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The Farrell-Jones Conjecture (Lecture IV)

Wolfgang Lück Bonn Germany

email wolfgang.lueck@him.uni-bonn.de http://131.220.77.52/lueck/

Oberwolfach, October 2017

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Outline

We introduceequivariant homology theories.

We give thegeneral formulation of the Farrell-Jones Conjecture.

We investigate how small one can make the relevant family of subgroups and prove aTransitivity Principle.

We give astatus reportabout the Farrell-Jones Conjecture.

We report on thesearch for counterexamples.

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Equivariant homology theories

Definition (G-homology theory)

AG-homology theoryH is a covariant functor from the category of G-CW-pairs to the category ofZ-gradedΛ-modules together with natural transformations

n(X,A) :Hn(X,A)→ Hn−1(A) forn∈Zsatisfying the following axioms:

G-homotopy invariance;

Long exact sequence of a pair;

Excision;

Disjoint union axiom.

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Exercise (Transformations ofG-homology theories)

LetHGandKG be two G-homology theories and let TG:HG→ KG be a natural transformation between them. LetC be a set of subgroups of G closed under conjugation such that for every H ∈ C and n∈Zthe map TnG(G/H) :HGn(G/H)→ KnG(G/H)is bijective.

Show that then for any G-CW -complex X with isotropy groups inCand any n∈Zthe map

TnG(X) :HGn(X)→ KGn(X) is bijective.

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Theorem (Bredon homology) Consider any covariant functor

M:OrG→Λ-Modules.

Then there is up to natural equivalence of G-homology theories precisely one G-homology theoryHG(−,M), calledBredon homology, with the property that the covariant functor

HnG:OrG→Λ-Modules, G/H 7→HnG(G/H) is trivial for n6=0and naturally equivalent to M for n=0.

LetM be the constant functor with value theΛ-moduleA. Then we get for everyG-CW-complexX

HnG(X;M)∼=ΛHn(X/G;A)

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Definition (Equivariant homology theory)

Anequivariant homology theoryH? assigns to every groupGa G-homology theoryHG.

These are linked together with the following so calledinduction structure: given a group homomorphismα:H→Gand aH-CW-pair (X,A), there are for alln∈Znatural homomorphisms

indα:HHn(X,A) → HGn(indα(X,A)) satisfying

Bijectivity

If ker(α)acts freely onX, then indα is a bijection;

Compatibility with the boundary homomorphisms;

Functoriality inα;

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Example (Equivariant homology theories)

Given a non-equivariant homology theoryK, put HG(X) := K(X/G);

HG(X) := K(EG×GX) (Borel homology).

Equivariant bordismΩ?(X)(for properG-spaces);

Equivariant topologicalK-theoryK?(X)(for properG-spaces). It is two-periodic, i.e.,KnG(X)∼=Kn+2G (X), and satisfies for a finite subgroupH⊆G

KnG(G/H) =

(RC(H) neven;

{0} nodd.

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Theorem (Lück-Reich)

Given a functorE:Groupoids→Spectrasending equivalences to weak equivalences, there exists an equivariant homology theory H?(−;E)satisfying

HHn(pt)∼=HGn(G/H)∼=πn(E(H)).

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Theorem (Equivariant homology theories associated toK and L-theory,Davis-Lück)

Let R be a ring (with involution). There exist covariant functors KR:Groupoids → Spectra;

Lh∞iR :Groupoids → Spectra, with the following properties:

They send equivalences of groupoids to weak equivalences of spectra;

For every group G and all n∈Zwe have πn(KR(G)) ∼= Kn(RG);

πn(Lh−∞iR (G)) ∼= Lh−∞in (RG).

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Example (Equivariant homology theories associated toK and L-theory)

We get equivariant homology theories H?(−;KR);

H?(−;Lh−∞iR ),

satisfying forH ⊆G

HnG(G/H;KR) ∼= HnH(pt;KR) ∼= Kn(RH);

HnG(G/H;Lh−∞iR ) ∼= HnH(pt;Lh−∞iR ) ∼= Lh−∞in (RH).

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The general formulation of the Farrell-Jones Conjecture

Conjecture (K-theoretic Farrell-Jones Conjecture)

TheK -theoretic Farrell-Jones Conjecturewith coefficients in R for the group G predicts that theassembly map, which is the map induced by the projection EVCYC(G)→pt,

HnG(EVCYC(G),KR)→HnG(pt,KR) =Kn(RG) is bijective for all n∈Z.

The basic idea is to understand theK-theory ofRGin terms of its values onRV for all virtually cyclic subgroupsV and just reduce the computation for generalGto the virtually cyclic subgroups V ⊆G.

