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Abelian Threefolds in ( P 2 ) 3

Th. Bauer 1 , T. Szemberg 2 March 3, 1994

De Gruyter, Berlin New York, 1995, pp. 19-23.

1. Introduction

The elliptic curves in a projective plane are the smooth cubics. In [3] Hulek proved that the only abelian surfaces in the product space P 2 × P 2 are the obvious ones, i.e. the products of two plane cubics. Here we consider the analogous question for abelian threefolds in P 2 × P 2 × P 2 .

We prove:

Theorem. Let A be an abelian threefold over C , embedded in P 2 × P 2 × P 2 . Then A is a product E 1 × E 2 × E 3 , where E 1 , E 2 and E 3 are smooth plane cubics.

We note that the existence of abelian threefolds in 6-dimensional products of projective spaces was recently studied by Birkenhake [1] in the case of two factors.

2. The Projections

Let ϕ = (ϕ 1 , ϕ 2 , ϕ 3 ) : A , → ( P 2 ) 3 be an embedding of an abelian threefold A over C given by line bundles L 1 , L 2 , L 3 . Further, let π i : ( P 2 ) 3 −→ P (i) 2 denote the projection onto the i-th factor and h i := [π i O P

2

(1)] ∈ H 2 (( P 2 ) 3 , Z ). By the K¨ unneth formula the class of A in H 6 (( P 2 ) 3 , Z ) is of the form

[A] = ah 1 h 2 h 3 + X

i,j=1,2,3 i6=j

a ij h 2 i h j (∗)

with integers a, a ij ≥ 0.

1

Supported by DFG grant Ba 423/3-3

2

Partially supported by Daimler-Benz Stiftung project number 2.92.34 and KBN grant number

2 1077 91 01

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Lemma 2.1 The coefficients of [A] in (∗) satisfy the equation a(a − 27) = X

σ∈S

3

a σ(1),σ(3) (9 − a σ(2),σ(3) ) Proof. The total Chern class of the normal bundle N A/(P

2

)

3

is

c(N A/( P

2

)

3

) =

3

Y

i=1

(1 + 3h i + 3h 2 i ) · [A], thus

c 3 (N A/( P

2

)

3

) = (27h 1 h 2 h 3 + 9 X

i6=j

h 2 i h j ) · [A] = 27a + 9 X

i6=j

a ij .

On the other hand we have

A 2 = a 2 + X

σ∈S

3

a σ(1),σ(3) a σ(2),σ(3)

Now our assertion follows from the self-intersection formula A 2 = c 3 (N A/( P

2

)

3

) ([2], p.103).

In the sequel we will need the following

Lemma 2.2 Let A be an abelian threefold, ψ : A −→ P 2 a morphism and E ⊂ A an elliptic curve such that all the restrictions ψ |t a E, a ∈ A, are embeddings. Then ψ(t a E) = ψ(E) for all a ∈ A.

Proof. Denote by P := P (H 0 ( P 2 , O P

2

(3))) the projective space of plane cubics and define a map

Φ : A −→ P a 7−→ ψ(t a E) We choose ten points e 1 , . . . , e 10 ∈ E. Then

Z := {(a, C) ∈ A × P | C contains ψ(e 1 − a), . . . , ψ(e 10 − a)}

= {(a, C) ∈ A × P | C = ψ(t a E)}

is a subvariety of A × P . The projection p : Z −→ A is bijective, hence an isomor- phism by Zariski’s Main Theorem. The map Φ is just the composition Φ = q ◦ p −1 , where q : Z −→ P is the second projection. So Φ is a morphism and the image Φ(A) is a subvariety of P . If Φ(A) is of dimension ≥ 1, then Φ(A) meets the hypersurface

{ singular plane cubics } ⊂ P,

Since this contradicts the assumption that all images of Φ are smooth curves, we conclude that Φ(A) is a point.

Further, we will frequently apply the following useful Lemma from [1]:

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Lemma 2.3 Let X be an abelian variety of dimension g and ϕ : X −→ P N a morphism with dim ϕ(X) = n < g. Then L := ϕ O P

N

(1) is semipositive of rank n and ϕ fits into a commutative diagram

0 −−→ Y −−→ X −−→ Z −−→ 0

ϕ @

@ @

 y f P N

where the upper row is an exact sequence of abelian varieties and f is a morphism, which is finite onto its image.

Now we are ready to prove:

Proposition 2.4 At least one of the projections ϕ 1 , ϕ 2 , ϕ 3 is not surjective.

Proof. Suppose to the contrary that all of them are surjective. Because of the surjectivity of ϕ 1 Lemma 2.3 gives a diagram

0 −−→ E 1 −−→ A −−→ S 1 −−→ 0

ϕ

1

@

@ @

 y f

1

P (1) 2

where the upper row is an exact sequence of abelian varieties, E 1 being an elliptic curve and S 1 an abelian surface, and f 1 is a finite morphism of degree d 1 , say.

By Riemann-Roch on S 1 and [4], Theorem 3.3.3, we have 3 ≤ h 0 (L 1 ) = 1

2 d 1 , hence d 1 ≥ 6. Since ϕ 1 (E 1 ) is a point, we have

[E 1 ] = αh 2 1 h 2 2 h 3 + βh 2 1 h 2 3 h 2 with α, β ≥ 0.

Claim: We have α 6= 1 and β 6= 1.

Proof: By symmetry it is enough to consider α. Applying the projection formula we get

α = E 1 · h 3 = (ϕ 3 ) ∗ (E 1 ) · O P

2

(1) = deg(ϕ 3 |E 1 ) · deg ϕ 3 (E 1 ).

