0
Date
r s t
s;t I
00
00
0
00
2
00 ULRICH ERLENMAIER
: Septemb er1997.
fj 0 j^j 0 j 2 g
fj 0 j^j 0 j g
2
f g
fj 0 jg
U I a;b
! U;I
U I
! U;I U r U s U s U t r;s;t I :
U
U
U r U s U s U t r;t
r s t I > >
K K ;
! U;I >
K
a;b :
U U
Z
! U;I U s U t
! U;I ! U;I ! U;I Z
f Abstract.
Correspondence to: Ulrich Erlenmaier, Institut f ur Angewandte Mathematik,
Universitat Heidelb erg, Im Neuenheimer Feld 294, D-69120 Heidelb erg, Germany;
uerlenma@p opix.urz.uni-heidelb erg.de
Let b e an arbitrary sto chastic pro cess on the real line and = [ ]an
interval onIR. We proveasto chasticinequality forthemo dulus of continuity ( )of
on :
( ):= sup ( ) ( ) ( ) ( ) :
Supp ose that hasrighthand (orlefthand)continuouspaths and that theincrementsof
can b e sto chastically b ounded in thefollowing way:
IP ( ) ( ) ( ) ( ) (] ])
forall ,forall 0,with a realnumb er 0 and asetfunction whichis
subadditive in a certainsense. Thenexists aconstant = ( )with:
IP ( ) (] ])
Ifin additionthepathsof arecadlag and thejumps of can b eb oundedbyarandom
variable wecanextendthisresulttoasto chasticinequalityforthemo dulusofcontinuity
( ):= sup ( ) ( )
using that ( )isb ounded in thefollowing way: ( ) 4 ( )+ .
Thisresultisusedtoprovetheweakconvergenceofa go o dness-of-tteststatisticforhy-
p othesesab outtheconditional medianfunction ofastationary,real-valued, Markovian
timeseries.
1.
0 1
X
0 1
0 0
0 0
2
Introduction
L 0 j
p f g 0
j 0 j
1
=1
0 1 1
0
=1
1 1
IR
1
0 t
n
t
t s
t t t
n
n
t
t t t
n
s;t
n n
n
n n n
n X
X X s <t
X f X X t ;::: ;n
f f
W s;f
n
X s X f X
T f W s;f W t;f :
T f
X
W W s W s;f
T f This pap er is concerned with stationary, real-valued, Markovian time series with
stationary transition probabilities. Let ( ) b e such a timeseries. The median
functionoftheconditionallawof given ( : )isimplicitlydenedthrough
the following condition:
Med ( ( ) ) =0 ( =1 )
Weprop ose aKuip ertyp estatisticto testthe hyp otheses = . Itisbasedon the
pro cess
( ):=
1
1 sign ( )
and has the following form:
( ):= sup ( ) ( )
The test willreject the hyp otheses if ( ) is to o large.
In a simular context Hong-zhi and Bing (1991) have intro duced a Kolmogorov-
Smirnov typ e statistic to test hyp otheses ab out the conditional mean function.
But for the weak convergence of their statistic they need quite restrictive mixing-
prop erties of the time series and also (4+ )-moments of . In my opinion the
assumptions that are made here are muchweaker. The idea of the pro of of tight-
ness is dierent and is due to Koul and Stute (1996). In their pro of seems to b e a
gapwhich -undersomeslightly stronger assumptions-is closedhere generalizinga
result ofBillingsley (1969, pp.98).
In section2 we formulatethis generalizationand show how it can b e used to prove
tightness. In section 3 we apply this metho d to show the weak convergence of the
pro cess () with ( ) := ( ) under some quite weak assumptions. By
the Continuos MappingTheoremthis resultimpliesthe weakconvergenceof ( ).
2.
1 2
1 2
00
00
00
00
Denition 1.
r s t
s;t
A
A
A
b b
b b
A
A Tightness Criterion
fj 0 j^j 0 j 2 g
D
fj 0 j 2 g
0 2
I
I f 2 g
I 2
I A
!
