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HP Prime Application Note Physics: 04. Orbiting Satellites

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Preparation and Copyright: MORAVIA Education, a division of MORAVIA Consulting Ltd.

www.moravia-consulting.com www.hp-prime.com

HP Prime Application Note Physics:

04. Orbiting Satellites

What is the speed and the period of satellites revolving around the Earth? All this is just mechanics going back to Isaac Newton’s 1687 Philosophiæ Naturalis Principia Mathematica.

Watch the video How Do Satellites Get & Stay in Orbit? at https://www.youtube.com/watch?v=IC1JQu9xGHQ.

The speed of a satellite moving around our planet is:

𝒗𝒗

𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨

= 𝑹𝑹

𝐄𝐄𝐄𝐄𝐨𝐨𝐨𝐨𝐄𝐄

∙ �

𝑹𝑹𝐄𝐄𝐄𝐄𝐨𝐨𝐨𝐨𝐄𝐄𝒈𝒈+𝑯𝑯

(in m/s) where 𝑅𝑅Earth = 6 371 000 m, g = 9.8 m/s² and H being the height of the satellite above the surface of the Earth.

Enter the formula in the Solve app:

The satellite’s orbital period is:

𝑻𝑻

𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨𝐨

=

𝟐𝟐𝟐𝟐∙(𝑹𝑹𝐄𝐄𝐄𝐄𝐨𝐨𝐨𝐨𝐄𝐄+𝑯𝑯)𝟑𝟑𝟐𝟐

𝑹𝑹𝐄𝐄𝐄𝐄𝐨𝐨𝐨𝐨𝐄𝐄∙�𝒈𝒈 (in s):

Now, use the Solve app to calculate the height of a geostationary satellite. For this, you must compute using —not the solar day but— the sidereal day. That is the length of a day with respect to the stars, which is about 23 hours, 56 minutes and 4 seconds (86 164 s). So solving the formula with the HP Prime, geostationary satellites orbit the Earth at a height of some 35,764 km and at a speed of about 3.1 km/s.

The GPS constellation was conceived in such a manner that each satellite sets and rises twice a day, reaching the same position in the sky at the same time as the

day before. So GPS satellites circulate around the Earth in half a sidereal day (43 082 s). Using the Solve app in the HP Prime, the corresponding height of the GPS satellites is 20 172 km, their speed being 3.9 km/s.

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