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Nonlinear di erential-algebraic equations with properly formulated leading term

R. Marz

1 Introduction

In BaMa], a uniform theory for investigating linear dierential-algebraic equations (DAEs) and their adjoint equations was proposed. By means of an additional coef- cient matrix it is exactly xed which derivatives of the solutions searched for are actually involved in the equation. Such a DAE is of the form

A(t)(D(t)x(t))0 +B(t)x(t) =q(t) t2I (1.1) where the coecients A(t) andD(t) match well.

As a nonlinear version,

A(x(t) t)(D(t)x(t))0+b(x(t) t) = 0 (1.2) can be taken into account rst (e.g. HiMa]). However, with somewhat more con- sistency, we obtain equations of the form

A(x(t) t)(d(x(t) t))0+b(x(t) t) = 0 (1.3) which we want to investigate in this paper.

Note that it is just this sort of equations that result in the simulation of electric circuits, which is the origin of DAEs (e.g. EsTi]). In this case, a transition to

A(x(t) t)dx(x(t) t)x0(t) +b(x(t) t) +A(x(t) t)dt(x(t) t) = 0 is problematical.

In the next section (x2) we will determine what we mean by a properly formulated leading term. In x3 DAEs with index , 2 f1 2g will be characterized by alge- braic criteria. x4 is devoted to linearization and perturbation theorems. A special structure, which is important for electric circuits for instance, will be analyzed in

x5. Finally, constraint sets will be investigated in x6.

2 Properly formulated leading terms and an equivalence theorem

We investigate the equation

A(x(t) t)(d(x(t) t))0+b(x(t) t) = 0 (2.1) 1

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2 R. Marz with coecient functions A(x t) 2 L(Rn Rm) d(x t) 2 Rn and b(x t) 2 Rm x 2

D Rm t 2 I R, that are continuous in their arguments, and which have the continuous partial derivatives Ax dx bx. Denote D(x t) = dx(x t).

De nition 2.1

The leading term in (2:1) is said to be properly formulated if kerA(x t) im D(x t) =Rn x2D t2I (2.2) and if there exists a projector function R 2 C1(I L(Rn)) such that R(t)2 = R(t), kerA(x t) = kerR(t) im D(x t) = im R(t), and d(x t) = R(t)d(x t) holds for x2D t 2I.

Consequently, the matrices A(x t) and D(x t) have constant rank for properly for- mulated leading terms. The subspaces A(x t) and imD(x t) are independent of x and have bases from the class C1. It holds that A=AR D =RD.

If A(x t) and D(x t) ful l the condition (2.2), but only ker A(x t) is independent of x and smooth, then we have, with a projector PA 2 C1(I L(Rn)), the relation A(x t) =A(x t)PA(t) and, hence

A(x(t) t)(d(x(t) t))0 =A(x(t) t)(PA(t)d(x(t) t))0;A(x(t) t)PA0(t)d(x(t) t): Then, with ~A(x t) := A(x t) ~d(x t) := PA(t)d(x t) ~b(x t) := b(x t);

;A(x t)PA0(t)d(x t), the equation

A~(x(t) t)(~d(x(t) t))0+ ~b(x(t) t) = 0 (2.3) has a proper leading term because of im ~D(x t) = imPA(t). We can proceed anal- ogously if only imD(x t) is independent of x, or if the last condition of De nition 2.1 in not ful lled. Hence, a proper formulation can be obtained if (2.2) holds and if one of the characteristic subspaces is independent of x and comes fromC1.

De nition 2.2

A function x 2 C(Ix Rm) Ix I, is said to be a solution of equation (2.1) if x(t) 2D t 2 Ix and d(x(:) :) 2 C1(Ix Rn), and if equation (2:1) is fullled pointwisely.

Unfortunately, regularity conditions do not de ne a linear function space here in general. In case d(x t) = D(t)x is linear itself (cf. (1.2)), a linear solution space is available by CD1 :=fx2C :Dx2C1g.

Fortunately, it is relatively simple to transform equation (2.1) into a (1.2) form.

This allows the application of standard-notions and -methods (dierentiability, lin- earization etc.) that are based on linear funtion spaces.

