• Keine Ergebnisse gefunden

Heden's bound on the tail of a vector space partition

N/A
N/A
Protected

Academic year: 2022

Aktie "Heden's bound on the tail of a vector space partition"

Copied!
5
0
0

Wird geladen.... (Jetzt Volltext ansehen)

Volltext

(1)

SASCHA KURZ?

ABSTRACT. A vector space partition ofFvq is a collection of subspaces such that every non-zero vector is contained in a unique element. We improve a lower bound of Heden, in a subcase, on the number of elements of the smallest occurring dimension in a vector space partition. To this end, we introduce the notion ofqr-divisible sets ofk-subspaces inFvq. By geometric arguments we obtain non-existence results for these objects, which then imply the improved result of Heden.

1. INTRODUCTION

Letq >1be a prime power,Fqbe the finite filed withqelements, andva positive integer. Avector space partitionP ofFvq is a collection of subspaces with the property that every non-zero vector is contained in a unique member ofP.

IfP containsmdsubspaces of dimensiond, thenP is of typekmk. . .1m1. We may leave out some of the cases with md = 0. Subspaces of dimensiondare also calledd-subspaces.1-subspaces are calledpoints,(v−1)-subspaces are calledhyperplanes, and eachk-subspace containsk

1

q := qq−1k−1 points. So, in a vector space partitionPeach point of the ambient spaceFvq is covered by exactly one point of one of the elements ofP. An example of a vector space partition is given by ak-spreadinFvq, wherev

1

q/k 1

qk-subspaces partition the set of points ofFvq. The corresponding type is given bykmk, wheremk = v

1

q/k 1

q. Ifkdividesv then considering the points ofFv/kqk as k-dimensional subspaces overFq gives a construction of k-spreads. Ifkdoes not dividev, then nok-spreads exist. Vector space partitions of typekmk1m1 are known under the namepartialk-spreads. More precisely, a partialk-spread inFvq is a setKofk-subspaces such that each point of the ambient spaceFvq is covered at most by one of its elements. Adding the set of uncovered points, which are also calledholes, gives a vector space partition of typekmk1m1. Maximizing mk = #Kis equivalent to the minimization ofm1. Ifd1is the smallest dimension withmd1 6= 0, we callmd1 the length of the tailand call the set of the correspondingd1-subspace thetail. Vector space partitions with a tail of small length are of special interest. In [4] Olof Heden obtained:

Theorem 1. (Theorem 1 in[4]) LetPbe a vector space partition of typedlul

. . . d2u2

d1u1

ofFvq, whereu1, u2 >0 anddl>· · ·> d2> d1≥1.

(i) Ifqd2−d1 does not divideu1and ifd2<2d1, thenu1≥qd1+ 1;

(ii) ifqd2−d1does not divideu1and ifd2≥2d1, then eitherd1dividesd2andu1=d2 1

q/d1 1

qoru1>2qd2−d1; (iii) ifqd2−d1dividesu1andd2<2d1, thenu1≥qd2−qd1+qd2−d1;

(iv) ifqd2−d1dividesu1andd2≥2d1, thenu1≥qd2.

Moreover, in Theorem 2 and Theorem 3 he classified the possible sets of d1-subspaces foru1 = qd1 + 1and u1=d2

1

q/d1 1

q, respectively. The results were obtained using the theory of mixed perfect1-codes, see e.g. [6].

In [2] the authors improved a lower bound of Heden on the size of inclusion-maximal partial2-spreads by translating the underlying techniques into geometry. Here we improve Theorem 1(ii). The underlying geometric structure is the setN ofd1-subspaces of a vector space partitionPof typedlul. . . d2u2d1u1. Ford1this is just a set of points inFvq. It can be shown that the existence ofPimplies#N ≡# (N ∩H) (mod qd2−1)for every hyperplaneHofFvq, see e.g.

[7]. Taking a vector representation of the elements ofN as columns of a generator matrix, we obtain a corresponding (projective) linear codeC overFq. The modulo constraints forN are equivalent to the property that the Hamming weights of the codewords ofC are divisible byqd2−1. The study of so-called divisible codes, where the Hamming weights of the codewords of a linear code are divisible by some factor∆>1, was initiated by Harold Ward, see e.g.