U A
! U;A U r U s U s U t r;s;t A
! U
! U;A U s U t s;t A
! U;a
! U;A
U s U t s;t I
A
I a;b a;b A
I a;c b A a < b < c
I ;I I
I a;b I b;c
J d;e I J c d
(intervals in with coordinates in A)
The set of all left open intervals with coordinates in will be denoted by :
For be an interval in . For every with we dene a
subdivision ( of by:
and
Let be another interval in . and are called neighbours if . In this section we formulate a Prop osition that generalizes a result of Billingsley.
Given an arbitrary subset of IR we want to state conditions under whichwe can
get a sto chastic inequationfor the mo dulus of continuity ofa sto chastic pro cess
on . It isdened inthe following way:
( ):= sup ( ) ( ) ( ) ( ) :
If weak convergence is studied in the context of the function space with the
Skohoro d-top o logy such inequations for ( ) are needed to prove tightness (see
Billingsley,pp.109). Within the theorythat isused here (seePollard1990) wehave
to treat with the following mo dulusof continuity:
( ):=sup ( ) ( ) :
The sto chastic inequation for ( ) will b e concluded from the inequality for
( ).
In order to formulate the conditions on the increments ( ) ( ) ( ) that
we need forthe Prop osition we haveto makesomeprep erations:
IR
:= =] ]:
:=] ]
)
:=] ] :=] ]
:=] ] =
0
00
1 2
1 2
U A
U
U
A
A A
A
A
b b
b b
A
A
Denition 2.
Denition 3.
Proposition 1.
I !
0
I
M I f I ! 1 g
2 I
2 I
2 M I
fj j^j j g [ g
2I
f g
U
U
I a;b U b U a
U I I
<
B;C B C
B C
M M <
I I > I ;I I
I I M I
A a
b U A
M < M
>
U I U J I J >
I;J :
KM;
! U;A
KM;
a;b
:
IR =] ] ( ) ( )
( ):= ( )
( ):= : IR: 0 ;
( ) ( )
1
( ) 0 ( )
( )+ ( ) ( )
Now we can state the Prop osition:
1 ( )
0
IP ( ) ( ) ( ) 0
( )
IP ( )
( )
(] ]) ( as distribution function of a set function)
One can think of theincrements of as a signed, additive set function
which maps intervals to . In order to simplify notation we
write .
(M - subadditive set functions)
Correspondingtothe signed set functions we neednonnegative nondecreasing set
functions on :
nondecreasing
There a set function is called nondecreasing if for arbitrary sets
implies .
Let now be a real number, . A set function is called M - subadditive if
for every interval with there exists a subdivision of so
that the following holds:
Let bea nitesubset ofthereal line withsmallest element and
largest element . Further let be a stochastic process on . Suppose that there
exists a real number , a -subadditive set function and a real
number which satise
for all
for all neighbouring intervalls
Then exists a constant with:
0 1
00
2 2 2
00
00
00
00 Remark1.
Remark2.
Remark3.
l A i A;i<l i A;i l
n
m
m
m
m
m m m m m m m
m
1 1
1
j 0 j_ j 0 j
f g
f
0
g
2
j 0 j^j 0 j
2 # # #
>
! !
! U;A U i U a U b U i
W
I a;b
U I U
I
! U;I >
KM;
a;b
KM;
U
I I
I a
i b a
i
> r<s<t I
! U;I U r U s U s U t
r;s;t r ;s ;t I r r;s s;t t
U ! U;I
()= ()
1 ()
~
~( ):=min max ( ) ( ) max ( ) ( )
=[ ]
IP ( )
( )
(] ])
( )
W.l.o.g. let have righthand continuous paths. We cho ose the following
dyadic subsets of :
:= +
( )
2
: 0 2
For every 0 we nd real numb ers with:
( ) ( ) ( ) ( ) ( ) +
Now we can approximate by elements : .
