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Munich Personal RePEc Archive

Technical Appendix to "Macroeconomic effects of public sector unions"

Vasilev, Aleksandar

AUBG

June 2013

Online at https://mpra.ub.uni-muenchen.de/68235/

MPRA Paper No. 68235, posted 09 Dec 2015 03:02 UTC

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Technical Appendix to ”Macroeconomic effects of public sector unions

Aleksandar Vasilev

December 6, 2015

1 Technical Appendix

1.1 Optimality conditions

1.1.1 Firm’s problem

The profit function is maximized when the derivatives of that function are set to zero.

Therefore, the optimal amount of capital - holding the level of technologyAt and labor input Ntp constant - is determined by setting the derivative of the profit function with respect to Ktp equal to zero. This derivative is

(1−θ)At(Ktp)θ(Ntp)θ(Ktg)ν−rt = 0 (1) where (1−θ)At(Ktp)θ(Ntp)θ(Ktg)ν is the marginal product of capital because it expresses how much output will increase if capital increases by one unit. The economic interpretation of this First-Order Condition (FOC) is that in equilibrium, firms will rent capital up to the point where the benefit of renting an additional unit of capital, which is the marginal product of capital, equals the rental cost, i.e the interest rate.

rt = (1−θ)At(Ktp)θ(Ntp)θ(Ktg)ν (2)

Asst. Professor, American University in Bulgaria, Department of Economics, Blagoevgrad 2700, Bul- garia. E-mail for correspondence: alvasilev@yahoo.com.

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Now, multiply byKtp and rearrange terms. This gives the following relationship:

Ktp(1−θ)At(Ktp)θ(Ntp)θ(Ktg)ν =rtKtp or (1−θ)Yt =rtKtp (3) because

Ktp(1−θ)At(Ktp)θ(Ntp)θ(Ktg)ν =At(Ktp)1θ(Ntp)θ(Ktg)ν = (1−θ)Yt

To derive firms’ optimal labor demand, set the derivative of the profit function with respect to the labor input equal to zero, holding technology and capital constant:

θAt(Ktp)1θ(Ntp)θ1(Ktg)ν −wpt = 0 or wpt =θAt(Ktp)1θ(Ntp)θ1(Ktg)ν (4) In equilibrium, firms will hire labor up to the point where the benefit of hiring an additional hour of labor services, which is the marginal product of labor, equals the cost, i.e the hourly wage rate.

Now multiply both sides of the equation by Ntp and rearrange terms to yield

NtpθAt(Ktp)1θ(Ntp)θ1(Ktg)ν =wtpNtp or θYt =wptNtp (5) Next, it will be shown that in equilibrium, economic profits are zero. Using the results above one can obtain

Πt = Yt−rtKtp−wptNtp =Yt−(1−θ)Yt−θYt= 0 (6) Indeed, in equilibrium, economic profits are zero.

1.1.2 Consumer problem

Set up the Lagrangian

L(Ct, Kt+1p , Ntp; Λt) =E0

X

t=0

(

(Ct+ωGct)ψ(1−Nt)(1ψ) 1α

−1

1−α + (7)

t

"

(1−τl)(wtpNtp+wgtNtg) + (1−τk)rtKtp + +τkδpKtp−(1 +τc)Ct−Kt+1p + (1−δ)Ktp

#)

(4)

This is a concave programming problem, so the FOCs, together with the additional, bound- ary (”transversality”) conditions for private physical capital and government bonds are both necessary and sufficient for an optimum.

To derive the FOCs, first take the derivative of the Lagrangian w.r.t Ct (holding all other variables unchanged) and set it to 0,i.e. LC

t = 0. That will result in the following expression βt

(1−α 1−α

(Ct+ωGct)ψ(1−Nth)(1ψ) α

×

ψ(Ct+ωGct)ψ1(1−Nth)(1ψ)−Λt(1 +τc) )

= 0 (8)

Cancel the βt and the 1−α terms to obtain

(Ct+ωGct)ψ(1−Nt)(1ψ) α

ψ(Ct+ωGct)ψ1(1−Nt)(1ψ)−Λt(1 +τc) = 0 (9) Move Λt to the right so that

(Ct+ωGct)ψ(1−Nt)(1ψ) α

ψ(Ct+ωGct)ψ1(1−Nt)(1ψ)= Λt(1 +τc) (10) This optimality condition equates marginal utility of consumption to the marginal utility of wealth.