[9]. The MacWilliams identities, linking the weight distribution of a linear code with the weight distribution of its dual code, can be relaxed to a linear program. Incorporating some information about the weight distribution of a linear code may result in an infeasible linear program, which then certifies the non-existence of such a code. This technique is known under the name linear programming method for codes and was more generally developed for association schemes by Philip Delsarte [3]. In [8] analytic solutions of linear programs for projectiveqr-divisible linear codes have been applied in order to compute upper bounds for partialk-spreads. Indeed, all currently known upper bounds for partialk-spreads can be deduced from this method, see [7] for a survey.

?Grant KU 2430/3-1 –Integer Linear Programming Models for Subspace Codes and Finite Geometry– German Research Foundation.

1

(2)

Here, we generalize the approach to the cased1 >1by studying the properties of the setN ofd1-subspaces of a vector space partitionP ofFvq of typedlul

. . . d2u2

d1u1

in Section 2. It turns out that we have#N ≡ #(N ∩H) (modqd2−d1)for every hyperplaneH ofFvq, see Lemma 3, which we introduce as a definition of aqd2−d1-divisible set ofk-subspaces with trivial intersection. By elementary counting techniques we obtain a partial substitute for the MacWilliams identities, see the equations (1) and (2). These imply some analytical criteria for the non-existence of such setsN, which are used in Section 3 to reprove Theorem 1. By an improved analysis we tighten Theorem 1 to Theorem 12. More precisely, the second lower bound of Theorem 1(ii) is improved. We close with some numerical results on the spectrum of the possible cardinalities ofN and pose some open problems.

2. SETS OF DISJOINTk-SUBSPACES AND THEIR INCIDENCES WITH HYPERPLANES

For a positive integerkletN be a set of pairwise disjoint, i.e., having trivial intersection,k-subspaces inFvq, where we assume that thek-subspaces fromN spanFvq, i.e.,vis minimally chosen. Byaiwe denote the number of hyperplanes HofFvq with#(N ∩H) := #{U ∈ N : U ≤H}=iand setn:= #N. Due to our assumption on the minimality of the dimensionvnot allnelements fromN can be contained in a hyperplane. Double-counting the incidences of the tuples(H),(B1, H), and(B1, B2, H), whereHis a hyperplane andB16=B2are elements ofN contained inH gives:

n−1

X

i=0

ai= v

1

q

,

n−1

X

i=0

iai=n· v−k

1

q

, and

n−1

X

i=0

i(i−1)ai=n(n−1)·

v−2k 1

q

. (1)

For three different elementsB1, B2, B3ofN their spanhB1, B2, B3ihas a dimensionibetween2kand3k. Denoting the number of corresponding triples bybi, double-counting tuples(B1, B2, B3, H), whereH is a hyperplane and B1, B2, B3are pairwise different elements ofN contained inH, gives:

n−1

X

i=0

i(i−1)(i−2)ai=

3k

X

i=2k

bi

v−i 1

q

and

3k

X

i=2k

bi=n(n−1)(n−2). (2) Given parametersq,k,n, andvthe so-called(integer) linear programming methodasks for a solution of the equation system given by (1) and (2) withai, bi ∈R≥0(ai, bi ∈ N). If no solution exists, then no corresponding setN can exist. Fork= 1the equations from (1) and (2) correspond to the first four MacWilliams identities, see e.g. [7].

If there is a single non-zero valueaithe system can be solved analytically.

Lemma 2. Ifai= 0for alli6=r >0andk < vin the above setting, then there exists an integers≥2withv=sk andN is ak-spread. Additionally we haver= qv−kqk−1−1.

PROOF. Solving (1) forr,ar, andngivesn= q2v−kqv−q−qv−kv−q−qv−kk+1+1. Writingv=sk+twiths, t∈Nand0≤t < kwe obtainn=Ps

i=1qv−ik+qv−k+tqv−q−qv−kv−k−q−qk+1t+1. Sincen∈Nand0≤qv−k+t−qv−k−qt+ 1< qv−qv−k−qk+ 1 we haveqv−k+t−qv−k−qt+ 1 = 0so thatt= 0andn=qqvk−1−1. Counting points gives thatN partitionsFvq. We remark thatr= 0forcesn∈ {0,1}so thatN is empty or consists of a singlek-subspace inFkq andv=kimplies the latter case. So, these degenerated cases correspond tos∈ {0,1}in Lemma 2. As pointed out after [4, Theorem 2], such results can be proved in different ways. While the case that only oneaiis non-zero is rather special, we can show that manyaiare equal to zero in our setting.

Lemma 3. LetP be a vector space partition of typedlul

. . . d2u2

d1u1

ofFvq, whereu1, u2>0, and letN be the set ofd1-subspaces. Then, we have#N ≡#(N ∩H) (modqd2−d1)for every hyperplaneH ofFvq.