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In general the right hand side is the hard part and the left side is the more accessible part since for equivariant homology theories there are methods for its computations available, for instance spectral sequences and equivariant Chern characters.

Often the assembly maps have a more structural geometric or analytic description, which are more sophisticated and harder to construct, but link the Farrell-Jones Conjecture to interesting problems in geometry, topology, algebra or operator theory and are relevant for proofs.

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Conjecture (L-theoretic Farrell-Jones Conjecture)

TheL-theoretic Farrell-Jones Conjecturewith coefficients in R for the group G predicts that the assembly map

HnG(EVCYC(G),Lh−∞iR )→HnG(pt,Lh−∞iR ) =Lh−∞in (RG) is bijective for all n∈Z.

Conjecture (Baum-Connes Conjecture)

TheBaum-Connes Conjecturepredicts that the assembly map KnG(EF IN(G))→Kn(Cr(G))

is bijective for all n∈Z.

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The assembly maps can also be interpreted in terms of homotopy colimits, where the functor of interest evaluated atGis assembled from its values on subgroups belonging to the relevant family.

For instance, forK-theory (and analogously forL-theory) we get an interpretation of the assembly map as the canonical map

hocolimV∈VCYCK(RV)→K(RG).

There are other theories for which one can formulate Isomorphism Conjectures in an analogous way, e.g.,pseudoisotopy,

Waldhausen’sA-theory,topological Hochschild homology, topological cyclic homology.

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Exercise (Trivial case)

Show that the Farrell-Jones Conjecture is true for G if G is virtually cyclic.

Obviously the Farrell-Jones Conjecture is more valuable if we can make the familyVCYC smaller. In general this is not possible but in some special cases this can be done using the Transitivity Principal which we explain next.

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Changing the family

Theorem (Transitivity Principle)

LetF ⊆ Gbe two families of subgroups of G. LetH?be an equivariant homology theory. Assume that for every element H ∈ Gand n∈Zthe assembly map

HHn(EF |H(H))→ HnH(pt) is bijective, whereF |H ={K∩H |K ∈ F }.

Then therelative assembly mapinduced by the up to G-homotopy unique G-map EF(G)→EG(G)

HnG(EF(G))→ HGn(EG(G)) is bijective for all n∈Z.

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Proof.

The projectionEF(G)×EG(G)→EF(G)is a G-homotopy equivalence. Hence it suffices to show that the projection

pr:EF(G)×EG(G)→EG(G)induces for everyn∈Za bijection HGn(pr) : HnG(EF(G)×EG(G))→ HGn(EG(G)).

We prove the more general statement that for anyG-CW-complex X with isotropy groups inGthe projection prX:EF(G)×X →X induces for everyn∈Zan isomorphism

HGn(prX) :HGn(EF(G)×X)→ HnG(X).

Since this can be interpreted as a transformation ofG-homology theories inX, it suffices to show that for everyH ∈ Gand every n∈Zwe get an isomorphism

HGn(prG/H) :HGn(EF(G)×G/H)→ HnG(G/H).

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Proof (continued).

The areG-homeomorphisms

indGHresHGEF(G) =G×HEF(G)−=→EF(G)×G/H sending(g,x)to(gx,gH)and indGHpt=G×Hpt−→= G/H.

The induction structure yields a commutative diagram for pr the projection with isomorphisms as vertical maps

HHn(resHGEF(G)) H

H

n(pr) //

=

HH(pt)

=

HGn(EF(G)×G/H)

HGn(prG/H)

//HGn(G/H).

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Exercise (Restriction and classifying space for families)

Let G be a group andF be a family of subgroups of G. Let H ⊆G be a subgroup and defineF |H ={K ∩H|K ∈ F }.

Show thatF |H is a family of subgroups of H and thatresHGEF(G)is a model for EF |H(H).

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Example (Passage fromF IN toVCYC for the Baum-Connes Conjecture)

The Baum-Connes Conjecture is known to be true for virtually cyclic groups.

The Transitivity Principle implies that the relative assembly KnG(EF IN(G))−=→KnG(EVCYC(G))

is bijective for alln∈Z.

Hence it does not matter in the context of the Baum-Connes Conjecture whether we consider the familyF IN orVCYC.