Now take the derivative of the Lagrangian w.r.tKt+1p (holding all other variables unchanged) and set it to 0, i.e. LKt+1p = 0. That will result in the following expression

βt (

−Λt+EtΛt+1

(1−τk)rt+1kδp + (1−δp) )

= 0 (11)

Cancel the βt term to obtain

−Λt+βEtΛt+1

(1−τk)rt+1kδp+ (1−δp)

= 0 (12)

Move Λt to the right so that βEtΛt+1

(1−τk)rt+1kδp+ (1−δp)

= Λt (13)

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Using the expression for the real interest rate shifted one period forward one can obtain rt+1 = (1−θ)Yt+1

Kt+1p βEtΛt+1

(1−τk)(1−θ)Yt+1

Kt+1pkδp+ (1−δp)

= Λt (14)

This is the Euler equation, which determines how consumption is allocated across periods.

Take now the derivative of the Lagrangian w.r.t Ntp (holding all other variables unchanged) and set it to 0, i.e. LNp

t = 0. That will result in the following expression βt

(1−α 1−α

(Ct+ωGct)ψ(1−Nt)(1ψ) α

×

(1−ψ)(Ct+ωGct)ψ(1−Nt)ψ(−1) + Λt(1−τl)wtp )

= 0 (15)

Cancel the βt and the 1−α terms to obtain

(Ct+ωGct)ψ(1−Nt)(1ψ) α

(1−ψ)

Ct+ωGct 1−Nt

ψ

(−1) + Λt(1−τl)wpt = 0 (16) Rearranging, one can obtain

(Ct+ωGct)ψ(1−Nt)(1ψ) α

(1−ψ)(Ct+ωGct)ψ(1−Nt)ψ = Λt(1−τl)wtp (17) Plug in the expression for wht, that is,

wpt =θ Yt

Ntp (18)

into the equation above. Rearranging, one can obtain

(Ct+ωGct)ψ(1−Nt)(1ψ) α

(1−ψ)(Ct+ωGct)ψ(1−Nt)ψ = Λt(1−τl)θ Yt

Ntp (19) Transversality conditions need to be imposed to prevent Ponzi schemes, i.e borrowing bigger and bigger amounts every subsequent period and never paying it off.

tlim→∞βtΛtKt+1p = 0 (20)

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1.1.3 The Objective Function of a Public Sector Union: Derivation

This subsection shows that the objective function in the government sector is a generalized version of Stone-Geary monopoly union utility function used in Dertouzos and Pencavel (1981) and Brown and Ashenfelter (1986). The utility function is

V(wg, Ng) = (wg −w¯g)φ(Ng−N¯g)(1φ), (21) where φ and 1−φ are the weights attached to public wage and hours, respectively, and ¯wg and ¯Ng denote subsistence wage rate and hours. Since there is no minimum wage in the model, ¯wg = 0. Additionally, as public hours are assumed to be unproductive, it follows that ¯Ng = 0 as well. Therefore, the utility function simplifies to

V(wg, Ng) = (wg)φ(Ng)(1φ). (22) Doiron (1992) uses a generalized representation, which encompasses (2) as a special case when ρ→0.

φ(Ng)ρ+ (1−φ)(wg−w)¯ ρ 1/ρ

, (23)

when ¯w= 0, the function simplifies to

φ(Ng)ρ+ (1−φ)(wg)ρ 1/ρ

, (24)

Union objective function used in the paper is very similar to Doiron’s (1992) simplified version:

(Ng)ρ+η(wg)ρ 1/ρ

, (25)

can be transformed to

(Ng)ρ+ φ

(1−φ)(wg)ρ 1/ρ

, (26)

Collecting terms under common denominator (1−φ)

(1−φ)(Ng)ρ+ φ

(1−φ)(wg)ρ 1/ρ

, (27)

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Factoring out the common term 1

1−φ 1/ρ

(1−φ)(Ng)ρ+φ(wg)ρ 1/ρ

, (28)

Note that the constant term

1 1φ

1/ρ

>0 can be ignored, as utility functions are invariant to positive affine transformations. After rearranging terms, the equivalent function