Using the righthand continuity of the paths of we nd therefore that ( ) In Billing sley's result there is a m ore restrictive condition on the set
function , namely,that:
with a real number and a nite measure .
It follows immediately fromthe proof that the statement of the Propo-
sition remains if we replace the functional by the functional which is dened
in the following way:
We will use this fact in one part of the proof of tightness for the process .
Let bean arbitraryinterval onthe real line. Suppose that the
pathsof arerighthand (or lefthand) continuous on and fulllls the conditions
of the Proposition on every nite subset of . Then the following inequality holds:
with the same constant as above.
Proof.
1
2 Remark4.
m
m
m
m
m
m
cadlag
cadlag
s s
t s
1 2
1 1
2 2
1 2 1 2
1 2
1 2
2 2
2 1
1 2 1 1 1 1 1 2
00
!1 00
!1 00
!1
00
00
00
00
00 00
00 00
00
0 0
0 0
f g f g
f g
f g
F f ! g
F
2
f 2 j 0 j g
f 2 j 0 j g
j 0 j j 0 j
j 0 j j 0 j j 0
j
j 0 jj 0 j j 0 j
j 0 j j 0 0 j j 0 0 j j 0 j
! U;I > ! U;I >
! U;I >
! U;I >
KM;
a;b
I a;b
I f I f
U I U
I Z
! U;I ! U;I Z
s <s I
I U s U s ! U;I
I U t U s ! U;I
< s;t s <t <
U s U s > ! U;I U t U s > ! U;I :
U s U s >! U;I U s U s ! U;I U s
U t ! U;I
U t U s U t U s U s U s ! U;I
U s U s U s U U U U U s
! U;I Z
For anarbitrary interval on we dene:
is righthand continuous and has existing lefthand limits
Suppose that the paths of are elements of and that the jumps of are
bounded uniformly on by a randomvariable .
Then we can conclude:
Proof.
Theoremwe can conclude:
IP ( ) =IE1 lim ( )
=IE lim 1 ( )
= lim IE1 ( )
( )
(] ])
=[ ] IR
( ):= : IR:
( )
( ) 4 ( )+
For arbitrary we dene:
:=sup : sup ( ) ( ) 2 ( )
:=inf : sup ( ) ( ) 2 ( )
If , then there existreal numb ers ( ) with:
( ) ( ) 2 ( ) and ( ) ( ) 2 ( )
But from ( ) ( ) ( )follows ( ) ( ) ( ) and ( )
( ) ( ). Thereforewecan conclude:
( ) ( ) ( ) ( ) + ( ) ( ) 2 ( )
which contradicts the assumption made ab ove and hence implies that .
Finallyweget:
( ) ( ) ( ) ( ) + ( ) ( +) + ( +) ( )
4 ( )+
W
t
1 3.
K K
P
P
p
2
0
1
01
0
IR
1
=0
1
+
=
q
q
c
c
x c
n
n
t X
n
n w
t
c
i
g
g
n
g Remark5.
K
K
K
K
K K
Theorem1.
1 1
!
j j
1
01 1
j 0 j
2 01 1
1
01 1
^
Weak Convergence of the Process
U
n
P ;
P A P A;x
A P =n
W
P P P
X
> P I I I
P i;i <
;
s;t g s g t g
g t > t ; ;
W
; ;
W Ks;t F s t F
There isalsoa multidimensional version of this Proposition,thatdeals
with stochastic processes on nite subsets of . It can in a simulare way be
extended to nonnite subsets of the (see Erlenmaier 1997).
Iftheconditions 1- 3aresatised, thesequence of stochas-
tic processes on convergesweakly toa pathwise uniformlycontinuous,
centered Gaussian process with covariance function , where IR
IR
We denote by ( )the kernelof the stationary transition probability of the time
series and dene:
( ):=sup ( )
for allmeasurable sets IRand
^
:=1 .
