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Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that

Its invariant lines are y+ 2 with co-factor 1;

2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that F · ∇`=c`.

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that (2x+y+ 1)∂`

∂x + (y+ 2)∂`

∂y =c`.

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

Its invariant lines are y+ 2 with co-factor 1;

2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Find `linear andc a scalar, such that

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2)

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2 1

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2 1

(2,2,3)

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2 1

(2,2,3) 2

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2 1

(2,2,3) 2 2x+ 2y+ 3

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Solve an eigenvalue problem for the linear operator whose matrix in the basis {x,y,1} is

the matrix the differential equation

eigenvector eigenvalue ` c

(0,1,2) 1 y+ 2 1

(2,2,3) 2 2x+ 2y+ 3 2

Its invariant lines are y+ 2 with co-factor 1; 2x+ 2y+ 3 with co-factor 2. Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Its invariant lines are y+ 2 with co-factor 1;

2x+ 2y+ 3 with co-factor 2.

Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Its invariant lines are y+ 2 with co-factor 1;

2x+ 2y+ 3 with co-factor 2.

Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations

An example: the Jacobi equation

Suppose that F = (2x+y+ 1,y+ 2).

Its invariant lines are y+ 2 with co-factor 1;

2x+ 2y+ 3 with co-factor 2.

Since 2·1 + (−1)·2 = 0,

h= (y+ 2)2(2x+ 2y+ 3)−1, is a first integral of ˙X =F(X).

S. C. Coutinho Proving the nonexistence of algebraic solutions of differential equations