V˜ =

φ(wg)ρ+ (1−φ)(Ng)ρ 1/ρ

. (29)

Take natural logarithms from both sides to obtain ln ˜V = 1

ρln

φ(wg)ρ+ (1−φ)(Ng)ρ

. (30)

Take the limit ρ→0

limρ0ln ˜V = lim

ρ0

ln

φ(wg)ρ+ (1−φ)(Ng)ρ

ρ (31)

Apply L’Hopital’s Rule on the R.H.S. to obtain

limρ0ln ˜V = lim

ρ0

∂ρln

φ(wg)ρ+ (1−φ)(Ng)ρ

∂ρ

∂ρ

(32) Thus

ln ˜V = lim

ρ0

φ(wgt)ρlnwg+ (1−φ)(Ng)ρlnNg

/

φ(wg)ρ+ (1−φ)(Ng)ρ

1 (33)

Simplify to obtain

ln ˜V =

limρ0

φ(wgt)ρlnwg+ (1−φ)(Ng)ρlnNg

limρ0

φ(wg)ρ+ (1−φ)(Ng)ρ

= φlnwg + (1−φ) lnNg

φ+ (1−φ) (34)

Therefore,

ln ˜V =φlnwg+ (1−φ) lnNg. (35)

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Exponentiate both sides of the equation to obtain

eln ˜V =eφlnwg+(1φ) lnNg. (36)

Thus

V˜ =eln(wg)φ+ln(Ng)(1φ). (37)

or

V˜ =eln(wg)φ(Ng)(1−φ). (38) Finally,

V˜ = (wg)φ(Ng)(1φ) (39) Furthermore, government period budget constraint serves the role of a labor demand func- tion. Additionally, the public sector demand curve will be subject to shock, resulting from innovations to the fiscal shares. The balanced budget assumption is thus important in the model setup. Since wage bill is a residual, if wage rate is increased, then hours need to be decreased. Additionally, government period budget constraint can be expressed in the form Ng =Ng(wg) as

Ng = τlwpNpk(r−δp)KpcC−Gc−Gi−Gt

(1−τl)wg (40)

Therefore, the problem in the government sector is reshaped in the standard formulation in the union literature:

wmaxg,NgV(wg, Ng) s.t. Ng =Ng(wg) (41)

Since union optimizes over both the public wage and hours, the outcome is efficient. The solution pair is on the contract curve (obtained from FOCs), at the intersection point with the labor demand curve (government budget constraint).

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1.1.4 Public sector union optimization problem

The union solves the following problem:

wmaxtg,Ntg

(Ntg)ρ+η(wgt)ρ 1/ρ

(42) s.t

Gct+Gtt+Git+wgtNtgcCtkrtKtp−τkδpKtl[wptNtp +wgtNtg] (43) Setup the Lagrangian

V(wgt, Ntgt) = max

wgt,Ntg

(Ntg)ρ+η(wgt)ρ 1/ρ

(44)

−νt

Gct +Gtt+Git+wgtNtg−τcCt−τkrtKtpkδpKt−τl[wtpNtp+wtgNtg]

Optimal public employment is obtained, when the derivative of the government Lagrangian is et to zero, i.e V

Ntg = 0 (1/ρ)

(Ntg)ρ+η(wtg)ρ

(1/ρ)1

ρ(Ntg)ρ1−(1−τltwgt = 0 (45) or, when ρ is canceled out and (1−τltwgt put to the right

(Ntg)ρ+η(wgt)ρ

(1/ρ)1

(Ntg)ρ1 = (1−τltwtg (46) Optimal public wage is obtained, when the derivative of the government Lagrandean is et to zero, i.e Vwg

t = 0 (1/ρ)

(Ntg)ρ+η(wtg)ρ

(1/ρ)1

ηρ(wgt)ρ1 −(1−τltNtg = 0 (47) or, when ρ is canceled out and(1−τltNtg term put to the right

(Ntg)ρ+η(wtg)ρ

(1/ρ)1

η(wtg)ρ1 = (1−τltNtg (48) Divide (11.1.46) and (11.1.48) side by side to obtain

(Ntg)ρ+η(wgt)ρ

(1/ρ)1

(Ntg)ρ1

(Ntg)ρ+η(wtg)ρ

(1/ρ)1

η(wtg)ρ1

= (1−τltwtg

(1−τltNtg (49)

