Laser machining of silicon with bursts of ultra-short laser pulses:
Factors influencing the process efficiency and surface quality
Beat Neuenschwander, Stefan M. Remund, Thorsten Kramer
source: https://doi.org/10.24451/arbor.9235 | downloaded: 14.2.2022
▶ Specific Removal Rate
▶ Experimental procedure
▶ Results for ps and fs
▶ Surface Roughness
▶ Calorimetry (ps vs fs)
▶ Transmission experiments (ps)
▶ Conclusion
Outline
Experimental Procedure
▶ Standard galvo-scanner set-up
▶ Machine squares in Si
with side length s = 1.6 mm
▶ select a fixed number of pulses per area i.e. NSl depends on the pitch p and
number of pulses per burst
▶ Increase 𝑃𝑎𝑣 i.e. the fluence from the threshold up to several J/cm2
▶ Measure the depth 𝑑 of the squares with a white-light interferometric microscope
▶ Specific removal rate g:
𝜸 = 𝑑𝑉 ൗ
𝑑𝑡 𝑃𝑎𝑣 = 𝑑𝑉
𝑑𝐸 = 𝑠2 ∙ 𝑑
𝑑𝑡 ∙ 𝑃𝑎𝑣 = 𝑑 ∙ 𝑝𝑥 ∙ 𝑝𝑦 ∙ 𝑓𝑟 𝑁𝑆𝑙 ∙ 𝑃𝑎𝑣
▶ p-type, 𝜌 = 1 − 100 Ω ∙ 𝑐𝑚, (100),
one side polished, thickness = 650 µm
Experimental Procedure
Picoblade2, Dt = 10 ps, 1064 nm
▶ Identical sub pulses, DtB = 12 ns
▶ Refer to sub pulse peak fluence
▶ 1, 2, ….. 6 Pulse burst
▶ w0 = 16.8 µm
▶ M2 = 1.35
▶ 8, 10 ad 14 pulse burst
▶ w0 = 13.9 µm
▶ M2 = 1.77
Dt
BExperimental Procedure
SATSUMA HPII, Dt = 350 fs, 1030 nm
-25 0 25 50 75 100
t / ns
fs Pulse Bursts
100% 88%
100%
100%
93% 82%
93% 87%
77%
▶ Varying sub pulses, DtB = 25 ns
▶ Refer to 1st sub pulse peak fluence
▶ 1, 2, 3 and 4 Pulse burst
▶ w0 = 16.5 µm
▶ M2 = 1.53
▶ Due to limited Pav @ fmin = 505kHz, only up to 4 PB
Comparison 10 ps vs 350 fs: Specific Removal Rate
0 1 2 3 4 5 6 7 8
0 2 4 6 8
g/ µm3 /µJ
Sub Pulse Peak Fluence f0/ J/cm2 Dt = 10 ps, DtB= 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
▶ Dt = 10 ps
▶ Except SP,
g increases with # of sub pulses
▶ Dt = 350 fs
▶ similar rates for
▶ SP and 2PB
▶ 3PB and 4PB
▶ Higher rates
compared to ps
0 1 2 3 4 5 6 7 8
0 2 4 6 8
g/ µm3 /µJ
First Sub Pulse Peak Fluence f0 / J/cm2
Dt = 350 fs, DtB= 25 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
Dt = 10 ps, up to 14 Pulses per Burst
[1] Kerse et al., ”Ablation-cooled material
removal with ultrafast bursts of pulses”, Nature, 2016 537 (7618):84-88
0 1 2 3 4 5 6 7 8
0 1 2 3 4 5 6 7
g/ µm3 /µJ
Sub Pulse Peak Fluence f0 / J/cm2 Dt = 10 ps, DtB= 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst 5 Pulse Burst 6 Pulse Burst 8 Pulse Burst 10 Pulse Burst 14 Pulse Burst
▶ Maximum specific removal rate
increases with the number of pulses in the burst
▶ Gain up to a factor of 5
▶ Optimum point is shifted towards lower fluences
▶ 𝛾𝑚𝑎𝑥 ≈ 8 𝜇𝑚3/𝜇𝐽
▶ Near the maximum value of 11 𝜇𝑚3/𝜇𝐽 obtained in [1] with 800pulse burst and ∆𝑡𝑏 = 290 𝑝𝑠
Comparison 10 ps vs 350 fs: Surface Roughness
0 1 2 3 4 5 6 7 8
0 2 4 6 8
sa/ µm
Sub Pulse Peak Fluence f0/ J/cm2 Dt = 10 ps, DtB= 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
0 1 2 3 4 5 6 7 8
0 2 4 6
sa/ µm
First Sub Pulse Peak Fluence f0 / J/cm2 Dt = 350 fs, DtB= 25 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
▶ Dt = 10 ps
▶ SP: sa increases and then decreases to low values
▶ sa increases with
#pulses per burst
▶ Dt = 350 fs
▶ SP: sa increases with f0
▶ sa lower for bursts
Comparison 10 ps vs 350 fs: Surface Roughness
0 0.5 1 1.5 2
0 2 4 6 8
sa/ µm
Sub Pulse Peak Fluence f0/ J/cm2 Dt = 10 ps, DtB= 12 ns
Comparison 10 ps vs 350 fs: Surface Roughness
0 1 2 3 4 5 6 7 8
0 2 4 6
sa/ µm
First Sub Pulse Peak Fluence f0/ J/cm2 Dt = 350 fs, DtB= 25 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
Dt = 10 ps, up to 14 Pulses per Burst
0 0.5 1 1.5 2 2.5 3 3.5 4
0 1 2 3 4 5 6 7
sa/ µm
Sub Pulse Peak Fluence f0 / J/cm2 Dt = 10 ps, DtB = 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst 5 Pulse Burst 6 Pulse Burst 8 Pulse Burst 10 Pulse Burst 14 Pulse Burst
▶ sa increases with increasing
▶ Peak fluence f0
▶ # pulses per burst
Dt = 10 ps, up to 14 Pulses per Burst
▶ sa increases with increasing
▶ Peak fluence f0
▶ # pulses per burst
▶ At optimum point (max g) sa shows a tendency to increase with the #pulses per burst
▶ Could the higher sa explain the gain in the specific removal rate?