We form the natural extension for equation (2.1) with proper leading term

A(x(t) t)(R(t)y(t))0+b(x(t) t) = 0 (2.4) y(t);d(x(t) t) = 0: (2.5)

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Nonlinear dierential-algebraic equations with properly formulated leading term 3 Withx=;xy A=;A0 d(x t)=R(t)y D(x t)=D(t)=(0 R(t)) b(x t)=;y;b(dx t(x t)) we can write (2.4), (2.5) as

A(x(t) t)(D(t)x(t))0+b(x(t) t) = 0: (2.6) Due to ker A(x t) = ker A(x t), imD(t) = im R(t) = imD(x t) also (2.6) has a properly formulated leading part with R(t) =R(t) as the corresponding projector.

Now the linear function space CD1 =

x=

x y

2C :Dx =Ry 2C1

(2.7) oers itself as solution space for (2.6). For (2.6) we seek functions x 2 CD1 whose function values lie in the domain of de nitionDof the coecients and ful l equation (2.6) pointwisely.

If x(:) is a solution of the original equation (2.1), then the pair x(:) y(:) with y(t) : d(x(t) t) is obviously a solution of the class CD1 for (2.6). If, reversely, a pair x(:) y(:) from CD1 forms a solution of (2.6), then d(x(:) :) = Rd(x(:) :) = Ry 2C1 also holds because of Ry 2C1, andx(:) is a solution of equation (2.1).

Theorem 2.3

Let the leading term of (2:1) be properly formulated.

(i) The the leading term of the extension (2:6) is properly formulated, too.

(ii) The equations(2:1) and (2:6) are equivalent via the relation y(:) =d(x(:) :): The sets

M

0(t) := fx2D:b(x t)2 im A(x t)g and

M

0(t) := fx=

x y

2DR

n :b(x t)2 im A(x t) y=d(x t)g

= fx2DRn :x2M0(t) y=d(x t)g:

are the geometrical location of the solutions of (2.1) and (2.6), respectively, It always holds that

x(t)2M0(t) x(t)2M0(t):

The problem in how far these sets are lled with solutions leads to notions of indices and corresponding solvability statements.

3 Subspaces, matrix chain and index

In this section we de ne characteristic subspaces and matrix chains for (2.1) and (2.6).

Further, let B(y x t) := (A(x t)y)x + bx(x t) for y 2 Rn x 2 D t 2 I and

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4 R. Marz B(y x t) := (A(x t)y)0x+bx(x t) fory 2Rn x2DRn t 2I. More precisely, we have B(y x t) =

A(x t)y 0

x+

bx(x t) 0

;D(x t) I

=

B(y x t) 0

;D(x t) I

For the original equation (2.1) we form for x2D t 2I y 2Rn: G0(x t) = A(x t)D(x t)

N0(x t) = kerG0(x t)

S0(y x t) = fz 2Rm :B(y x t)z2 im G0(x t)g G1(y x t) = G0(x t) +B(y x t)Q0(x t)

with a projector Q0(x t)2L(Rm) onto N0(x t), P0(x t) = I;Q0(x t)

N1(y x t) = kerG1(y x t)

S1(y x t) = fz 2Rm :B(y x t)P0(x t)z 2 im G1(y x t)g:

For (2.6) this yields G0(x t) = A(x t)D(x t) etc. for x 2 DRn t 2 I y 2 Rn. N0(t) =RmkerR(t) depending ont only and being smooth is a special feature of (2.6).

Now, the relations among the subspaces of (2.1) and (2.6) are important, because the index will be de ned via these subspaces later on.