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Cancel out the common terms

(Ntg)ρ1

η(wtg)ρ1 = wtg

Ntg (50)

Now cross-multiply to obtain

(Ntg)ρ

η = (wtg)ρ (51)

Hence

wtg = 1

η 1/ρ

Ntg (52)

The wage bill expression, which is obtained after simple rearrangement of the government budget constraint, is as follows

wtgNtg = τcCtkrtKtp−τkδpKtlwptNtp−Gct−Gtt−Git

1−τl (53)

Use the wage bill equation and the relationship between public wage and employment in order to obtain

wtg1

τcCtkrtKtp−τkδpKtlwtpNtp−Gct−Gtt−Git 1−τl

12

(54) and

Ntg1

τcCtkrtKtp−τkδpKtlwptNtp−Gct −Gtt−Git 1−τl

12

(55)

(11)

1.2 Log-linearized model equations

1.2.1 Linearized market clearing

ct+kpt+1+gtc+gti−(1−δp)kpt = yt (56) Take logs from both sides to obtain

ln[ct+kpt+1+gtc+gti−(1−δp)ktp] = ln(yt) (57) Totally differentiate with respect to time

dln[ct+kpt+1+gtc+gti−(1−δp)ktp]

dt = dln(yt) (58)

[ 1

c+gc +gipkp][dct dt

c c +dgct

dt g g + dgti

dt gi

gi + dkt+1p dt

kp

kp −(1−δp)dkpt dt

kp

kp] = dyt dt

1

y (59) Define ˆz = dzdtt1z. Thus passing to log-deviations

1

y[ˆctc+ ˆgtcgc + ˆgitgi + ˆkt+1p kp−(1−δp)ˆkptkp] = ˆyt (60) ˆ

ctc+ ˆgtcgc + ˆgitgi + ˆkt+1p kp−(1−δp)ˆkptkp = yˆyt (61) kpˆkpt+1 = yˆyt−cˆct−gcˆgtc−giˆgti+ (1−δp)kppt (62) 1.2.2 Linearized production function

yt = at(kpt)1θ(npt)θ(kgt)ν (63) Take natural logs from both sides to obtain

lnyt = lnat+ (1−θ) lnktp+θlnnpt +νlnkgt (64) Totally differentiate with respect to time to obtain

dlnyt

dt = dlnat

dt + (1−θ)dlnkpt

dt +θdlnnpt

dt +νdlnkgt

dt (65)

1 y

dyt

dt = 1 a

dat

dt +1−θ kp

dkpt dt + θ

np dnpt

dt + ν kg

dktg

dt (66)

Pass to log-deviations to obtain

0 = −yˆt+ (1−θ)ˆkpt + ˆat+θnˆpt +νkˆtg (67)

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1.2.3 Linearized FOC consumption

[(ct+ωgtc)ψ(1−nt)(1ψ)]αψ(ct+ωgtc)ψ1(1−nt)(1ψ) = (1 +τct (68) Simplify to obtain

ψ(ct+ωgtc)ψ1αψ(1−nt)(1α)(1ψ) = (1 +τct (69) Take natural logs from both sides to obtain

lnψ(ct+ωgtc)ψ1αψ(1−nt)(1α)(1ψ) = ln(1 +τc) + lnλt (70) ln(ct+ωgtc)ψ1αψ(1−nt)(1α)(1ψ) = ln(1 +τc) + lnλt (71) (ψ−1−αψ) ln(ct+ωgtc) + (1−α)(1−ψ) ln(1−nt) = ln(1 +τc) + lnλt (72) Totally differentiate with respect to time to obtain

(ψ−1−αψ)dln(ct+ωgtc)

dt + (1−α)(1−ψ)dln(1−nt)

dt =

= dln(1 +τc)

dt +dlnλt

dt (73)