PROOF. For eachU ∈ Pwe havedim(U∩H)∈ {dim(U),dim(U)−1}. So counting points inFvq andH gives the existence of integersa, a0withm·d2

1

q+aqd2+u1d1

1

q =v 1

qandm·d2−1 1

q+a0qd2−1+u01qd1−1+u1d1−1 1

q = v−1

1

q, wherem:=Pl

i=2uiandu01:= #(N ∩H). By subtraction we obtainmqd2−1+aqd2−a0qd2−1+u1qd1−1− u01qd1−1=qv−1, so thatu1qd1−1≡u01qd1−1 (mod qd2−1).

Definition 4. LetN be a set ofk-subspaces inFvq. If there exists a positive integerrsuch thataiis non-zero only if

#N −iis divisible byqrand thek-subspaces are pairwise disjoint, then we callN qr-divisible.

Using the notation of Lemma 3,N isqd2−d1-divisible. As mentioned in the introduction, ford1 = 1, taking the elements ofN as columns of a generator matrix, we obtain a projective linear code, whose Hamming weights are divisible byqd2−1.

Example 5. For integersk ≥ 2andr = ak+bwith0 ≤ b < kletN be ak-spread ofF(a+2)kq . Starting from a(a+ 2)k-spread inF2(a+2)kq we obtain a vector space partitionP by replacing one(a+ 2)k-dimensional spread

(3)

element withN. From Lemma 3 andqr|q(a+2)k−k=q(a+1)kwe deduce that the setN ofk-subspaces isqr-divisible.

Its cardinality is given by(a+2)k 1

q/k 1

q.

Example 6. For integersk ≥ 2andr ≥ 1letn = k+rand consider a matrix representationM: Fqn → Fn×nq

of Fqn/Fq, obtained by expressing the multiplication maps µα: Fqn → Fqn, x 7→ αx, which are linear overFq, in terms of a fixed basis of Fqn/Fq. Then, all matrices in M(Fqn)are invertible and have mutual rank distance dR(A, B) := rk(A−B) =n, see e.g. [7] for proofs of these and the subsequent facts. In other words, the matrices of M(Fqn)form a maximum rank distance code with minimum rank distancenand cardinalityqn.

Now letB ⊆Fk×nq be the matrix code obtained fromM(Fqn)by deleting the lastn−krows, say, of every matrix.

ThenBhas cardinality minimum rank distancek. Hence, by applying the lifting constructionB7→(Ik|B), whereIk is thek×kidentity matrix, toBwe obtain a partialk-spreadN inFvq of sizeqn =qk+r. Since precisely the points outside the (k+r)-subspaceS=

x∈Fvq : x1=x2=· · ·=xk = 0 are covered,P =N ∪ {S}is a vector space partition ofF2k+rq andN isqk+r-divisible with cardinalityqk+r.

From the first two equations of (1) we deduce:

Lemma 7. For aqr-divisible setN ofk-subspaces inFvq, there exists a hyperplaneHwith#(N ∩H)≤n/qk. PROOF. Letibe the smallest index withai6= 0. Then, the first two equations of (1) are equivalent toP

j≥0ai+qrj= v

1

q andP

j≥0(i+qrj)·ai+qrj =nv−k 1

q. Subtractingitimes the first equation from the second equation gives P

j>0qrjai+qrj =n·qv−kq−1−1 −i·qq−1v−1. Since the left-hand side is non-negative, we havei≤qv−kqv−1−1·n≤ qnk. Stated less technical, the proof of Lemma 7 is given by the fact that the hyperplane with the minimum number of k-subspaces contains at most as manyk-subspaces as the average number ofk-subspaces per hyperplane.

Taking also the third equation of (1) into account implies a quadratic criterion:

Lemma 8. Letm∈ZandNbe aqr-divisible set ofk-subspaces inFvq. Then,τ(n, qr, qk, m)·qv−2k−2r−m(m−1)≥ 0, whereτ(n,∆, u, m) := ∆2u2m(m−1)−n(2m−1)u(u−1)∆ +n(u−1)(n(u−1) + 1).