Bartels-Lückhave shown that in the Baum-Connes Conjecture

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Example (Passage fromF IN toVCYC for the Farrell-Jones Conjecture)

TheBass-Heller Swan decomposition

Kn−1(R)⊕Kn(R)⊕NKn(R)⊕NKn(R))−=→Kn(R[t,t−1])∼=Kn(R[Z]) and the isomorphism

HnZ(EZ;KR) =HnZ(EZ;KR) =Hn{1}(S1,KR) =Kn−1(R)⊕Kn(R) show that

HnZ(EZ;KR)→HnZ(pt;KR) =Kn(RZ) is bijective if and only if NKn(R) =0.

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Hence in the Farrell-Jones setting one has to pass toVCYCand cannot use the easier to handle familyF IN.

Exercise (Torsionfree groups and regular rings)

Show that the K -theoretic Farrell-Jones Conjecture implies the version for torsionfree groups and regular rings.

Theorem (L-theory and torsionfree groups)

If the torsionfree group G satisfies the L-theoretic Farrell-Jones

Conjecture, then it satisfies the L-theoretic Farrell-Jones Conjecture for torsionfree groups.

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Proof.

TheShanesonsplitting shows the assembly map HnZ(EZ;Lh−∞iR )→Lh−∞n (RZ) is bijective forn∈Z.

Since every infinite torsionfree virtually cyclic group is isomorphic toZ, we conclude from the Transitivity Principle that for any torsionfree groupGandn∈Zthe map

HnZ(EG;Lh−∞iR )−=→HnZ(EVCYC(G);Lh−∞iR ) is bijective.

The induction structure yields an isomorphism HnG(EG;Lh−∞iR )−=→Hn(BG;Lh−∞iR ).

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Proof (continued).

Hence for a torsionfree groupGthe assembly map Hn(BG;Lh−∞iR )→Lh−∞in (ZG)

is bijective, if theL-theoretic Farrell-Jones Conjecture holds forG.

Exercise (Computation of certainL-groups) Compute Ln(ZG)for n∈Zfor the group

G=hai,bi,i =1,2,· · ·,k |

k

Y

i=1

[ai,bi]i.

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An infinite virtually cyclic groupGis called oftypeIif it admits an epimorphism ontoZand oftypeII otherwise.

A virtually cyclic group is of typeII if and only if it admits an epimorphism ontoD.

LetVCYCI orVCYCII respectively be the family of subgroups which are either finite or which are virtually cyclic of typeIorII respectively.

Exercise (Virtually cyclic subgroups)

Show that an infinite virtually cyclic group G is of type I if and only if its abelianization is infinite.

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Theorem (Lück, Quinn, Reich)

The following maps are bijective for all n ∈Z

HnG(EVCYCI(G);KR) → HnG(EVCYC(G);KR);

HnG(EF IN(G);Lh−∞iR ) → HnG(EVCYCI(G);Lh−∞iR ).

Theorem (Cappell, Grunewald, Waldhausen) The following maps are bijective for all n∈Z.

HnG(EF IN(G);KZ)⊗ZQ → HnG(EVCYC(G);KZ)⊗ZQ; HnG(EF IN(G);Lh−∞iR )

1 2

→ HnG(EVCYC(G);Lh−∞iR ) 1

2

; If R is regular andQ⊆R, then for all n∈Zwe get a bijection

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Exercise (K0(FG)and finite subgroups ofG)

Let F be a field of characteristic zero. Suppose that G satisfies the K -theoretic Farrell-Jones Conjecture. Show that the obvious map

M

H⊆G,|H|<∞

K0(FH)→K0(FG)

is surjective.

Theorem (Bartels)

For every n∈Zthe two maps

HnG(EF IN(G);KR) → HnG(EVCYC(G);KR);

HnG(EF IN(G);Lh−∞iR ) → HnG(EVCYC(G);Lh−∞iR ), are split injective.

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Hence we get (natural) isomorphisms

HnG(EVCYC(G);KR)∼=HnG(EF IN(G);KR)⊕HnG(EVCYC(G),E G;KR);

and

HnG(EVCYC(G);Lh−∞iR )

∼=HnG(EF IN(G);Lh−∞iR )⊕HnG(EVCYC(G),E G;Lh−∞iR ).

The analysis of the termsHnG(EVCYC(G),EF IN(G);KR)and HnG(EVCYC(G),EF IN(G);Lh−∞iR )boils down to investigating

Nil-termsandUNil-termsin the sense ofWaldhausenandCappell.

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Status of the Farrell-Jones Conjecture

There is also a version, which we will call theFull Farrell-Jones Conjecture, which works for all groups and rings and where one can even allow twisted group rings and non-trivial orientation homomorphisms in theL-theory case.

For the experts, we mean the Farrell-Jones Conjecture for bothK- andL-theory withcoefficients in equivariant additive categories andwith finite wreath products.

