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Proof of Proposition 1: We have to show that for all lotteries = (1 1;  ; ) obtaining the expected value of the lottery, (), for sure is weakly preferred to the lottery . That is,

(1 ())< for all lotteries .

Let be the smallest outcome of some arbitrary lottery. Substitution of CT into the previous preference gives

Observe that for any∈N the following identity holds

(())−() = we assumed that  is continuously differentiable over R. Then, there exists   0 such that ∆+ ≥ [(+)−()] for all 0    . Note that the latter inequality is strict, unless  is linear on [ ()]. It then follows that

(())−()≥ (+)−()

 [()−] (10)

for all 0    with a strict inequality unless is linear on[ ()].

Let  = min{ 0}. Then, the Inequalities (10) and (11) above hold for all 0    . Recall that Inequality (3) in the main text also holds, i.e.,

(0+0)−(0)≥(0)−(0−0)

for all 0 ∈ R 0  0  0, and thus, it holds in particular for 0 =  0 =  and 0 =  for all 0   . Therefore,

(+)−()

 [()−]≥ ()−(−)

 [()−]

holds for all 0   . Invoking Inequality (10) for the term on the left and Inequality (11) for the term on the right implies Inequality (9) as desired. Further, Inequality (9) is strict unless  is linear on [0max∈{1}{−}]or is linear on [ ()].

As  was an arbitrary non-degenerate lottery, it follows that CT implies weak risk aversion for decision under risk. This completes the proof of Proposition 1. ¤

Proof of Proposition 2: We have to show that strong concavity of  under CT is equivalent to  = (1 1;  ; ) Â 0 = (1 1;  ;  +;  ;0 0 −0;  ; ) whenever

 0 and  0.

Step (i): Suppose that 0 −0 is not the minimal outcome of0, i.e.  and 0 have the same minimal outcome. In this case CT reduces to an expected utility representation. As a result, it follows that  is concave. Conversely, strict concavity of  is sufficient for  Â 0 if 0 −0 is not the minimal outcome of 0.

Step (ii): Suppose now that 0 is the minimal outcome of such that0 −0 is the minimal

outcome of0. We have to show that  Â0 or, equivalently, after substitution of CT that

As is strictly concave it holds that

(+−0+0) +0(0) (−0 +) +0(0)

From condition (3) we know that the utility of wealth difference on the left side of the exceeds each chance utility difference on the right hand side of the inequality. Therefore,  Â0 follows whenever

0 is the minimal outcome of.

Step (iii): It remains to consider the case that0 is not the minimal outcome of but0−0

is the minimal outcome of0. Suppose that  is the minimal outcome of . We have 0  

0 −0. If  = 0 −0, then  Â 0 follows from strict concavity of  using arguments similar to those in Step (i). Alternatively, if0   0−0, then we can the mean-preserving

spread from  to 0 can be obtained from two successive mean-preserving spreads follows. Define 0 such that =0 +00 and set00= (1 1;  ; +;  ;0 0−0;  ; ). By construction00 is a mean-preserving spread of and both lotteries have the same minimal outcome.

Thus,  Â00 follows as  is concave. Further, 0 is a mean-preserving spread of 00 with minimal outcome 0 +00 and 0 +00 −0. By Step (ii) it then follows that 00 Â 0. Thus,

 Â00,00 Â0 and transitivity yields implies Â0. Thus, Steps (i)—(iii), complete the proof of

Proposition 2. ¤

Proof of Proposition 3: The proof follows immediately from the arguments provided preceding

the proposition in the main text. ¤

follows (see above) that  . Consider defined by

Suppose now that  converges to zero. This implies that  and  converge to . This follows from the fact that CT is continuous in probabilities. Now    can only hold if

0 ()()  0 ()(). As this argument is valid arbitrary   0  ∈R, it is also valid for all

 0  ∈R.

This completes the proof of Proposition 4. ¤

Proof of Proposition 5: The proof follows immediately from the arguments provided preceding

the proposition in the main text. ¤

Proof of Lemma 6: First we note that by Debreu (1954) the preference conditions imply the existence of a strongly monotonic continuous function :R→Rthat represents the preference<

on F. Obviously,  also represents <on each setF = 1     .