PROOF. Withy =qv−2k,u=qk, and∆ =qr, we can rewrite the equations of (1) tou2y−1 = (q−1)P

i∈Zai, n·(uy−1) = (q−1)P

i∈Ziai, andn(n−1)·(y−1) =P

i∈Zi(i−1)ai.(n−m∆)(n−(m−1)∆)times the first minus2n−(2m−1)∆−1times the second plus the third equation givesy·τ(n,∆, u, m)−∆2m(m−1) = (q−1)P

i∈Z(n−m∆−i)(n−(m−1)∆−i)ai= (q−1)P

h∈Z2(m−h)(m−h+ 1)an−h∆≥0.

As a preparation we present another classification result:

Lemma 9. IfN is aq-divisible set ofk-subspaces inFvq of cardinalityqk+ 1, thenN partitionsF2kq . PROOF. Settingci := (q−1)a1+iqandl :=qk−1−1we can rewrite the equations of (1) toPl

i=0ci = qv−1, Pl

i=0(1 +iq)ci = (qk+ 1) qv−k−1

, andPl

i=0iq(1 +iq)ci = (qk+ 1)qk qv−2k−1

. Sinceql+ 1times the second minusql+ 1times the first minus the third equation gives0≤Pl

i=0iq2(l−i)ci=−qk+1 qv−2k−1 , we havev= 2k. Every point ofFvq is covered by an element fromN due to2k

1

q/k 1

q =qk+ 1.

3. PROOF OFHEDENS RESULTS AND FURTHER IMPROVEMENTS

LetPbe a vector space partition of typedlul

. . . d2u2

d1u1

ofFv

0

q , whereu1, u2>0,dl>· · ·> d2> d1≥1. LetN be the set ofd1-subspaces andV be the subspace spanned byN. Bynwe denote the cardinality ofN and byaiwe denote the number of hyperplanes ofV that contain exactlyielements fromN.

Assume thatqd2−d1does not divideu1. We have#(N ∩H)≥1for every hyperplaneH ofV due to Lemma 3, so that Lemma 7 givesu1≥qd1. Thus, we haveu1 ≥qd1+ 1. Ifu=qd1+ 1then we can apply Lemma 9 for the classification of the possible setsN. Ifu1<2qd2−d1then forai>0we havei < qd2−d1 andi≡u1 (mod qd2−d1) so that we can apply Lemma 2. Thus, eitherd2dividesd1andu1= (qd2 −1)/(qd1−1)oru1>2qd2−d1. The first case can be attained by ad2-spread where one d2-subspace is replaced by ad1-spread, see Example 5. We remark that no assumption on the relation betweend2andd1is used in our derivation. However, ifd2 <2d1thend1cannot divided2andq1d+ 1>2qd2−d1.

Assume thatqd2−d1dividesu1. Setting∆ =qd2−d1,u=qd1,n= ∆l, andm=lfor some integerl, we conclude τ(n,∆, u, m) = ∆l(∆l−∆u+u−1)≥0from Lemma 8, so thatl≥

u−u +1

. The right-hand side is equal tou=qd1 ifd2 ≥2d1and tou−u/∆ + 1 = qd1−q2d1−d2+ 1otherwise, which is equivalent ton≥ qd2 and n≥qd2−qd1+qd2−d1. We remark that equality is achievable in the latter case via the2-weight codes constructed in [1] (with parametersn0 =d1andm=d2−d1). We do not know whether the correspondingqd2−d1-divisible set of d1-subspaces can be realized as a vector space partition ofFvq. For the first case see Example 6.

The choice formcan be obtained by minimizingτ(n,∆, u, m), i.e., solving∂τ(n,∆,u,m)

∂m = 0and rounding.

A suitable test case might be to decide whether a vector space partition of type44313526exists inF102 .

(4)

The above comprises [4, Theorems 1-4]. Given the stated examples, just Theorem 1(ii), for the case whered1

does not divided2, leaves some space for improving the lower bound onu1. To that end we analyze Lemma 8 in more detail. Since the statements look rather technical and complicated we first give a justification for the necessity of this fact. Via the quadratic inequality of Lemma 8 intervals of cardinalities can be excluded for different values of the parameterm. However, some cardinalities are indeed feasible. Ifr = ak+bwith0 ≤b < kthen the two constructions from Example 5 and Example 6 giveqr-divisible set ofk-subspaces of cardinality(a+2)k

1

q/k 1

q and qk+r, respectively. Forq = 2,r = 3,k = 2the cardinalities of these two examples are given by21and32. In general, each twoqr-divisible setsN1andN2ofk-subspaces can be combined to aqr-divisible set ofk-subspaces of cardinality#N1+ #N2. Since(a+2)k

1

q/k 1

qandqk+rare coprime there exists some integerFq(k, r)such that qr-divisible sets ofk-subspaces exist for every cardinalityn > Fq(k, r). Below that number some cardinalities can be excluded, but their density decreases with increasingn. Our numerical example is continued after the proof of Theorem 12.