Lemma 3.1

Let equation (2:1) have a proper leading term, then

N0(t)\S0(y x t) = (N0(x t)\S0(y x t))0 (3.1) and

N1(y x t)\S1(y x t) =n;2RmRn :=Q0(x t) =R(t)

D(x t);+2 N1(y x t)\S1(y x t)o: (3.2) P r o o f. We determine

G0(x t) = A(x t)D(x t) =

0 A(x t)

0 0

N0(t) =

2R

m

R

n :A(x t) = 0

=Rm kerR(t)

S0(y x t) =

:B(y x t) 2 im A(x t) ;D(x t)+ = 0

=

: 2S0(y x t) =d(x t)

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Nonlinear dierential-algebraic equations with properly formulated leading term 5

N0(t)\S0(y x t) =

:R(t) = 0 =D(x t) 2S0(y x t)

=

: 2N0(x t)\S0(y x t) = 0

: Furthermore, by Q0(t) =

I 0

0 I;R(t)

P0(t) =

0 0 0 R(t)

we also have B(y x t)P0(t) =

0 0 0 R(t)

G1(y x t) =

B(y x t) A(x t)

;D(x t) I;R(t)

: which implies

S1(y x t) =

8

>

<

>

:

;

:;R(0t)2 im

2

6

4

B(y x t) A(x t)

;D(x t) I;R(t)

3

7

5 9

>

=

>

= n;:R(t) =;D(x t)+ (I ;R(t))

with 2Rm 2Rn B(y x t)+A(x t) = 0o

= n;:R(t) =;D(x t) with 2S0(y x t)o

N1(y x t) = n;:B(y x t)+A(x t) = 0 D(x t) = 0 =R(t)o

= n;: 2N0(x t) =R(t) 0 = (A(x t)D(x t)+

+B(y x t)Q0(x t))(D(x t);+)o

= n;: =Q0(x t) =R(t) D(x t);+ 2N1(y x t)o: Finally, we obtain

=Q0(x t) =R(t) =;D(x t) 2S0(y x t) D(x t); + 2N1(y x t) for ;2N1(y x t)\S1(y x t). Thus,

B(y x t)P0(x t)(D(x t);+) = B(y x t)P0(x t)D(x t);

= ;B(y x t)P0(x t) 2 im G1(y x t) because of B(y x t)=G0(x t)w, i. e.,

B(y x t)P0(x t)= (G0(x t) +B(y x t)Q0(x t))(P0(x t)w;Q0(x t)): 2

Conclusion 3.2

For (2:1) and (2:6) it holds that

dim(N0(t)\S0(y x t)) = dim(N0(x t)\S0(y x t)) and dim(N1(y x t)\S1(y x t)) = dim(N1(y x t)\S1(y x t)):

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6 R. Marz

De nition 3.3

An equation (2:1) with properly formulated leading term is called a DAE of index 1 if

N0(x t)\S0(y x t) = 0 for x2D t2I y2Rn or a DAE of index 2 if

dim(N0(x t)\S0(y x t)) = const

N1(y x t)\S1(y x t) = 0 for x2D t 2I y 2Rn:

Theorem 3.4

The original equation (2:1) with proper leading term and its natural extension (2:6) have the index 2f1 2g simultaneously.

Now we continue the above matrix chain with

G2(y x t) :=G1(y x t) +B(y x t)P0(x t)Q1(y x t) and G2(y x t) :=G1(y x t) +B(y x t)P0(t)Q1(y x t)

where Q1(y x t) 2 L(Rm), Q1(y x t) 2 L(Rm+n) are projectors onto N1(y x t) and N1(y x t), respectively. We will investigate only problems (2.1) with index

2f1 2ghere, hence,

N1(y x t)S1(y x t) =Rm (3.3) holds on principle, in fact for = 1 with N1(y x t) = 0, S1(y x t) = Rm trivially, and for= 2 due to GrMa], Theorem A.13. Hence, we may assume thatQ1(y x t) projects onto N1(y x t) alongS1(y x t).

Analogously, letQ1(y x t) be the projector ontoN1(y x t) alongS1(y x t). Simple computation now yield

Lemma 3.5

For 2 f1 2g it holds that Q1 =

0 Q0Q1D; 0 DQ1D;

D P1D; =DP1D; D Q1D;=DQ1D; and D Q1G;12 = (DQ1G;12 DQ1D;).

4 Linearization and perturbation theorems

First, we consider the equation

A(x(t) t)(D(t)x(t))0+b(x(t) t) = 0 (4.1) i.e., the case that D(x t) = D(t)x x 2 D t 2 I. Later on, we apply the obtained results via (2.6) to the general form (2.1).

