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Mathematics for linguists

Gerhard J¨ager

gerhard.jaeger@uni-tuebingen.de

Uni T¨ubingen, WS 2009/2010

November 19, 2009

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Automata (informally)

imaginary machine/abstract model of a machine

behaves according to certain rules.

behavior of the automata depends on information, that the automate receives from the environment

automata “make decisions”

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An example

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Language automata

automaton receivesinput from it environment (for instance key stroke by user)

input can be represetned as string of symbols from an alaphabet (in the simplest case, these are just “0” and “1”)

automaton produces output

can also be represented as string of symbols

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The laughing automaton (according to Stefan

M¨ uller)

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Finite automata

A finite automaton

has finitely many states,

receives as input strings over some alphabetΣ,

returns as output either “yes” or “no”

A finite automaton thus defines a formal language — the set of inputs for which it returns the symbol “yes”

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Finite automata

Definition (Deterministic finite automaton)

Adeterministic finite automaton (DFA)M is a 5-tuple M =hK,Σ, δ, q0, Fi

HereK is the set ofstates and Σtheinput alphabet,K∩Σ =∅.

K andΣ are finite sets.q0 ∈K is theinitial state,F ⊆K is the set offinal states, andδ :K×Σ→K is thetransition function.

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Finite automata: example

LetM =hK,Σ, δ, q0, Fi, where

K = {q0, z1, z2, z3} Σ = {a, b}

F = {z3} δ(q0, a) = z1

δ(q0, b) = z3

δ(z1, a) = z2

δ(z1, b) = q0

δ(z2, a) = z3 δ(z2, b) = z1 δ(z3, a) = q0

δ(z3, b) = z2

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Finite automata: example

Finite automata can be represented as graphs:

initial state is represented by an arrow

final states are marked by double circle

transition function is represented by labeled directed edges

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Finite automata

intuition:

automaton starts at initial state

input is written on some input tape (like a punchcard)

Per temporal unit, the automaton reads a symbolαon the input tape and moves along an arrow with the labelαtowards a new state

If the automaton is in a final state after reading the entire input tape, the string on the input tape isaccepted(output:

“yes”)

else the string is not accepted (output: “no”)

Question: which language is accepted by the automaton from the example?

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Finite automata and formal languages

Definition

For a given DFAM =hK,Σ, δ, q0, Fiwe define a function ˆδ:K×Σ →K via a recursive definition as follows:

δ(z, )ˆ = z

ˆδ(z, a~x) = δ(δ(z, a), ~ˆ x)

Here it holds thatz∈K, ~x∈Σ anda∈Σ.

The language that isacceptedbyM is

L(M) ={~x∈Σ|δ(qˆ 0, ~x)∈F}

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Finite automata and formal languages

definition of ˆδ extends definition ofδ from single symbols to strings of symbols

for single symbols, it holds that: ˆδ(z, a) =δ(z, a)

it also holds that

δ(z, aˆ 1a2. . . an) =δ(. . . δ(δ(z, a1), a2). . . , an)

Theorem

Every language that is accepted by a deterministic finite automaton is regular (Type 3 in the Chomsky hierarchy).

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Idea of proof

Let

M =hK,Σ, δ, q0, Fi be a DFA. We construct a regular grammar G=hVT, VN, S, Ri

as follows:

VT = Σ

VN =K

S =q0

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Idea of proof

For every transition

δ(z1, a) =z2 there is a rule

z1 →az2

Ifz2 ∈F, there is the additional rule z1→a

Ifq0∈F, there is the additional rule q0

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Non-deterministic automata

With a deterministic automaton, it is uniquely determined for each state and each input symbol, into which state the automaton moves

With a non-deterministicautomaton it may be due to chance into which state the automaton moves

In a non-deterministic automaton, δ need not be a function, but it is a relation.

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Non-deterministic automaton

Definition (Non-deterministic finite automaton1)

Anon-deterministic finite automaton(NFA) M is a ein 5-tuple M =hK,Σ, δ, q0, Fi

Here

K is a finite set, the set of states,

Σ is a finite set, theinput alphabet, with K∩Σ =∅,

δ ⊆K×Σ×K is a relation, the transition relation,

q0 is the initial state, and

F ⊆K is the set of final states.

1Differs in an inessential way from PtMW.

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Non-deterministic automata

The non-deterministic transition relation can also be extended to a relationδˆ⊆K×Σ×K for strings of symbols:

δ(q, , q)ˆ for all q∈K

δ(qˆ 1, a~x, q2) iff δ(q1, a, q3),ˆδ(q3, ~x, q2)for someq3∈K The languageL(M)that is acceptedby a NFAM is defined as

L(M) ={~x∈Σ|there is aq ∈F such thatδ(qˆ 0, ~x, q)}

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Non-deterministic automata

example:

the following NFA accepts all words~xover{0,1}that end in0.

0

0 0

0

1

z0 z1 z2

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Non-deterministic automata

Theorem

Every language that is accepted by a NFA is also accepted by some DFA.

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Idea of proof

Let

M1=hK,Σ, δ, q0, Fi

be a non-deterministic finite automaton. We construct a corresponding finite automaton

M0=hK00, δ0, q00, F0i

in the following way:

K0 =℘(K)

Σ0 = Σ

δ0(q10, a) ={q ∈K|there is a q1 ∈q01 such that δ(q1, a, q)}

q00={q0}

F0 ={q0 ∈℘(K)|q0∩F 6=∅}

M0 accepts the same language as M.

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Finite automata and regular grammars

Theorem

For every regular grammar

G=hVT, VN, S, Ri

there is a NFA

M =hK,Σ, δ, q0, Fi with

L(G) =L(M)

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Idea of proof

We assume that every ruleR has the form A→aB,A→aor S→. Every regular grammar can be transformed into this form.

We constructM as follows:

K =VN∪ {zω}

Σ =VT

δ(z1, a, z2) ifz1 →az2∈R

δ(z1, a, zω) ifz1 →a∈R

q0=S

IfS →∈R,F ={q0, zω}; otherwise F ={zω} M accepts exactly the language that is generated byG.

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Finite automata and regular languages

Theorem

Both deterministic and non-deterministic finite automata accept exactly the regular languages.

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