Let us fix an arbitrary state  ∈ S. Without loss of generality let  = 1. Continuity and monotonicity imply that for each act  ∈ F1 there exists a unique outcome  such that  ∼ (1      ). Next we restrict the analysis to the set of quasi binary acts{ ∈F1|(1      )}. In our notation for acts (i.e.,  = (1 : 1; −1)) this set is isomorphic to the two dimensional set

1 := { ∈ F1|(1 : 1; −1)} (∼= R×R+). The restriction of the preference < to 1, which for simplicity we also denote <, inherits weak order, continuity and monotonicity from < on F1. Ad-ditionally, it satisfies the triple cancellation condition formulated with indifferences on 1. In the presence of weak order, monotonicity and continuity, and the structural richness that we have in 1, the indifference version of triple cancellation is equivalent to the preference version of the triple can-cellation (see Köbberling and Wakker, 2003, for a similar argument showing that their indifference version of tradeoffconsistency is equivalent to the preference version of tradeoffconsistency). Hence, by Corollary 3.6 and Remark 3.7 of Wakker (1993a) it follows that there exists (jointly cardinal) continuous and strictly increasing functions 1 : R → R and 1 : R+ → R such that < on 1 is represented by

1() =1(1) +1( −1)

Note that continuity and monotonicity imply that 1(0) = 0. This means that, for   0 and

 real, 1 can be replaced by 1 + whenever 1 is replaced by 1. Next we extend 1

from R+ to {0} ×R+1. Using the indifference  ∼ (1 : 1; 0  −1      −1) we can define

1 :{0} ×R+1→R through

1(0 −1) :=1(0  −1      −1)≡1(0 −1).

This way continuity and strong monotonicity of 1 is inherited through . Then, for  ∈F1, we have

 < ⇔ (1  −1)<(1 −1)

⇔ 1(1) +1(−1)≥1(1) +1(−1)

⇔ 1(1) +1( −1)≥1(1) +1(−1)

demonstrating that 1() = 1(1) +1( −1) represents < on F1. Obviously, the uniqueness results for1 and 1 are maintained through this extension of the representation.

In the preceding analysis we have fixed state  = 1. The proof for any arbitrary state  ∈ S is completely analogous. Hence, we can conclude that for each state  ∈ S there exists strongly monotonic and continuous functions  :R→ R  :{0} ×R+1 → R such that on each set F the preference<is represented by

() =() +(−)

The functions  satisfy the corresponding uniqueness results for the representation onF for all ∈S.

Next we apply once more WOS. We take two arbitrary but distinct states 0 ∈S. Locally, in a small neighborhood, we canfind for all  ,  and  , such that the following three indifferences hold: (:;)∼(:;),(:;)∼(:;) and(0 :;0)∼(0 :;0)and all acts are from

F∩F0. By WOS it follows that(0 :;0)∼(0 :;0)with these acts being from F∩F0. As both and0 represent preferences onF∩F0 these functions must be ordinal transformations of each other. Further, substitution of in the former two indifferences and taking differences of the resulting equations and cancelling common terms, implies()−() =()−(). Similarly, substitution of 0 in the latter two indifferences, implies 0()−0() =0()−0(). As,

  and   were arbitrary, it follows that  and 0 are (first locally and by continuity also globally) proportional. As= and 0 =0 for all constant acts, and the latter are included in F ∩F0, it follows that  and 0 are, actually, cardinally related. Hence, we can choose them identical on the set of common acts F∩F0. In particular this means that  =0 on (R+× {0}×→R+1)∩(R+0× {0}×→R+01). As and0 were arbitrary chosen, we can set

:= for all∈S. That is

() =() +( −)

holds on each setF. Further, uniqueness results are maintained for and ∈S. This completes

the proof of Lemma 6. ¤

Proof of Theorem 7: First we prove that statement (ii) implies statement (i). Monotonicity of

<follows from the strong monotonicity of. Continuity of<follows from the continuity of. The fact that  is representing < on F implies that < is a weak order. Notice that on each set F the act  is evaluated by () =() +(−) where( −) =P