We x x 2 CD1(I Rm) with x(t) 2 D t 2 I. Let I I be compact. For all

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Nonlinear dierential-algebraic equations with properly formulated leading term 7 x from a suciently small neighbourhood U(x) of x inCD1(I Rm) we can de ne the map

F : U(x)CD1(I Rm)!C(I Rm)

F(x) := A(x(:) :)(Dx)0(:) +b(x(:) :) x2U(x) (4.2) and we can write equation (4.1) as

F(x) = 0 where F is Frechet-dierentiable. The derivative

Fx(x)2Lb(CD1(I Rm) C(I Rm)) is given by

Fx(x)4x = A(x(:) :)(D4x)0(:) +B((Dx)0(:) x(:) :)4x(:)

for 4x2CD1(I Rm) (4.3)

where we assume natural norms on CD1(I Rm) and C(I Rm).

For applying the implicit function theorem (e.g. KaAk]), the property of the image imFx(x) is of crucial importance.

With A(t) =A(x(t) t) B(t) =B((D(t)x(t))0 x(t) t) t2I, the linear DAE A(t)(D(t)4x(t))0 +B(t)4x(t) =q(t) t 2I (4.4) is nothing else but the equation

Fx(x)4x=q:

Let S0(t) N0(t) G1(t) etc. denote the chain of subspaces and matrices generated for (4.4).

Lemma 4.1

Let the DAE (4:1) have a properly formulatd leading term. Let DP1D; DQ1D;2C1(I L(Rn)).

(i) The index--property, 2 f1 2g, transforms itself from (4:1) onto the lin- earization (4:4).

(ii) For = 1, Fx(x) is surjective.

(iii) For = 2 it holds that imFx(x) = CDQ1 1G;12(I Rm).

P r o o f. The assumption (i) immediately results from the construction of the subspaces and the matrices in x3. The assumptions (ii) and (iii) are concluded from the existence theorems for linear DAEs in BaMa]. 2

Conclusion 4.2

In the index-2 case, imFx(x) is a non-closed proper subset in C(I Rm).

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8 R. Marz If the DAE (4.1) has a dynamic degree of freedom, it has to be completed by initial or boundary conditions. Since A and D are singular, we cannot expect a degree of freedom mas in the case of regular DAEs, but a lower one. An IVP with the initial condition x(t0) = x0 2Rm is not solvable in general. Hence,x0 has to be consistent to an extend.

Basing on our experience with linear DAEs ( BaMa]), we impose an initial condition for (4.1) with t0 2I in the form

D(t0)(x(t0);x0) = 0 with x0 2Rm (4.5) where 2L(Rm) will still have to be xed. By means of the mapping

FIV P : U(x)CD1(I Rm)!C(I Rm)LIC

LIC := im D(t0)

FIV P(x) := (Fx D(t0)x(t0)) x2U(x) (4.6) we can describe the IVP (4.1), (4.5) in a compact way by

FIV P(x) = (0 D(t0)x0): Now, the equation

FIV P(x) = (q D(t0)x0) corresponds to the perturbed IVP

A(x(t) t)(D(t)x(t))0 +b(x(t) t) =q(t) t2I (4.7) D(t0)(x(t0);x0) = 0: (4.8)

Theorem 4.3

Let (4:1) be a DAE with proper leading term and index 2 f1 2g, and let x 2CD1(I Rm) be a solution of (4:1) and

DP1D; DQ1D; 2C1(I L(Rn)) :=P1(t0): Further, for x2U(x), let

D(t)Q 1(t)G2(t);1b(x(t) t) be continuously dierentiable w.r.t. t: (4.9) (i) If = 1, then the IVP (4:7) (4:8) is uniquely solvable on I for arbitrary x0 2 Rm with jD(t0)(x0 ;x(t0))j , and q 2 C(I Rm) with k q k1 , >0 su ciently small. For the solutions x2CD1(I Rm) it holds that

kx;x kCD1 const (jD(t0)(x0;x(t0))j+kqk1):

(ii) If = 2, then the IVP (4:7) (4:8) is uniquely solvable on I for arbitrary x0 2Rm with

jD(t0)(x0;x(t0))j and q2CDQ;1 1G 2(I Rm) kqk1 +

k(DQ 1G;12q)0 k1 >0 su ciently small.