(ψ−1−αψ) 1

c+ωgc(dct

dt +ωdgtc

dt ) + (1−α)(1−ψ) −1 1−n

dnt

dt = dλt

dt 1

λ (74) (ψ−1−αψ)

c+ωgc dct

dt c

c +ω(ψ−1−αψ) c+ωgc

dgtc dt

gc gc +

−(1−α)(1−ψ) 1 1−n

dnt dt

n

n = dλt dt

1

λ (75)

c(ψ−1−αψ)

c+ωgct+ ωgc(ψ−1−αψ)

c+ωgctc−(1−α)(1−ψ) n

1−nnˆ = ˆλt (76) Since

ˆ

n = np

np+ngˆnp+ ng

np+ngg = np

n nˆp+ ng

nnˆg, (77)

and consumers choose np only, pass to log-deviations to obtain c(ψ−1−αψ)

c+ωgct+ ωgc(ψ−1−αψ)

cc+ωg gˆtc−(1−α)(1−ψ) n 1−n

np

np +ngˆnp = ˆλt (78) Since n=np +ng, it follows that

c(ψ−1−αψ)

c+ωgc ˆct+ωgc(ψ−1−αψ)

c+ωgc ˆgtc−(1−α)(1−ψ) np

1−nnˆp = 0 (79)

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1.2.4 Linearized no-arbitrage condition for capital

λt = βEtλt+1[(1−τk)rt+1kδp+ (1−δp)] (80) Substitute out rt+1 on the right hand side of the equation to obtain

λt = βEtt+1((1−τk)(1−θ)yt+1

kt+1pkδp+ 1−δp)] (81) Take natural logs from both sides of the equation to obtain

lnλt = lnEtt+1((1−τk)(1−θ)yt+1

kt+1pkδp+ 1−δp)] (82) Totally differentiate with respect to time to obtain

dlnλt

dt =

dlnEtt+1((1−τk)(1−θ)ykt+1p

t+1kδp+ 1−δp)]

dt (83)

1 λ

t dt =Et

( 1

λ((1−τk)(1−θ)kyp + 1−δpkδp ×

"

((1−τk)(1−θ)y

kpkδp + 1−δp)dλt+1

dt λ λ +λ(1−τk)(1−θ)

kp

dyt+1

dt y y −

λ(1−τk)(1−θ)y (kp)2

dkt+1p dt

kp kp

#)

(84) Pass to log-deviations to obtain

λˆt=Et (

λˆt+1+

(1−τk)(1−θ)y ((1−τk)(1−θ)kyt+1p

t+1kδp+ 1−δp)kpt+1

− (1−τk)(1−θ)y ((1−θ)ykt+1p

t+1kδp+ 1−δp)kpt+1p )

(85) Observe that

(1−τk)(1−θ)yt+1

kt+1pkδp+ 1−δp = 1/β (86) Plug it into the equation to obtain

λˆt = Et

λˆt+1+β(1−τk)(1−θ)y

kpt+1− β(1−τk)(1−θ)y kp ˆkpt+1

(87)

λˆt = Etλˆt+1+β(1−τk)(1−θ)y

kp Ett+1− β(1−τk)(1−θ)y

kp Etˆkt+1p (88)

(14)

1.2.5 Linearized MRS

(1−ψ)(ct+ωgtc) = ψ(1−nt)(1−τl) (1 +τc)θyt

npt (89)

Take natural logs from both sides of the equation to obtain ln(1−ψ)(ct+ωgtc) = lnψ(1−nt)(1−τl)

(1 +τc)θyt

npt (90)

ln(ct+ωgct) = ln(1−nt) + lnyt−lnnpt (91) Totally differentiate with respect to time to obtain

dln(ct+ωgtc)

dt = dln(1−nt)

dt +dlnyt

dt −dlnnpt

dt (92)

1

c+ωgc(dct

dt +ωdgtc

dt ) = − 1 1−n

dnt dt + 1

y dyt

dt − 1 np

dnpt

dt (93)

1 c+ωgc

dct

dt c

c+ ω c+ωgc

dgtc dt

gc

gc = − 1 1−n

dnt

dt n n + 1

y dyt

dt − 1 np

dnpt

dt (94)

c c+ωgc

dct dt

1

c + ωgc c+ωgc

dgct dt

1

gc = − n 1−n

dnt dt

1 n + 1

y dyt

dt − 1 np

dnpt

dt (95)