Now we are able to state the conditions under which the pro cess converges
weakly:
1
^
(in probability) where is the stationary measure of the time
series ( )
2 Thereexistsarealnumb er 0sothat ( ) forallintervalls IR.
3 ([ +1])
Condition 1 is needed for the convergence of the nite-dimensional distributions
(dis), 2 and 3 willb eused to prove tightness.
The pro of of tightnessuses a functional CLT (seePollard 1990). In order to apply
this Theoremwe rst of allhave to dene a pseudometric on [ ]. Wewrite
( ) := ( ) ( ), where is a continuously dierentiable function on the
compact real line with ( ) 0 for every IR. That implies that ([ ] )
isa totally b ounded pseudometricspace.
()
([ ] )
( ):= ( )
K
K K
X
2 3
2 2
2
0
0
0
K
Corollary 1.
Remark6.
0
IR [01]
[01]
=1
1
=1
0
=0
2
1
1
1
! j 0 j j 0 j
j 0 j
p
f g
j 1 2
p
p f 2 gj j
n w
s;t s;t ;
s;t ;
n;Z
n
t
t n;t
n;t n
t
t n
t
n;t
n;t t
n;Z
n
t n
t n;t
W
I
B
;
T f W s W t B F s B F t
B s B t
W s
n
X s Z
Z
X ;:::X
Z
Z X K < n t ;:::;n
W = n
I
Z X I Z
IR
The convergenceofthedis follows fromcondition 1andthe CLTfor mar-
tingaledierencearrays(seePollard1984). Thepro ofofthesto casticequicontinuity
isdefered to section4.
[0 1]
( ) sup ( ) ( ) = sup ( ( )) ( ( ))
= sup ( ) ( )
( ):=
1
1
( )
( )
IE IN; =1
Mostoftheargumentationisidentical. Theonlydierenceis,thatthejumps
of their pro cess cannot b e b ounded by 1 . But it is sucient to observe
that on an interval they are b oundedby
:= max 1
1
If condition 3 isnot satised at least the sequence converges to on every nite
intervall .
Proof.
If 1 - 3 hold the Continuous Mapping Theoremimpliesthe weak
convergence of the teststatistic to a functional of the standard Brownian motion
on :
in law
Thestochasticequicontinuityof themoregeneralmarkedempiricalpro-
cesses
whichKoulandStuteinvestigate insection3oftheirpapercanbeprovedinasimilar
way. There the series of randomvariables forma martingale dierence
arraywith respect to the series of -algebra (for details see Koul
and Stute 1996). The assumption about the randomvariable can be replaced by
the weaker assumption:
for all a.s
Proof.
. 4.
X
X
2 3
Some Proofs
0
0 0
00
=1
1
=1 2
1
2
1
2
1 1
1 Proof of Proposition 1
n
n
t
t n;t
n
t
t
n;t t
i
l m i<l i
l i m
m i
f g
fp
f 2 gj j g
f 2 g j
f g
j 0 j_ j 0 j
0
0
Z
n
X I Z
n
X I Z X
K P I
A ;:::;m U U i
i ;::: ;m
! U
! U U U U U
! U ! U
!
m
m ; ! m m
h ;h h ;m M ;m
Thereforewecan conclude:
IP IP
1
1
1
IE1 IE
1
( )
Therefore in this context we end up with the same tightness result as in the pro of
of Theorem1.
Withinsomepro ofs therearestatementswhich-forthesakeofclearity-arepro ofed
afterthe mainargumentationis nished.
In most partsof thepro of we followthe argumentation
of Billingsley(1968).
W.l.o.g. supp ose that = 1 . In the following we write := ( )
( =1 ).
First of allwe recall the denition of ~( ):
~( ):= min max max
The following inequality ispro ofed b elow:
( ) 2~( ) (4.1)
Therefore itis sucientto show the result of the prop osition for ~. We do this by
induction over .