For the solutions x2CD1(I Rm) it holds that

k x;x kCD1 const (jD(t0)(x0;x(t0))j+kqk1 + k(DQ1G;12q)0 k1):

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Nonlinear dierential-algebraic equations with properly formulated leading term 9 (iii) The solution x of the IVP (4:1) (4:8) is continuously dierentiable w.r.t. x0.

The sensitivity matrix xx0(t) =:X(t)2L(Rm) satises the IVP A(x(t) t)(D(t)X(t))0 +B((D(t)x(t))0 x(t) t)X(t) = 0 t2I

D(t0)(X(t0);I) = 0:

Remark:

If we take into account that P1(t) = I, Q1(t) = 0 for = 1, then the smoothness assumptions of Theorem 4.3. are always trivially given in this case. For = 2 the regularity condition (4.9) implies restrictions of the admissible structure of (4.1). The following condition is sucient for (4.9):

D;2C1(I L(Rn Rm))

(x t) := D(t)Q 1(t)G2(t);1b(x t) is continuously dierentiable and

b0x(P0(t)x+sQ0(t)x t)Q0(t)x2 im G1(t) s2 0 1] x2D t2I: (4.10) Namely, thend (x t) (P0(t)x t) is true and for x(:) 2 U(x) it holds that

dt(x(t) t) = dtd(P0(t)x t) = dtd(D(t);D(t)x(t) t) = x(D(t);D(t)x(t) t)

fD(t);0D(t)x(t) +D(t);(D(t)x(t))0g +t(D(t);D(t)x(t) t). The condition (4.10) is equivalent to

W 0(t)b0x(P0(t)x+sQ0(t)x t)Q0(t)x2 im W 0(t)B 0(t)Q0(t): (4.11) If the derivative free part of (4.1) is linear in x or if (4.1) is a DAE in Hessenberg form, then (4.11) is given.

P r o o f of Theorem 4.3:

FIV P x(x) is a bijection from CD1(I Rm) onto C(I Rm)LIC for = 1.

For = 2, FIV P x(x) is injective but not surjective. According to Lemma 4.1, imFIV P x(x)LIC =CDQ1 1G;12(I Rm)LIC =:X.

Equipped with a natural norm, X is a Banach space. We summarize the two cases that = 1 = 2 by using Q1 = 0 P 1 =I for = 1.

For the mapping

H(x d q) := FIV P(x);(q d) x2U(x) (q d)2X it holds, due to the condition (4.9), that

H(x d q)2X:

With d :=D(t0)x(t0) we obtain

H(x d 0) = 0 Hx(x d 0) = FIV P x(x):

Hx(x d 0) is a homeomorphism for = 1 as well as for = 2. Due to the im- plicit function theorem there exists a uniquely determined continuously dierentiable mapping

f :B(d )B(0 )X !CD1(I Rm)

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10 R. Marz withf(d 0) = x,H(f(d q) d q) = 0,kf(d q);f(d 0)kCD1 K(jd;dj+kqkX) for jd;dj kqkX:=kqk1 +k(DQ1G;12q)0 k1 .

Then the two assumption (i) and (ii) follow because of d=D(t0)x0.

In particular, f(d 0) is continuously dierentiable w.r.t. d, i.e., the solution x(:) of the IVP (4.1) with D(t0)x(t0) = d has a continuous derivative w.r.t. d. With d=D(t0)x0 this impliesxx0(t) =xd(t)D(t0). As usually, the variational equation (4.10) now results by dierentiation w.r.t. x0: 2

If we introduce a perturbation index for (4.1.) analogously to the standard case of DAEs, then the inequalities in (i) and (ii) mean that a DAE (4.1) with index has the perturbation index 2f1 2g, too.