Pass to log-deviations to obtain c

c+ωgct+ ωgc

c+ωggˆct = − n

1−nnˆ+ ˆyt−nˆpt (96) Since

ˆ

n= np

np+ngp+ ng

np+ngg, (97)

and noting that consumers are only choosing np, then c

c+ωgct+ ωgc

c+ωgcˆgtc = − n 1−n

np

np+ngˆnp+ ˆyt−nˆpt (98) c

c+ωgct+ ωgc

c+ωgcˆgtc = − n 1−n

np

np+ngˆnp+ ˆyt−nˆpt (99) c

c+ωgcˆct+ ωgc

c+ωgctc = −

1 + n 1−n

np np+ng

ˆ

np+ ˆyt (100) Since n=np +ng, it follows that

c

c+ωgcˆct+ ωgc

c+ωgcct = −

1 + np 1−n

ˆ

np+ ˆyt (101) c

c+ωgcˆct+ ωgc

c+ωgcˆgtc+

1 + np 1−n

ˆ

np−yˆt = 0 (102)

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1.2.6 Linearized private capital accumulation

kt+1p = it+ (1−δp)ktp (103) Take natural logs from both sides of the equation to obtain

lnkpt+1 = ln(it+ (1−δp)ktp) (104) Totally differentiate with respect to time to obtain

dlnkpt+1

dt = 1

i+ (1−δp)kp

d(it+ (1−δp)ktp)

dt (105)

Observe that since

i=δpkp, it follows that i+ (1−δp)kppkp+ (1−δp)kp =kp. Then (106) dkt+1p

dt 1

kp = 1 kp

dit dt i

i + kp i+ (1−δp)ktp

dkpt dt

kp

kp (107)

Pass to log-deviations to obtain

ˆkpt+1 = δpkp

kp ˆit+ (1−δp)kp

kppt (108)

t+1p = δpˆit+ (1−δp)ˆktp (109) 1.2.7 Linearized government capital accumulation

kgt+1 = gti+ (1−δg)kgt (110) Take natural logs from both sides to obtain

lnkt+1g = ln(gti+ (1−δg)kgt) (111) Totally differentiate with respect to time to obtain

dlnkt+1g

dt = 1

gi+ (1−δg)kg

d(git+ (1−δg)ktg)

dt (112)

Observe that since

gigkg, (113)

(16)

it follows that

gi+ (1−δg)kggkg+ (1−δg)kg =kg. (114) Hence,

dkt+1g dt

1 kg = 1

kg dgit

dt gi

gi + kg x+ (1−δg)

dkgt dt

kg

kg (115)

Pass to log-deviations to obtain

t+1g = δgkg

kg ˆgti+(1−δg)kg

kg ˆktg (116)

Cancel out the kg terms to obtain

ˆkgt+1 = δgˆgti+ (1−δg)ˆktg (117) 1.2.8 Public wage rate rule

wgt1

τcctkrtktp−τkδpkptlwtpnpt −gct−gtt−gti 1−τl

12

(118) Take logs from both sides to obtain

lnwgt =− 1

2ρlnη− 1

2ln(1−τl) + 1

2ln

τcctkrtktp−τkδpktplwtpnpt −gct −gtt−gti

(119) Totally differentiate with respect to time to obtain

dlnwgt dt = 1

2 d dtln

τcctkrtktp−τkδpktplwtpnpt −gct −gtt−gti

(120) Observe that

τkrtkpt −τkδpktlwtpnptk(1−θ)ytlθyt−τkδpkpt =

=

τk(1−θ) +τlθ

yt−τkδpktp (121) Also

(1−τl)wgngcc+ [τk(1−θ) +τlθ]y−τkδpkp−gc−gi−gtt (122)

(17)

Thus dwtg

dt 1 wg = 1

2

1 (1−τl)wgng

τcdct

dt + [τk(1−θ) +τlθ]dyt

dt −τkδpdkpt dt − dgtc

dt − dgti dt − dgtt

dt

(123) dwtg

dt 1 wg = 1

2

1

(1−τl)wgng ×

τcdct

dt c c+

τk(1−θ) +τlθ dyt

dt y

y −τkδpdktp dt

kp kp − dgtc

dt gc gc − dgti

dt gi gi − dgtt

dt gt gt

(124)

dwtg dt

1

wg = (1/2)τcc (1−τl)wgng

dct

dt 1 c +

(1/2)