The Full Farrell-Jones Conjecture implies the Farrell-Jones Conjectures stated above.

One decisive advantage of the Full Farrell-Jones Conjecture is that it has much better inheritance properties than the

Farrell-Jones Conjecture itself.

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Theorem (Bartels, Bestvina, Farrell, Kammeyer, Lück, Reich, Rüping, Wegner)

LetFJ be the class of groups for which the Full Farrell-Jones Conjecture holds. ThenFJ contains the following groups:

Hyperbolic groups;

CAT(0)-groups;

Solvable groups,

(Not necessarily uniform) lattices in almost connected Lie groups;

Fundamental groups of (not necessarily compact) d -dimensional manifolds (possibly with boundary) for d ≤3.

Subgroups of GLn(Q)and of GLn(F[t])for a finite field F . All S-arithmetic groups.

mapping class groups.

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Theorem (continued)

Moreover,FJ has the following inheritance properties:

If G1and G2belong toFJ, then G1×G2and G1∗G2belong to FJ;

If H is a subgroup of G and G∈ FJ, then H ∈ FJ;

If H ⊆G is a subgroup of G with[G:H]<∞and H ∈ FJ, then G∈ FJ;

Let{Gi |i ∈I}be a directed system of groups (with not

necessarily injective structure maps) such that Gi ∈ FJ for i ∈I.

Thencolimi∈IGi belongs toFJ;

Let1→K →G−→p Q→1be an exact sequence. Suppose that Q and p−1(V)for every virtually cyclic subgroup V ⊆Q belong to FJ. Then also G belongs toFJ.

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Exercise (Groups inFJ)

Show that the following groups G belong toFJ

There is an extension1→K →G→Q→1for virtually solvable H and hyperbolic Q.

G=hx,y |yxy−1xy =xyx−1yxi.

G is locally finite.

G is the fundamental group of the total space of a bundle whose fiber and base space are manifolds of dimension≤2.

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Problem (Open cases)

It is unknown whetherFJ contains the following classes of groups:

(Elementary) amenable groups;

Residually finite groups;

Fundamental groups of complete Riemannian manifolds with non-positive sectional curvature;

Linear groups;

One-relator-groups;

Semidirect products Fno Z; Out(Fn);

Thompson’s groups.

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Problem (Open inheritance properties) It is not known whetherFJ is closed under:

amalgamated products.

HNN-extensions.

Infinite direct products.

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Limit groupsin the sense ofZelaare CAT(0)-groups.

(Alibegovic-Bestvina).

There are manyconstructions of groups with exotic properties which arise as colimits of hyperbolic groups.

One example is the construction ofgroups with expandersdue to Gromov, seeArzhantseva-Delzant. These yieldcounterexamples to theBaum-Connes Conjecture with coefficientsdue to

Higson-Lafforgue-Skandalis.

However, our results show that these groups do satisfy the Full Farrell-Jones Conjecture.

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Many groups of the region ‘Hic abundant leones’in the universe of groups in the sense ofBridsondo satisfy the Full Farrell-Jones Conjecture.

We do not know a (prominent) property of groups, e.g., Kazdhan’s property (T), selfsimilarity, unsolvable word problem, unsolvable conjugacy problem, . . . , for which the intersection of the class of groups with this property and ofFJ is empty.

Hence we have no promising candidate or property of a group for which one may hope to disprove the Farrell-Jones Conjecture.

Probably finding a counterexample may not be given by looking at a concrete group, but may come from very general methods and non explicite methods such asrandom groupsormodel theory.

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There are certain non-trivial results which are known to be true for all groups and which are consequences of the Farrell-Jones Conjecture.

Theorem (Lück-Roerdam)

Let H ⊆G be a normal finite subgroup. Then the canonical map Wh(H)⊗ZGZ→Wh(G)

is rationally injective.

Theorem (Yu)

If R is the ring of all Schatten class operators on an infinite dimensional and separable Hilbert space, then the assembly map appearing in the K -theoretic Farrell-Jones Conjecture is rationally injective.

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It is unlikely that it will be decided in the near future whether the Farrell-Jones Conjecture is true or not.

There exists auniversal finitely presented groupU that contains all finitely presented groups as subgroups. There is such a group U with 14 generators and 42 relations.

If I could choose a group for which I can prove the Farrell-Jones Conjecture, it would beU.

Exercise (Universal finitely presented group)

Show that the Full Farrell-Jones Conjecture holds for all groups if it holds for a universal finitely presented group U.

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To be continued

Stay tuned

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