For =1 2 ~ equals0. Hereis the induction step from 1to :
Cho ose an integer which satises (]1 1])+ (] +1 ]) (]1 ]) and
dene
1
1
.
.
00
00
0
0
1 2 1 2
1 2
1 1
2
1
+2
2
+2
( +2)
+2 1
1 1
1 1 +1
1 1
r s s t
=
r s r s
s t s m m t
h m h
h
Proof of inequality 4.1
Proof of inequality 4.2
j 0 j^j 0 j
0 _ 0 _ 0 _
_
f g f _ g f g
f g f g f g
0
0
j 0 jj 0 j j 0 j
j 0 jj 0 j j 0 j
j 0 j j 0 j
j 0 j
j 0 j
! Y ! Z
r;s;t U U U U
B ;h ;m ;h ;h h ;h ;m ;h ;m
! U ! Y ! Z B
; > =
! U ! Y ! Z B
! Y ! Z B
KM;
;h h ;m
a;b
KM;
M a;b
a;b
a;b
MKM;
KM; = M
! ! r;s;t
! l
!
U U U U U U ! l>r;s
U U U U U U ! l s;t
U U B U U B
U U >B
U U >B
Later on we want to apply the induction hyp otheses to ~( ) and ~( ). Now we
dene ( ):= and nally
:= (1 1 ) (1 1 +1) ( 1 +1 ) (1 +1 )
to conclude:
~( ) ~( ) ~( )+2 (pro ofed b elow) (4.2)
Let 0b earbitrarynumb erswith + =1and dene :=1 (1+ ). From
condition (a) and induction hyp otheses follows:
IP ~( ) IP ~( ) ~( ) +IP 2
IP ~( ) +IP ~( ) +IP
2
( )
(]1 1])+ (] +1 ]) + 2
(] ])
( )
(] ]) + 2
(] ])
(] ])
( ) +2
Cho osing ( ):=2 (1 ) completesthe pro of.
We have to show that 2~. Let b e the
integers that minimize the expression for and the one that maximizes the
expressionfor ~. We observe:
+ 2~ ( )
+ 2~ ( )
We distinguish the followingthree cases
a) und
b)
c)
.
0 0
0 0
0 0
0 0
Proof of Theorem 1 1
1
1 2 1 2
1 1
1 1 1 1 1
+1 +1 2
2
1 +1 1
1 1
1 1 1
1 1 +1 +1 2
2
0
0
0 0
i<l i
l i m
m i
i
i i h h
m i m h h i
m i
m h h h
i
m i m h h i
m i m h h h h i
m i
n g
k k ;m
m
m
m
m
j 0 j_ j 0 j _
j 0 j
j 0 j j 0 j j 0 j
j 0 j j 0 j j 0 j
j 0 j
j 0 j j 0 j
j 0 j
j 0 j j 0 j j 0 j
j 0 j j 0 j j 0 j j 0 j
j 0 j
f j g
0
f
0
g
l
U U U U ! Y ! Z B
l h l l l l l l
! Y ! Z
U U ! Y i<l
U U U U U U ! Y B l i<l h
U U U U U U B ! Z h l i<l
U U ! Z l i m
U U B U U B
U U ! Y i<l l
U U U U U U ! Y B l l i<h
U U U U U U U U B ! Z h i<l
U U ! Z l i m
n
>
! W ; > n n
I k ;k I
k ; ;::: m ; ::: I a;b
I
I a
i b a
i In eachcase wewantto cho ose a numb er which satises
max max ~( ) ~( )+2
In case a) we can cho ose = , in b) = and in case c) = , where and
are supp osed to b e the integers that minimizethe expressions for ~( ) and ~( )
resp ectively. Imcase a) we provethis by the followinglines:
~( ) (1 )
+ ~( )+ ( = )
+ +~( ) ( = )
~( ) ( )
Case b)implies:
and
Now we can argue as ab ove:
~( ) (1 = )
+ ~( )+ ( = )
+ + 2 +~( ) ( )
~( ) ( )
Case c)can b e treatedsimularly.