For the extended system (2.4), (2.5) and for (2.6), respectively, it holds withx=;xy,

4x=;44xy that

Fx(x)4x=

A(x(:) :)(R4y)0(:) +B((Ry)0(:) x(:) :)4x(:)

4y(:);D(x(:) :)4x(:)

:

In particular, the equationFx(x)4x= (q r) withx =;xy is nothing else but the linear DAE

A(x(t) t)(R(t)4y(t))0+B((R(t)y(t))0 x(t) t)4x(t) = q(t)

4y(t);D(x(t) t)4x(t) = r(t): (4.12) Now, let x(:) be a solution of the nonlinear equation (2.1) and y = d(x(:) :).

Then x(:) solves the extended form (2.4), (2.5) with y =Ry =d(x(:) :).

With the coecients

A(t) = A(x(t) t) D(t) =D(x(t) t)

B(t) = B((d(x(t) t))0 x(t) t) (4.13) (4.12) can be reduced to

A(t)(R(t)4y(t))0+B(t)4x(t) = q(t)

4y(t);D(t)4x(t) = r(t): (4.14) For r(t) = 0 this yields

A(t)(D(t)4x(t))0 +B(t)4x(t) =q(t) (4.15) which can be regarded as a linearization of the initial equation (2.1).

By Theorem 3.4 and Lemma 4.1 the index 2f1 2g is transformed from (2.1) to (4.14) and (4.15).

Now, let N0, S 0, G1 etc. be the subspaces and matrices of the chain formed for A,D and B from (4.13).

We investigate the perturbed IVP

A(x(t) t)(d(x(t) t))0+b(x(t) t) =q(t) (4.16)

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Nonlinear dierential-algebraic equations with properly formulated leading term 11 D(t0)D(t0);(d(x(t0) t0);y0) = 0 (4.17)

y0 2Rn q2C(I Rm):

For =I the initial condition (4.17) simpli es to R(t0)(d(x(t0) t0);y0) = 0, i.e., d(x(t0) t0) =R(t0)y0: (4.18)

Theorem 4.4

Let the DAE (2:1) with proper leading part be of index = 1. Let x(:) be the solution of (2.1) on the interval I. Further, let = I. Then the IVP (4:16) (4:18) is uniquely solvable with a solution x(:) dened on I for q 2 C(I Rm), k qk1 , y0 2Rn, jR(t0)(y0;d(x(t0) t0))j , >0 su ciently small. x(:) depends continuously dierentiably on y0. It holds that

kx;x k1 + kd(x(:) :);d(x(:) :)kC1

const(jR(t0)(d(x(t0) t0);d(x(t0) t0))j+kqk1):

P r o o f of the theorem: We form the extended system for the DAE (4.16) and apply Theorem 4.3 for = 1. 2

In the nature of things DAEs of index 2 require a higher regularity of some compo- nents. Here it is essential in how far we can assume (4.9) for the extended equation (2.6). We have (cf. x2)

n(x t) := D(t)Q1(t)G2(t);1b(x t)

= n(x t) +D(t)Q1(t)D(t);(y;d(x t)) (4.19) with n(x t) :=D(t)Q1(t)G2(t);1b(x t): (4.20) In the case of a linear original equation (2.1) with A(x t)A(t), b(x t)B(t)x+ q(t), d(x t)D(t)xthe expressions (4.19), (4.20) simplify to

n(x t) = D(t)Q1(t)G2(t);1q(t) +D(t)Q1(t)D(t);y n(x t) = D(t)Q1(t)x+D(t)Q1(t)G2(t);1q(t):

It is natural to demand that DQ1G;12 q 2 C1 for index-2 DAEs, and likewise that DQ1D; 2 C1. Thus, condition (4.9), which requires that n(x(:) :) has to belong to the class C1 for continuous x(:) y(:) and continuously dierentiable (Ry)(:), is ful lled for (2.1) in the linear case.

Theorem 4.5

Let the DAE (2:1) with proper leading term be of index = 2. Let x 2 C(I Rm) be the solution of (2:1), and DP1D;, DQ1D; be continuously dierentiable. Moreover, let :=P1(t0).

Let n(x(:) :)2C1(I Rn) for all x2C(I Rm) from a neighbourhood ofx and for y 2CR1(I Rn) from a neighbourhood of y =d(x(:) :).

