my PrüfungsterminePhilosophie

Assume, for the sake of contradiction, that there exists a non- trivial finite subgroup U of Ker Φ.. Then, this subgroup U contains an element f

Let X, Y, Z be the midpoints of the arcs BC, CA, AB (not containing A, B, C, respectively) of the unit circle (which, of course, is the circumcircle of triangle ABC).. Then, Lemma

American Mathematical Monthly Problem 11401 by Marius Cavachi, Constant ¸a, Romania.. Let A be a nonsingular square matrix whose entries

This will be easier than directly solving the problem, because Lemma 1 is a coordinate-free (and thus, basis-independent) assertion about three linear maps H, A and G, so we

American Mathematical Monthly Problem 11426

American Mathematical Monthly Problem 11433 by Marius Cavachi, Constant ¸a, Romania.. Let n be a

American Mathematical Monthly Problem 11434 by Slavko Simic, Belgrade, Serbia.. Let n be an integer such that n

(The n-th Euler secant-and-tangent number is defined as the number of ”up-down” permutations of length n, by which we mean permutations like 25341 (written as strings) that