0 0.2 0.4 0.6 0.8 1 1.2
0 2 4 6 8 10 12 14
sa,opt/ µm
#Sub Pulses per Burst
Roughness @ Optimum for Dt = 10 ps, DtB= 12 ns
T / °C
t / s Sensor SIgnal
Calorimetry
[2]: F. Bauer, A. Michalowski, Th. Kiedrowski, S. Nolte, Opt.
Expr. 23, 1035 – 1043, (2015)
▶ From the incoming energy a part is always converted to heat
▶ Sample is heated up and cooled after irradiation
▶ T measured with a PT1000
▶ From this curve the residual energy in the sample can be calculated [2]
▶ 𝐸𝐻𝑒𝑎𝑡 respectively 𝜂𝐻𝑒𝑎𝑡 = 𝐸𝐻𝑒𝑎𝑡/𝐸𝑖𝑛 is measured
Silicon
Copper
Calorimetry
▶ With ablation:
▶ 𝜂𝐻𝑒𝑎𝑡 corresponds to the part of the incoming energy finally remaining in the sample
▶ 𝜂𝑟𝑒𝑠 = 𝜂𝐻𝑒𝑎𝑡 = 𝐸𝑟𝑒𝑠/𝐸𝑖𝑛
Calorimetry
▶ With ablation:
▶ 𝜂𝐻𝑒𝑎𝑡 corresponds to the part of the incoming energy finally remaining in the sample
▶ 𝜂𝑟𝑒𝑠 = 𝜂𝐻𝑒𝑎𝑡 = 𝐸𝑟𝑒𝑠/𝐸𝑖𝑛
▶ No ablation
▶ 𝜂𝐻𝑒𝑎𝑡 = 𝐸𝐻𝑒𝑎𝑡/𝐸𝑖𝑛 corresponds to the absorbed part of the energy (nontransparent materials)
▶ Absorptance 𝜂𝑎𝑏𝑠 = 𝜂𝐻𝑒𝑎𝑡 = (1 − 𝑅)
▶ For non-transparent materials the part of the absorbed energy effectively remaining in the sample reads:
𝜂𝑟𝑒𝑠,𝑒𝑓𝑓 = 𝜂𝑟𝑒𝑠/𝜂𝑎𝑏𝑠
Comparison 10 ps vs 350 fs: Calorimetry
0 0.2 0.4 0.6 0.8 1 1.2
0 1 2 3 4 5 6 7
hres/habs
Sub Pulse Peak Fluence f0/ J/cm2 Dt= 10 ps, DtB= 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
0 0.2 0.4 0.6 0.8 1 1.2
0 1 2 3 4 5 6
hres/habs
First Sub Pulse Peak Fluence f0/ J/cm2 Dt= 350 fs, DtB= 25 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst
▶ Except SP similar behavior of hres/habs
▶ For all burst situations 𝜂𝑟𝑒𝑠 is almost identical
▶ Almost constant values at optimum point
▶ The Surface Roughness cannot
explain gain in the specific removal rate
0 0.2 0.4 0.6 0.8 1
0 2 4 6 8 10 12 14
h
# Sub Pulses per Burst hresand habs @ Optimum Point
res abs res/abs
Dt = 10 ps, up to 14 Pulses per Burst
Results from 1d Two-Temperature Model
▶ Strong non linear absorption in Silicon
▶ Situation changes during the pulse
Intensity Carrier density
t / ps z / µm
0
1.5
-30 30
t / ps z / µm
0
1.5
-30 30
Results from 1d Two-Temperature Model
▶ Even when ablation takes place first part of the pulse
▶ penetrates deep into the material
▶ can ev. be transmitted
▶ Calculation is
▶ time consuming for simulating a burst sequence
▶ sensitive to unknown initial values
Transmission through Si-wafer
PD
▶ The focused laser beam is guided
▶ via a scattering surface (white paper)
▶ onto a fast photodiode
▶ monitored with oscilloscope
▶ A thin silicon wafer is moved trough the focal position
(p-type, 𝜌 = 0.1 − 10 Ω ∙ 𝑐𝑚, (100)
both sides polished, thickness = 220 µm)
Transmission through Si-wafer
▶ The transmission significantly drops when the wafer reaches the focal
position
0 0.05 0.1 0.15 0.2 0.25 0.3 0.35
26 27 28 29 30
T / %
z / mm
Transmission Silicon 220 µm
Ep = 1.0 µJ Ep = 2.5 µJ Ep = 7.5 µJ
Focal position
Transmission through Si-wafer
▶ The transmission significantly drops when the wafer reaches the focal
position
▶ Transmission as a function of the peak fluence (assumed Gaussian
beam) depends on the pulse energy?