We have to show that there is an integer and a real
numb er 0 so that the following holds:
IP ( ) if and
Firstofallwedeneintervals :=[ 1 ]and niteapproximations ofthem
( = 1 2 ; = 1 2 ) , where for an arbitrary intervall = [ ] its nite
approximation is denedas follows:
:= +
( )
: 0 2
00 00
00
1
00
X
X X
X p
X
p
X
X X
X
p +1
= +2
4
= +2 = +2
= +2
2
= +2
+1
= +2
= +1 = +2
4
4
= +2
0
2 2
j 0 j
f g
0
j 0 j j 0 j
0
0
f g f g
f g
f g f j 0 j g
f g f j 0 j g
1
0
2
f 1 g 8 2
l
n l;m
a k l
n k ;m
l
k a n
n k ;m
l
k a n
l
k a
n
l
k a
n
l
k a
n l n l;m
n
n l;m
a k l
n k ;m
l
k a n
l
k a
n k ;m
l
k a n
k a
n
a;l l >a J a;l n;m
! W ;J ! W ;I W k ;k
! W ;I
KP k ;k
K
W k ;k W k ;k
W k ;k
P k ;k
! W ;J > ! W ;J
W
! W ;J
! W ;I
W k ;k
! W ;I
W k ;k
KP a;
P k ;k
n;m
W
a
! W ; a ; = n;m
With IN ( ) and :=[ ] one can show for all IN:
~( ) max ~( ) + (] 1 ]) (pro ofed b elow)
(4.3)
and
IP ~( )
(] 1 ])
(pro ofed b elow) (4.4)
with auniversal constant . If we use that
IE (] 1 ]) = IE (] 1 ])
IE (] 1 ])
= (] 1 ])
we can conclude:
IP ( ) IP ( )
(b ecause has cadlag paths)
IP 2~( )
(seeinequality 4.1)
IP max ~( )
4
+IP (] 1 ])
4
IP ( )
2
+IP (] 1 ])
2
4 (] ])
+ 4
(] 1 ])
for all IN.
Togetherwith thefact, thatthe pathsof has only aniteamountofvaluesthis
impliesthat wecan nd areal numb er so that the followingholds:
IP ( [ ]) 5 IN
1
0 1
X X
n
n
n
=
k k
n j
k
j
k
g
g g
g
j
k
n g
u
k
n
k
u
k
n
k
n n
0 0
2
1
1 0
0 1
4 4 1
1 2
1 0
0
0 1
0 0 1
0
0 1
0
=0
1
=0
2
0 1
0 p
f 1 g
f 01 g
^
0
d 0 e
f g
j 0 j 2
^ 01 ^ 1
2
01 1
f j g f g f g
f 01 g f 1 g
W
= n
! W ; a ; n n = :
a
! W ; ;a n n
a ;a
= K
I a k ;a k I a
k
;a
k
k u a a =
! W ;I P I n n k u j ;
g L
s;t Ls t s;t a ;a
L
;a a ;
s;t s;t I
k u ;a a ;
! W ; ! W ;I ! W ;I
! W ; ;a ! W ; a ;
n n
Nowweuse thefactthatthejumpsofalmostallpathsof areuniformlyb ounded
by 1 and apply Remark4. That leads to the inequality:
IP ( [ ]) for all :=1
In the sameway one can nd a real numb er for the left edge with the prop erty:
IP ( [ ]) for all
Thereforeitjust remainsto treat themo dulus ofcontinuityon the compact[ ].