τk(1−θ) +τlθ

y (1−τl)wgng

dyt

dt 1 y

−(1/2)τkδpkp (1−τl)wgng

dktp dt

1

kp − (1/2)gc (1−τl)wgng

dgct dt

1 gc

− (1/2)gi (1−τl)wgng

dgit dt

1

gi − (1/2)gt (1−τl)wgng

dgtt dt

1

gt (125)

Pass to log-deviations to obtain

ˆ

wgt = (1/2)τcc (1−τl)wgngt+

(1/2)

τk(1−θ) +τlθ

y (1−τl)wgngt

−(1/2)τkδpkp

(1−τl)wgngˆkt− (1/2)gc

(1−τl)wgngct − (1/2)gi

(1−τl)wgngˆgti− (1/2)gt

(1−τl)wgngtt (126) 1.2.9 Public hours/employment rule

ngt = η1ρwgt (127)

Take logs from both sides to obtain

lnngt = 1

ρlnη+ lnwgt (128)

Totally differentiate both sides to obtain dlnngt

dt = dlnwgt

dt (129)

dngt dt

1

ng = dwgt dt

1

wg (130)

Pass to log-deviations to obtain

ˆ

ngt = wˆtg (131)

(18)

1.2.10 Total hours/employment

nt = ngt +npt (132)

Take logs from both sides to obtain

lnnt = ln(ngt +npt) (133)

Totally differentiate to obtain

dlnnt

dt = dln(ngt +npt)

dt (134)

dnt

dt 1 n =

dngt

dt + dnpt dt

1

n (135)

dnt

dt 1 n =

dngt dt

ng

ng + dnpt dt

np np

1

n (136)

dnt dt

1

n = dngt dt

1 ng

ng

n + dnpt dt

1 np

np

n (137)

Pass to log-deviations to obtain ˆ

nt = ng

n nˆgt +np

n nˆpt (138)

1.2.11 Linearized private wage rate

wpt =θyt

npt (139)

Take natural logarithms from both sides to obtain

lnwtp = lnθ+ lnyt−lnnpt (140) Totally differentiate with respect to time to obtain

dlnwpt

dt = dlnθ

dt +dlnyt

dt −dlnnpt

dt (141)

Simplify to obtain

dwpt dt

1

wp = dyt

dt 1

y − dnpt dt

1

np (142)

Pass to log-deviations to obtain

ˆ

wpt = ˆyt−nˆpt (143)

(19)

1.2.12 Linearized real interest rate

rt=θyt

kpt (144)

Take natural logarithms from both sides to obtain

lnrt = lnθ+ lnyt−lnktp (145) Totally differentiate with respect to time to obtain

dlnrt

dt = dlnθ

dt +dlnyt

dt − dlnktp

dt (146)

Simplify to obtain

dr dt

1 r = dyt

dt 1 y − dktp

dt 1

kp (147)

Pass to log-deviations to obtain

ˆ

rt = ˆyt−ˆktp (148)

1.2.13 Public/private wage ratio

rwt = wgt/wpt (149)

Take logs from both sides of the equation

lnrwt = lnwtg−lnwpt (150)

Totally differentiate to obtain

dlnrwt

dt = dlnwtg

dt −dlnwpt

dt (151)

drwt

dt 1

rw = dwgt dt

1

wg − dwtp dt

1

wp (152)

Pass to log-deviations to obtain

ˆ

rwt = wˆgt −wˆpt (153)

(20)

1.2.14 Public/private hours/employment ratio

rlt = ngt/npt (154)

Take logs from both sides of the equation

lnrlt = lnngt −lnnpt (155)

Totally differentiate to obtain

dlnrlt

dt = dlnngt

dt − dlnnpt

dt (156)

drlt

dt 1

rl = dngt dt

1

ng −dnpt dt

1

np (157)

Pass to log-deviations to obtain

rlˆt = ˆngt −nˆpt (158)

1.2.15 Linearized technology shock process

lnat+1 = ρalnatat+1 (159) Totally differentiate with respect to time to obtain

dlnat+1

dt = ρa

dlnat

dt +dǫat+1

dt (160)

dat+1

dt = ρadat

dt +ǫat+1 (161)

where for t = 1 dtat+1 ≈ ln(eǫat+1/eǫa) = ǫat+1−ǫaat+1 since ǫa = 0. Pass to log-deviations to obtain

ˆ

at+1 = ρaˆatat+1 (162)

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