▶ Beam not Gaussian (M2=1.77)
▶ Nonlinear effects like self focusing?
0 0.1 0.2 0.3 0.4
0 0.5 1 1.5 2 2.5
T / %
f0/ J/cm2
Transmission Silicon 220 µm
Ep = 1.0 µJ Ep = 2.5 µJ Ep = 7.5 µJ
Burst Transmission through Si-wafer
▶ Wafer in the focal plane
▶ For 14 single pulses with ∆𝑡 ≈ 1𝑠 (blue)
Transmission slightly drops by about 15%
0 50 100 150 200 250 300
-20 30 80 130 180
A / mV
t / ns
Focal Plane, f0 = 2.47 J/cm2
Burst Transmission through Si-wafer
▶ Wafer in the focal plane
▶ For 14 single pulses with ∆𝑡 ≈ 1𝑠 (blue)
Transmission slightly drops by about 15%
▶ Significant drop of about 75% for the 14 pulse burst (orange)
0 50 100 150 200 250 300
-20 0 20 40 60 80 100 120 140 160 180
A / mV
t / ns
Focal Plane, f0= 2.47 J/cm2
Burst Transmission through Si-wafer
▶ The drop for the burst depends on the peak
fluence of the sub-pulses
▶ Energy part responsible for ablation is dominated by the change in the
transmission
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
-25 0 25 50 75 100 125 150 175
PD Signal / V
t / ns
200µm Wafer: Transmitted 14 Pulse Burst @ Different Peak Fluences
1.7 mJ/cm2 10 mJ/cm2 16 mJ/cm2 28 mJ/cm2 62 mJ/cm2 0.23 J/cm2 0.72 J/cm2 2.47 J/cm2
∆𝑈 ∝ ∆𝐸
𝑛𝑜𝑛,𝑙𝑖𝑛Burst Transmission through Si-wafer
▶ The drop for the burst depends on the peak
fluence of the sub-pulses
▶ Energy part responsible for ablation is dominated by the change in the
transmission
▶ For Bursts this part changes with f0
▶ Effect might partially be responsible for the
observed higher specific removal rate with bursts
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
-25 0 25 50 75 100 125 150 175
PD Signal / V
t / ns
200µm Wafer: Transmitted 14 Pulse Burst @ Different Peak Fluences
1.7 mJ/cm2 10 mJ/cm2 16 mJ/cm2 28 mJ/cm2 62 mJ/cm2 0.23 J/cm2 0.72 J/cm2 2.47 J/cm2
0 1 2 3 4 5 6 7 8
0 1 2 3 4 5 6 7
g/ µm3/µJ
Sub Pulse Peak Fluence f0/ J/cm2 Dt= 10 ps, DtB= 12 ns
1 Pulse 2 Pulse Burst 3 Pulse Burst 4 Pulse Burst 5 Pulse Burst 6 Pulse Burst 8 Pulse Burst 10 Pulse Burst 14 Pulse Burst
▶ Silicon shows a higher maximum specific removal rate when it is machined with bursts
▶ Gain of a factor of 5 for a 14 pulse burst compared to single pulses for 10 ps
▶ fs pulses (1030nm) are more efficient than ps pulses (1064nm)
▶ low surface roughness achievable with single pulses of 10ps (melting effect) or bursts of fs pulses
▶ Calorimetry for ps and fs bursts
▶ Similar behavior of effective residual heat 𝜂𝑟𝑒𝑠/𝜂𝑎𝑏𝑠
▶ Aborptance can not explain the gain in the specific removal rate
▶ Transmission experiments clearly show the nonlinear absorption of silicon at 1064nm
▶ Nonlinearities might be responsible for the achieved significant gain in the specific removal rate
Conclusion
▶ We thank
▶ Josef Zürcher for all the SEM pictures
▶ Patrick Neuenschwander the calorimetry measurements