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Symplectic Topology Example Sheet 10

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Symplectic Topology Example Sheet 10

Dietmar Salamon ETH Z¨ urich

2 May 2013

Let (M, ω) be a closed symplectic manifold and let H : [0,1]×M →R

be a smooth function. For 0 ≤t≤1 defineHt:M →Rby Ht(p) := H(t, p)

and let {φt}0≤t≤1 be the isotopy generated by H via

tφt=Xt◦φt, φ0 = id, ι(Xt)ω =dHt. (1) We have seen in the lecture course thatφtis a symplectomorphism of (M, ω) for every t. The time-1 map is called the Hamiltonian symplectomor- phism generated by H and will be denoted by

φH :=φ1.

The set of Hamiltonian symplectomorphisms of (M, ω) will be denoted by Ham(M, ω) := {φH|H ∈C([0,1]×M)}.

Note that for every φ ∈ Ham(M, ω) there are many Hamiltonian functions H : [0,1]×M →R such thatφH =φ.

Exercise 10.1. Prove that Ham(M, ω) is a subgroup of Diff(M, ω).

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Exercise 10.2. TheHofer normof a functionH : [0,1]×M →Ris defined by

kHk:=

Z 1

0

max

M Ht−min

M Ht dt

The Hofer distanceof two symplectomorphismsφ0, φ1 ∈Ham(M, ω) is the real number

d(φ0, φ1) := inf

φH1◦φ−10

kHk,

where the infimum is taken over all smooth functions H : [0,1]×M → R that generate the symplectomorphism φ1 ◦φ−10H. Prove that the Hofer distanced: Ham(M, ω)×Ham(M, ω)→[0,∞) satisfies the following axioms.

(Symmetry) For all φ0, φ1 ∈Ham(M, ω) d(φ0, φ1) =d(φ1, φ0).

(Triangle Inequality) For all φ0, φ1, φ2 ∈Ham(M, ω) d(φ0, φ2)≤d(φ0, φ1) +d(φ1, φ2).

(Invariance) For all φ0, φ1, ψ ∈Ham(M, ω)

d(φ0◦ψ, φ1◦ψ) = d(ψ◦φ0, ψ◦φ1) =d(φ0, φ1) (Conjugacy) For allφ0, φ1 ∈Ham(M, ω) and all ψ ∈Diff(M, ω)

d(ψ−1◦φ0◦ψ, ψ−1 ◦φ1◦ψ) =d(φ0, φ1) Exercise 10.3. ForH : [0,1]×M →R define

kHk0 :=

Z 1

0

sZ

M

Ht2ωn n! dt.

For φ0, φ1 ∈Ham(M, ω) define

d00, φ1) := inf

φH1◦φ−10

kHk0,

where the infimum is taken over all smooth functions H : [0,1]×M → R that satisfy φH = φ1 ◦φ−10 and R

MHtωn = 0 for all t. Prove that the function d0 : Ham(M, ω)×Ham(M, ω) → R also satisfies the axioms listed in Exercisee 10.2. (Note: It turns out that the Hofer distance is always nondegenerate, however, a theorem by Eliashberg and Polterovich asserts that the function d0 vanishes on every symplectic manifold.)

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Let (Σ, j,dvolΣ) be a closed Riemann surface, (M, ω) be a symplectic manifold, let Σ → J(M, ω) : z 7→ Jz be a smooth family of ω-compatible almost complex structures, and let K ∈ Ω1(Σ, C(M)) be a 1-form on Σ with values in the space of smooth functions on M. Thus K assigns to each z ∈Σ a linear map

TzΣ→C(M) :bz 7→Kz,zb

and to each point p ∈ M a 1-form K(p) ∈ Ω1(Σ) via K(p)z(z) :=b Kz,

bz(p).

Note that K can be also thought of as a 1-form on the product manifold Mf:= Σ×M

which assigns to a tangent vector (z,b p)b ∈T(z,p)Mf=TzΣ×TpM →Rthe real numberKz,

zb(p). When understood as a 1-form onMfthe differential ofK will be denoted by dMfK ∈Ω2(M). When understood as 1-form on Σ with valuesf in C(M), the differential of K will be denoted by dΣK ∈ Ω2(Σ, C(M));

this 2-form is defined by defined by

(dΣK)z(bz1zb2)(p) := (d(K(p)))z(zb1,zb2) for p∈M,z ∈Σ, and bz1,bz2 ∈TzΣ.

Define the functionRK : Σ×M →R by

RKdvolΣ :=dΣK+ 12{K∧K}.

Here 12{K ∧K} ∈ Ω2(Σ, C(M)) is the 2-form which assigns to each pair zb1,zb2 ∈TzΣ the Poisson bracket {Kz,

bz1, Kz,

bz2} ∈C(M).

Denote by prΣ : Mf → Σ and prM : Mf → M the obvious projections, choose a function κ: Σ→(0,∞), and define ωe∈Ω2(Mf) by

ωe:= prMω−dMfK + prΣ(κdvolΣ) Foru: Σ→M define

dKu:=du+XK(u),

where XK(u)∈Ω1(Σ, uT M) is defined by (XK(u))z(z) :=b XKz,bz(u(z)), and

∂¯J,K(u) := (dKu)0,1 := 12(dKu+J(u)◦dKu◦j).

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Exercise 10.4. Prove that ωen+1

(n+ 1)! := (κ−RK)prΣdvolΣ∧prMωn n!.

If ¯∂J,K(u) = 0 prove that EK(u) := 12

Z

Σ

|dKu|2J dvolΣ = Z

Σ

uω+ Z

Σ

RK(u) dvolΣ.

Relate this to the energy identity for the Je-holomorphic curve eu: Σ→Mf defined by eu(z) := (z, u(z)). Do the solutions of the perturbed equation

∂¯J,K(u) = 0 minimize the energy EK(u) in their homology class? What is the relation between EK(u) and E(eu). Hint: See Exercise 4.1. Carry out the calculations in local coordinates on Σ.

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