineE1 :={aibi|i∈N}, E2 :={aibi+1|i∈N},E3 :={bir|i∈N}and E4 :={bibi+1|i∈N}. Finally, we complete the definition of D by setting

E(D) =E1E2E3E4.

Now let us first consider the left instance ofD in Figure6.7.1 more closely. The set of grey edges in that instance is FL:=E2 and it is easy to check that FL is a finitary dijoin of D. In particular, FL is feasible, which follows by checking that the following mapπFL :V(D)→Z is a feasible potential:

πFL(v) =

−1 if vA, 0 otherwise.

Actually, πFL is even a feasible rooted potential with r as its root. Here we see that the potential threshold τ−1 decomposes into a nested set of disjoint dicuts forming a nested optimal pair for D together with FL for D. Hence, D is not a counterexample to Conjecture 6.1.5.

Next, let us consider the right instance ofD in Figure 6.7.1. There the set of grey edges is FR:=E1∪ {b0r}. Again it is easy to verify that FR is a finitary dijoin of D. Furthermore, FR is feasible, which is witnessed by the following map πFR :V(D)→Z being a feasible potential:

πFR(v) =

−2 if vA,

−1 if vB, 0 if v =r.

πFL = −1 0 0 r

πFR =−2 −1 0

r

Figure 6.7.1.: Two instances of the digraph D. All edges that are not already directed are meant to be directed from left to right. Each instance of D contains a feasible finitary dijoin FL andFR, resp., marked by the grey edges. These dijoins each give rise to a feasible potentialπFL and πFR, resp.. However, FR is not part of any optimal pair for D, while FL is part of some optimal pair for D.

As for πFL, the map πFR is even a feasible rooted potential with root r.

Now we shall see that FR does not feature in any optimal pair for D. In order to see this, consider an edge aibi from FR for some arbitrary i∈N. The only dibond aibi is contained in is δ+({ai}). Hence, in order for FR to feature in an optimal pair (FR,B) for D, we know that δ+({ai})∈ B must hold for every i∈N. However, every finite dicut containing the edge b0rFR must also contain an edge aibi+1 for some i∈N. This shows that we cannot find an optimal pair for D in which FR features as a finitary dijoin of D. Note that this is in contrast to Example 6.3.1, where FR could feature as a finitary dijoin in an optimal pair, just not in a nested one.

We conclude this subsection with a lemma that will help us prove Conjec-ture 6.7.17 for special classes of digraphs in Section 6.8.

Lemma 6.7.19. LetD be a weakly connected digraph and let Bbe a finite-corner-closed class of dibonds of D. Then there is a B-dijoin F such that for all finite XV(D) there is a B-dijoin FX of D such that FE(D[X]) =FXE(D[X]) and such that DFX[X] does not contain any negative cycles.

Proof. Without loss of generality we may assume by Lemma 6.4.1 that D is B-separable. We prove this lemma by compactness.

For a finiteXV(D), letJX be the set of allJE(D[X]) such that there is a B-dijoinFXE(D) ofDwithFXE(D[X]) =J with the property thatDFX[X]

does not contain any negative directed cycles. This set is non-empty since by applying Lemmas 6.7.13 and 6.7.15 successively we can eliminate all negative cycles in DFX[X], as well as finite, since E(D[X]) is finite due to X being finite andDbeingB-separable. Moreover, for finite sets XYV(D) we obtain that JE(D[X])∈ JX for eachJ ∈ JY as witnessed by the sameB-dijoinFY ofD. By the compactness principle there is a set FE(D) such that FE(D[X])∈ JX for all finite XV(D). We claim that this F is a B-dijoin as desired.

First note that for any dibond B ∈B there is a finite set XV(D) with BE(D[X]). But since the B-dijoin FX witnessing that FE(D[A])∈ JA

meets B, so does F. Thus F is indeed a B-dijoin, finishing the proof.