If we had α = 1, then the morphism ϕ 3 |E 1 : E 1 −→ ϕ 3 (E 1 ) would be of degree 1 onto a line in P 2 , which of course is impossible.

Let us distinguish between two cases:

Case I: α = 0 or β = 0.

Suppose α = 0, i.e. ϕ 3 (E 1 ) is a point. Since both of ϕ 1 (E 1 ) and ϕ 3 (E 1 ) are then

points, ϕ 2 must embed E 1 and all of its translates t a E 1 , a ∈ A, into P 2 . By Lemma

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2.2 then ϕ 2 (t a E 1 ) = ϕ 2 (E 1 ) for all a ∈ A. Since every point of A lies on a translate of E 1 , we conclude that ϕ 2 is not surjective and the Proposition is proved in this case.

Case II: α ≥ 2 and β ≥ 2.

Let F 1 be a general fibre of ϕ 1 . Then we obtain

[F 1 ] = [A] · h 2 1 = a 23 h 2 1 h 2 2 h 3 + a 32 h 2 1 h 2 3 h 2 . Furthermore, we have [F 1 ] = d 1 · [E 1 ], hence

a 23 = d 1 · α ≥ 6 · 2 = 12

and also a 32 ≥ 12. Arguing in the same way with the projections ϕ 2 and ϕ 3 we obtain

a ij ≥ 12 for i, j = 1, 2, 3, i 6= j.

Lemma 2.1 then yields

−183 ≤ a(a − 27) = X

(i,j,k)∈S

3

a ij (9 − a kj ) ≤ −216,

a contradiction. We conclude that not all of the projections ϕ 1 , ϕ 2 and ϕ 3 can be surjective.

3. The Product Decomposition

Now we can prove the Theorem stated in the Introduction:

Theorem 3.1 Let A be an abelian threefold over C , embedded in P 2 × P 2 × P 2 . Then A is a product E 1 × E 2 × E 3 , where E 1 , E 2 and E 3 are smooth plane cubics.

Proof. By Proposition 2.4 we may assume that ϕ 1 is not surjective. By Lefschetz hyperplane theorem there are no abelian threefolds in P 2 × P 2 , since P 2 × P 2 is simply connected. Thus the image ϕ 1 (A) ⊂ P (1) 2 must be a curve. Then we have a diagram

0 −−→ S 1 −−→ A −−→ E 1 −−→ 0

ϕ

1

@

@ @

 y f

1

P (1) 2

where E 1 is an elliptic curve, S 1 an abelian surface and f 1 a morphism, which is finite

onto its image. Since the image ϕ 1 (S 1 ) is a point, S 1 is embedded into P (2) 2 × P (3) 2 by

(ϕ 2 , ϕ 3 ). According to [3], 2.1, S 1 is then a product of elliptic curves E 2 = ϕ 2 (S 1 )

and E 3 = ϕ 3 (S 1 ). Identifying S 1 with its image under (ϕ 2 , ϕ 3 ) we may consider E 2 ,

E 3 as elliptic curves on A.

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Furthermore, we have t a S 1 = t a E 2 × t a E 3 for all a ∈ A. Since ϕ 1 (t a S 1 ) is again a point (ϕ 2 , ϕ 3 ) embeds t a S 1 . In particular ϕ 2 embeds each translate t a E 2 . According to Lemma 2.2 we must have ϕ 2 (t a E 2 ) = E 2 . Hence ϕ 2 is not surjective, i.e. ϕ 2 (A) = E 2 . Thus we obtain a diagram

0 −−→ S 2 −−→ A −−→ E 2 0 −−→ 0

ϕ

2

@

@ @

 y f

2

P (2) 2

with an abelian surface S 2 , an elliptic curve E 2 0 and a finite morphism f 2 . Since ϕ 2 (S 2 ) is a point, S 2 is embedded into P (1) 2 × P (3) 2 by (ϕ 1 , ϕ 3 ) and again S 2 = ϕ 1 (S 2

ϕ 3 (S 2 ) according to [3]. In fact S 2 = E 1 × E 3 . The morphism f 2 is an isomorphism because ϕ 2 embeds E 2 , hence E 2 0 ∼ = E 2 . Since E 2 is contained in A the exact sequence

0 −→ S 2 −→ A −→ E 2 −→ 0 splits. Then it follows

A ∼ = S 2 × E 2 ∼ = E 1 × E 2 × E 3 and the Theorem is proved.

We conclude with the following

Question. Is every abelian variety of dimension n in ( P 2 ) n a product of smooth plane cubics?

Acknowledgements. We would like to thank Prof. W. Barth for helpful discussions.

References

[1] Birkenhake, Ch: Abelian Threefolds in Products of Projective Spaces. To appear.

[2] Fulton, W.: Intersection Theory. Springer-Verlag, New York 1984

[3] Hulek, K.: Abelian Surfaces in Products of Projective Spaces. Algebraic Geometry L’Aquila, SLN 1417 (1988)

[4] Lange, H., Birkenhake, Ch.: Complex Abelian Varieties. Springer-Verlag, Grundlehren 302 (1992)

Th. Bauer, T. Szemberg

Mathematisches Institut der Universit¨ at Bismarckstr. 1 1/2

D-91054 Erlangen

email: bauerth@mi.uni-erlangen.de szember@mi.uni-erlangen.de

permanent address of the second author:

Instytut Matematyki Uniwersytet Jagiello´ nski Reymonta 4

PL-30-059 Krak´ ow

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