Proposition 10. LetN be aqr-divisible set ofk-subspaces inFvq,u=qkand∆ =qr. Then,n /∈h

1,qk+rqr−1−1

and

n /∈ 1

u−1 ·

∆um−∆u+ 1 2 −1

2

√ω

, 1

u−1 ·

∆um−∆u+ 1 2 +1

2

√ω

, whereω= (∆u−2m)2+ 2∆u+ 1−4m2

, for allm∈Nwith2≤m≤∆u

4 +12+4∆u1 .

PROOF. We set∆ = ∆uandn=n(u−1)so thatτ(n,∆, u, m) = ∆2m(m−1)−n∆(2m−1) +n(n+ 1). We haveτ(n,∆, u, m) ≤0iff

n−∆m+∆+1212

q

2−4m∆ + 2∆ + 1andm ≤ 4 +12 + 1

4∆. Rewriting and applying Lemma 8 with1≤m≤∆u

4 +12+4∆u1

gives the result sincem(m−1)>0form≥2.

Proposition 11. LetN be aqr-divisible set ofk-subspaces inFvq, wherer=ak+bwitha, b∈N,0 < b < kand a≥1. Then,n≥ q(a+2)kqk−1−1 =qr·qk−b+qr·qqkk−b−1−1 = ∆qk−b+qkΘ + 1, where∆ :=qrandΘ := qqakk−1−1. PROOF. From Lemma 2 we concluden≥2qrand setu=qk. For2 ≤m≤qk−bwe have2∆u+ 1−4m2 >0, so that Proposition 10 givesn /∈hl∆u(m−1)−1/2+m

u−1

m

,j∆um−1/2−m

u−1

ki

. Since∆(m−1)≤l∆u(m−1)−1/2+m u−1

m

=

∆(m−1) +l

∆(m−1)−1/2+m u−1

m≤∆mand

j∆um−1/2−m u−1

k

= ∆m+mqbΘ +jmqb−1/2−m qk−1

k

= ∆m+mqbΘ, we concluden /∈

∆m,∆m+mqbΘ

for2≤m≤qk−b. It remains to shown /∈

∆m,∆m+mqbΘ + 1,∆(m+ 1)−1

=:Imfor all2 ≤m ≤qk−b−1. Ifn∈ Im, then we can writen= ∆m+mqbΘ +xwithx≥1andmqbΘ +x <∆, so thatqk· mqbΘ +x

= ∆m+mqbΘ + xqk−mqb

<∆m+mqbΘ +x=n, which contradicts Lemma 7.

In other words, in the case of Theorem 1(ii), whered2 = ad1+b with0 < b < d1 anda, b ∈ N, we have u1 ≥ qd2−d1 ·qd1−b+ q(a+1)dqd1−11−1 = q(a+2)dqd1−11−1, which can be attained by and1-spread inF(a+2)dq 1. Without the knowledge ofb, we can stateu1≥q·qd2−d1+lqd2 +1−1

qd1−1

m

, which also improves Theorem 1(ii) and is tight whenever d2+ 1is divisible byd1. Summarizing our findings we obtain our main theorem:

Theorem 12. For a non-emptyqr-divisible setN ofk-subspaces inFvq the following bounds onn= #N are tight.

(i) We haven≥qk+ 1and ifr≥kthen eitherkdividesrandn≥ qk+rqk−1−1 orn≥ q(a+2)kqk−1−1, wherer=ak+b with0< b < kanda, b∈N.

(ii) Letqrdividen. Ifr < kthenn≥qk+r−qk+qrandn≥qk+rotherwise.

For (i) the lower bounds are attained byk-spreads, see Example 5. For (ii) the second lower bound is attained by a construction based on lifted MRD codes, see Example 6. In the other case the2-weight codes constructed in [1] attain the lower bound. Thus, Theorem 12 is tight and implies an improvement of Theorem 1(ii).