We dene:
~
:= ( ) 5 1 and intervals
:=[ +
~
+( +1)
~
] :=[ +
(2 1)
~
2
+
(2 +1)
~
2
] (0 := ( )
~
)
We use Prop osition 1and the Remarks3 and 4to conclude:
IP ( ) ( ) for all (0 ; =1 2)
(detailscan b e found b elow). Now by the prop ertiesof we can nd aconstant
with ( ) for all [ ]. Ifwedene
:=(
~
2
) ( ) ( + )
we know that two p oints IR with ( ) lie in one of the intervals
(0 ), [ ] or [ ]. Therefore we can write:
IP ( ) IP ( ) + IP ( )
+IP ( [ ]) +IP ( [ ])
4
(for all )
.
.
0 0
(
X
)
X
X
X X
_ j 0 j
j 0 j _ j 0 j
j 0 j
F
p
I
f 2 g f 2 g
f ^ g
+1 +1
+1
= +2
+1
+1 +1
+1
= +2
IR
1 1
4
2 2
4 2
1
4 2
2 2
Proof of inequality 4.3
Proof of inequality 4.4
l
l
! W ;J ! W ;J ! W ;I W k ;k
! W ;I W k ;k ! W ;I W k ;k
! W ;I W k ;k
W
= n
I J
U X I V X J
W I W J
W I W J
n
UU V V
n
UU V V V U
n l ;m n l;m n l ;m n
a k l
n k ;m
l
k a
n n l ;m n
a k l
n k ;m
l
k a n
n cadlag
i i i i i i
n n n n
i;j;k ;l n
i j k l
i j
k
i j
k We use induction over . The start of induction is
trivial. Supp ose nowthat the resultholds for each integer up to . That implies:
~( ) ~( ) ~( )+ (] 1 ])
(seethe pro of ofinequality 4.2)
max ~( ) + (] 1 ]) ~( )+ (] 1 ])
max ~( ) + (] 1 ])
Weknowthatthepathsof are elementsof
and that the jumpsof almost allof themare b ounded by 1 . Therefore we just
haveto show that Prop osition 1 is applicable on arbitrary nite subsets of the real
line.
Thussupp ose that and are intervalsin . With
:=1 sign :=1 sign
we get:
IP ( ) ( )
1
IE ( ) ( )
= 1
IE
= 1
IE +IE
1
1 1
0
0
0
0
0
0
0
0
0
0
0
Acknowledgements X
X
X
X
X
X
X
j j
0
0
f ^ g _ [
j [ j [
jj 1
2
1
=1 2
2
2
=1 2
2 2
1 2
2
=1 2
2
2
2
1 2
2
2
=1 2
2
1
2
=1 2
1
2
4
4
4 i;j<k
i j
k
k
i i
k
k
i i
k k k
k
i i
k k
k k
k
c
k
i
i c
k
c k
i
i
c
c
i;j<k i j
k
c
n n c c
c c
k n
UU V U V
U V U V
U V X U V X
P J U P J U
P J U P J P I
k P J P I
V V U k P I P J
k
W I W J
P I P J P I J
P J P I P I P J
I J P I J
: P : M M
For xed wecan conclude:
IE =IE
2IE +2IE
=2IE IE( )+2IE IE( )
2 ( )IE +2 ( )IE
2 ( ) IE +2 ( ) ( )
2( 1) ( ) ( )
The sameargumentationapplied to the second sumleads to:
IE 2( 1) ( ) ( )
Summing over we nd
IP ( ) ( )
1
( ) ( ) ( )
1
( ) ( )+ ( ) ( )
1
( )
The setfunction ()is -subadditivewith :=2 . One gets thisconstant
by halving the intervallsaccordingto Leb esgues measure.
The content of this pap er is part of my diploma thesis on which I am working
right now. I want to thank my advisor, Lutz D umbgen, for his patience with my
sillyquestions,formanyhelpfulsuggestionsandingeneralforhisp erfectadvice. In
addition I would like to thank Hira Koul for drawing my attention to his preprint
59 W
A
I
References
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[5] Koul,H.L.andStute,W.(1991).Nonparametricmo delchecksfortimeseries.Preprint.
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