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12 R. Marz (i) For

q2CD Q1 1G;12(I Rm) kqk1+k(DQ1G;12q)0k1 y0 2Rn jDP1D;(y0;d(x(t0) t0))j

> 0 su ciently small, the IVP (4:16) (4:17) is uniquely solvable and for the solution x2C(I Rm) it holds that

kx;xk1+kd(x(:) :);d(x(:) :)kC1

const fkqk1+k(DQ1G;12q)0k1 + jD(t0)D(t0);(d(x(t0) t0);d(x(t0) t0))jg: (ii) The solution x(:) of the IVP depends contiuously dierentiably on y0.

P r o o f. We use the extended form (2.6) for (2.1) and write the IVP (4.16), (4.17) in the following way (cf. xx1,2)

A(x (t) t)(D(t)x(t))0+b(x(t) t) =q(t) (4.21) D(t0)P1(t0)(x(t0);x0) = 0 (4.22) with D(t0)P1(t0) = (0 DP1D;) andq(t) = ;q(0t). For (2.6), the condition (4.9) is given by the assumption.

q 2 CDQ1

1G;12(I Rm+n) holds if and only if q 2 CD Q1

1G;12(I Rm). Consequently, Theorem 4.3 yields the assertion. 2

We formulate a further perturbation theorem, whose assumptions are possibly easier to be checked.

Theorem 4.6

Let the DAE (2:1) with proper leading term be of index = 2. Let x 2C(I Rm) be the solution of (2:1), and letDP1D;, DQ1D; as well asDx be continuously dierentiable. Let :=P1(t0).

For all x 2 CD1 (I Rm) from a neighbourhood of x let n(x(:) :) and d(x(:) :) be continuously dierentiable. Then the assumptions from Theorem 4:5 remain true, where the solutions of the IVP (4:16) (4:17) are even from CD1 (I Rm).

P r o o f. We check immediately whether the linear index-2 DAE (4.12) has solutions

4x2CD1 (I Rm),4y2CR1(I Rn) for right-hand sidesq 2CD Q1 1G;12(I Rm) r2 CR1(I Rn). With X :=CD1 (I Rm)CR1(I Rm) and Y :=CD Q1 1G;12(I Rm) CR1(I Rn) we obtain Fx(x)2Lb(X Y) imFx(x) =Y.

Then the related mappping FIV P x(x) acts bijectively between the spaces X and Y LIC. By assumption it holds that x =;xy 2X.

The regularity conditions forn(x t) andd(x t) ensure that F(x)2Y is always true for x 2 X from a neighbourhood of x. We can further argue analogously to the proof of Theorem 4.3, where the mappingH(x d q) :=FIV P(x);(q d) operates in the spaces XLIC Y and Y LIC now. 2

The additional regularity conditions in case of DAEs of index = 2, which shall

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Nonlinear dierential-algebraic equations with properly formulated leading term 13 guarantee certain properties of the mappings (the images F(x) have to lie in the

"right" space), imply restrictions on the admissible structure.

An interesting special class of DAEs, which is important for applications, consists of DAEs for which N0(x t) does not depend on x, i.e.,

kerD(x t) =N0(t) x2D t2I (4.23) and P0(t) is continuously dierentiable w.r.t. t. Quite often N0(x t) is even inde- pendent of x and t.

Then it holds that

d(x t) =d(P0(t)x t) x2D t2I (4.24) and further dx(x t) =dx(P0(t)x t), in particular,

D(t) =dx(P0(t)x(t) t):

Lemma 4.7

Let (2:1) be a DAE with proper leading term. Let (4:3) be valid and d 2 C1(DI Rn), P0 2 C1(I L(Rm)). Let x 2 C(I Rm) be a solution of the DAE (2:1).

(i) Then P0x D D; and Dx are continuously dierentiable on I. (ii) d(x(:) :) is continuously dierentiable on I for all x2CD1 (I Rm).

P r o o f. Provided that P0x is continuously dierentiable, then D(t) = dx(P0(t)x(t) t) is so, too. As a reexive generalized inverse with C1-projectors P0(t) = D(t);D(t),R(t) =D(t)D(t); alsoD(t);is continuously dierentiable.