∈S\{}(−), which is an additively separable representation of <on F and has  independent of. Hence, substitution of

 for the indifferences in the definition of WOS immediately shows that <satisfies WOS. To derive tradeoff consistency for chance assume that the acts in the following indifferences are all from the

same set F for some state∈S, and that

(+) ∼ (+)

(+) ∼ (+) and (0 +)00 ∼ (0 +)00 hold

but(0 +)00 Â (0 +)00

for some 0 6=. Substitution of  into thefirst two indifferences implies that

() + X

∈S\{}

(−) +() = () + X

∈S\{}

(−) +() and

() + X

∈S\{}

(−) +() = () + X

∈S\{}

(−) +()

hold. Subtracting the second equation from thefirst and cancelling common terms gives:

[()−()] =[()−()]

or

()−() =()−()

as the probability  is positive.

Substitution of  into the third indifference and the latter preference gives, by using similar calculus,

()−() ()−()

a contradiction.

If in the previous analysis, instead of (0 +)00 Â (0 +)00, we assume (0 +)00

(0 +)00, a similar contradiction (i.e., ()−() =()−() and ()−() ()−()) is obtained. Hence, (0 +)00 ∼ (0 +)00 must hold. As  ∈S was arbitrary, it follows that tradeoffconsistency for chance holds on each set F. Hence, it holds onF.

Finally, the property that for all ∈R    0

(+)−() ()−(−)

holds follows from the strong monotonicity property of and Lemma 6.

Next we assume statement (ii) and derive statement (i). The assumptions of Lemma 6 are satisfied, hence, there exists continuous strongly monotonic functions  :R → R  : R+× {0}× → R+1

with(0    0) = 0 ∈S, such that the preference <is represented by

() =() +(−)

for ∈ F. Further, for  0 and real-valued the function  can be replaced by +whenever

is replaced by ,∈{1     }.

Take any arbitrary state ∈S. Tradeoff consistency for chance implies that if

(+) ∼ (+)

(+) ∼ (+)

and(0 +)00 ∼ (0 +)00 hold,

then(0 +)00 ∼(0 +)00 follows, provided that  0 6= and all acts involved are from the set

F. Substituting =+ we obtain that onR+× {0}×→R+1 the equalities

((+) −) = ((+)−)

((+) −) = ((+)−) and ((0 +)00−0 ) = ((0 +)00−0 ) imply((0 +)00−0 ) = ((0 +)00−0 )

This condition is analogous to tradeoff consistency (see Köbberling and Wakker 2003) for the func-tion  (representing a continuous monotonic preference) on R+× {0}× → R+1. Following Köbberling and Wakker (2003) this implies that there exist positive numbers ∈S\{} and a continuous strictly increasing utility function :R+→R such that

(−) = X

∈S\{}

(−).

From(0) = 0it follows that (0) = 0. This means that <on F is represented by

() =() + X

∈S\{}

(−)

We now set (0) = 0 tofix the location of.

Recall that ∈S was arbitrary chosen. Hence, we conclude that for each state∈S there exist strictly increasing and continuous function  : R+ → R with (0) = 0, and positive numbers

 ∈S\{}such that() :=() +P

∈S\{}(−)represents the preference on the set of actsF. Further the functionsand  are unique up to multiplication by a positive constant (i.e., they are ratio scales).

Take any two distinct states 0 ∈S and consider the restriction of<on the set of actsF{0} :=

F∩F0. On this set both  and 0 represent <. Uniqueness results imply that 0 =  (as

both have  in common) and that  = 0 =:  for all  ∈ S\{ 0}. As 0 ∈ S was chosen arbitrary it follows that the positive numbers  are independent of  ∈ S, such that we have  positive numbers  ∈S.

We define ˜:=. Further, we set =P

∈S and define

:= 

 for each ∈S

and obtain a subjective probability distribution over the states in S. Finally, we define :=˜.

Hence, we have shown that the representations  of <on F is of the form

() =() + X

∈S\{}

(−)for  ∈F ∈S

Hence, we have derived statement (i) of the theorem.

By construction the probabilities  ∈S are uniquely determined. By construction, for positive

and some constant, we can replace andby+and, respectively. That there is no further flexibility in the choice of these functions follows from Lemma 6. This concludes the proof of Theorem

7. ¤

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