While the smallest cardinality of a non-emptyqr-divisible set ofk-subspaces overFq has been determined, the spectrum of possible cardinalities remains widely unknown. Fork= 1[7, Theorem 12] states that eithern > rqr+1 or there exist integersa, bwithn =ar+1

1

q +bqr+1and bounds for the maximum excluded cardinality have been determined in [5]. However, Lemma 7 and Lemma 8, applied via Proposition 10, give restrictions going far beyond Theorem 12. For q = 2, r = 3, k = 2, andn ≤ 81 we exemplarily state that only n ∈ {21,31,32,33,42, 43,44,52, . . . ,55,62, . . . ,66,72, . . . ,78} might be attainable. The mentioned constructions cover the cases n ∈ {21,32,42,53,63,64,74} ⊆ {21a+ 32b : a, b ∈ N}. Replacing the lines by their contained3points, we obtain 24-divisible sets of1-subspaces inFvq of cardinality3n, for which two further exclusion criteria have been presented in [7], excluding the casesn∈ {33,44}. [7, Lemma 23] is based on a cubic polynomial obtained from (1) and (2), similar to the quadratic polynomial from Lemma 8 obtained from (1). Here, the presence ofkadditionalbi-variables

(5)

may make the analysis more difficult fork > 1. For aqr-divisible setN of 1-subspaces we have thatN ∩H is qr−1-divisible for every hyperplaneH, which allows a recursive application of the linear programming method. For k >1we need to considerk-subspaces andk−1-subspaces inH, see [7, Section 6.3], which makes the bookkeeping more complicated.

The determination of the possible spectrum of cardinalities ofqr-divisible sets ofk-subspaces remains an interesting open problem. Even for small parameters this might be challenging. A possible intermediate step is the determination of the number Fq(k, r) being similar to the Frobenius number. Extending the small list of constructions is also worthwhile.

ACKNOWLEDGEMENT

I am very thankful for the comments of two anonymous reviewers, which helped to improve the paper.

REFERENCES

[1] J. Bierbrauer and Y. Edel,A family of2-weight codes related to BCH-codes, Journal of Combinatorial Designs5(1997), no. 5, 391.

[2] A. Blokhuis, A.E. Brouwer, and H.A. Wilbrink,Heden’s bound on maximal partial spreads, Discrete Mathematics74(1989), no. 3, 335–339.

[3] P. Delsarte,An algebraic approach to the association schemes of coding theory, Philips research reports (1973), no. 10, 103.

[4] O. Heden,On the length of the tail of a vector space partition, Discrete Mathematics309(2009), no. 21, 6169–6180.

[5] D. Heinlein, T. Honold, M. Kiermaier, S. Kurz, and A. Wassermann,Projective divisible binary codes, The Tenth International Workshop on Coding and Cryptography 2017, 2017.

[6] M Herzog and J Sch¨onheim,Group partition, factorization and the vector covering problem, Canad. Math. Bull15(1972), no. 2, 207–214.

[7] T. Honold, M. Kiermaier, and S. Kurz,Partial spreads and vector space partitions, Network Coding and Subspace Designs (M. Greferath, M.O. Pavˇcevi´c, N. Silberstein, and A. Vazquez-Castro, eds.), Springer, 2018, pp. 131–170.

[8] S. Kurz,Packing vector spaces into vector spaces, The Australasian Journal of Combinatorics68(2017), no. 1, 122–130.

[9] H.N. Ward,Divisible codes, Archiv der Mathematik36(1981), no. 1, 485–494.

DEPARTMENT OFMATHEMATICS, UNIVERSITY OFBAYREUTH, 95440 BAYREUTH, GERMANY E-mail address:sascha.kurz@uni-bayreuth.de

Referenzen

ÄHNLICHE DOKUMENTE

In this paper we give a linear algebraic proof of the known upper bound for the size of some special spherical s-distance sets.. This result generalizes Gerzon’s general upper bound

Finally we show that the h-vector of a standard determinantal scheme of codimension 3 is of decreasing type if the largest entry in the corresponding degree matrix is sufficiently

In addition, it can make use of the scientific community’s heightened awareness of mobility and transport, networks, flows and nodes (C ASTELLS 1996; C RANG 2002). In this context,

1) Recall the denition of accumulation point of a lter of a topological space. What is the relation between accumulation points and limit points of a lter of a t.v.s.?. 2) Recall

In this section we are going to consider vector spaces over the field K of real or complex numbers which is given the usual euclidean topology defined by means of the

A topological space X is said to be (T1) if, given two distinct points of X, each lies in a neighborhood which does not contain the other point; or equivalently if, for any two

then we aim to show that the filter of neighbour- hoods of the origin F satisfies the properties 1,2,3,4,5. Since by the definition of t.v.s. Therefore, the preimage of any

A topological space X is said to be Hausdorff or (T2) if any two distinct points of X have neighbourhoods without common points; or equivalently if two distinct points always lie