Furthermore, Dx = DP0x belongs to the class C1. Then x 2 CD1 (I Rm) implies

d(x(:) :) =d(D(:);D(:)x(:) :)2C1(I Rn):

It remains to show that P0x is actually C1. Therefore, we investigate the function

K(x y t) :=y;d(x t) x2D y2Rn t2I:

We have K(x(t) y(t) t) = 0, and Kx(x(t) y(t) t) = ;D(t) acts bijectively between imP0(t) and imR(t).

For each t 2 I the equation K(x y t) = 0 provides a solution function (: t) with K((y t) y t) = 0, (y t) = P0(t)(y t), (y t) = (R(t)y t), P0(t)x(t) = (y(t) t). Then the regularity of P0x results from that of , since y(t) is contin- uously dierentiable. 2

For a better understanding let us remark that, in case of d(x t)D(t)x+(t), the equation y;D(t)x;(t) = 0 leads to y = R(t)y and P0(t)x = D(t);y;D(t);, i.e., (y t) =D(t);y;D(t);(t).

For nonlinear DAEs (2.1) satisfying the assumptions of Lemma 4.7, i.e., DAEs with a smooth functiondand an only time-dependent smooth subspaceN0, it is convenient to work with the function space CP10(I Rm) = CD1 (I Rm). (2.1) can be left in the original form or we may take

(d(x(t) t))0 =dx(P0(t)x(t) t)(P0(t)x(t))0 +dt(P0(t)x(t) t):

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14 R. Marz

5 Special systems of circuit simulation

The modi ed nodal analysis (MNA) used in industrial simulation packages gener- ates, for large classes of circuits, systems of the form (cf. EsTi])

Ac(q(A>ce(t) t)0 +bc(e(t) jL(t) jV(t)) = 0 ((jL(t) t))0 +bL(e(t) jL(t) jV(t)) = 0 bV(e(t) jL(t) jV(t)) = 0

9

=

(5.1) where e(t), jL(t), jV(t) denote the nodal potentials and the currents of inductances and the voltage sources, respectively. The functions q(z t) and (w t) are continu- ously dierentiable and the Jacobians qz(z t),w(w t) are positive de nit. With

x:=

0

@

jeL

jV

1

A A~:=

0

@

Ac 0 0 I 0 0

1

A d~(x t) :=

q(A>ce t (jL t)

M(x t) :=

qz(A>ce t) 0 0 w(jL t)

~b(x t) :=

0

@

bc(e jL jV t) bL(e jL jV t) bV(e jL jV t

1

A

it holds that

D~ :=dx=MA~> G0 := ~AD~ = ~AMA~>

imG0 = im ~A kerG0 = ker ~D= ker ~A>:

The matrix G0(x t) has a nullspace N0 that is independent of x and t. Obviously, (5.1) is nothing else but

A~(~d(x(t) t))0+ ~b(x(t) t) = 0: (5.2) If im ~D(x t) is independent of x, then (5.2) has a proper leading term. Because of the constant nullspace N0, Lemma 4.7 is relevant.

If im ~D(x t) changes with x, we can put ~A = ~APA~ in (5.2) and shift the constant projector PA~ with ker PA~ = ker ~A below the derivative. The DAE

A~(PA~d~(x(t) t))0+ ~b(x(t) t) = 0 (5.3) has a proper leading term with constant subspace N0 and ~R = PA~. Here, too, Lemma 4.7 may be applied. Moreover, PA~D~(x t) is also constant now.

On the other hand, we can dierentiate

A~(~d(x(t) t))0 = ~AfM(x(t) t)( ~A>x(t))0 +dt(x(t) t)g and investigate the equation

AM~ (x(t) t)( ~A>x(t))0+ ~b(x(t) t) + ~Adt(x(t) t) = 0: (5.4) If ker( ~AM(x t)) is independent of x, (5.4) represents a DAE with proper leading term. If ker( ~AM(x t)) depends on x, we proceed to

AM~ (x(t) t)PA>~( ~A>x(t))0+ ~b(x(t) t) + ~Adt(x(t) t) = 0: (5.5)

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